Simplifying probablity equation based on its cumulative distribution function (CDF)

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How can I simplify the following probability equation based on cumulative distribution function of X:



P(X>a)>b


which P is the probability of X and X has a known probability distribution function and a & b are real positive numbers.







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    Do you the definition of a CDF?
    – user190080
    Jul 31 at 14:48











  • Back to the problem: Start with $X$ has cdf $F_X(X le a) = 1 - P(X > a).$ You can get other, possibly useful, relationships from there. Not sure whether I'd call the 'simplifications'.
    – BruceET
    Aug 1 at 4:40














up vote
1
down vote

favorite












How can I simplify the following probability equation based on cumulative distribution function of X:



P(X>a)>b


which P is the probability of X and X has a known probability distribution function and a & b are real positive numbers.







share|cite|improve this question

















  • 1




    Do you the definition of a CDF?
    – user190080
    Jul 31 at 14:48











  • Back to the problem: Start with $X$ has cdf $F_X(X le a) = 1 - P(X > a).$ You can get other, possibly useful, relationships from there. Not sure whether I'd call the 'simplifications'.
    – BruceET
    Aug 1 at 4:40












up vote
1
down vote

favorite









up vote
1
down vote

favorite











How can I simplify the following probability equation based on cumulative distribution function of X:



P(X>a)>b


which P is the probability of X and X has a known probability distribution function and a & b are real positive numbers.







share|cite|improve this question













How can I simplify the following probability equation based on cumulative distribution function of X:



P(X>a)>b


which P is the probability of X and X has a known probability distribution function and a & b are real positive numbers.









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Aug 1 at 15:26









BCLC

7,01221973




7,01221973









asked Jul 31 at 14:44









Dastnegar Parseh

124




124







  • 1




    Do you the definition of a CDF?
    – user190080
    Jul 31 at 14:48











  • Back to the problem: Start with $X$ has cdf $F_X(X le a) = 1 - P(X > a).$ You can get other, possibly useful, relationships from there. Not sure whether I'd call the 'simplifications'.
    – BruceET
    Aug 1 at 4:40












  • 1




    Do you the definition of a CDF?
    – user190080
    Jul 31 at 14:48











  • Back to the problem: Start with $X$ has cdf $F_X(X le a) = 1 - P(X > a).$ You can get other, possibly useful, relationships from there. Not sure whether I'd call the 'simplifications'.
    – BruceET
    Aug 1 at 4:40







1




1




Do you the definition of a CDF?
– user190080
Jul 31 at 14:48





Do you the definition of a CDF?
– user190080
Jul 31 at 14:48













Back to the problem: Start with $X$ has cdf $F_X(X le a) = 1 - P(X > a).$ You can get other, possibly useful, relationships from there. Not sure whether I'd call the 'simplifications'.
– BruceET
Aug 1 at 4:40




Back to the problem: Start with $X$ has cdf $F_X(X le a) = 1 - P(X > a).$ You can get other, possibly useful, relationships from there. Not sure whether I'd call the 'simplifications'.
– BruceET
Aug 1 at 4:40










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$$P(X>a)>b$$



$$-P(X>a)<-b$$
$$1-P(X>a)<1-b$$



$$P(X le a)<1-b$$



$$F_X(a)<1-b$$






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    1 Answer
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    up vote
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    down vote













    $$P(X>a)>b$$



    $$-P(X>a)<-b$$
    $$1-P(X>a)<1-b$$



    $$P(X le a)<1-b$$



    $$F_X(a)<1-b$$






    share|cite|improve this answer

























      up vote
      1
      down vote













      $$P(X>a)>b$$



      $$-P(X>a)<-b$$
      $$1-P(X>a)<1-b$$



      $$P(X le a)<1-b$$



      $$F_X(a)<1-b$$






      share|cite|improve this answer























        up vote
        1
        down vote










        up vote
        1
        down vote









        $$P(X>a)>b$$



        $$-P(X>a)<-b$$
        $$1-P(X>a)<1-b$$



        $$P(X le a)<1-b$$



        $$F_X(a)<1-b$$






        share|cite|improve this answer













        $$P(X>a)>b$$



        $$-P(X>a)<-b$$
        $$1-P(X>a)<1-b$$



        $$P(X le a)<1-b$$



        $$F_X(a)<1-b$$







        share|cite|improve this answer













        share|cite|improve this answer



        share|cite|improve this answer











        answered Aug 1 at 5:20









        BCLC

        7,01221973




        7,01221973






















             

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