Determine type of set

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Given complement to set $M$ is recursively enumerable and recursive set $R$. What will be the type of the subset of M, elements of which are in R ?



I think they will be also recursively enumerable, but I'm not quite sure about it.




computability




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  • Both $M$ and $R$ are co-recursively enumerable (meaning the complement of $M$ and the complement of $R$ are r.e.). The intersection of two co-r.e. sets is always co-r.e.
    – realdonaldtrump
    Aug 3 at 10:41














up vote
0
down vote

favorite












Given complement to set $M$ is recursively enumerable and recursive set $R$. What will be the type of the subset of M, elements of which are in R ?



I think they will be also recursively enumerable, but I'm not quite sure about it.




computability




share|cite|improve this question





















  • Both $M$ and $R$ are co-recursively enumerable (meaning the complement of $M$ and the complement of $R$ are r.e.). The intersection of two co-r.e. sets is always co-r.e.
    – realdonaldtrump
    Aug 3 at 10:41












up vote
0
down vote

favorite









up vote
0
down vote

favorite











Given complement to set $M$ is recursively enumerable and recursive set $R$. What will be the type of the subset of M, elements of which are in R ?



I think they will be also recursively enumerable, but I'm not quite sure about it.




computability




share|cite|improve this question













Given complement to set $M$ is recursively enumerable and recursive set $R$. What will be the type of the subset of M, elements of which are in R ?



I think they will be also recursively enumerable, but I'm not quite sure about it.





computability





share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 31 at 19:55









Asaf Karagila

291k31401731




291k31401731









asked Jul 31 at 19:52









Kevin

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184











  • Both $M$ and $R$ are co-recursively enumerable (meaning the complement of $M$ and the complement of $R$ are r.e.). The intersection of two co-r.e. sets is always co-r.e.
    – realdonaldtrump
    Aug 3 at 10:41
















  • Both $M$ and $R$ are co-recursively enumerable (meaning the complement of $M$ and the complement of $R$ are r.e.). The intersection of two co-r.e. sets is always co-r.e.
    – realdonaldtrump
    Aug 3 at 10:41















Both $M$ and $R$ are co-recursively enumerable (meaning the complement of $M$ and the complement of $R$ are r.e.). The intersection of two co-r.e. sets is always co-r.e.
– realdonaldtrump
Aug 3 at 10:41




Both $M$ and $R$ are co-recursively enumerable (meaning the complement of $M$ and the complement of $R$ are r.e.). The intersection of two co-r.e. sets is always co-r.e.
– realdonaldtrump
Aug 3 at 10:41










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the complement of $M := Bbb N$ is recursively enumerable; $R := Bbb N$ is recursive; good luck classifying the subsets of $Bbb N$.






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    the complement of $M := Bbb N$ is recursively enumerable; $R := Bbb N$ is recursive; good luck classifying the subsets of $Bbb N$.






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      the complement of $M := Bbb N$ is recursively enumerable; $R := Bbb N$ is recursive; good luck classifying the subsets of $Bbb N$.






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        up vote
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        the complement of $M := Bbb N$ is recursively enumerable; $R := Bbb N$ is recursive; good luck classifying the subsets of $Bbb N$.






        share|cite|improve this answer













        the complement of $M := Bbb N$ is recursively enumerable; $R := Bbb N$ is recursive; good luck classifying the subsets of $Bbb N$.







        share|cite|improve this answer













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        answered Jul 31 at 20:06









        Kenny Lau

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