Find the indicated term of the geometric sequence algebraically. [on hold]

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a1=18, r=4/3, 8th term

1.Find the indicated term of the geometric sequence algebraically.

geometric-series

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asked Aug 3 at 20:07

Lala

11

put on hold as off-topic by amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson Aug 3 at 22:22

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Welcome to MSE! What do you know about geometric series that might be useful in solving this problem?
  – Robert Howard
  Aug 3 at 20:08
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  I know first term is 18, and difference is 4/3. We need to find 8th term so we?
  – Lala
  Aug 3 at 20:16
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Let's start with something a little simpler. How would you find the second term?
  – Robert Howard
  Aug 3 at 20:17
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  multiple 18 with 4/3
  – Lala
  Aug 3 at 20:19
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  second term is 24
  – Lala
  Aug 3 at 20:20
  

  
  
  
  

 | 
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up vote
0
down vote

favorite

a1=18, r=4/3, 8th term

1.Find the indicated term of the geometric sequence algebraically.

geometric-series

share|cite|improve this question

asked Aug 3 at 20:07

Lala

11

put on hold as off-topic by amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson Aug 3 at 22:22

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Welcome to MSE! What do you know about geometric series that might be useful in solving this problem?
  – Robert Howard
  Aug 3 at 20:08
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  I know first term is 18, and difference is 4/3. We need to find 8th term so we?
  – Lala
  Aug 3 at 20:16
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Let's start with something a little simpler. How would you find the second term?
  – Robert Howard
  Aug 3 at 20:17
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  multiple 18 with 4/3
  – Lala
  Aug 3 at 20:19
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  second term is 24
  – Lala
  Aug 3 at 20:20
  

  
  
  
  

 | 
show 7 more comments

up vote
0
down vote

favorite

up vote
0
down vote

favorite

a1=18, r=4/3, 8th term

1.Find the indicated term of the geometric sequence algebraically.

geometric-series

share|cite|improve this question

asked Aug 3 at 20:07

Lala

11

a1=18, r=4/3, 8th term

1.Find the indicated term of the geometric sequence algebraically.

geometric-series

share|cite|improve this question

asked Aug 3 at 20:07

Lala

11

share|cite|improve this question

share|cite|improve this question

asked Aug 3 at 20:07

Lala

11

asked Aug 3 at 20:07

Lala

11

asked Aug 3 at 20:07

Lala

11

11

put on hold as off-topic by amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson Aug 3 at 22:22

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson

If this question can be reworded to fit the rules in the help center, please edit the question.

put on hold as off-topic by amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson Aug 3 at 22:22

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Welcome to MSE! What do you know about geometric series that might be useful in solving this problem?
  – Robert Howard
  Aug 3 at 20:08
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  I know first term is 18, and difference is 4/3. We need to find 8th term so we?
  – Lala
  Aug 3 at 20:16
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Let's start with something a little simpler. How would you find the second term?
  – Robert Howard
  Aug 3 at 20:17
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  multiple 18 with 4/3
  – Lala
  Aug 3 at 20:19
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  second term is 24
  – Lala
  Aug 3 at 20:20
  

  
  
  
  

 | 
show 7 more comments

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Welcome to MSE! What do you know about geometric series that might be useful in solving this problem?
  – Robert Howard
  Aug 3 at 20:08
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  I know first term is 18, and difference is 4/3. We need to find 8th term so we?
  – Lala
  Aug 3 at 20:16
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Let's start with something a little simpler. How would you find the second term?
  – Robert Howard
  Aug 3 at 20:17
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  multiple 18 with 4/3
  – Lala
  Aug 3 at 20:19
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  second term is 24
  – Lala
  Aug 3 at 20:20
  

  
  
  
  

1

1

Welcome to MSE! What do you know about geometric series that might be useful in solving this problem?
– Robert Howard
Aug 3 at 20:08

Welcome to MSE! What do you know about geometric series that might be useful in solving this problem?
– Robert Howard
Aug 3 at 20:08

I know first term is 18, and difference is 4/3. We need to find 8th term so we?
– Lala
Aug 3 at 20:16

I know first term is 18, and difference is 4/3. We need to find 8th term so we?
– Lala
Aug 3 at 20:16

1

1

Let's start with something a little simpler. How would you find the second term?
– Robert Howard
Aug 3 at 20:17

Let's start with something a little simpler. How would you find the second term?
– Robert Howard
Aug 3 at 20:17

multiple 18 with 4/3
– Lala
Aug 3 at 20:19

multiple 18 with 4/3
– Lala
Aug 3 at 20:19

second term is 24
– Lala
Aug 3 at 20:20

second term is 24
– Lala
Aug 3 at 20:20

 | 
show 7 more comments

1 Answer
1

active

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votes

up vote
1
down vote

Just to summarize what transpired in the comments:

Notice that
$$a_colorred1=18timesleft(frac43right)^colorred0=18times1=18$$
$$a_colorred2=18timesleft(frac43right)^colorred1=18timesfrac43=24$$
$$a_colorred3=18timesleft(frac43right)^colorred2=18timesfrac169=32$$
$$dots$$
Continuing the pattern a few more times, you'll find that
$$a_colorred8=18timesleft(frac43right)^colorred7=18timesfrac163842187approx134.85$$
Problems like this become much simpler if you can find a pattern!

share|cite|improve this answer

answered Aug 3 at 20:38

Robert Howard

1,241620

add a comment | 

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
1
down vote

Just to summarize what transpired in the comments:

Notice that
$$a_colorred1=18timesleft(frac43right)^colorred0=18times1=18$$
$$a_colorred2=18timesleft(frac43right)^colorred1=18timesfrac43=24$$
$$a_colorred3=18timesleft(frac43right)^colorred2=18timesfrac169=32$$
$$dots$$
Continuing the pattern a few more times, you'll find that
$$a_colorred8=18timesleft(frac43right)^colorred7=18timesfrac163842187approx134.85$$
Problems like this become much simpler if you can find a pattern!

share|cite|improve this answer

answered Aug 3 at 20:38

Robert Howard

1,241620

add a comment | 

up vote
1
down vote

Just to summarize what transpired in the comments:

Notice that
$$a_colorred1=18timesleft(frac43right)^colorred0=18times1=18$$
$$a_colorred2=18timesleft(frac43right)^colorred1=18timesfrac43=24$$
$$a_colorred3=18timesleft(frac43right)^colorred2=18timesfrac169=32$$
$$dots$$
Continuing the pattern a few more times, you'll find that
$$a_colorred8=18timesleft(frac43right)^colorred7=18timesfrac163842187approx134.85$$
Problems like this become much simpler if you can find a pattern!

share|cite|improve this answer

answered Aug 3 at 20:38

Robert Howard

1,241620

add a comment | 

up vote
1
down vote

up vote
1
down vote

Just to summarize what transpired in the comments:

Notice that
$$a_colorred1=18timesleft(frac43right)^colorred0=18times1=18$$
$$a_colorred2=18timesleft(frac43right)^colorred1=18timesfrac43=24$$
$$a_colorred3=18timesleft(frac43right)^colorred2=18timesfrac169=32$$
$$dots$$
Continuing the pattern a few more times, you'll find that
$$a_colorred8=18timesleft(frac43right)^colorred7=18timesfrac163842187approx134.85$$
Problems like this become much simpler if you can find a pattern!

share|cite|improve this answer

answered Aug 3 at 20:38

Robert Howard

1,241620

Just to summarize what transpired in the comments:

Notice that
$$a_colorred1=18timesleft(frac43right)^colorred0=18times1=18$$
$$a_colorred2=18timesleft(frac43right)^colorred1=18timesfrac43=24$$
$$a_colorred3=18timesleft(frac43right)^colorred2=18timesfrac169=32$$
$$dots$$
Continuing the pattern a few more times, you'll find that
$$a_colorred8=18timesleft(frac43right)^colorred7=18timesfrac163842187approx134.85$$
Problems like this become much simpler if you can find a pattern!

share|cite|improve this answer

answered Aug 3 at 20:38

Robert Howard

1,241620

share|cite|improve this answer

share|cite|improve this answer

answered Aug 3 at 20:38

Robert Howard

1,241620

answered Aug 3 at 20:38

Robert Howard

1,241620

answered Aug 3 at 20:38

Robert Howard

1,241620

1,241620

add a comment | 

add a comment |