Boat Word Problem

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A crew can row a certain course upstream in 84 minutes;
they can row the same course down stream in 9 minutes less than
they can row it in still water: how long would they take to row
down with the stream.




The equations I came up with are:



$$fracdx - y = 84$$
$$fracdx + y = fracdx - 9$$



Where $d$ is the distance covered in their course, $x$ is the rate of the people rowing the boat, and $y$ is the rate of the stream.



I tried substituting $d$ with $84(x -y)$, and that rendered the equation $3x^2 - 25xy + 28y^2 = 0$. As far as I know, this equation isn't solvable. Any attempts I make to obtain other equations or results leads to this same equation.



If there's any alternate method to solving this, I would love to know.



Thanks.







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    up vote
    0
    down vote

    favorite













    A crew can row a certain course upstream in 84 minutes;
    they can row the same course down stream in 9 minutes less than
    they can row it in still water: how long would they take to row
    down with the stream.




    The equations I came up with are:



    $$fracdx - y = 84$$
    $$fracdx + y = fracdx - 9$$



    Where $d$ is the distance covered in their course, $x$ is the rate of the people rowing the boat, and $y$ is the rate of the stream.



    I tried substituting $d$ with $84(x -y)$, and that rendered the equation $3x^2 - 25xy + 28y^2 = 0$. As far as I know, this equation isn't solvable. Any attempts I make to obtain other equations or results leads to this same equation.



    If there's any alternate method to solving this, I would love to know.



    Thanks.







    share|cite|improve this question























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite












      A crew can row a certain course upstream in 84 minutes;
      they can row the same course down stream in 9 minutes less than
      they can row it in still water: how long would they take to row
      down with the stream.




      The equations I came up with are:



      $$fracdx - y = 84$$
      $$fracdx + y = fracdx - 9$$



      Where $d$ is the distance covered in their course, $x$ is the rate of the people rowing the boat, and $y$ is the rate of the stream.



      I tried substituting $d$ with $84(x -y)$, and that rendered the equation $3x^2 - 25xy + 28y^2 = 0$. As far as I know, this equation isn't solvable. Any attempts I make to obtain other equations or results leads to this same equation.



      If there's any alternate method to solving this, I would love to know.



      Thanks.







      share|cite|improve this question














      A crew can row a certain course upstream in 84 minutes;
      they can row the same course down stream in 9 minutes less than
      they can row it in still water: how long would they take to row
      down with the stream.




      The equations I came up with are:



      $$fracdx - y = 84$$
      $$fracdx + y = fracdx - 9$$



      Where $d$ is the distance covered in their course, $x$ is the rate of the people rowing the boat, and $y$ is the rate of the stream.



      I tried substituting $d$ with $84(x -y)$, and that rendered the equation $3x^2 - 25xy + 28y^2 = 0$. As far as I know, this equation isn't solvable. Any attempts I make to obtain other equations or results leads to this same equation.



      If there's any alternate method to solving this, I would love to know.



      Thanks.









      share|cite|improve this question












      share|cite|improve this question




      share|cite|improve this question








      edited 7 hours ago
























      asked 7 hours ago









      A Silent Cat

      1227




      1227




















          2 Answers
          2






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          up vote
          1
          down vote



          accepted










          That equation is perfectly solvable. You're implicitly assuming $x$ and $y$ are non-negative from the way you've structured your equations, so you can fix a non-negative $y$ and try and figure out if there exists a positive solution $x$. That is, if we fix $y$, then



          $$3x^2-75yx+28y^2=0$$



          is a regular old quadratic equation in $x$. The solution will be some formula involving $y$, and you can check for which $y$ that formula gives a positive real number.






          share|cite|improve this answer





















          • Can't believe I didn't realize that...Thanks.
            – A Silent Cat
            7 hours ago

















          up vote
          0
          down vote













          HINT



          Your task is not to figure out $d,x,$ or $y$, your task is to figure out how long it takes the crew to go down with the stream.






          share|cite|improve this answer





















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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            1
            down vote



            accepted










            That equation is perfectly solvable. You're implicitly assuming $x$ and $y$ are non-negative from the way you've structured your equations, so you can fix a non-negative $y$ and try and figure out if there exists a positive solution $x$. That is, if we fix $y$, then



            $$3x^2-75yx+28y^2=0$$



            is a regular old quadratic equation in $x$. The solution will be some formula involving $y$, and you can check for which $y$ that formula gives a positive real number.






            share|cite|improve this answer





















            • Can't believe I didn't realize that...Thanks.
              – A Silent Cat
              7 hours ago














            up vote
            1
            down vote



            accepted










            That equation is perfectly solvable. You're implicitly assuming $x$ and $y$ are non-negative from the way you've structured your equations, so you can fix a non-negative $y$ and try and figure out if there exists a positive solution $x$. That is, if we fix $y$, then



            $$3x^2-75yx+28y^2=0$$



            is a regular old quadratic equation in $x$. The solution will be some formula involving $y$, and you can check for which $y$ that formula gives a positive real number.






            share|cite|improve this answer





















            • Can't believe I didn't realize that...Thanks.
              – A Silent Cat
              7 hours ago












            up vote
            1
            down vote



            accepted







            up vote
            1
            down vote



            accepted






            That equation is perfectly solvable. You're implicitly assuming $x$ and $y$ are non-negative from the way you've structured your equations, so you can fix a non-negative $y$ and try and figure out if there exists a positive solution $x$. That is, if we fix $y$, then



            $$3x^2-75yx+28y^2=0$$



            is a regular old quadratic equation in $x$. The solution will be some formula involving $y$, and you can check for which $y$ that formula gives a positive real number.






            share|cite|improve this answer













            That equation is perfectly solvable. You're implicitly assuming $x$ and $y$ are non-negative from the way you've structured your equations, so you can fix a non-negative $y$ and try and figure out if there exists a positive solution $x$. That is, if we fix $y$, then



            $$3x^2-75yx+28y^2=0$$



            is a regular old quadratic equation in $x$. The solution will be some formula involving $y$, and you can check for which $y$ that formula gives a positive real number.







            share|cite|improve this answer













            share|cite|improve this answer



            share|cite|improve this answer











            answered 7 hours ago









            Jack M

            16.9k33473




            16.9k33473











            • Can't believe I didn't realize that...Thanks.
              – A Silent Cat
              7 hours ago
















            • Can't believe I didn't realize that...Thanks.
              – A Silent Cat
              7 hours ago















            Can't believe I didn't realize that...Thanks.
            – A Silent Cat
            7 hours ago




            Can't believe I didn't realize that...Thanks.
            – A Silent Cat
            7 hours ago










            up vote
            0
            down vote













            HINT



            Your task is not to figure out $d,x,$ or $y$, your task is to figure out how long it takes the crew to go down with the stream.






            share|cite|improve this answer

























              up vote
              0
              down vote













              HINT



              Your task is not to figure out $d,x,$ or $y$, your task is to figure out how long it takes the crew to go down with the stream.






              share|cite|improve this answer























                up vote
                0
                down vote










                up vote
                0
                down vote









                HINT



                Your task is not to figure out $d,x,$ or $y$, your task is to figure out how long it takes the crew to go down with the stream.






                share|cite|improve this answer













                HINT



                Your task is not to figure out $d,x,$ or $y$, your task is to figure out how long it takes the crew to go down with the stream.







                share|cite|improve this answer













                share|cite|improve this answer



                share|cite|improve this answer











                answered 7 hours ago









                Bram28

                54.5k33776




                54.5k33776






















                     

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