Find the indicated term of the geometric sequence algebraically. [on hold]

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a1=18, r=4/3, 8th term



1.Find the indicated term of the geometric sequence algebraically.




geometric-series




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put on hold as off-topic by amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson Aug 3 at 22:22


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    Welcome to MSE! What do you know about geometric series that might be useful in solving this problem?
    – Robert Howard
    Aug 3 at 20:08










  • I know first term is 18, and difference is 4/3. We need to find 8th term so we?
    – Lala
    Aug 3 at 20:16






  • 1




    Let's start with something a little simpler. How would you find the second term?
    – Robert Howard
    Aug 3 at 20:17










  • multiple 18 with 4/3
    – Lala
    Aug 3 at 20:19










  • second term is 24
    – Lala
    Aug 3 at 20:20














up vote
0
down vote

favorite












a1=18, r=4/3, 8th term



1.Find the indicated term of the geometric sequence algebraically.




geometric-series




share|cite|improve this question











put on hold as off-topic by amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson Aug 3 at 22:22


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    Welcome to MSE! What do you know about geometric series that might be useful in solving this problem?
    – Robert Howard
    Aug 3 at 20:08










  • I know first term is 18, and difference is 4/3. We need to find 8th term so we?
    – Lala
    Aug 3 at 20:16






  • 1




    Let's start with something a little simpler. How would you find the second term?
    – Robert Howard
    Aug 3 at 20:17










  • multiple 18 with 4/3
    – Lala
    Aug 3 at 20:19










  • second term is 24
    – Lala
    Aug 3 at 20:20












up vote
0
down vote

favorite









up vote
0
down vote

favorite











a1=18, r=4/3, 8th term



1.Find the indicated term of the geometric sequence algebraically.




geometric-series




share|cite|improve this question











a1=18, r=4/3, 8th term



1.Find the indicated term of the geometric sequence algebraically.





geometric-series





share|cite|improve this question










share|cite|improve this question




share|cite|improve this question









asked Aug 3 at 20:07









Lala

11




11




put on hold as off-topic by amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson Aug 3 at 22:22


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson
If this question can be reworded to fit the rules in the help center, please edit the question.




put on hold as off-topic by amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson Aug 3 at 22:22


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Leucippus, Henrik, Isaac Browne, Xander Henderson
If this question can be reworded to fit the rules in the help center, please edit the question.







  • 1




    Welcome to MSE! What do you know about geometric series that might be useful in solving this problem?
    – Robert Howard
    Aug 3 at 20:08










  • I know first term is 18, and difference is 4/3. We need to find 8th term so we?
    – Lala
    Aug 3 at 20:16






  • 1




    Let's start with something a little simpler. How would you find the second term?
    – Robert Howard
    Aug 3 at 20:17










  • multiple 18 with 4/3
    – Lala
    Aug 3 at 20:19










  • second term is 24
    – Lala
    Aug 3 at 20:20












  • 1




    Welcome to MSE! What do you know about geometric series that might be useful in solving this problem?
    – Robert Howard
    Aug 3 at 20:08










  • I know first term is 18, and difference is 4/3. We need to find 8th term so we?
    – Lala
    Aug 3 at 20:16






  • 1




    Let's start with something a little simpler. How would you find the second term?
    – Robert Howard
    Aug 3 at 20:17










  • multiple 18 with 4/3
    – Lala
    Aug 3 at 20:19










  • second term is 24
    – Lala
    Aug 3 at 20:20







1




1




Welcome to MSE! What do you know about geometric series that might be useful in solving this problem?
– Robert Howard
Aug 3 at 20:08




Welcome to MSE! What do you know about geometric series that might be useful in solving this problem?
– Robert Howard
Aug 3 at 20:08












I know first term is 18, and difference is 4/3. We need to find 8th term so we?
– Lala
Aug 3 at 20:16




I know first term is 18, and difference is 4/3. We need to find 8th term so we?
– Lala
Aug 3 at 20:16




1




1




Let's start with something a little simpler. How would you find the second term?
– Robert Howard
Aug 3 at 20:17




Let's start with something a little simpler. How would you find the second term?
– Robert Howard
Aug 3 at 20:17












multiple 18 with 4/3
– Lala
Aug 3 at 20:19




multiple 18 with 4/3
– Lala
Aug 3 at 20:19












second term is 24
– Lala
Aug 3 at 20:20




second term is 24
– Lala
Aug 3 at 20:20










1 Answer
1






active

oldest

votes

















up vote
1
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Just to summarize what transpired in the comments:



Notice that
$$a_colorred1=18timesleft(frac43right)^colorred0=18times1=18$$
$$a_colorred2=18timesleft(frac43right)^colorred1=18timesfrac43=24$$
$$a_colorred3=18timesleft(frac43right)^colorred2=18timesfrac169=32$$
$$dots$$
Continuing the pattern a few more times, you'll find that
$$a_colorred8=18timesleft(frac43right)^colorred7=18timesfrac163842187approx134.85$$
Problems like this become much simpler if you can find a pattern!






share|cite|improve this answer




























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    1
    down vote













    Just to summarize what transpired in the comments:



    Notice that
    $$a_colorred1=18timesleft(frac43right)^colorred0=18times1=18$$
    $$a_colorred2=18timesleft(frac43right)^colorred1=18timesfrac43=24$$
    $$a_colorred3=18timesleft(frac43right)^colorred2=18timesfrac169=32$$
    $$dots$$
    Continuing the pattern a few more times, you'll find that
    $$a_colorred8=18timesleft(frac43right)^colorred7=18timesfrac163842187approx134.85$$
    Problems like this become much simpler if you can find a pattern!






    share|cite|improve this answer

























      up vote
      1
      down vote













      Just to summarize what transpired in the comments:



      Notice that
      $$a_colorred1=18timesleft(frac43right)^colorred0=18times1=18$$
      $$a_colorred2=18timesleft(frac43right)^colorred1=18timesfrac43=24$$
      $$a_colorred3=18timesleft(frac43right)^colorred2=18timesfrac169=32$$
      $$dots$$
      Continuing the pattern a few more times, you'll find that
      $$a_colorred8=18timesleft(frac43right)^colorred7=18timesfrac163842187approx134.85$$
      Problems like this become much simpler if you can find a pattern!






      share|cite|improve this answer























        up vote
        1
        down vote










        up vote
        1
        down vote









        Just to summarize what transpired in the comments:



        Notice that
        $$a_colorred1=18timesleft(frac43right)^colorred0=18times1=18$$
        $$a_colorred2=18timesleft(frac43right)^colorred1=18timesfrac43=24$$
        $$a_colorred3=18timesleft(frac43right)^colorred2=18timesfrac169=32$$
        $$dots$$
        Continuing the pattern a few more times, you'll find that
        $$a_colorred8=18timesleft(frac43right)^colorred7=18timesfrac163842187approx134.85$$
        Problems like this become much simpler if you can find a pattern!






        share|cite|improve this answer













        Just to summarize what transpired in the comments:



        Notice that
        $$a_colorred1=18timesleft(frac43right)^colorred0=18times1=18$$
        $$a_colorred2=18timesleft(frac43right)^colorred1=18timesfrac43=24$$
        $$a_colorred3=18timesleft(frac43right)^colorred2=18timesfrac169=32$$
        $$dots$$
        Continuing the pattern a few more times, you'll find that
        $$a_colorred8=18timesleft(frac43right)^colorred7=18timesfrac163842187approx134.85$$
        Problems like this become much simpler if you can find a pattern!







        share|cite|improve this answer













        share|cite|improve this answer



        share|cite|improve this answer











        answered Aug 3 at 20:38









        Robert Howard

        1,241620




        1,241620












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