Inference in Bayesian network

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Consider the following figure



Now, I need to calculate $P(l^1)$ and $P(l^1 mid i^o)$



$$P(l^1) = P(l^1, g^1) + P(l^1, g^2) + P(l^1, g^3) $$



$$= P(g^1)P(l^1mid g^1) + P(g^2)P(l^1mid g^2) + P(g^3)P(l^1mid g^3) $$



We can calculate remaining (in above) as follows



$$P(g^1) = P(g^1mid i^0 d^0) P(i^0) P(d^0) + P(g^1mid i^0 d^1) P(i^0) P(d^1) + P(g^1mid i^1 d^0) P(i^1) P(d^0) + P(g^1mid i^1 d^1) P(i^1) P(d^1)$$



My doubt is the to calculate $P(l^1 mid i^0)$



I got struck after this



$$P(l^1 mid i^0) = dfracP(l^1, i^0)P(i^0) = dfrac?0.7$$




bayesian-network




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    Consider the following figure



    Now, I need to calculate $P(l^1)$ and $P(l^1 mid i^o)$



    $$P(l^1) = P(l^1, g^1) + P(l^1, g^2) + P(l^1, g^3) $$



    $$= P(g^1)P(l^1mid g^1) + P(g^2)P(l^1mid g^2) + P(g^3)P(l^1mid g^3) $$



    We can calculate remaining (in above) as follows



    $$P(g^1) = P(g^1mid i^0 d^0) P(i^0) P(d^0) + P(g^1mid i^0 d^1) P(i^0) P(d^1) + P(g^1mid i^1 d^0) P(i^1) P(d^0) + P(g^1mid i^1 d^1) P(i^1) P(d^1)$$



    My doubt is the to calculate $P(l^1 mid i^0)$



    I got struck after this



    $$P(l^1 mid i^0) = dfracP(l^1, i^0)P(i^0) = dfrac?0.7$$




    bayesian-network




    share|cite|improve this question























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Consider the following figure



      Now, I need to calculate $P(l^1)$ and $P(l^1 mid i^o)$



      $$P(l^1) = P(l^1, g^1) + P(l^1, g^2) + P(l^1, g^3) $$



      $$= P(g^1)P(l^1mid g^1) + P(g^2)P(l^1mid g^2) + P(g^3)P(l^1mid g^3) $$



      We can calculate remaining (in above) as follows



      $$P(g^1) = P(g^1mid i^0 d^0) P(i^0) P(d^0) + P(g^1mid i^0 d^1) P(i^0) P(d^1) + P(g^1mid i^1 d^0) P(i^1) P(d^0) + P(g^1mid i^1 d^1) P(i^1) P(d^1)$$



      My doubt is the to calculate $P(l^1 mid i^0)$



      I got struck after this



      $$P(l^1 mid i^0) = dfracP(l^1, i^0)P(i^0) = dfrac?0.7$$




      bayesian-network




      share|cite|improve this question













      Consider the following figure



      Now, I need to calculate $P(l^1)$ and $P(l^1 mid i^o)$



      $$P(l^1) = P(l^1, g^1) + P(l^1, g^2) + P(l^1, g^3) $$



      $$= P(g^1)P(l^1mid g^1) + P(g^2)P(l^1mid g^2) + P(g^3)P(l^1mid g^3) $$



      We can calculate remaining (in above) as follows



      $$P(g^1) = P(g^1mid i^0 d^0) P(i^0) P(d^0) + P(g^1mid i^0 d^1) P(i^0) P(d^1) + P(g^1mid i^1 d^0) P(i^1) P(d^0) + P(g^1mid i^1 d^1) P(i^1) P(d^1)$$



      My doubt is the to calculate $P(l^1 mid i^0)$



      I got struck after this



      $$P(l^1 mid i^0) = dfracP(l^1, i^0)P(i^0) = dfrac?0.7$$





      bayesian-network





      share|cite|improve this question












      share|cite|improve this question




      share|cite|improve this question








      edited Aug 1 at 10:04
























      asked Aug 1 at 9:46









      hanugm

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