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Isosceles or Right Triangle?
Clash Royale CLAN TAG#URR8PPP
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Do the points $A(6,4)$, $B(4,-3)$, and $C(-2,3)$ form an isosceles triangle or a right triangle? How do you know?
I tried converting these to polar coordinates..
geometry triangle
edited Jul 31 at 17:22
Math Lover
12.2k21132
asked Jul 31 at 17:07
amber patel
6
add a comment |Â
up vote
0
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favorite
Do the points $A(6,4)$, $B(4,-3)$, and $C(-2,3)$ form an isosceles triangle or a right triangle? How do you know?
I tried converting these to polar coordinates..
geometry triangle
edited Jul 31 at 17:22
Math Lover
12.2k21132
asked Jul 31 at 17:07
amber patel
6
2
How about computing the side-lengths of the triangle?
– Lord Shark the Unknown
Jul 31 at 17:08
Why polar? Compute the distances between all the points.
– Randall
Jul 31 at 17:08
I highly recommend graphing those points and then computing the distances between them.
– é«˜ç”°èˆª
Jul 31 at 17:09
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Do the points $A(6,4)$, $B(4,-3)$, and $C(-2,3)$ form an isosceles triangle or a right triangle? How do you know?
I tried converting these to polar coordinates..
geometry triangle
edited Jul 31 at 17:22
Math Lover
12.2k21132
asked Jul 31 at 17:07
amber patel
6
Do the points $A(6,4)$, $B(4,-3)$, and $C(-2,3)$ form an isosceles triangle or a right triangle? How do you know?
I tried converting these to polar coordinates..
geometry triangle
edited Jul 31 at 17:22
Math Lover
12.2k21132
asked Jul 31 at 17:07
amber patel
6
edited Jul 31 at 17:22
Math Lover
12.2k21132
edited Jul 31 at 17:22
Math Lover
12.2k21132
edited Jul 31 at 17:22
Math Lover
12.2k21132
12.2k21132
asked Jul 31 at 17:07
amber patel
6
asked Jul 31 at 17:07
amber patel
6
asked Jul 31 at 17:07
amber patel
6
6
2
How about computing the side-lengths of the triangle?
– Lord Shark the Unknown
Jul 31 at 17:08
Why polar? Compute the distances between all the points.
– Randall
Jul 31 at 17:08
I highly recommend graphing those points and then computing the distances between them.
– é«˜ç”°èˆª
Jul 31 at 17:09
add a comment |Â
2
How about computing the side-lengths of the triangle?
– Lord Shark the Unknown
Jul 31 at 17:08
Why polar? Compute the distances between all the points.
– Randall
Jul 31 at 17:08
I highly recommend graphing those points and then computing the distances between them.
– é«˜ç”°èˆª
Jul 31 at 17:09
2
2
How about computing the side-lengths of the triangle?
– Lord Shark the Unknown
Jul 31 at 17:08
How about computing the side-lengths of the triangle?
– Lord Shark the Unknown
Jul 31 at 17:08
Why polar? Compute the distances between all the points.
– Randall
Jul 31 at 17:08
Why polar? Compute the distances between all the points.
– Randall
Jul 31 at 17:08
I highly recommend graphing those points and then computing the distances between them.
– é«˜ç”°èˆª
Jul 31 at 17:09
I highly recommend graphing those points and then computing the distances between them.
– é«˜ç”°èˆª
Jul 31 at 17:09
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
2
down vote
Hint: Compute $$AB=sqrt(4-6)^2+(-3-4)^2=…$$
$$BC=sqrt(-2-4)^2+(3-(-3))^2=…$$
answered Jul 31 at 17:09
Dr. Sonnhard Graubner
66.6k32659
add a comment |Â
up vote
2
down vote
$$AB=sqrt(4-6)^2+(-3-4)^2=sqrt53\BC=sqrt(-2-4)^2+(3-(-3))^2=sqrt72\AC=sqrt(-2-6)^2+(3-4)^2=sqrt65$$This is not a right triangle because $a^2+b^2ne c^2$.
This not an isosceles triangle because no two sides are equal.
answered Jul 31 at 17:23
Key Flex
3,817423
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
Hint: Compute $$AB=sqrt(4-6)^2+(-3-4)^2=…$$
$$BC=sqrt(-2-4)^2+(3-(-3))^2=…$$
answered Jul 31 at 17:09
Dr. Sonnhard Graubner
66.6k32659
add a comment |Â
up vote
2
down vote
Hint: Compute $$AB=sqrt(4-6)^2+(-3-4)^2=…$$
$$BC=sqrt(-2-4)^2+(3-(-3))^2=…$$
answered Jul 31 at 17:09
Dr. Sonnhard Graubner
66.6k32659
add a comment |Â
up vote
2
down vote
up vote
2
down vote
Hint: Compute $$AB=sqrt(4-6)^2+(-3-4)^2=…$$
$$BC=sqrt(-2-4)^2+(3-(-3))^2=…$$
answered Jul 31 at 17:09
Dr. Sonnhard Graubner
66.6k32659
Hint: Compute $$AB=sqrt(4-6)^2+(-3-4)^2=…$$
$$BC=sqrt(-2-4)^2+(3-(-3))^2=…$$
answered Jul 31 at 17:09
Dr. Sonnhard Graubner
66.6k32659
answered Jul 31 at 17:09
Dr. Sonnhard Graubner
66.6k32659
answered Jul 31 at 17:09
Dr. Sonnhard Graubner
66.6k32659
answered Jul 31 at 17:09
Dr. Sonnhard Graubner
66.6k32659
66.6k32659
add a comment |Â
add a comment |Â
up vote
2
down vote
$$AB=sqrt(4-6)^2+(-3-4)^2=sqrt53\BC=sqrt(-2-4)^2+(3-(-3))^2=sqrt72\AC=sqrt(-2-6)^2+(3-4)^2=sqrt65$$This is not a right triangle because $a^2+b^2ne c^2$.
This not an isosceles triangle because no two sides are equal.
answered Jul 31 at 17:23
Key Flex
3,817423
add a comment |Â
up vote
2
down vote
$$AB=sqrt(4-6)^2+(-3-4)^2=sqrt53\BC=sqrt(-2-4)^2+(3-(-3))^2=sqrt72\AC=sqrt(-2-6)^2+(3-4)^2=sqrt65$$This is not a right triangle because $a^2+b^2ne c^2$.
This not an isosceles triangle because no two sides are equal.
answered Jul 31 at 17:23
Key Flex
3,817423
add a comment |Â
up vote
2
down vote
up vote
2
down vote
$$AB=sqrt(4-6)^2+(-3-4)^2=sqrt53\BC=sqrt(-2-4)^2+(3-(-3))^2=sqrt72\AC=sqrt(-2-6)^2+(3-4)^2=sqrt65$$This is not a right triangle because $a^2+b^2ne c^2$.
This not an isosceles triangle because no two sides are equal.
answered Jul 31 at 17:23
Key Flex
3,817423
$$AB=sqrt(4-6)^2+(-3-4)^2=sqrt53\BC=sqrt(-2-4)^2+(3-(-3))^2=sqrt72\AC=sqrt(-2-6)^2+(3-4)^2=sqrt65$$This is not a right triangle because $a^2+b^2ne c^2$.
This not an isosceles triangle because no two sides are equal.
answered Jul 31 at 17:23
Key Flex
3,817423
edited Jul 31 at 18:11
answered Jul 31 at 17:23
Key Flex
3,817423
answered Jul 31 at 17:23
Key Flex
3,817423
answered Jul 31 at 17:23
Key Flex
3,817423
3,817423
add a comment |Â
add a comment |Â
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2
How about computing the side-lengths of the triangle?
– Lord Shark the Unknown
Jul 31 at 17:08
Why polar? Compute the distances between all the points.
– Randall
Jul 31 at 17:08
I highly recommend graphing those points and then computing the distances between them.
– é«˜ç”°èˆª
Jul 31 at 17:09