Maxima CAS Simplifying [on hold]

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Could someone please point me in the right direction as to how to enter this equation into Maxima CAS so I can simplify it?



(8a^2 + b^5 + c^-2) / (2a^5 + b^2 + c^-1/2)^-1/6


Many thanks



Amanda




maxima-software




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put on hold as off-topic by Claude Leibovici, amWhy, John Ma, Adrian Keister, Xander Henderson yesterday


This question appears to be off-topic. The users who voted to close gave these specific reasons:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – John Ma, Xander Henderson

  • "This question is not about mathematics, within the scope defined in the help center." – Claude Leibovici, amWhy, Adrian Keister

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    Be much more precise with your brackets for a start - its easy to add brackets and get a completely different formula in my CAS $$( (8a)^2 + b^5 + c^(-2 )) / ( (2a)^5 + b^2 + c^(-1/2) )^(-1/6)$$
    – James Arathoon
    2 days ago







  • 1




    @Amanda: In any case, what makes you think the expression can be made simpler?
    – quasi
    2 days ago










  • Because that's what I have been asked to do for my assignment
    – Amanda
    2 days ago















up vote
0
down vote

favorite












Could someone please point me in the right direction as to how to enter this equation into Maxima CAS so I can simplify it?



(8a^2 + b^5 + c^-2) / (2a^5 + b^2 + c^-1/2)^-1/6


Many thanks



Amanda




maxima-software




share|cite|improve this question











put on hold as off-topic by Claude Leibovici, amWhy, John Ma, Adrian Keister, Xander Henderson yesterday


This question appears to be off-topic. The users who voted to close gave these specific reasons:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – John Ma, Xander Henderson

  • "This question is not about mathematics, within the scope defined in the help center." – Claude Leibovici, amWhy, Adrian Keister

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    Be much more precise with your brackets for a start - its easy to add brackets and get a completely different formula in my CAS $$( (8a)^2 + b^5 + c^(-2 )) / ( (2a)^5 + b^2 + c^(-1/2) )^(-1/6)$$
    – James Arathoon
    2 days ago







  • 1




    @Amanda: In any case, what makes you think the expression can be made simpler?
    – quasi
    2 days ago










  • Because that's what I have been asked to do for my assignment
    – Amanda
    2 days ago













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Could someone please point me in the right direction as to how to enter this equation into Maxima CAS so I can simplify it?



(8a^2 + b^5 + c^-2) / (2a^5 + b^2 + c^-1/2)^-1/6


Many thanks



Amanda




maxima-software




share|cite|improve this question











Could someone please point me in the right direction as to how to enter this equation into Maxima CAS so I can simplify it?



(8a^2 + b^5 + c^-2) / (2a^5 + b^2 + c^-1/2)^-1/6


Many thanks



Amanda





maxima-software





share|cite|improve this question










share|cite|improve this question




share|cite|improve this question









asked 2 days ago









Amanda

102




102




put on hold as off-topic by Claude Leibovici, amWhy, John Ma, Adrian Keister, Xander Henderson yesterday


This question appears to be off-topic. The users who voted to close gave these specific reasons:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – John Ma, Xander Henderson

  • "This question is not about mathematics, within the scope defined in the help center." – Claude Leibovici, amWhy, Adrian Keister

If this question can be reworded to fit the rules in the help center, please edit the question.




put on hold as off-topic by Claude Leibovici, amWhy, John Ma, Adrian Keister, Xander Henderson yesterday


This question appears to be off-topic. The users who voted to close gave these specific reasons:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – John Ma, Xander Henderson

  • "This question is not about mathematics, within the scope defined in the help center." – Claude Leibovici, amWhy, Adrian Keister

If this question can be reworded to fit the rules in the help center, please edit the question.







  • 1




    Be much more precise with your brackets for a start - its easy to add brackets and get a completely different formula in my CAS $$( (8a)^2 + b^5 + c^(-2 )) / ( (2a)^5 + b^2 + c^(-1/2) )^(-1/6)$$
    – James Arathoon
    2 days ago







  • 1




    @Amanda: In any case, what makes you think the expression can be made simpler?
    – quasi
    2 days ago










  • Because that's what I have been asked to do for my assignment
    – Amanda
    2 days ago













  • 1




    Be much more precise with your brackets for a start - its easy to add brackets and get a completely different formula in my CAS $$( (8a)^2 + b^5 + c^(-2 )) / ( (2a)^5 + b^2 + c^(-1/2) )^(-1/6)$$
    – James Arathoon
    2 days ago







  • 1




    @Amanda: In any case, what makes you think the expression can be made simpler?
    – quasi
    2 days ago










  • Because that's what I have been asked to do for my assignment
    – Amanda
    2 days ago








1




1




Be much more precise with your brackets for a start - its easy to add brackets and get a completely different formula in my CAS $$( (8a)^2 + b^5 + c^(-2 )) / ( (2a)^5 + b^2 + c^(-1/2) )^(-1/6)$$
– James Arathoon
2 days ago





Be much more precise with your brackets for a start - its easy to add brackets and get a completely different formula in my CAS $$( (8a)^2 + b^5 + c^(-2 )) / ( (2a)^5 + b^2 + c^(-1/2) )^(-1/6)$$
– James Arathoon
2 days ago





1




1




@Amanda: In any case, what makes you think the expression can be made simpler?
– quasi
2 days ago




@Amanda: In any case, what makes you think the expression can be made simpler?
– quasi
2 days ago












Because that's what I have been asked to do for my assignment
– Amanda
2 days ago





Because that's what I have been asked to do for my assignment
– Amanda
2 days ago











1 Answer
1






active

oldest

votes

















up vote
1
down vote



accepted










As @JamesArathoon already mentioned, your expression as it is now admits multiple interpretations. Also you seem to miss the second part of the equation.
Make sure you use parenthesis as well as the multiplication sign (*). If you want to use it in maxima, I'd recommend assigning it to a variable (in this case t). Try following:



t : (8*a^2 + b^5 + c^(-2))/(2*a^5 + b^2 + c^(-1/2))^(-1/6);
print(t);


Try it online!






share|cite|improve this answer





















  • Thank you so much it worked
    – Amanda
    2 days ago

















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










As @JamesArathoon already mentioned, your expression as it is now admits multiple interpretations. Also you seem to miss the second part of the equation.
Make sure you use parenthesis as well as the multiplication sign (*). If you want to use it in maxima, I'd recommend assigning it to a variable (in this case t). Try following:



t : (8*a^2 + b^5 + c^(-2))/(2*a^5 + b^2 + c^(-1/2))^(-1/6);
print(t);


Try it online!






share|cite|improve this answer





















  • Thank you so much it worked
    – Amanda
    2 days ago














up vote
1
down vote



accepted










As @JamesArathoon already mentioned, your expression as it is now admits multiple interpretations. Also you seem to miss the second part of the equation.
Make sure you use parenthesis as well as the multiplication sign (*). If you want to use it in maxima, I'd recommend assigning it to a variable (in this case t). Try following:



t : (8*a^2 + b^5 + c^(-2))/(2*a^5 + b^2 + c^(-1/2))^(-1/6);
print(t);


Try it online!






share|cite|improve this answer





















  • Thank you so much it worked
    – Amanda
    2 days ago












up vote
1
down vote



accepted







up vote
1
down vote



accepted






As @JamesArathoon already mentioned, your expression as it is now admits multiple interpretations. Also you seem to miss the second part of the equation.
Make sure you use parenthesis as well as the multiplication sign (*). If you want to use it in maxima, I'd recommend assigning it to a variable (in this case t). Try following:



t : (8*a^2 + b^5 + c^(-2))/(2*a^5 + b^2 + c^(-1/2))^(-1/6);
print(t);


Try it online!






share|cite|improve this answer













As @JamesArathoon already mentioned, your expression as it is now admits multiple interpretations. Also you seem to miss the second part of the equation.
Make sure you use parenthesis as well as the multiplication sign (*). If you want to use it in maxima, I'd recommend assigning it to a variable (in this case t). Try following:



t : (8*a^2 + b^5 + c^(-2))/(2*a^5 + b^2 + c^(-1/2))^(-1/6);
print(t);


Try it online!







share|cite|improve this answer













share|cite|improve this answer



share|cite|improve this answer











answered 2 days ago









flawr

10.9k32043




10.9k32043











  • Thank you so much it worked
    – Amanda
    2 days ago
















  • Thank you so much it worked
    – Amanda
    2 days ago















Thank you so much it worked
– Amanda
2 days ago




Thank you so much it worked
– Amanda
2 days ago


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