Convergence of series to a $C^infty$ function
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Let $S_+ = mathbbR times t>0$ and $,f in C^infty(S^+)$ such that $,f$ and all its derivatives have continuous limits as $t to 0^+$.
In this paper the author defines the following extension of $f$ for $t<0$:
beginequation
Ef(x,t) = sum_k=1^infty a_k ,phi(b_k t), f(x,b_k t)
endequation
where
$phi in C^infty(mathbbR)$ with: $phi(t)=1$ for $0leq tleq1$ and $,phi(t)=0$ for $tgeq$2;
$a_k, b_k$ such that:
- $b_k < 0$ and $b_k to - infty$,
- $sum_k=1^infty|a_k||b_k|^n <infty$ for $, n = 0,1, 2, dots$,
- $sum_k=1^infty (a_k)(b_k)^n = 1$ for $, n = 0,1, 2, dots$.
The existence of sequences $a_k, b_k$ such that 2. holds is proved in the paper.
My observations
- Since $b_k to -infty$, for each $t<0$ the sum in $Ef$ is finite and therefore $Ef$ is pointwise well defined.
- If $C$ is a compact set in $mathbbRtimes(-infty,0)$ and $bart = max_(x,t) in C t$, let $barN$ be such that for every $k geq barN$ one has $b_k bart > 2$. Then since $b_k t geq b_k bart > 2 $ for all $t in C$, it follows that:
$$ Ef(x,t) = sum_k=1^barN a_k ,phi(b_k t), f(x,b_k t)qquad forall (x,t) in C $$
It follows that on every compact set $C subset mathbbRtimes(-infty,0)$ $Ef$ is uniform limit of functions in $C^infty(mathbbRtimes(-infty,0))$. Then it easy to see that the restriction of
$Ef$ to $t<0$ is in $C^infty(mathbbRtimes(-infty,0))$.
My question:
I have shown that $Ef(t,x)$ is well defined for every $(t,x) in R^2$,
moreover the restriction of $Ef$ to $t<0$ is in $C^infty(mathbbRtimes(-infty,0))$. I'm left with $Ef(t,x)$ has derivative as $tto 0^-$.
Question: How to prove that
$lim_tto 0^- Ef(x,t)$ and
$ lim_tto 0^- partial_t^n partial_x^j Ef(x,t)$
exist finite?
Remarks
a) I believe that to answer the question "dominated convergence" using the second point of 2.2 is what
is needed, but I'm missing the details.
b) If the limit exist then they agree to those for $tto 0^+$, since using the third point in 2.:
$$ lim_tto 0^- Ef(x,t) = sum_k=1^infty lim_tto 0^- a_k ,phi(b_k t), f(x,b_k t) = f(x, 0^+) sum_k=1^infty a_k = f(x, 0^+)$$
$$ lim_tto 0^- partial_t^n partial_x^j Ef(x,t) = sum_k=1^infty lim_tto 0^- a_k sum_j leq n C_j,k partial_t^n-j ,phi(b_k t),partial_t^j partial_x^j f(x,b_k t) = partial_t^m partial_x^n f(x, 0^+) sum_k=1^infty a_k b_k^n = partial_t^m partial_x^n f(x,0^+)$$
real-analysis sequences-and-series derivatives
add a comment |Â
up vote
1
down vote
favorite
Let $S_+ = mathbbR times t>0$ and $,f in C^infty(S^+)$ such that $,f$ and all its derivatives have continuous limits as $t to 0^+$.
In this paper the author defines the following extension of $f$ for $t<0$:
beginequation
Ef(x,t) = sum_k=1^infty a_k ,phi(b_k t), f(x,b_k t)
endequation
where
$phi in C^infty(mathbbR)$ with: $phi(t)=1$ for $0leq tleq1$ and $,phi(t)=0$ for $tgeq$2;
$a_k, b_k$ such that:
- $b_k < 0$ and $b_k to - infty$,
- $sum_k=1^infty|a_k||b_k|^n <infty$ for $, n = 0,1, 2, dots$,
- $sum_k=1^infty (a_k)(b_k)^n = 1$ for $, n = 0,1, 2, dots$.
The existence of sequences $a_k, b_k$ such that 2. holds is proved in the paper.
My observations
- Since $b_k to -infty$, for each $t<0$ the sum in $Ef$ is finite and therefore $Ef$ is pointwise well defined.
- If $C$ is a compact set in $mathbbRtimes(-infty,0)$ and $bart = max_(x,t) in C t$, let $barN$ be such that for every $k geq barN$ one has $b_k bart > 2$. Then since $b_k t geq b_k bart > 2 $ for all $t in C$, it follows that:
$$ Ef(x,t) = sum_k=1^barN a_k ,phi(b_k t), f(x,b_k t)qquad forall (x,t) in C $$
It follows that on every compact set $C subset mathbbRtimes(-infty,0)$ $Ef$ is uniform limit of functions in $C^infty(mathbbRtimes(-infty,0))$. Then it easy to see that the restriction of
$Ef$ to $t<0$ is in $C^infty(mathbbRtimes(-infty,0))$.
My question:
I have shown that $Ef(t,x)$ is well defined for every $(t,x) in R^2$,
moreover the restriction of $Ef$ to $t<0$ is in $C^infty(mathbbRtimes(-infty,0))$. I'm left with $Ef(t,x)$ has derivative as $tto 0^-$.
Question: How to prove that
$lim_tto 0^- Ef(x,t)$ and
$ lim_tto 0^- partial_t^n partial_x^j Ef(x,t)$
exist finite?
Remarks
a) I believe that to answer the question "dominated convergence" using the second point of 2.2 is what
is needed, but I'm missing the details.
b) If the limit exist then they agree to those for $tto 0^+$, since using the third point in 2.:
$$ lim_tto 0^- Ef(x,t) = sum_k=1^infty lim_tto 0^- a_k ,phi(b_k t), f(x,b_k t) = f(x, 0^+) sum_k=1^infty a_k = f(x, 0^+)$$
$$ lim_tto 0^- partial_t^n partial_x^j Ef(x,t) = sum_k=1^infty lim_tto 0^- a_k sum_j leq n C_j,k partial_t^n-j ,phi(b_k t),partial_t^j partial_x^j f(x,b_k t) = partial_t^m partial_x^n f(x, 0^+) sum_k=1^infty a_k b_k^n = partial_t^m partial_x^n f(x,0^+)$$
real-analysis sequences-and-series derivatives
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down vote
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up vote
1
down vote
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Let $S_+ = mathbbR times t>0$ and $,f in C^infty(S^+)$ such that $,f$ and all its derivatives have continuous limits as $t to 0^+$.
In this paper the author defines the following extension of $f$ for $t<0$:
beginequation
Ef(x,t) = sum_k=1^infty a_k ,phi(b_k t), f(x,b_k t)
endequation
where
$phi in C^infty(mathbbR)$ with: $phi(t)=1$ for $0leq tleq1$ and $,phi(t)=0$ for $tgeq$2;
$a_k, b_k$ such that:
- $b_k < 0$ and $b_k to - infty$,
- $sum_k=1^infty|a_k||b_k|^n <infty$ for $, n = 0,1, 2, dots$,
- $sum_k=1^infty (a_k)(b_k)^n = 1$ for $, n = 0,1, 2, dots$.
The existence of sequences $a_k, b_k$ such that 2. holds is proved in the paper.
My observations
- Since $b_k to -infty$, for each $t<0$ the sum in $Ef$ is finite and therefore $Ef$ is pointwise well defined.
- If $C$ is a compact set in $mathbbRtimes(-infty,0)$ and $bart = max_(x,t) in C t$, let $barN$ be such that for every $k geq barN$ one has $b_k bart > 2$. Then since $b_k t geq b_k bart > 2 $ for all $t in C$, it follows that:
$$ Ef(x,t) = sum_k=1^barN a_k ,phi(b_k t), f(x,b_k t)qquad forall (x,t) in C $$
It follows that on every compact set $C subset mathbbRtimes(-infty,0)$ $Ef$ is uniform limit of functions in $C^infty(mathbbRtimes(-infty,0))$. Then it easy to see that the restriction of
$Ef$ to $t<0$ is in $C^infty(mathbbRtimes(-infty,0))$.
My question:
I have shown that $Ef(t,x)$ is well defined for every $(t,x) in R^2$,
moreover the restriction of $Ef$ to $t<0$ is in $C^infty(mathbbRtimes(-infty,0))$. I'm left with $Ef(t,x)$ has derivative as $tto 0^-$.
Question: How to prove that
$lim_tto 0^- Ef(x,t)$ and
$ lim_tto 0^- partial_t^n partial_x^j Ef(x,t)$
exist finite?
Remarks
a) I believe that to answer the question "dominated convergence" using the second point of 2.2 is what
is needed, but I'm missing the details.
b) If the limit exist then they agree to those for $tto 0^+$, since using the third point in 2.:
$$ lim_tto 0^- Ef(x,t) = sum_k=1^infty lim_tto 0^- a_k ,phi(b_k t), f(x,b_k t) = f(x, 0^+) sum_k=1^infty a_k = f(x, 0^+)$$
$$ lim_tto 0^- partial_t^n partial_x^j Ef(x,t) = sum_k=1^infty lim_tto 0^- a_k sum_j leq n C_j,k partial_t^n-j ,phi(b_k t),partial_t^j partial_x^j f(x,b_k t) = partial_t^m partial_x^n f(x, 0^+) sum_k=1^infty a_k b_k^n = partial_t^m partial_x^n f(x,0^+)$$
real-analysis sequences-and-series derivatives
Let $S_+ = mathbbR times t>0$ and $,f in C^infty(S^+)$ such that $,f$ and all its derivatives have continuous limits as $t to 0^+$.
In this paper the author defines the following extension of $f$ for $t<0$:
beginequation
Ef(x,t) = sum_k=1^infty a_k ,phi(b_k t), f(x,b_k t)
endequation
where
$phi in C^infty(mathbbR)$ with: $phi(t)=1$ for $0leq tleq1$ and $,phi(t)=0$ for $tgeq$2;
$a_k, b_k$ such that:
- $b_k < 0$ and $b_k to - infty$,
- $sum_k=1^infty|a_k||b_k|^n <infty$ for $, n = 0,1, 2, dots$,
- $sum_k=1^infty (a_k)(b_k)^n = 1$ for $, n = 0,1, 2, dots$.
The existence of sequences $a_k, b_k$ such that 2. holds is proved in the paper.
My observations
- Since $b_k to -infty$, for each $t<0$ the sum in $Ef$ is finite and therefore $Ef$ is pointwise well defined.
- If $C$ is a compact set in $mathbbRtimes(-infty,0)$ and $bart = max_(x,t) in C t$, let $barN$ be such that for every $k geq barN$ one has $b_k bart > 2$. Then since $b_k t geq b_k bart > 2 $ for all $t in C$, it follows that:
$$ Ef(x,t) = sum_k=1^barN a_k ,phi(b_k t), f(x,b_k t)qquad forall (x,t) in C $$
It follows that on every compact set $C subset mathbbRtimes(-infty,0)$ $Ef$ is uniform limit of functions in $C^infty(mathbbRtimes(-infty,0))$. Then it easy to see that the restriction of
$Ef$ to $t<0$ is in $C^infty(mathbbRtimes(-infty,0))$.
My question:
I have shown that $Ef(t,x)$ is well defined for every $(t,x) in R^2$,
moreover the restriction of $Ef$ to $t<0$ is in $C^infty(mathbbRtimes(-infty,0))$. I'm left with $Ef(t,x)$ has derivative as $tto 0^-$.
Question: How to prove that
$lim_tto 0^- Ef(x,t)$ and
$ lim_tto 0^- partial_t^n partial_x^j Ef(x,t)$
exist finite?
Remarks
a) I believe that to answer the question "dominated convergence" using the second point of 2.2 is what
is needed, but I'm missing the details.
b) If the limit exist then they agree to those for $tto 0^+$, since using the third point in 2.:
$$ lim_tto 0^- Ef(x,t) = sum_k=1^infty lim_tto 0^- a_k ,phi(b_k t), f(x,b_k t) = f(x, 0^+) sum_k=1^infty a_k = f(x, 0^+)$$
$$ lim_tto 0^- partial_t^n partial_x^j Ef(x,t) = sum_k=1^infty lim_tto 0^- a_k sum_j leq n C_j,k partial_t^n-j ,phi(b_k t),partial_t^j partial_x^j f(x,b_k t) = partial_t^m partial_x^n f(x, 0^+) sum_k=1^infty a_k b_k^n = partial_t^m partial_x^n f(x,0^+)$$
real-analysis sequences-and-series derivatives
edited 3 hours ago
asked 11 hours ago
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