Inclusion of Reflective Subcategory Creates Limits
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(Full) subcategory $D$ of the category $C$ is called reflexive if there exists a localization functor $L : C to D$ and it is left adjoint to the inclusion functor $I : D hookrightarrow C$.
There is theorem:
If $D$ is a reflective subcategory of $C$, then $I$ creates all limits that $C$ admits.
But if this theorem is true, then every diagram $x: I toD$, which admits a limit $y = lim_i in I Ix_i $, will also have a limit in $D$. But as inclusion $I$ is right adjoint, it preserves limits, and so $y = IBig(lim_i in I x_i Big)$. Then, as $y$ is included into $C$, it must hold that $lim_i in I x_i = Ly cong y$. But, I don't know how to prove this fact, as $L$ only preserves colimits.
I can prove that $Ly$ indeed forms a cone over $x$ and for any other cone $c$
there exists a morphism $psi: c to Ly$, but I don't know how to prove uniqueness.
I construct $psi$ as $Lphi$, there $phi: Ic to y$, which exists by universal property of limit $y$.
What am I missing here? áan you help me prove uniqueness?
category-theory localization adjoint-functors
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up vote
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$
newcommandCmathcalC
newcommandDmathcalD
newcommandImathcalI
$
(Full) subcategory $D$ of the category $C$ is called reflexive if there exists a localization functor $L : C to D$ and it is left adjoint to the inclusion functor $I : D hookrightarrow C$.
There is theorem:
If $D$ is a reflective subcategory of $C$, then $I$ creates all limits that $C$ admits.
But if this theorem is true, then every diagram $x: I toD$, which admits a limit $y = lim_i in I Ix_i $, will also have a limit in $D$. But as inclusion $I$ is right adjoint, it preserves limits, and so $y = IBig(lim_i in I x_i Big)$. Then, as $y$ is included into $C$, it must hold that $lim_i in I x_i = Ly cong y$. But, I don't know how to prove this fact, as $L$ only preserves colimits.
I can prove that $Ly$ indeed forms a cone over $x$ and for any other cone $c$
there exists a morphism $psi: c to Ly$, but I don't know how to prove uniqueness.
I construct $psi$ as $Lphi$, there $phi: Ic to y$, which exists by universal property of limit $y$.
What am I missing here? áan you help me prove uniqueness?
category-theory localization adjoint-functors
add a comment |Â
up vote
2
down vote
favorite
up vote
2
down vote
favorite
$
newcommandCmathcalC
newcommandDmathcalD
newcommandImathcalI
$
(Full) subcategory $D$ of the category $C$ is called reflexive if there exists a localization functor $L : C to D$ and it is left adjoint to the inclusion functor $I : D hookrightarrow C$.
There is theorem:
If $D$ is a reflective subcategory of $C$, then $I$ creates all limits that $C$ admits.
But if this theorem is true, then every diagram $x: I toD$, which admits a limit $y = lim_i in I Ix_i $, will also have a limit in $D$. But as inclusion $I$ is right adjoint, it preserves limits, and so $y = IBig(lim_i in I x_i Big)$. Then, as $y$ is included into $C$, it must hold that $lim_i in I x_i = Ly cong y$. But, I don't know how to prove this fact, as $L$ only preserves colimits.
I can prove that $Ly$ indeed forms a cone over $x$ and for any other cone $c$
there exists a morphism $psi: c to Ly$, but I don't know how to prove uniqueness.
I construct $psi$ as $Lphi$, there $phi: Ic to y$, which exists by universal property of limit $y$.
What am I missing here? áan you help me prove uniqueness?
category-theory localization adjoint-functors
$
newcommandCmathcalC
newcommandDmathcalD
newcommandImathcalI
$
(Full) subcategory $D$ of the category $C$ is called reflexive if there exists a localization functor $L : C to D$ and it is left adjoint to the inclusion functor $I : D hookrightarrow C$.
There is theorem:
If $D$ is a reflective subcategory of $C$, then $I$ creates all limits that $C$ admits.
But if this theorem is true, then every diagram $x: I toD$, which admits a limit $y = lim_i in I Ix_i $, will also have a limit in $D$. But as inclusion $I$ is right adjoint, it preserves limits, and so $y = IBig(lim_i in I x_i Big)$. Then, as $y$ is included into $C$, it must hold that $lim_i in I x_i = Ly cong y$. But, I don't know how to prove this fact, as $L$ only preserves colimits.
I can prove that $Ly$ indeed forms a cone over $x$ and for any other cone $c$
there exists a morphism $psi: c to Ly$, but I don't know how to prove uniqueness.
I construct $psi$ as $Lphi$, there $phi: Ic to y$, which exists by universal property of limit $y$.
What am I missing here? áan you help me prove uniqueness?
category-theory localization adjoint-functors
edited 14 hours ago
asked 14 hours ago
Nik Pronko
678617
678617
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Let the adjunction take the form of a natural isomorphism $Psi: textHom_D(L(-),-)cong textHom_D(-,I(-))$ between functors mapping $C^textoptimes DtotextbfSet$. Let $x:mathcal Ito D$ be a functor, and suppose $Ix:mathcal Ito C$ has a limit given by the cone $mathcal K=lim(Ix)oversetpi_ilongrightarrow IX(i), iintextOb(mathcal I)$.
Lemma: $forall dintextOb(D), exists eta_d: LI(d)cong d$, and this correspondence is natural in $d$. In other words, $LI$ and $textid_D$ are naturally isomorphic as functors.
Fullness of the inclusion functor $I$ gives canonical isomorphisms $$textHom_D(LI(d_1),d_2)cong textHom_C(LI(d_1),I(d_2))oversetPsicong textHom_C(I(d_1),d_2) cong textHom_D(d_1,d_2)$$ Natural in pairs $left<d_1,d_2right>intextOb(D^textoptimes D)$. In particular, there is a natural mapping $$Psi_:textHom_D(LI(-),-)cong textHom_D(-,-)$$ Where $textHom_D(LI(-),-)$ and $textHom_D(-,-)$ are functors $D^textoptimes Dto textbfSet$. The existence of $eta$ follows by the Yoneda Lemma (or Yoneda Lemma-style arguments) $Box$
Conceptually, we want to show that $Lmathcal K$ "behaves" in $D$ as $mathcalK$ does in $D$, and in particular, that $L(lim(Ix))$ is itself the limit of $x$. After all, "pre-filling" the the left argument with $lim(Ix)intextOb(C)$ and discarding the "irrelevant" components of $Psi$ gives natural isomorphism $$Psi_lim(Ix):textHom_D(L(lim(Ix)),-)cong textHom_C(lim(Ix),I(-))$$ So the two should "see $D$ in the same way" in some sense.
Consider some arbitrary cone $K$ in $D$ over $x$ of the form $K=koversetp_ilongrightarrow X(i), iintextOb(mathcal I)$.
Passing this cone through $I$ gives another cone $IK=I(k)oversetIp_ilongrightarrow IX(i), iintextOb(mathcal I)$âÂÂthis time in $C$âÂÂover $Ix$. Definitionally there exists some (unique!) $C$-morphism $kappa:kto lim(IX)$ commuting with $IK$, $mathcal K$ and $Ix$. Passing everything "back into $D$" through $L$ gives $D$-morphism $Lkappa:LI(k)to L(lim(IX))$ commuting with $LIK$, $Lmathcal K$ and $LIx$.
Finally, applying $eta$ to $LIK$ and $LIX$ gives an arrow $kappacirc eta_k^-1:kto L(lim(IX))$ making cones $K$, $Lmathcal K$ and diagram $x$ commute. Uniqueness of $kappacirc eta_k^-1$ in this regard follows from fullness of $LI:Dto D$ and isomorphism of $eta^-1$.
So $Lmathcal K$ is in fact the limiting cone of $x:mathcal Ito C$, as desired $blacksquare$
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1 Answer
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1 Answer
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active
oldest
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active
oldest
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active
oldest
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up vote
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down vote
Let the adjunction take the form of a natural isomorphism $Psi: textHom_D(L(-),-)cong textHom_D(-,I(-))$ between functors mapping $C^textoptimes DtotextbfSet$. Let $x:mathcal Ito D$ be a functor, and suppose $Ix:mathcal Ito C$ has a limit given by the cone $mathcal K=lim(Ix)oversetpi_ilongrightarrow IX(i), iintextOb(mathcal I)$.
Lemma: $forall dintextOb(D), exists eta_d: LI(d)cong d$, and this correspondence is natural in $d$. In other words, $LI$ and $textid_D$ are naturally isomorphic as functors.
Fullness of the inclusion functor $I$ gives canonical isomorphisms $$textHom_D(LI(d_1),d_2)cong textHom_C(LI(d_1),I(d_2))oversetPsicong textHom_C(I(d_1),d_2) cong textHom_D(d_1,d_2)$$ Natural in pairs $left<d_1,d_2right>intextOb(D^textoptimes D)$. In particular, there is a natural mapping $$Psi_:textHom_D(LI(-),-)cong textHom_D(-,-)$$ Where $textHom_D(LI(-),-)$ and $textHom_D(-,-)$ are functors $D^textoptimes Dto textbfSet$. The existence of $eta$ follows by the Yoneda Lemma (or Yoneda Lemma-style arguments) $Box$
Conceptually, we want to show that $Lmathcal K$ "behaves" in $D$ as $mathcalK$ does in $D$, and in particular, that $L(lim(Ix))$ is itself the limit of $x$. After all, "pre-filling" the the left argument with $lim(Ix)intextOb(C)$ and discarding the "irrelevant" components of $Psi$ gives natural isomorphism $$Psi_lim(Ix):textHom_D(L(lim(Ix)),-)cong textHom_C(lim(Ix),I(-))$$ So the two should "see $D$ in the same way" in some sense.
Consider some arbitrary cone $K$ in $D$ over $x$ of the form $K=koversetp_ilongrightarrow X(i), iintextOb(mathcal I)$.
Passing this cone through $I$ gives another cone $IK=I(k)oversetIp_ilongrightarrow IX(i), iintextOb(mathcal I)$âÂÂthis time in $C$âÂÂover $Ix$. Definitionally there exists some (unique!) $C$-morphism $kappa:kto lim(IX)$ commuting with $IK$, $mathcal K$ and $Ix$. Passing everything "back into $D$" through $L$ gives $D$-morphism $Lkappa:LI(k)to L(lim(IX))$ commuting with $LIK$, $Lmathcal K$ and $LIx$.
Finally, applying $eta$ to $LIK$ and $LIX$ gives an arrow $kappacirc eta_k^-1:kto L(lim(IX))$ making cones $K$, $Lmathcal K$ and diagram $x$ commute. Uniqueness of $kappacirc eta_k^-1$ in this regard follows from fullness of $LI:Dto D$ and isomorphism of $eta^-1$.
So $Lmathcal K$ is in fact the limiting cone of $x:mathcal Ito C$, as desired $blacksquare$
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Let the adjunction take the form of a natural isomorphism $Psi: textHom_D(L(-),-)cong textHom_D(-,I(-))$ between functors mapping $C^textoptimes DtotextbfSet$. Let $x:mathcal Ito D$ be a functor, and suppose $Ix:mathcal Ito C$ has a limit given by the cone $mathcal K=lim(Ix)oversetpi_ilongrightarrow IX(i), iintextOb(mathcal I)$.
Lemma: $forall dintextOb(D), exists eta_d: LI(d)cong d$, and this correspondence is natural in $d$. In other words, $LI$ and $textid_D$ are naturally isomorphic as functors.
Fullness of the inclusion functor $I$ gives canonical isomorphisms $$textHom_D(LI(d_1),d_2)cong textHom_C(LI(d_1),I(d_2))oversetPsicong textHom_C(I(d_1),d_2) cong textHom_D(d_1,d_2)$$ Natural in pairs $left<d_1,d_2right>intextOb(D^textoptimes D)$. In particular, there is a natural mapping $$Psi_:textHom_D(LI(-),-)cong textHom_D(-,-)$$ Where $textHom_D(LI(-),-)$ and $textHom_D(-,-)$ are functors $D^textoptimes Dto textbfSet$. The existence of $eta$ follows by the Yoneda Lemma (or Yoneda Lemma-style arguments) $Box$
Conceptually, we want to show that $Lmathcal K$ "behaves" in $D$ as $mathcalK$ does in $D$, and in particular, that $L(lim(Ix))$ is itself the limit of $x$. After all, "pre-filling" the the left argument with $lim(Ix)intextOb(C)$ and discarding the "irrelevant" components of $Psi$ gives natural isomorphism $$Psi_lim(Ix):textHom_D(L(lim(Ix)),-)cong textHom_C(lim(Ix),I(-))$$ So the two should "see $D$ in the same way" in some sense.
Consider some arbitrary cone $K$ in $D$ over $x$ of the form $K=koversetp_ilongrightarrow X(i), iintextOb(mathcal I)$.
Passing this cone through $I$ gives another cone $IK=I(k)oversetIp_ilongrightarrow IX(i), iintextOb(mathcal I)$âÂÂthis time in $C$âÂÂover $Ix$. Definitionally there exists some (unique!) $C$-morphism $kappa:kto lim(IX)$ commuting with $IK$, $mathcal K$ and $Ix$. Passing everything "back into $D$" through $L$ gives $D$-morphism $Lkappa:LI(k)to L(lim(IX))$ commuting with $LIK$, $Lmathcal K$ and $LIx$.
Finally, applying $eta$ to $LIK$ and $LIX$ gives an arrow $kappacirc eta_k^-1:kto L(lim(IX))$ making cones $K$, $Lmathcal K$ and diagram $x$ commute. Uniqueness of $kappacirc eta_k^-1$ in this regard follows from fullness of $LI:Dto D$ and isomorphism of $eta^-1$.
So $Lmathcal K$ is in fact the limiting cone of $x:mathcal Ito C$, as desired $blacksquare$
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Let the adjunction take the form of a natural isomorphism $Psi: textHom_D(L(-),-)cong textHom_D(-,I(-))$ between functors mapping $C^textoptimes DtotextbfSet$. Let $x:mathcal Ito D$ be a functor, and suppose $Ix:mathcal Ito C$ has a limit given by the cone $mathcal K=lim(Ix)oversetpi_ilongrightarrow IX(i), iintextOb(mathcal I)$.
Lemma: $forall dintextOb(D), exists eta_d: LI(d)cong d$, and this correspondence is natural in $d$. In other words, $LI$ and $textid_D$ are naturally isomorphic as functors.
Fullness of the inclusion functor $I$ gives canonical isomorphisms $$textHom_D(LI(d_1),d_2)cong textHom_C(LI(d_1),I(d_2))oversetPsicong textHom_C(I(d_1),d_2) cong textHom_D(d_1,d_2)$$ Natural in pairs $left<d_1,d_2right>intextOb(D^textoptimes D)$. In particular, there is a natural mapping $$Psi_:textHom_D(LI(-),-)cong textHom_D(-,-)$$ Where $textHom_D(LI(-),-)$ and $textHom_D(-,-)$ are functors $D^textoptimes Dto textbfSet$. The existence of $eta$ follows by the Yoneda Lemma (or Yoneda Lemma-style arguments) $Box$
Conceptually, we want to show that $Lmathcal K$ "behaves" in $D$ as $mathcalK$ does in $D$, and in particular, that $L(lim(Ix))$ is itself the limit of $x$. After all, "pre-filling" the the left argument with $lim(Ix)intextOb(C)$ and discarding the "irrelevant" components of $Psi$ gives natural isomorphism $$Psi_lim(Ix):textHom_D(L(lim(Ix)),-)cong textHom_C(lim(Ix),I(-))$$ So the two should "see $D$ in the same way" in some sense.
Consider some arbitrary cone $K$ in $D$ over $x$ of the form $K=koversetp_ilongrightarrow X(i), iintextOb(mathcal I)$.
Passing this cone through $I$ gives another cone $IK=I(k)oversetIp_ilongrightarrow IX(i), iintextOb(mathcal I)$âÂÂthis time in $C$âÂÂover $Ix$. Definitionally there exists some (unique!) $C$-morphism $kappa:kto lim(IX)$ commuting with $IK$, $mathcal K$ and $Ix$. Passing everything "back into $D$" through $L$ gives $D$-morphism $Lkappa:LI(k)to L(lim(IX))$ commuting with $LIK$, $Lmathcal K$ and $LIx$.
Finally, applying $eta$ to $LIK$ and $LIX$ gives an arrow $kappacirc eta_k^-1:kto L(lim(IX))$ making cones $K$, $Lmathcal K$ and diagram $x$ commute. Uniqueness of $kappacirc eta_k^-1$ in this regard follows from fullness of $LI:Dto D$ and isomorphism of $eta^-1$.
So $Lmathcal K$ is in fact the limiting cone of $x:mathcal Ito C$, as desired $blacksquare$
Let the adjunction take the form of a natural isomorphism $Psi: textHom_D(L(-),-)cong textHom_D(-,I(-))$ between functors mapping $C^textoptimes DtotextbfSet$. Let $x:mathcal Ito D$ be a functor, and suppose $Ix:mathcal Ito C$ has a limit given by the cone $mathcal K=lim(Ix)oversetpi_ilongrightarrow IX(i), iintextOb(mathcal I)$.
Lemma: $forall dintextOb(D), exists eta_d: LI(d)cong d$, and this correspondence is natural in $d$. In other words, $LI$ and $textid_D$ are naturally isomorphic as functors.
Fullness of the inclusion functor $I$ gives canonical isomorphisms $$textHom_D(LI(d_1),d_2)cong textHom_C(LI(d_1),I(d_2))oversetPsicong textHom_C(I(d_1),d_2) cong textHom_D(d_1,d_2)$$ Natural in pairs $left<d_1,d_2right>intextOb(D^textoptimes D)$. In particular, there is a natural mapping $$Psi_:textHom_D(LI(-),-)cong textHom_D(-,-)$$ Where $textHom_D(LI(-),-)$ and $textHom_D(-,-)$ are functors $D^textoptimes Dto textbfSet$. The existence of $eta$ follows by the Yoneda Lemma (or Yoneda Lemma-style arguments) $Box$
Conceptually, we want to show that $Lmathcal K$ "behaves" in $D$ as $mathcalK$ does in $D$, and in particular, that $L(lim(Ix))$ is itself the limit of $x$. After all, "pre-filling" the the left argument with $lim(Ix)intextOb(C)$ and discarding the "irrelevant" components of $Psi$ gives natural isomorphism $$Psi_lim(Ix):textHom_D(L(lim(Ix)),-)cong textHom_C(lim(Ix),I(-))$$ So the two should "see $D$ in the same way" in some sense.
Consider some arbitrary cone $K$ in $D$ over $x$ of the form $K=koversetp_ilongrightarrow X(i), iintextOb(mathcal I)$.
Passing this cone through $I$ gives another cone $IK=I(k)oversetIp_ilongrightarrow IX(i), iintextOb(mathcal I)$âÂÂthis time in $C$âÂÂover $Ix$. Definitionally there exists some (unique!) $C$-morphism $kappa:kto lim(IX)$ commuting with $IK$, $mathcal K$ and $Ix$. Passing everything "back into $D$" through $L$ gives $D$-morphism $Lkappa:LI(k)to L(lim(IX))$ commuting with $LIK$, $Lmathcal K$ and $LIx$.
Finally, applying $eta$ to $LIK$ and $LIX$ gives an arrow $kappacirc eta_k^-1:kto L(lim(IX))$ making cones $K$, $Lmathcal K$ and diagram $x$ commute. Uniqueness of $kappacirc eta_k^-1$ in this regard follows from fullness of $LI:Dto D$ and isomorphism of $eta^-1$.
So $Lmathcal K$ is in fact the limiting cone of $x:mathcal Ito C$, as desired $blacksquare$
edited 2 hours ago
answered 6 hours ago
Rafay A.
564
564
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