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Find all roots for the equation [duplicate]
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Solve for $x$: $2^x=4x$
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I am trying to solve $2^x = 4x$. Have taken logs on both sides, represented as an exponent and haven't got it close to the form from which I could find a solution.
algebra-precalculus
asked Aug 3 at 20:13
Alexander
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marked as duplicate by Dietrich Burde, amWhy algebra-precalculus
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Aug 3 at 20:17
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This question already has an answer here:
Solve for $x$: $2^x=4x$
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I am trying to solve $2^x = 4x$. Have taken logs on both sides, represented as an exponent and haven't got it close to the form from which I could find a solution.
algebra-precalculus
asked Aug 3 at 20:13
Alexander
1
marked as duplicate by Dietrich Burde, amWhy algebra-precalculus
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Aug 3 at 20:17
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
See here, and this question.
– Dietrich Burde
Aug 3 at 20:15
The difference function $xto 2^x-4x$ is convex, there are two solutions, the one is $4$, the other one is numerically $0.30990693238069053545461578388772986095dots$ (as delivered by pari/gp via the commandsolve( x=0, 3.5, 2^x-4*x )).
– dan_fulea
Aug 3 at 20:19
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This question already has an answer here:
Solve for $x$: $2^x=4x$
2 answers
I am trying to solve $2^x = 4x$. Have taken logs on both sides, represented as an exponent and haven't got it close to the form from which I could find a solution.
algebra-precalculus
asked Aug 3 at 20:13
Alexander
1
This question already has an answer here:
Solve for $x$: $2^x=4x$
2 answers
I am trying to solve $2^x = 4x$. Have taken logs on both sides, represented as an exponent and haven't got it close to the form from which I could find a solution.
This question already has an answer here:
Solve for $x$: $2^x=4x$
2 answers
algebra-precalculus
asked Aug 3 at 20:13
Alexander
1
asked Aug 3 at 20:13
Alexander
1
asked Aug 3 at 20:13
Alexander
1
asked Aug 3 at 20:13
Alexander
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1
marked as duplicate by Dietrich Burde, amWhy algebra-precalculus
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marked as duplicate by Dietrich Burde, amWhy algebra-precalculus
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Aug 3 at 20:17
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
See here, and this question.
– Dietrich Burde
Aug 3 at 20:15
The difference function $xto 2^x-4x$ is convex, there are two solutions, the one is $4$, the other one is numerically $0.30990693238069053545461578388772986095dots$ (as delivered by pari/gp via the commandsolve( x=0, 3.5, 2^x-4*x )).
– dan_fulea
Aug 3 at 20:19
add a comment |Â
See here, and this question.
– Dietrich Burde
Aug 3 at 20:15
The difference function $xto 2^x-4x$ is convex, there are two solutions, the one is $4$, the other one is numerically $0.30990693238069053545461578388772986095dots$ (as delivered by pari/gp via the commandsolve( x=0, 3.5, 2^x-4*x )).
– dan_fulea
Aug 3 at 20:19
See here, and this question.
– Dietrich Burde
Aug 3 at 20:15
See here, and this question.
– Dietrich Burde
Aug 3 at 20:15
The difference function $xto 2^x-4x$ is convex, there are two solutions, the one is $4$, the other one is numerically $0.30990693238069053545461578388772986095dots$ (as delivered by pari/gp via the command
solve( x=0, 3.5, 2^x-4*x )).– dan_fulea
Aug 3 at 20:19
The difference function $xto 2^x-4x$ is convex, there are two solutions, the one is $4$, the other one is numerically $0.30990693238069053545461578388772986095dots$ (as delivered by pari/gp via the command
solve( x=0, 3.5, 2^x-4*x )).– dan_fulea
Aug 3 at 20:19
add a comment |Â
1 Answer
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Note you can write $4=2^2$ so that you have $2^x=2^2x$, dividing by $2^2$ you have $2^x-2=x$. But this is really as far as this goes since these type of equations require special functions to solve. WolframAlpha gives
$$
x= - dfracW_nleft(-dfraclog 24right)log 2
$$
Note that you can try a few 'nice' solutions and see that $x=4$ works.
answered Aug 3 at 20:17
mathematics2x2life
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1 Answer
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1 Answer
1
active
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active
oldest
votes
active
oldest
votes
up vote
0
down vote
Note you can write $4=2^2$ so that you have $2^x=2^2x$, dividing by $2^2$ you have $2^x-2=x$. But this is really as far as this goes since these type of equations require special functions to solve. WolframAlpha gives
$$
x= - dfracW_nleft(-dfraclog 24right)log 2
$$
Note that you can try a few 'nice' solutions and see that $x=4$ works.
answered Aug 3 at 20:17
mathematics2x2life
7,58121636
add a comment |Â
up vote
0
down vote
Note you can write $4=2^2$ so that you have $2^x=2^2x$, dividing by $2^2$ you have $2^x-2=x$. But this is really as far as this goes since these type of equations require special functions to solve. WolframAlpha gives
$$
x= - dfracW_nleft(-dfraclog 24right)log 2
$$
Note that you can try a few 'nice' solutions and see that $x=4$ works.
answered Aug 3 at 20:17
mathematics2x2life
7,58121636
add a comment |Â
up vote
0
down vote
up vote
0
down vote
Note you can write $4=2^2$ so that you have $2^x=2^2x$, dividing by $2^2$ you have $2^x-2=x$. But this is really as far as this goes since these type of equations require special functions to solve. WolframAlpha gives
$$
x= - dfracW_nleft(-dfraclog 24right)log 2
$$
Note that you can try a few 'nice' solutions and see that $x=4$ works.
answered Aug 3 at 20:17
mathematics2x2life
7,58121636
Note you can write $4=2^2$ so that you have $2^x=2^2x$, dividing by $2^2$ you have $2^x-2=x$. But this is really as far as this goes since these type of equations require special functions to solve. WolframAlpha gives
$$
x= - dfracW_nleft(-dfraclog 24right)log 2
$$
Note that you can try a few 'nice' solutions and see that $x=4$ works.
answered Aug 3 at 20:17
mathematics2x2life
7,58121636
answered Aug 3 at 20:17
mathematics2x2life
7,58121636
answered Aug 3 at 20:17
mathematics2x2life
7,58121636
answered Aug 3 at 20:17
mathematics2x2life
7,58121636
7,58121636
add a comment |Â
add a comment |Â
See here, and this question.
– Dietrich Burde
Aug 3 at 20:15
The difference function $xto 2^x-4x$ is convex, there are two solutions, the one is $4$, the other one is numerically $0.30990693238069053545461578388772986095dots$ (as delivered by pari/gp via the command
solve( x=0, 3.5, 2^x-4*x )).– dan_fulea
Aug 3 at 20:19