Boat Word Problem
Clash Royale CLAN TAG#URR8PPP
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0
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A crew can row a certain course upstream in 84 minutes;
they can row the same course down stream in 9 minutes less than
they can row it in still water: how long would they take to row
down with the stream.
The equations I came up with are:
$$fracdx - y = 84$$
$$fracdx + y = fracdx - 9$$
Where $d$ is the distance covered in their course, $x$ is the rate of the people rowing the boat, and $y$ is the rate of the stream.
I tried substituting $d$ with $84(x -y)$, and that rendered the equation $3x^2 - 25xy + 28y^2 = 0$. As far as I know, this equation isn't solvable. Any attempts I make to obtain other equations or results leads to this same equation.
If there's any alternate method to solving this, I would love to know.
Thanks.
word-problem
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up vote
0
down vote
favorite
A crew can row a certain course upstream in 84 minutes;
they can row the same course down stream in 9 minutes less than
they can row it in still water: how long would they take to row
down with the stream.
The equations I came up with are:
$$fracdx - y = 84$$
$$fracdx + y = fracdx - 9$$
Where $d$ is the distance covered in their course, $x$ is the rate of the people rowing the boat, and $y$ is the rate of the stream.
I tried substituting $d$ with $84(x -y)$, and that rendered the equation $3x^2 - 25xy + 28y^2 = 0$. As far as I know, this equation isn't solvable. Any attempts I make to obtain other equations or results leads to this same equation.
If there's any alternate method to solving this, I would love to know.
Thanks.
word-problem
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
A crew can row a certain course upstream in 84 minutes;
they can row the same course down stream in 9 minutes less than
they can row it in still water: how long would they take to row
down with the stream.
The equations I came up with are:
$$fracdx - y = 84$$
$$fracdx + y = fracdx - 9$$
Where $d$ is the distance covered in their course, $x$ is the rate of the people rowing the boat, and $y$ is the rate of the stream.
I tried substituting $d$ with $84(x -y)$, and that rendered the equation $3x^2 - 25xy + 28y^2 = 0$. As far as I know, this equation isn't solvable. Any attempts I make to obtain other equations or results leads to this same equation.
If there's any alternate method to solving this, I would love to know.
Thanks.
word-problem
A crew can row a certain course upstream in 84 minutes;
they can row the same course down stream in 9 minutes less than
they can row it in still water: how long would they take to row
down with the stream.
The equations I came up with are:
$$fracdx - y = 84$$
$$fracdx + y = fracdx - 9$$
Where $d$ is the distance covered in their course, $x$ is the rate of the people rowing the boat, and $y$ is the rate of the stream.
I tried substituting $d$ with $84(x -y)$, and that rendered the equation $3x^2 - 25xy + 28y^2 = 0$. As far as I know, this equation isn't solvable. Any attempts I make to obtain other equations or results leads to this same equation.
If there's any alternate method to solving this, I would love to know.
Thanks.
word-problem
edited 7 hours ago
asked 7 hours ago
A Silent Cat
1227
1227
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2 Answers
2
active
oldest
votes
up vote
1
down vote
accepted
That equation is perfectly solvable. You're implicitly assuming $x$ and $y$ are non-negative from the way you've structured your equations, so you can fix a non-negative $y$ and try and figure out if there exists a positive solution $x$. That is, if we fix $y$, then
$$3x^2-75yx+28y^2=0$$
is a regular old quadratic equation in $x$. The solution will be some formula involving $y$, and you can check for which $y$ that formula gives a positive real number.
Can't believe I didn't realize that...Thanks.
– A Silent Cat
7 hours ago
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up vote
0
down vote
HINT
Your task is not to figure out $d,x,$ or $y$, your task is to figure out how long it takes the crew to go down with the stream.
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
That equation is perfectly solvable. You're implicitly assuming $x$ and $y$ are non-negative from the way you've structured your equations, so you can fix a non-negative $y$ and try and figure out if there exists a positive solution $x$. That is, if we fix $y$, then
$$3x^2-75yx+28y^2=0$$
is a regular old quadratic equation in $x$. The solution will be some formula involving $y$, and you can check for which $y$ that formula gives a positive real number.
Can't believe I didn't realize that...Thanks.
– A Silent Cat
7 hours ago
add a comment |Â
up vote
1
down vote
accepted
That equation is perfectly solvable. You're implicitly assuming $x$ and $y$ are non-negative from the way you've structured your equations, so you can fix a non-negative $y$ and try and figure out if there exists a positive solution $x$. That is, if we fix $y$, then
$$3x^2-75yx+28y^2=0$$
is a regular old quadratic equation in $x$. The solution will be some formula involving $y$, and you can check for which $y$ that formula gives a positive real number.
Can't believe I didn't realize that...Thanks.
– A Silent Cat
7 hours ago
add a comment |Â
up vote
1
down vote
accepted
up vote
1
down vote
accepted
That equation is perfectly solvable. You're implicitly assuming $x$ and $y$ are non-negative from the way you've structured your equations, so you can fix a non-negative $y$ and try and figure out if there exists a positive solution $x$. That is, if we fix $y$, then
$$3x^2-75yx+28y^2=0$$
is a regular old quadratic equation in $x$. The solution will be some formula involving $y$, and you can check for which $y$ that formula gives a positive real number.
That equation is perfectly solvable. You're implicitly assuming $x$ and $y$ are non-negative from the way you've structured your equations, so you can fix a non-negative $y$ and try and figure out if there exists a positive solution $x$. That is, if we fix $y$, then
$$3x^2-75yx+28y^2=0$$
is a regular old quadratic equation in $x$. The solution will be some formula involving $y$, and you can check for which $y$ that formula gives a positive real number.
answered 7 hours ago
Jack M
16.9k33473
16.9k33473
Can't believe I didn't realize that...Thanks.
– A Silent Cat
7 hours ago
add a comment |Â
Can't believe I didn't realize that...Thanks.
– A Silent Cat
7 hours ago
Can't believe I didn't realize that...Thanks.
– A Silent Cat
7 hours ago
Can't believe I didn't realize that...Thanks.
– A Silent Cat
7 hours ago
add a comment |Â
up vote
0
down vote
HINT
Your task is not to figure out $d,x,$ or $y$, your task is to figure out how long it takes the crew to go down with the stream.
add a comment |Â
up vote
0
down vote
HINT
Your task is not to figure out $d,x,$ or $y$, your task is to figure out how long it takes the crew to go down with the stream.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
HINT
Your task is not to figure out $d,x,$ or $y$, your task is to figure out how long it takes the crew to go down with the stream.
HINT
Your task is not to figure out $d,x,$ or $y$, your task is to figure out how long it takes the crew to go down with the stream.
answered 7 hours ago
Bram28
54.5k33776
54.5k33776
add a comment |Â
add a comment |Â
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