Find a great strategy to a pentomino type game
Clash Royale CLAN TAG#URR8PPP
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2
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I have a game.
Given an $8times 8$ square and a set, which contains the pentominoes and four $1times 1$ squares. Players alternately pick one item from the set. Then players (starting with the player who had chosen the first item) take turns in placing pentominoes on the board so that they do not overlap with existing tiles and no tile is used more than once. The objective is to be the last player to place a tile on the board.
So I need a great strategy. I am sure there doesn’t exist a winning strategy (and if so, then it is complicated), so I only need a strategy which helps to win.
game-theory combinatorial-game-theory polyomino
add a comment |Â
up vote
2
down vote
favorite
I have a game.
Given an $8times 8$ square and a set, which contains the pentominoes and four $1times 1$ squares. Players alternately pick one item from the set. Then players (starting with the player who had chosen the first item) take turns in placing pentominoes on the board so that they do not overlap with existing tiles and no tile is used more than once. The objective is to be the last player to place a tile on the board.
So I need a great strategy. I am sure there doesn’t exist a winning strategy (and if so, then it is complicated), so I only need a strategy which helps to win.
game-theory combinatorial-game-theory polyomino
3
What's the origin of this problem? What have you tried so far? (There most certainly does exist a winning strategy, since the game is finite and always has a winner). Also, your description of the problem suggests that the pentominos could be flipped (since $12times5+4=64$), but your image is of the 18 'one-sided' pentominoes; which is it?
– Steven Stadnicki
Jul 31 at 15:47
You are able to rotate and mirror each pentomino
– Leo Gardner
Jul 31 at 20:27
Please help to find as good strategy as possible
– Leo Gardner
Jul 31 at 20:28
add a comment |Â
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I have a game.
Given an $8times 8$ square and a set, which contains the pentominoes and four $1times 1$ squares. Players alternately pick one item from the set. Then players (starting with the player who had chosen the first item) take turns in placing pentominoes on the board so that they do not overlap with existing tiles and no tile is used more than once. The objective is to be the last player to place a tile on the board.
So I need a great strategy. I am sure there doesn’t exist a winning strategy (and if so, then it is complicated), so I only need a strategy which helps to win.
game-theory combinatorial-game-theory polyomino
I have a game.
Given an $8times 8$ square and a set, which contains the pentominoes and four $1times 1$ squares. Players alternately pick one item from the set. Then players (starting with the player who had chosen the first item) take turns in placing pentominoes on the board so that they do not overlap with existing tiles and no tile is used more than once. The objective is to be the last player to place a tile on the board.
So I need a great strategy. I am sure there doesn’t exist a winning strategy (and if so, then it is complicated), so I only need a strategy which helps to win.
game-theory combinatorial-game-theory polyomino
edited Aug 5 at 2:47
Herman Tulleken
782416
782416
asked Jul 31 at 15:39
Leo Gardner
35911
35911
3
What's the origin of this problem? What have you tried so far? (There most certainly does exist a winning strategy, since the game is finite and always has a winner). Also, your description of the problem suggests that the pentominos could be flipped (since $12times5+4=64$), but your image is of the 18 'one-sided' pentominoes; which is it?
– Steven Stadnicki
Jul 31 at 15:47
You are able to rotate and mirror each pentomino
– Leo Gardner
Jul 31 at 20:27
Please help to find as good strategy as possible
– Leo Gardner
Jul 31 at 20:28
add a comment |Â
3
What's the origin of this problem? What have you tried so far? (There most certainly does exist a winning strategy, since the game is finite and always has a winner). Also, your description of the problem suggests that the pentominos could be flipped (since $12times5+4=64$), but your image is of the 18 'one-sided' pentominoes; which is it?
– Steven Stadnicki
Jul 31 at 15:47
You are able to rotate and mirror each pentomino
– Leo Gardner
Jul 31 at 20:27
Please help to find as good strategy as possible
– Leo Gardner
Jul 31 at 20:28
3
3
What's the origin of this problem? What have you tried so far? (There most certainly does exist a winning strategy, since the game is finite and always has a winner). Also, your description of the problem suggests that the pentominos could be flipped (since $12times5+4=64$), but your image is of the 18 'one-sided' pentominoes; which is it?
– Steven Stadnicki
Jul 31 at 15:47
What's the origin of this problem? What have you tried so far? (There most certainly does exist a winning strategy, since the game is finite and always has a winner). Also, your description of the problem suggests that the pentominos could be flipped (since $12times5+4=64$), but your image is of the 18 'one-sided' pentominoes; which is it?
– Steven Stadnicki
Jul 31 at 15:47
You are able to rotate and mirror each pentomino
– Leo Gardner
Jul 31 at 20:27
You are able to rotate and mirror each pentomino
– Leo Gardner
Jul 31 at 20:27
Please help to find as good strategy as possible
– Leo Gardner
Jul 31 at 20:28
Please help to find as good strategy as possible
– Leo Gardner
Jul 31 at 20:28
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
0
down vote
This game is described in Golombs' Polyominoes (p. 8-9). He writes:
It is difficult to advise what strategy should be followed, but
there are two valuable strategic principles:
- Try to move in such a way that there will be room for
an even number of pieces. (This applies only when there
are two players.)
- If a player cannot analyze the situation, he should do
something to complicate the placement so that the next
player will have even more difficulty analyzing it than
he did.
Since this reference is quite old, you may be able to dig up some further work on this topic.
Here is a proof that the first player can always win: Pentominoes: A First Player Win. They describe various ways in which the search algorithm can be sped up; doing the opposite then can be a good way to implement number (2) above. They also give two winning moves.
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
This game is described in Golombs' Polyominoes (p. 8-9). He writes:
It is difficult to advise what strategy should be followed, but
there are two valuable strategic principles:
- Try to move in such a way that there will be room for
an even number of pieces. (This applies only when there
are two players.)
- If a player cannot analyze the situation, he should do
something to complicate the placement so that the next
player will have even more difficulty analyzing it than
he did.
Since this reference is quite old, you may be able to dig up some further work on this topic.
Here is a proof that the first player can always win: Pentominoes: A First Player Win. They describe various ways in which the search algorithm can be sped up; doing the opposite then can be a good way to implement number (2) above. They also give two winning moves.
add a comment |Â
up vote
0
down vote
This game is described in Golombs' Polyominoes (p. 8-9). He writes:
It is difficult to advise what strategy should be followed, but
there are two valuable strategic principles:
- Try to move in such a way that there will be room for
an even number of pieces. (This applies only when there
are two players.)
- If a player cannot analyze the situation, he should do
something to complicate the placement so that the next
player will have even more difficulty analyzing it than
he did.
Since this reference is quite old, you may be able to dig up some further work on this topic.
Here is a proof that the first player can always win: Pentominoes: A First Player Win. They describe various ways in which the search algorithm can be sped up; doing the opposite then can be a good way to implement number (2) above. They also give two winning moves.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
This game is described in Golombs' Polyominoes (p. 8-9). He writes:
It is difficult to advise what strategy should be followed, but
there are two valuable strategic principles:
- Try to move in such a way that there will be room for
an even number of pieces. (This applies only when there
are two players.)
- If a player cannot analyze the situation, he should do
something to complicate the placement so that the next
player will have even more difficulty analyzing it than
he did.
Since this reference is quite old, you may be able to dig up some further work on this topic.
Here is a proof that the first player can always win: Pentominoes: A First Player Win. They describe various ways in which the search algorithm can be sped up; doing the opposite then can be a good way to implement number (2) above. They also give two winning moves.
This game is described in Golombs' Polyominoes (p. 8-9). He writes:
It is difficult to advise what strategy should be followed, but
there are two valuable strategic principles:
- Try to move in such a way that there will be room for
an even number of pieces. (This applies only when there
are two players.)
- If a player cannot analyze the situation, he should do
something to complicate the placement so that the next
player will have even more difficulty analyzing it than
he did.
Since this reference is quite old, you may be able to dig up some further work on this topic.
Here is a proof that the first player can always win: Pentominoes: A First Player Win. They describe various ways in which the search algorithm can be sped up; doing the opposite then can be a good way to implement number (2) above. They also give two winning moves.
answered Aug 5 at 2:33
Herman Tulleken
782416
782416
add a comment |Â
add a comment |Â
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3
What's the origin of this problem? What have you tried so far? (There most certainly does exist a winning strategy, since the game is finite and always has a winner). Also, your description of the problem suggests that the pentominos could be flipped (since $12times5+4=64$), but your image is of the 18 'one-sided' pentominoes; which is it?
– Steven Stadnicki
Jul 31 at 15:47
You are able to rotate and mirror each pentomino
– Leo Gardner
Jul 31 at 20:27
Please help to find as good strategy as possible
– Leo Gardner
Jul 31 at 20:28