What is the maximum volume of lebesgue measurable set $Asubseteq [0,6]$ such that…
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$textI came accross an interesting question:$
$ $
$textWhat is the maximum volume of a lebesgue measurable set Asubseteq[0,6]^2 text such that: $
$A cap bigl(A+binom 12bigl)=emptyset $
$textI got only to 5pi text but the answer is 24. What am I missing?$
real-analysis lebesgue-measure volume
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$textI came accross an interesting question:$
$ $
$textWhat is the maximum volume of a lebesgue measurable set Asubseteq[0,6]^2 text such that: $
$A cap bigl(A+binom 12bigl)=emptyset $
$textI got only to 5pi text but the answer is 24. What am I missing?$
real-analysis lebesgue-measure volume
1
Could you say a rough word on how you got $5pi$?
– Arnaud Mortier
7 hours ago
What if $A=[0,6]^2setminus (1,2)$? Maybe you mean $cup$ instead of $cap$?
– Arnaud Mortier
6 hours ago
@ArnaudMortier Sorry I mistranslated the question, see edit :)
– Gil Or
6 hours ago
It makes more sense now, but still... $5pi$?
– Arnaud Mortier
6 hours ago
@ArnaudMortier I just thought about the open circle: $(x-a)^2+(x-b)^2 < 5$ that is inside $[0,6]^2$. I mean, if (a+1, b+2) > (x,y) for (x,y) $in$ A
– Gil Or
6 hours ago
 |Â
show 2 more comments
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up vote
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$textI came accross an interesting question:$
$ $
$textWhat is the maximum volume of a lebesgue measurable set Asubseteq[0,6]^2 text such that: $
$A cap bigl(A+binom 12bigl)=emptyset $
$textI got only to 5pi text but the answer is 24. What am I missing?$
real-analysis lebesgue-measure volume
$textI came accross an interesting question:$
$ $
$textWhat is the maximum volume of a lebesgue measurable set Asubseteq[0,6]^2 text such that: $
$A cap bigl(A+binom 12bigl)=emptyset $
$textI got only to 5pi text but the answer is 24. What am I missing?$
real-analysis lebesgue-measure volume
edited 6 hours ago
asked 7 hours ago


Gil Or
623
623
1
Could you say a rough word on how you got $5pi$?
– Arnaud Mortier
7 hours ago
What if $A=[0,6]^2setminus (1,2)$? Maybe you mean $cup$ instead of $cap$?
– Arnaud Mortier
6 hours ago
@ArnaudMortier Sorry I mistranslated the question, see edit :)
– Gil Or
6 hours ago
It makes more sense now, but still... $5pi$?
– Arnaud Mortier
6 hours ago
@ArnaudMortier I just thought about the open circle: $(x-a)^2+(x-b)^2 < 5$ that is inside $[0,6]^2$. I mean, if (a+1, b+2) > (x,y) for (x,y) $in$ A
– Gil Or
6 hours ago
 |Â
show 2 more comments
1
Could you say a rough word on how you got $5pi$?
– Arnaud Mortier
7 hours ago
What if $A=[0,6]^2setminus (1,2)$? Maybe you mean $cup$ instead of $cap$?
– Arnaud Mortier
6 hours ago
@ArnaudMortier Sorry I mistranslated the question, see edit :)
– Gil Or
6 hours ago
It makes more sense now, but still... $5pi$?
– Arnaud Mortier
6 hours ago
@ArnaudMortier I just thought about the open circle: $(x-a)^2+(x-b)^2 < 5$ that is inside $[0,6]^2$. I mean, if (a+1, b+2) > (x,y) for (x,y) $in$ A
– Gil Or
6 hours ago
1
1
Could you say a rough word on how you got $5pi$?
– Arnaud Mortier
7 hours ago
Could you say a rough word on how you got $5pi$?
– Arnaud Mortier
7 hours ago
What if $A=[0,6]^2setminus (1,2)$? Maybe you mean $cup$ instead of $cap$?
– Arnaud Mortier
6 hours ago
What if $A=[0,6]^2setminus (1,2)$? Maybe you mean $cup$ instead of $cap$?
– Arnaud Mortier
6 hours ago
@ArnaudMortier Sorry I mistranslated the question, see edit :)
– Gil Or
6 hours ago
@ArnaudMortier Sorry I mistranslated the question, see edit :)
– Gil Or
6 hours ago
It makes more sense now, but still... $5pi$?
– Arnaud Mortier
6 hours ago
It makes more sense now, but still... $5pi$?
– Arnaud Mortier
6 hours ago
@ArnaudMortier I just thought about the open circle: $(x-a)^2+(x-b)^2 < 5$ that is inside $[0,6]^2$. I mean, if (a+1, b+2) > (x,y) for (x,y) $in$ A
– Gil Or
6 hours ago
@ArnaudMortier I just thought about the open circle: $(x-a)^2+(x-b)^2 < 5$ that is inside $[0,6]^2$. I mean, if (a+1, b+2) > (x,y) for (x,y) $in$ A
– Gil Or
6 hours ago
 |Â
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1
Could you say a rough word on how you got $5pi$?
– Arnaud Mortier
7 hours ago
What if $A=[0,6]^2setminus (1,2)$? Maybe you mean $cup$ instead of $cap$?
– Arnaud Mortier
6 hours ago
@ArnaudMortier Sorry I mistranslated the question, see edit :)
– Gil Or
6 hours ago
It makes more sense now, but still... $5pi$?
– Arnaud Mortier
6 hours ago
@ArnaudMortier I just thought about the open circle: $(x-a)^2+(x-b)^2 < 5$ that is inside $[0,6]^2$. I mean, if (a+1, b+2) > (x,y) for (x,y) $in$ A
– Gil Or
6 hours ago