General formula for natural power summation nested

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Is there any general formula (even non concise) for



$$sum sum sum cdots sum limits_m - times n^k $$



For m = 1



$$sum n^k = 1^k + 2^k +3^k +cdots + n^k$$



For m = 2



$$sum sum n^k = 1^k +(1^k + 2^k) + (1^k + 2^k +3^k) +cdots + (1^k +2^k +3^k +cdots +n^k)$$
and so on....







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  • 3




    Be careful with your summing indices, $n$ shouldn't be the upper bound of summation and the running index
    – user190080
    Aug 1 at 13:02










  • @user190080 unless ofc, that this is an indefinite sum. Regardless though, the formatting is ambiguous.
    – Simply Beautiful Art
    Aug 1 at 15:08






  • 2




    For $k=0,1,$ you may note the hockey-stick identity: $$sum_n=0^Nbinom nk=binomN+1k+1$$
    – Simply Beautiful Art
    Aug 1 at 15:11















up vote
0
down vote

favorite












Is there any general formula (even non concise) for



$$sum sum sum cdots sum limits_m - times n^k $$



For m = 1



$$sum n^k = 1^k + 2^k +3^k +cdots + n^k$$



For m = 2



$$sum sum n^k = 1^k +(1^k + 2^k) + (1^k + 2^k +3^k) +cdots + (1^k +2^k +3^k +cdots +n^k)$$
and so on....







share|cite|improve this question

















  • 3




    Be careful with your summing indices, $n$ shouldn't be the upper bound of summation and the running index
    – user190080
    Aug 1 at 13:02










  • @user190080 unless ofc, that this is an indefinite sum. Regardless though, the formatting is ambiguous.
    – Simply Beautiful Art
    Aug 1 at 15:08






  • 2




    For $k=0,1,$ you may note the hockey-stick identity: $$sum_n=0^Nbinom nk=binomN+1k+1$$
    – Simply Beautiful Art
    Aug 1 at 15:11













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Is there any general formula (even non concise) for



$$sum sum sum cdots sum limits_m - times n^k $$



For m = 1



$$sum n^k = 1^k + 2^k +3^k +cdots + n^k$$



For m = 2



$$sum sum n^k = 1^k +(1^k + 2^k) + (1^k + 2^k +3^k) +cdots + (1^k +2^k +3^k +cdots +n^k)$$
and so on....







share|cite|improve this question













Is there any general formula (even non concise) for



$$sum sum sum cdots sum limits_m - times n^k $$



For m = 1



$$sum n^k = 1^k + 2^k +3^k +cdots + n^k$$



For m = 2



$$sum sum n^k = 1^k +(1^k + 2^k) + (1^k + 2^k +3^k) +cdots + (1^k +2^k +3^k +cdots +n^k)$$
and so on....









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Aug 1 at 13:13
























asked Aug 1 at 12:55









hanugm

789419




789419







  • 3




    Be careful with your summing indices, $n$ shouldn't be the upper bound of summation and the running index
    – user190080
    Aug 1 at 13:02










  • @user190080 unless ofc, that this is an indefinite sum. Regardless though, the formatting is ambiguous.
    – Simply Beautiful Art
    Aug 1 at 15:08






  • 2




    For $k=0,1,$ you may note the hockey-stick identity: $$sum_n=0^Nbinom nk=binomN+1k+1$$
    – Simply Beautiful Art
    Aug 1 at 15:11













  • 3




    Be careful with your summing indices, $n$ shouldn't be the upper bound of summation and the running index
    – user190080
    Aug 1 at 13:02










  • @user190080 unless ofc, that this is an indefinite sum. Regardless though, the formatting is ambiguous.
    – Simply Beautiful Art
    Aug 1 at 15:08






  • 2




    For $k=0,1,$ you may note the hockey-stick identity: $$sum_n=0^Nbinom nk=binomN+1k+1$$
    – Simply Beautiful Art
    Aug 1 at 15:11








3




3




Be careful with your summing indices, $n$ shouldn't be the upper bound of summation and the running index
– user190080
Aug 1 at 13:02




Be careful with your summing indices, $n$ shouldn't be the upper bound of summation and the running index
– user190080
Aug 1 at 13:02












@user190080 unless ofc, that this is an indefinite sum. Regardless though, the formatting is ambiguous.
– Simply Beautiful Art
Aug 1 at 15:08




@user190080 unless ofc, that this is an indefinite sum. Regardless though, the formatting is ambiguous.
– Simply Beautiful Art
Aug 1 at 15:08




2




2




For $k=0,1,$ you may note the hockey-stick identity: $$sum_n=0^Nbinom nk=binomN+1k+1$$
– Simply Beautiful Art
Aug 1 at 15:11





For $k=0,1,$ you may note the hockey-stick identity: $$sum_n=0^Nbinom nk=binomN+1k+1$$
– Simply Beautiful Art
Aug 1 at 15:11
















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