Inclusion of Reflective Subcategory Creates Limits

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
2
down vote

favorite
1












$
newcommandCmathcalC
newcommandDmathcalD
newcommandImathcalI
$



(Full) subcategory $D$ of the category $C$ is called reflexive if there exists a localization functor $L : C to D$ and it is left adjoint to the inclusion functor $I : D hookrightarrow C$.



There is theorem:




If $D$ is a reflective subcategory of $C$, then $I$ creates all limits that $C$ admits.




But if this theorem is true, then every diagram $x: I toD$, which admits a limit $y = lim_i in I Ix_i $, will also have a limit in $D$. But as inclusion $I$ is right adjoint, it preserves limits, and so $y = IBig(lim_i in I x_i Big)$. Then, as $y$ is included into $C$, it must hold that $lim_i in I x_i = Ly cong y$. But, I don't know how to prove this fact, as $L$ only preserves colimits.



I can prove that $Ly$ indeed forms a cone over $x$ and for any other cone $c$
there exists a morphism $psi: c to Ly$, but I don't know how to prove uniqueness.



I construct $psi$ as $Lphi$, there $phi: Ic to y$, which exists by universal property of limit $y$.




What am I missing here? Сan you help me prove uniqueness?








share|cite|improve this question

























    up vote
    2
    down vote

    favorite
    1












    $
    newcommandCmathcalC
    newcommandDmathcalD
    newcommandImathcalI
    $



    (Full) subcategory $D$ of the category $C$ is called reflexive if there exists a localization functor $L : C to D$ and it is left adjoint to the inclusion functor $I : D hookrightarrow C$.



    There is theorem:




    If $D$ is a reflective subcategory of $C$, then $I$ creates all limits that $C$ admits.




    But if this theorem is true, then every diagram $x: I toD$, which admits a limit $y = lim_i in I Ix_i $, will also have a limit in $D$. But as inclusion $I$ is right adjoint, it preserves limits, and so $y = IBig(lim_i in I x_i Big)$. Then, as $y$ is included into $C$, it must hold that $lim_i in I x_i = Ly cong y$. But, I don't know how to prove this fact, as $L$ only preserves colimits.



    I can prove that $Ly$ indeed forms a cone over $x$ and for any other cone $c$
    there exists a morphism $psi: c to Ly$, but I don't know how to prove uniqueness.



    I construct $psi$ as $Lphi$, there $phi: Ic to y$, which exists by universal property of limit $y$.




    What am I missing here? Сan you help me prove uniqueness?








    share|cite|improve this question























      up vote
      2
      down vote

      favorite
      1









      up vote
      2
      down vote

      favorite
      1






      1





      $
      newcommandCmathcalC
      newcommandDmathcalD
      newcommandImathcalI
      $



      (Full) subcategory $D$ of the category $C$ is called reflexive if there exists a localization functor $L : C to D$ and it is left adjoint to the inclusion functor $I : D hookrightarrow C$.



      There is theorem:




      If $D$ is a reflective subcategory of $C$, then $I$ creates all limits that $C$ admits.




      But if this theorem is true, then every diagram $x: I toD$, which admits a limit $y = lim_i in I Ix_i $, will also have a limit in $D$. But as inclusion $I$ is right adjoint, it preserves limits, and so $y = IBig(lim_i in I x_i Big)$. Then, as $y$ is included into $C$, it must hold that $lim_i in I x_i = Ly cong y$. But, I don't know how to prove this fact, as $L$ only preserves colimits.



      I can prove that $Ly$ indeed forms a cone over $x$ and for any other cone $c$
      there exists a morphism $psi: c to Ly$, but I don't know how to prove uniqueness.



      I construct $psi$ as $Lphi$, there $phi: Ic to y$, which exists by universal property of limit $y$.




      What am I missing here? Сan you help me prove uniqueness?








      share|cite|improve this question













      $
      newcommandCmathcalC
      newcommandDmathcalD
      newcommandImathcalI
      $



      (Full) subcategory $D$ of the category $C$ is called reflexive if there exists a localization functor $L : C to D$ and it is left adjoint to the inclusion functor $I : D hookrightarrow C$.



      There is theorem:




      If $D$ is a reflective subcategory of $C$, then $I$ creates all limits that $C$ admits.




      But if this theorem is true, then every diagram $x: I toD$, which admits a limit $y = lim_i in I Ix_i $, will also have a limit in $D$. But as inclusion $I$ is right adjoint, it preserves limits, and so $y = IBig(lim_i in I x_i Big)$. Then, as $y$ is included into $C$, it must hold that $lim_i in I x_i = Ly cong y$. But, I don't know how to prove this fact, as $L$ only preserves colimits.



      I can prove that $Ly$ indeed forms a cone over $x$ and for any other cone $c$
      there exists a morphism $psi: c to Ly$, but I don't know how to prove uniqueness.



      I construct $psi$ as $Lphi$, there $phi: Ic to y$, which exists by universal property of limit $y$.




      What am I missing here? Сan you help me prove uniqueness?










      share|cite|improve this question












      share|cite|improve this question




      share|cite|improve this question








      edited 14 hours ago
























      asked 14 hours ago









      Nik Pronko

      678617




      678617




















          1 Answer
          1






          active

          oldest

          votes

















          up vote
          0
          down vote













          Let the adjunction take the form of a natural isomorphism $Psi: textHom_D(L(-),-)cong textHom_D(-,I(-))$ between functors mapping $C^textoptimes DtotextbfSet$. Let $x:mathcal Ito D$ be a functor, and suppose $Ix:mathcal Ito C$ has a limit given by the cone $mathcal K=lim(Ix)oversetpi_ilongrightarrow IX(i), iintextOb(mathcal I)$.




          Lemma: $forall dintextOb(D), exists eta_d: LI(d)cong d$, and this correspondence is natural in $d$. In other words, $LI$ and $textid_D$ are naturally isomorphic as functors.



          Fullness of the inclusion functor $I$ gives canonical isomorphisms $$textHom_D(LI(d_1),d_2)cong textHom_C(LI(d_1),I(d_2))oversetPsicong textHom_C(I(d_1),d_2) cong textHom_D(d_1,d_2)$$ Natural in pairs $left<d_1,d_2right>intextOb(D^textoptimes D)$. In particular, there is a natural mapping $$Psi_:textHom_D(LI(-),-)cong textHom_D(-,-)$$ Where $textHom_D(LI(-),-)$ and $textHom_D(-,-)$ are functors $D^textoptimes Dto textbfSet$. The existence of $eta$ follows by the Yoneda Lemma (or Yoneda Lemma-style arguments) $Box$




          Conceptually, we want to show that $Lmathcal K$ "behaves" in $D$ as $mathcalK$ does in $D$, and in particular, that $L(lim(Ix))$ is itself the limit of $x$. After all, "pre-filling" the the left argument with $lim(Ix)intextOb(C)$ and discarding the "irrelevant" components of $Psi$ gives natural isomorphism $$Psi_lim(Ix):textHom_D(L(lim(Ix)),-)cong textHom_C(lim(Ix),I(-))$$ So the two should "see $D$ in the same way" in some sense.



          Consider some arbitrary cone $K$ in $D$ over $x$ of the form $K=koversetp_ilongrightarrow X(i), iintextOb(mathcal I)$.
          Passing this cone through $I$ gives another cone $IK=I(k)oversetIp_ilongrightarrow IX(i), iintextOb(mathcal I)$—this time in $C$—over $Ix$. Definitionally there exists some (unique!) $C$-morphism $kappa:kto lim(IX)$ commuting with $IK$, $mathcal K$ and $Ix$. Passing everything "back into $D$" through $L$ gives $D$-morphism $Lkappa:LI(k)to L(lim(IX))$ commuting with $LIK$, $Lmathcal K$ and $LIx$.



          Finally, applying $eta$ to $LIK$ and $LIX$ gives an arrow $kappacirc eta_k^-1:kto L(lim(IX))$ making cones $K$, $Lmathcal K$ and diagram $x$ commute. Uniqueness of $kappacirc eta_k^-1$ in this regard follows from fullness of $LI:Dto D$ and isomorphism of $eta^-1$.



          So $Lmathcal K$ is in fact the limiting cone of $x:mathcal Ito C$, as desired $blacksquare$






          share|cite|improve this answer























            Your Answer




            StackExchange.ifUsing("editor", function ()
            return StackExchange.using("mathjaxEditing", function ()
            StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
            StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
            );
            );
            , "mathjax-editing");

            StackExchange.ready(function()
            var channelOptions =
            tags: "".split(" "),
            id: "69"
            ;
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function()
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled)
            StackExchange.using("snippets", function()
            createEditor();
            );

            else
            createEditor();

            );

            function createEditor()
            StackExchange.prepareEditor(
            heartbeatType: 'answer',
            convertImagesToLinks: true,
            noModals: false,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: 10,
            bindNavPrevention: true,
            postfix: "",
            noCode: true, onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            );



            );








             

            draft saved


            draft discarded


















            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2873070%2finclusion-of-reflective-subcategory-creates-limits%23new-answer', 'question_page');

            );

            Post as a guest






























            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            0
            down vote













            Let the adjunction take the form of a natural isomorphism $Psi: textHom_D(L(-),-)cong textHom_D(-,I(-))$ between functors mapping $C^textoptimes DtotextbfSet$. Let $x:mathcal Ito D$ be a functor, and suppose $Ix:mathcal Ito C$ has a limit given by the cone $mathcal K=lim(Ix)oversetpi_ilongrightarrow IX(i), iintextOb(mathcal I)$.




            Lemma: $forall dintextOb(D), exists eta_d: LI(d)cong d$, and this correspondence is natural in $d$. In other words, $LI$ and $textid_D$ are naturally isomorphic as functors.



            Fullness of the inclusion functor $I$ gives canonical isomorphisms $$textHom_D(LI(d_1),d_2)cong textHom_C(LI(d_1),I(d_2))oversetPsicong textHom_C(I(d_1),d_2) cong textHom_D(d_1,d_2)$$ Natural in pairs $left<d_1,d_2right>intextOb(D^textoptimes D)$. In particular, there is a natural mapping $$Psi_:textHom_D(LI(-),-)cong textHom_D(-,-)$$ Where $textHom_D(LI(-),-)$ and $textHom_D(-,-)$ are functors $D^textoptimes Dto textbfSet$. The existence of $eta$ follows by the Yoneda Lemma (or Yoneda Lemma-style arguments) $Box$




            Conceptually, we want to show that $Lmathcal K$ "behaves" in $D$ as $mathcalK$ does in $D$, and in particular, that $L(lim(Ix))$ is itself the limit of $x$. After all, "pre-filling" the the left argument with $lim(Ix)intextOb(C)$ and discarding the "irrelevant" components of $Psi$ gives natural isomorphism $$Psi_lim(Ix):textHom_D(L(lim(Ix)),-)cong textHom_C(lim(Ix),I(-))$$ So the two should "see $D$ in the same way" in some sense.



            Consider some arbitrary cone $K$ in $D$ over $x$ of the form $K=koversetp_ilongrightarrow X(i), iintextOb(mathcal I)$.
            Passing this cone through $I$ gives another cone $IK=I(k)oversetIp_ilongrightarrow IX(i), iintextOb(mathcal I)$—this time in $C$—over $Ix$. Definitionally there exists some (unique!) $C$-morphism $kappa:kto lim(IX)$ commuting with $IK$, $mathcal K$ and $Ix$. Passing everything "back into $D$" through $L$ gives $D$-morphism $Lkappa:LI(k)to L(lim(IX))$ commuting with $LIK$, $Lmathcal K$ and $LIx$.



            Finally, applying $eta$ to $LIK$ and $LIX$ gives an arrow $kappacirc eta_k^-1:kto L(lim(IX))$ making cones $K$, $Lmathcal K$ and diagram $x$ commute. Uniqueness of $kappacirc eta_k^-1$ in this regard follows from fullness of $LI:Dto D$ and isomorphism of $eta^-1$.



            So $Lmathcal K$ is in fact the limiting cone of $x:mathcal Ito C$, as desired $blacksquare$






            share|cite|improve this answer



























              up vote
              0
              down vote













              Let the adjunction take the form of a natural isomorphism $Psi: textHom_D(L(-),-)cong textHom_D(-,I(-))$ between functors mapping $C^textoptimes DtotextbfSet$. Let $x:mathcal Ito D$ be a functor, and suppose $Ix:mathcal Ito C$ has a limit given by the cone $mathcal K=lim(Ix)oversetpi_ilongrightarrow IX(i), iintextOb(mathcal I)$.




              Lemma: $forall dintextOb(D), exists eta_d: LI(d)cong d$, and this correspondence is natural in $d$. In other words, $LI$ and $textid_D$ are naturally isomorphic as functors.



              Fullness of the inclusion functor $I$ gives canonical isomorphisms $$textHom_D(LI(d_1),d_2)cong textHom_C(LI(d_1),I(d_2))oversetPsicong textHom_C(I(d_1),d_2) cong textHom_D(d_1,d_2)$$ Natural in pairs $left<d_1,d_2right>intextOb(D^textoptimes D)$. In particular, there is a natural mapping $$Psi_:textHom_D(LI(-),-)cong textHom_D(-,-)$$ Where $textHom_D(LI(-),-)$ and $textHom_D(-,-)$ are functors $D^textoptimes Dto textbfSet$. The existence of $eta$ follows by the Yoneda Lemma (or Yoneda Lemma-style arguments) $Box$




              Conceptually, we want to show that $Lmathcal K$ "behaves" in $D$ as $mathcalK$ does in $D$, and in particular, that $L(lim(Ix))$ is itself the limit of $x$. After all, "pre-filling" the the left argument with $lim(Ix)intextOb(C)$ and discarding the "irrelevant" components of $Psi$ gives natural isomorphism $$Psi_lim(Ix):textHom_D(L(lim(Ix)),-)cong textHom_C(lim(Ix),I(-))$$ So the two should "see $D$ in the same way" in some sense.



              Consider some arbitrary cone $K$ in $D$ over $x$ of the form $K=koversetp_ilongrightarrow X(i), iintextOb(mathcal I)$.
              Passing this cone through $I$ gives another cone $IK=I(k)oversetIp_ilongrightarrow IX(i), iintextOb(mathcal I)$—this time in $C$—over $Ix$. Definitionally there exists some (unique!) $C$-morphism $kappa:kto lim(IX)$ commuting with $IK$, $mathcal K$ and $Ix$. Passing everything "back into $D$" through $L$ gives $D$-morphism $Lkappa:LI(k)to L(lim(IX))$ commuting with $LIK$, $Lmathcal K$ and $LIx$.



              Finally, applying $eta$ to $LIK$ and $LIX$ gives an arrow $kappacirc eta_k^-1:kto L(lim(IX))$ making cones $K$, $Lmathcal K$ and diagram $x$ commute. Uniqueness of $kappacirc eta_k^-1$ in this regard follows from fullness of $LI:Dto D$ and isomorphism of $eta^-1$.



              So $Lmathcal K$ is in fact the limiting cone of $x:mathcal Ito C$, as desired $blacksquare$






              share|cite|improve this answer

























                up vote
                0
                down vote










                up vote
                0
                down vote









                Let the adjunction take the form of a natural isomorphism $Psi: textHom_D(L(-),-)cong textHom_D(-,I(-))$ between functors mapping $C^textoptimes DtotextbfSet$. Let $x:mathcal Ito D$ be a functor, and suppose $Ix:mathcal Ito C$ has a limit given by the cone $mathcal K=lim(Ix)oversetpi_ilongrightarrow IX(i), iintextOb(mathcal I)$.




                Lemma: $forall dintextOb(D), exists eta_d: LI(d)cong d$, and this correspondence is natural in $d$. In other words, $LI$ and $textid_D$ are naturally isomorphic as functors.



                Fullness of the inclusion functor $I$ gives canonical isomorphisms $$textHom_D(LI(d_1),d_2)cong textHom_C(LI(d_1),I(d_2))oversetPsicong textHom_C(I(d_1),d_2) cong textHom_D(d_1,d_2)$$ Natural in pairs $left<d_1,d_2right>intextOb(D^textoptimes D)$. In particular, there is a natural mapping $$Psi_:textHom_D(LI(-),-)cong textHom_D(-,-)$$ Where $textHom_D(LI(-),-)$ and $textHom_D(-,-)$ are functors $D^textoptimes Dto textbfSet$. The existence of $eta$ follows by the Yoneda Lemma (or Yoneda Lemma-style arguments) $Box$




                Conceptually, we want to show that $Lmathcal K$ "behaves" in $D$ as $mathcalK$ does in $D$, and in particular, that $L(lim(Ix))$ is itself the limit of $x$. After all, "pre-filling" the the left argument with $lim(Ix)intextOb(C)$ and discarding the "irrelevant" components of $Psi$ gives natural isomorphism $$Psi_lim(Ix):textHom_D(L(lim(Ix)),-)cong textHom_C(lim(Ix),I(-))$$ So the two should "see $D$ in the same way" in some sense.



                Consider some arbitrary cone $K$ in $D$ over $x$ of the form $K=koversetp_ilongrightarrow X(i), iintextOb(mathcal I)$.
                Passing this cone through $I$ gives another cone $IK=I(k)oversetIp_ilongrightarrow IX(i), iintextOb(mathcal I)$—this time in $C$—over $Ix$. Definitionally there exists some (unique!) $C$-morphism $kappa:kto lim(IX)$ commuting with $IK$, $mathcal K$ and $Ix$. Passing everything "back into $D$" through $L$ gives $D$-morphism $Lkappa:LI(k)to L(lim(IX))$ commuting with $LIK$, $Lmathcal K$ and $LIx$.



                Finally, applying $eta$ to $LIK$ and $LIX$ gives an arrow $kappacirc eta_k^-1:kto L(lim(IX))$ making cones $K$, $Lmathcal K$ and diagram $x$ commute. Uniqueness of $kappacirc eta_k^-1$ in this regard follows from fullness of $LI:Dto D$ and isomorphism of $eta^-1$.



                So $Lmathcal K$ is in fact the limiting cone of $x:mathcal Ito C$, as desired $blacksquare$






                share|cite|improve this answer















                Let the adjunction take the form of a natural isomorphism $Psi: textHom_D(L(-),-)cong textHom_D(-,I(-))$ between functors mapping $C^textoptimes DtotextbfSet$. Let $x:mathcal Ito D$ be a functor, and suppose $Ix:mathcal Ito C$ has a limit given by the cone $mathcal K=lim(Ix)oversetpi_ilongrightarrow IX(i), iintextOb(mathcal I)$.




                Lemma: $forall dintextOb(D), exists eta_d: LI(d)cong d$, and this correspondence is natural in $d$. In other words, $LI$ and $textid_D$ are naturally isomorphic as functors.



                Fullness of the inclusion functor $I$ gives canonical isomorphisms $$textHom_D(LI(d_1),d_2)cong textHom_C(LI(d_1),I(d_2))oversetPsicong textHom_C(I(d_1),d_2) cong textHom_D(d_1,d_2)$$ Natural in pairs $left<d_1,d_2right>intextOb(D^textoptimes D)$. In particular, there is a natural mapping $$Psi_:textHom_D(LI(-),-)cong textHom_D(-,-)$$ Where $textHom_D(LI(-),-)$ and $textHom_D(-,-)$ are functors $D^textoptimes Dto textbfSet$. The existence of $eta$ follows by the Yoneda Lemma (or Yoneda Lemma-style arguments) $Box$




                Conceptually, we want to show that $Lmathcal K$ "behaves" in $D$ as $mathcalK$ does in $D$, and in particular, that $L(lim(Ix))$ is itself the limit of $x$. After all, "pre-filling" the the left argument with $lim(Ix)intextOb(C)$ and discarding the "irrelevant" components of $Psi$ gives natural isomorphism $$Psi_lim(Ix):textHom_D(L(lim(Ix)),-)cong textHom_C(lim(Ix),I(-))$$ So the two should "see $D$ in the same way" in some sense.



                Consider some arbitrary cone $K$ in $D$ over $x$ of the form $K=koversetp_ilongrightarrow X(i), iintextOb(mathcal I)$.
                Passing this cone through $I$ gives another cone $IK=I(k)oversetIp_ilongrightarrow IX(i), iintextOb(mathcal I)$—this time in $C$—over $Ix$. Definitionally there exists some (unique!) $C$-morphism $kappa:kto lim(IX)$ commuting with $IK$, $mathcal K$ and $Ix$. Passing everything "back into $D$" through $L$ gives $D$-morphism $Lkappa:LI(k)to L(lim(IX))$ commuting with $LIK$, $Lmathcal K$ and $LIx$.



                Finally, applying $eta$ to $LIK$ and $LIX$ gives an arrow $kappacirc eta_k^-1:kto L(lim(IX))$ making cones $K$, $Lmathcal K$ and diagram $x$ commute. Uniqueness of $kappacirc eta_k^-1$ in this regard follows from fullness of $LI:Dto D$ and isomorphism of $eta^-1$.



                So $Lmathcal K$ is in fact the limiting cone of $x:mathcal Ito C$, as desired $blacksquare$







                share|cite|improve this answer















                share|cite|improve this answer



                share|cite|improve this answer








                edited 2 hours ago


























                answered 6 hours ago









                Rafay A.

                564




                564






















                     

                    draft saved


                    draft discarded


























                     


                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function ()
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2873070%2finclusion-of-reflective-subcategory-creates-limits%23new-answer', 'question_page');

                    );

                    Post as a guest













































































                    Comments

                    Popular posts from this blog

                    Color the edges and diagonals of a regular polygon

                    Relationship between determinant of matrix and determinant of adjoint?

                    What is the equation of a 3D cone with generalised tilt?