One-Sided Notion of Topological Closure

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Has the following notion already been studied? I am really stuck on a problem that seems to require some general results concerning this:



Let $A$ be a subspace of $mathbbR$. Define an operation called 'left closure' to be $lcl(A)$, that sends $A$ to the subset



$lbrace x in mathbbR : text there exist y_n in A text s.t. y_n leq x$ $forall$ $n text and y_n rightarrow x rbrace$



So this is like the left-sided closure of $A$; it contains all the points that $A$ 'converges to' from the left. We can define $rcl(A)$ similarly. I am wondering what the best way to think about these objects is. There seem like too many choices. In my particular situation, I am dealing with topologically unpleasant objects (uncountable unions of pw-disjoint Cantor Sets), so anything that is well suited to such applications is preferable.



To ask more of a question than a reference request, what can be said about infinite unions of Cantor sets, either countably or uncountable? Anything that falls out of the definition?



The problem that I am especially interested in is this: If $C$ is the union of an uncountable collection of pw disjoint Cantor Sets $C_alpha$, is it possible to apply an order to the indices taking values from $[0,1]$ so that the union of $C_alpha, 0 leq alpha leq alpha_0$ is right-closed in $C$ for any fixed $alpha_0$? That is to say that any collection of sets 'to the left' of some $C_alpha_0$ doesn't accumulate to one of its points from the right.



Thanks! I tagged some topics that seem most likely to contribute, but if anyone has other suggestions, then that would also be helpful.







share|cite|improve this question





















  • I don't understand the question. What do you mean by "what can be said about infinite unions of Cantor sets"? What are "these objects"? What would "fall out" of which definition?
    – tomasz
    Aug 7 at 0:08











  • What are some rules for how families of Cantor Sets can left-converge onto each other? For example, is it possible to place an order on an uncountable collection of Cantor Sets so that only predecessors can converge from the left onto a point of some fixed Cantor Set? For example, see this problem. math.stackexchange.com/questions/2872483/…
    – John Samples
    Aug 7 at 2:22











  • Yeah. I still don't get it. If you want anyone to answer the question, I think you need to make it more precise.
    – tomasz
    Aug 7 at 12:11










  • Suppose instead of Cantor set, you say "Uncountable nowhere-dense perfect set". Do you really want $C$ to be a collection of isometric copies of "the" Cantor set?
    – DanielWainfleet
    Aug 7 at 16:03










  • No no, not isometric copies. Just topological homeomorphs.
    – John Samples
    Aug 7 at 20:10














up vote
2
down vote

favorite












Has the following notion already been studied? I am really stuck on a problem that seems to require some general results concerning this:



Let $A$ be a subspace of $mathbbR$. Define an operation called 'left closure' to be $lcl(A)$, that sends $A$ to the subset



$lbrace x in mathbbR : text there exist y_n in A text s.t. y_n leq x$ $forall$ $n text and y_n rightarrow x rbrace$



So this is like the left-sided closure of $A$; it contains all the points that $A$ 'converges to' from the left. We can define $rcl(A)$ similarly. I am wondering what the best way to think about these objects is. There seem like too many choices. In my particular situation, I am dealing with topologically unpleasant objects (uncountable unions of pw-disjoint Cantor Sets), so anything that is well suited to such applications is preferable.



To ask more of a question than a reference request, what can be said about infinite unions of Cantor sets, either countably or uncountable? Anything that falls out of the definition?



The problem that I am especially interested in is this: If $C$ is the union of an uncountable collection of pw disjoint Cantor Sets $C_alpha$, is it possible to apply an order to the indices taking values from $[0,1]$ so that the union of $C_alpha, 0 leq alpha leq alpha_0$ is right-closed in $C$ for any fixed $alpha_0$? That is to say that any collection of sets 'to the left' of some $C_alpha_0$ doesn't accumulate to one of its points from the right.



Thanks! I tagged some topics that seem most likely to contribute, but if anyone has other suggestions, then that would also be helpful.







share|cite|improve this question





















  • I don't understand the question. What do you mean by "what can be said about infinite unions of Cantor sets"? What are "these objects"? What would "fall out" of which definition?
    – tomasz
    Aug 7 at 0:08











  • What are some rules for how families of Cantor Sets can left-converge onto each other? For example, is it possible to place an order on an uncountable collection of Cantor Sets so that only predecessors can converge from the left onto a point of some fixed Cantor Set? For example, see this problem. math.stackexchange.com/questions/2872483/…
    – John Samples
    Aug 7 at 2:22











  • Yeah. I still don't get it. If you want anyone to answer the question, I think you need to make it more precise.
    – tomasz
    Aug 7 at 12:11










  • Suppose instead of Cantor set, you say "Uncountable nowhere-dense perfect set". Do you really want $C$ to be a collection of isometric copies of "the" Cantor set?
    – DanielWainfleet
    Aug 7 at 16:03










  • No no, not isometric copies. Just topological homeomorphs.
    – John Samples
    Aug 7 at 20:10












up vote
2
down vote

favorite









up vote
2
down vote

favorite











Has the following notion already been studied? I am really stuck on a problem that seems to require some general results concerning this:



Let $A$ be a subspace of $mathbbR$. Define an operation called 'left closure' to be $lcl(A)$, that sends $A$ to the subset



$lbrace x in mathbbR : text there exist y_n in A text s.t. y_n leq x$ $forall$ $n text and y_n rightarrow x rbrace$



So this is like the left-sided closure of $A$; it contains all the points that $A$ 'converges to' from the left. We can define $rcl(A)$ similarly. I am wondering what the best way to think about these objects is. There seem like too many choices. In my particular situation, I am dealing with topologically unpleasant objects (uncountable unions of pw-disjoint Cantor Sets), so anything that is well suited to such applications is preferable.



To ask more of a question than a reference request, what can be said about infinite unions of Cantor sets, either countably or uncountable? Anything that falls out of the definition?



The problem that I am especially interested in is this: If $C$ is the union of an uncountable collection of pw disjoint Cantor Sets $C_alpha$, is it possible to apply an order to the indices taking values from $[0,1]$ so that the union of $C_alpha, 0 leq alpha leq alpha_0$ is right-closed in $C$ for any fixed $alpha_0$? That is to say that any collection of sets 'to the left' of some $C_alpha_0$ doesn't accumulate to one of its points from the right.



Thanks! I tagged some topics that seem most likely to contribute, but if anyone has other suggestions, then that would also be helpful.







share|cite|improve this question













Has the following notion already been studied? I am really stuck on a problem that seems to require some general results concerning this:



Let $A$ be a subspace of $mathbbR$. Define an operation called 'left closure' to be $lcl(A)$, that sends $A$ to the subset



$lbrace x in mathbbR : text there exist y_n in A text s.t. y_n leq x$ $forall$ $n text and y_n rightarrow x rbrace$



So this is like the left-sided closure of $A$; it contains all the points that $A$ 'converges to' from the left. We can define $rcl(A)$ similarly. I am wondering what the best way to think about these objects is. There seem like too many choices. In my particular situation, I am dealing with topologically unpleasant objects (uncountable unions of pw-disjoint Cantor Sets), so anything that is well suited to such applications is preferable.



To ask more of a question than a reference request, what can be said about infinite unions of Cantor sets, either countably or uncountable? Anything that falls out of the definition?



The problem that I am especially interested in is this: If $C$ is the union of an uncountable collection of pw disjoint Cantor Sets $C_alpha$, is it possible to apply an order to the indices taking values from $[0,1]$ so that the union of $C_alpha, 0 leq alpha leq alpha_0$ is right-closed in $C$ for any fixed $alpha_0$? That is to say that any collection of sets 'to the left' of some $C_alpha_0$ doesn't accumulate to one of its points from the right.



Thanks! I tagged some topics that seem most likely to contribute, but if anyone has other suggestions, then that would also be helpful.









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Aug 7 at 6:07
























asked Aug 6 at 23:08









John Samples

1,011416




1,011416











  • I don't understand the question. What do you mean by "what can be said about infinite unions of Cantor sets"? What are "these objects"? What would "fall out" of which definition?
    – tomasz
    Aug 7 at 0:08











  • What are some rules for how families of Cantor Sets can left-converge onto each other? For example, is it possible to place an order on an uncountable collection of Cantor Sets so that only predecessors can converge from the left onto a point of some fixed Cantor Set? For example, see this problem. math.stackexchange.com/questions/2872483/…
    – John Samples
    Aug 7 at 2:22











  • Yeah. I still don't get it. If you want anyone to answer the question, I think you need to make it more precise.
    – tomasz
    Aug 7 at 12:11










  • Suppose instead of Cantor set, you say "Uncountable nowhere-dense perfect set". Do you really want $C$ to be a collection of isometric copies of "the" Cantor set?
    – DanielWainfleet
    Aug 7 at 16:03










  • No no, not isometric copies. Just topological homeomorphs.
    – John Samples
    Aug 7 at 20:10
















  • I don't understand the question. What do you mean by "what can be said about infinite unions of Cantor sets"? What are "these objects"? What would "fall out" of which definition?
    – tomasz
    Aug 7 at 0:08











  • What are some rules for how families of Cantor Sets can left-converge onto each other? For example, is it possible to place an order on an uncountable collection of Cantor Sets so that only predecessors can converge from the left onto a point of some fixed Cantor Set? For example, see this problem. math.stackexchange.com/questions/2872483/…
    – John Samples
    Aug 7 at 2:22











  • Yeah. I still don't get it. If you want anyone to answer the question, I think you need to make it more precise.
    – tomasz
    Aug 7 at 12:11










  • Suppose instead of Cantor set, you say "Uncountable nowhere-dense perfect set". Do you really want $C$ to be a collection of isometric copies of "the" Cantor set?
    – DanielWainfleet
    Aug 7 at 16:03










  • No no, not isometric copies. Just topological homeomorphs.
    – John Samples
    Aug 7 at 20:10















I don't understand the question. What do you mean by "what can be said about infinite unions of Cantor sets"? What are "these objects"? What would "fall out" of which definition?
– tomasz
Aug 7 at 0:08





I don't understand the question. What do you mean by "what can be said about infinite unions of Cantor sets"? What are "these objects"? What would "fall out" of which definition?
– tomasz
Aug 7 at 0:08













What are some rules for how families of Cantor Sets can left-converge onto each other? For example, is it possible to place an order on an uncountable collection of Cantor Sets so that only predecessors can converge from the left onto a point of some fixed Cantor Set? For example, see this problem. math.stackexchange.com/questions/2872483/…
– John Samples
Aug 7 at 2:22





What are some rules for how families of Cantor Sets can left-converge onto each other? For example, is it possible to place an order on an uncountable collection of Cantor Sets so that only predecessors can converge from the left onto a point of some fixed Cantor Set? For example, see this problem. math.stackexchange.com/questions/2872483/…
– John Samples
Aug 7 at 2:22













Yeah. I still don't get it. If you want anyone to answer the question, I think you need to make it more precise.
– tomasz
Aug 7 at 12:11




Yeah. I still don't get it. If you want anyone to answer the question, I think you need to make it more precise.
– tomasz
Aug 7 at 12:11












Suppose instead of Cantor set, you say "Uncountable nowhere-dense perfect set". Do you really want $C$ to be a collection of isometric copies of "the" Cantor set?
– DanielWainfleet
Aug 7 at 16:03




Suppose instead of Cantor set, you say "Uncountable nowhere-dense perfect set". Do you really want $C$ to be a collection of isometric copies of "the" Cantor set?
– DanielWainfleet
Aug 7 at 16:03












No no, not isometric copies. Just topological homeomorphs.
– John Samples
Aug 7 at 20:10




No no, not isometric copies. Just topological homeomorphs.
– John Samples
Aug 7 at 20:10















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