A probability problem.

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A club has five members $A,B,C,D$ and $E$. It is required to select a
chairman and secretary. Assuming that one member cannot occupy both
positions, write the sample space associated with these selections




.



My input



In my mind I thought of selecting two from these $5$ people first one as chairman and second one as secretary. $5$ choose $2$ makes it $10$ but order doesn't matter because first one can also b secretary and $2$nd can be chairman. Using permutation makes it $20$ possible pairs.
$AB,BA,AC,CA....$
Did i think it right ?







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  • 3




    You've got the right answer, but I think you meant to say, "Order does matter."
    – saulspatz
    Jul 31 at 13:42










  • @saulspatz I meant AB and BA are not same thing. So what do I write here ? Order matters or doesn't matter? I am confused.
    – Damn1o1
    Jul 31 at 13:44






  • 1




    Order matters. If AB and BA are the same, then order doesn't matter. (We don't care what order they are listed in.) By AB and BA are different, so the order in which they are listed matters.
    – saulspatz
    Jul 31 at 13:46






  • 1




    "AB and BA are not the same thing" implies order matters. On the other hand "AB and BA are the same thing" implies order doesn't matter.
    – JMoravitz
    Jul 31 at 13:47










  • @JMoravitz Thanks for pointing that out. I am learning these things.
    – Damn1o1
    Jul 31 at 13:51














up vote
1
down vote

favorite













A club has five members $A,B,C,D$ and $E$. It is required to select a
chairman and secretary. Assuming that one member cannot occupy both
positions, write the sample space associated with these selections




.



My input



In my mind I thought of selecting two from these $5$ people first one as chairman and second one as secretary. $5$ choose $2$ makes it $10$ but order doesn't matter because first one can also b secretary and $2$nd can be chairman. Using permutation makes it $20$ possible pairs.
$AB,BA,AC,CA....$
Did i think it right ?







share|cite|improve this question

















  • 3




    You've got the right answer, but I think you meant to say, "Order does matter."
    – saulspatz
    Jul 31 at 13:42










  • @saulspatz I meant AB and BA are not same thing. So what do I write here ? Order matters or doesn't matter? I am confused.
    – Damn1o1
    Jul 31 at 13:44






  • 1




    Order matters. If AB and BA are the same, then order doesn't matter. (We don't care what order they are listed in.) By AB and BA are different, so the order in which they are listed matters.
    – saulspatz
    Jul 31 at 13:46






  • 1




    "AB and BA are not the same thing" implies order matters. On the other hand "AB and BA are the same thing" implies order doesn't matter.
    – JMoravitz
    Jul 31 at 13:47










  • @JMoravitz Thanks for pointing that out. I am learning these things.
    – Damn1o1
    Jul 31 at 13:51












up vote
1
down vote

favorite









up vote
1
down vote

favorite












A club has five members $A,B,C,D$ and $E$. It is required to select a
chairman and secretary. Assuming that one member cannot occupy both
positions, write the sample space associated with these selections




.



My input



In my mind I thought of selecting two from these $5$ people first one as chairman and second one as secretary. $5$ choose $2$ makes it $10$ but order doesn't matter because first one can also b secretary and $2$nd can be chairman. Using permutation makes it $20$ possible pairs.
$AB,BA,AC,CA....$
Did i think it right ?







share|cite|improve this question














A club has five members $A,B,C,D$ and $E$. It is required to select a
chairman and secretary. Assuming that one member cannot occupy both
positions, write the sample space associated with these selections




.



My input



In my mind I thought of selecting two from these $5$ people first one as chairman and second one as secretary. $5$ choose $2$ makes it $10$ but order doesn't matter because first one can also b secretary and $2$nd can be chairman. Using permutation makes it $20$ possible pairs.
$AB,BA,AC,CA....$
Did i think it right ?









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 31 at 14:19
























asked Jul 31 at 13:39









Damn1o1

57113




57113







  • 3




    You've got the right answer, but I think you meant to say, "Order does matter."
    – saulspatz
    Jul 31 at 13:42










  • @saulspatz I meant AB and BA are not same thing. So what do I write here ? Order matters or doesn't matter? I am confused.
    – Damn1o1
    Jul 31 at 13:44






  • 1




    Order matters. If AB and BA are the same, then order doesn't matter. (We don't care what order they are listed in.) By AB and BA are different, so the order in which they are listed matters.
    – saulspatz
    Jul 31 at 13:46






  • 1




    "AB and BA are not the same thing" implies order matters. On the other hand "AB and BA are the same thing" implies order doesn't matter.
    – JMoravitz
    Jul 31 at 13:47










  • @JMoravitz Thanks for pointing that out. I am learning these things.
    – Damn1o1
    Jul 31 at 13:51












  • 3




    You've got the right answer, but I think you meant to say, "Order does matter."
    – saulspatz
    Jul 31 at 13:42










  • @saulspatz I meant AB and BA are not same thing. So what do I write here ? Order matters or doesn't matter? I am confused.
    – Damn1o1
    Jul 31 at 13:44






  • 1




    Order matters. If AB and BA are the same, then order doesn't matter. (We don't care what order they are listed in.) By AB and BA are different, so the order in which they are listed matters.
    – saulspatz
    Jul 31 at 13:46






  • 1




    "AB and BA are not the same thing" implies order matters. On the other hand "AB and BA are the same thing" implies order doesn't matter.
    – JMoravitz
    Jul 31 at 13:47










  • @JMoravitz Thanks for pointing that out. I am learning these things.
    – Damn1o1
    Jul 31 at 13:51







3




3




You've got the right answer, but I think you meant to say, "Order does matter."
– saulspatz
Jul 31 at 13:42




You've got the right answer, but I think you meant to say, "Order does matter."
– saulspatz
Jul 31 at 13:42












@saulspatz I meant AB and BA are not same thing. So what do I write here ? Order matters or doesn't matter? I am confused.
– Damn1o1
Jul 31 at 13:44




@saulspatz I meant AB and BA are not same thing. So what do I write here ? Order matters or doesn't matter? I am confused.
– Damn1o1
Jul 31 at 13:44




1




1




Order matters. If AB and BA are the same, then order doesn't matter. (We don't care what order they are listed in.) By AB and BA are different, so the order in which they are listed matters.
– saulspatz
Jul 31 at 13:46




Order matters. If AB and BA are the same, then order doesn't matter. (We don't care what order they are listed in.) By AB and BA are different, so the order in which they are listed matters.
– saulspatz
Jul 31 at 13:46




1




1




"AB and BA are not the same thing" implies order matters. On the other hand "AB and BA are the same thing" implies order doesn't matter.
– JMoravitz
Jul 31 at 13:47




"AB and BA are not the same thing" implies order matters. On the other hand "AB and BA are the same thing" implies order doesn't matter.
– JMoravitz
Jul 31 at 13:47












@JMoravitz Thanks for pointing that out. I am learning these things.
– Damn1o1
Jul 31 at 13:51




@JMoravitz Thanks for pointing that out. I am learning these things.
– Damn1o1
Jul 31 at 13:51










1 Answer
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Let $M =A,B,C,D,E$, then set of interest $S$ (The probability space) is as follows
$$S = (s,c)in Mtimes M :sneq c$$






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    1 Answer
    1






    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    1
    down vote



    accepted










    Let $M =A,B,C,D,E$, then set of interest $S$ (The probability space) is as follows
    $$S = (s,c)in Mtimes M :sneq c$$






    share|cite|improve this answer

























      up vote
      1
      down vote



      accepted










      Let $M =A,B,C,D,E$, then set of interest $S$ (The probability space) is as follows
      $$S = (s,c)in Mtimes M :sneq c$$






      share|cite|improve this answer























        up vote
        1
        down vote



        accepted







        up vote
        1
        down vote



        accepted






        Let $M =A,B,C,D,E$, then set of interest $S$ (The probability space) is as follows
        $$S = (s,c)in Mtimes M :sneq c$$






        share|cite|improve this answer













        Let $M =A,B,C,D,E$, then set of interest $S$ (The probability space) is as follows
        $$S = (s,c)in Mtimes M :sneq c$$







        share|cite|improve this answer













        share|cite|improve this answer



        share|cite|improve this answer











        answered Jul 31 at 14:08









        Atif Farooq

        2,7352824




        2,7352824






















             

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