Maximal torus and the structure of complex flag manifolds
Clash Royale CLAN TAG#URR8PPP
up vote
1
down vote
favorite
Consider the compact Lie group $G=Tcdot S$ with finite intersection $I:=Tcap S$, where $T$ is the central torus and $S$ the maximal semisimple subgroup. Now, $S/Icong G/T$ has the structure of a complex flag manifold.
Since $S/I$ is a Lie group, Does it mean that it has the structure of a complex Lie group? I was thinking in the case where the intersection is finite then if $S$ is complex Lie group then it is abelian since it is compact!
So if $S/I$ is not a complex Lie group, what its complexification?
differential-geometry lie-groups
add a comment |Â
up vote
1
down vote
favorite
Consider the compact Lie group $G=Tcdot S$ with finite intersection $I:=Tcap S$, where $T$ is the central torus and $S$ the maximal semisimple subgroup. Now, $S/Icong G/T$ has the structure of a complex flag manifold.
Since $S/I$ is a Lie group, Does it mean that it has the structure of a complex Lie group? I was thinking in the case where the intersection is finite then if $S$ is complex Lie group then it is abelian since it is compact!
So if $S/I$ is not a complex Lie group, what its complexification?
differential-geometry lie-groups
It is both a complex manifold and a Lie group, but as you observe $S$ is usually rather nonabelian, so the multiplication map is not holomorphic. I don't know the answer to your second question.
– Mike Miller
13 mins ago
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Consider the compact Lie group $G=Tcdot S$ with finite intersection $I:=Tcap S$, where $T$ is the central torus and $S$ the maximal semisimple subgroup. Now, $S/Icong G/T$ has the structure of a complex flag manifold.
Since $S/I$ is a Lie group, Does it mean that it has the structure of a complex Lie group? I was thinking in the case where the intersection is finite then if $S$ is complex Lie group then it is abelian since it is compact!
So if $S/I$ is not a complex Lie group, what its complexification?
differential-geometry lie-groups
Consider the compact Lie group $G=Tcdot S$ with finite intersection $I:=Tcap S$, where $T$ is the central torus and $S$ the maximal semisimple subgroup. Now, $S/Icong G/T$ has the structure of a complex flag manifold.
Since $S/I$ is a Lie group, Does it mean that it has the structure of a complex Lie group? I was thinking in the case where the intersection is finite then if $S$ is complex Lie group then it is abelian since it is compact!
So if $S/I$ is not a complex Lie group, what its complexification?
differential-geometry lie-groups
asked 2 hours ago
Ronald
1,5601820
1,5601820
It is both a complex manifold and a Lie group, but as you observe $S$ is usually rather nonabelian, so the multiplication map is not holomorphic. I don't know the answer to your second question.
– Mike Miller
13 mins ago
add a comment |Â
It is both a complex manifold and a Lie group, but as you observe $S$ is usually rather nonabelian, so the multiplication map is not holomorphic. I don't know the answer to your second question.
– Mike Miller
13 mins ago
It is both a complex manifold and a Lie group, but as you observe $S$ is usually rather nonabelian, so the multiplication map is not holomorphic. I don't know the answer to your second question.
– Mike Miller
13 mins ago
It is both a complex manifold and a Lie group, but as you observe $S$ is usually rather nonabelian, so the multiplication map is not holomorphic. I don't know the answer to your second question.
– Mike Miller
13 mins ago
add a comment |Â
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2873356%2fmaximal-torus-and-the-structure-of-complex-flag-manifolds%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
It is both a complex manifold and a Lie group, but as you observe $S$ is usually rather nonabelian, so the multiplication map is not holomorphic. I don't know the answer to your second question.
– Mike Miller
13 mins ago