Find all roots for the equation [duplicate]

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
0
down vote

favorite













This question already has an answer here:



  • Solve for $x$: $2^x=4x$

    2 answers



I am trying to solve $2^x = 4x$. Have taken logs on both sides, represented as an exponent and haven't got it close to the form from which I could find a solution.




algebra-precalculus




share|cite|improve this question











marked as duplicate by Dietrich Burde, amWhy algebra-precalculus
Users with the  algebra-precalculus badge can single-handedly close algebra-precalculus questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();

);
);
);
 Aug 3 at 20:17


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • See here, and this question.
    – Dietrich Burde
    Aug 3 at 20:15











  • The difference function $xto 2^x-4x$ is convex, there are two solutions, the one is $4$, the other one is numerically $0.30990693238069053545461578388772986095dots$ (as delivered by pari/gp via the command solve( x=0, 3.5, 2^x-4*x )).
    – dan_fulea
    Aug 3 at 20:19














up vote
0
down vote

favorite













This question already has an answer here:



  • Solve for $x$: $2^x=4x$

    2 answers



I am trying to solve $2^x = 4x$. Have taken logs on both sides, represented as an exponent and haven't got it close to the form from which I could find a solution.




algebra-precalculus




share|cite|improve this question











marked as duplicate by Dietrich Burde, amWhy algebra-precalculus
Users with the  algebra-precalculus badge can single-handedly close algebra-precalculus questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();

);
);
);
 Aug 3 at 20:17


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • See here, and this question.
    – Dietrich Burde
    Aug 3 at 20:15











  • The difference function $xto 2^x-4x$ is convex, there are two solutions, the one is $4$, the other one is numerically $0.30990693238069053545461578388772986095dots$ (as delivered by pari/gp via the command solve( x=0, 3.5, 2^x-4*x )).
    – dan_fulea
    Aug 3 at 20:19












up vote
0
down vote

favorite









up vote
0
down vote

favorite












This question already has an answer here:



  • Solve for $x$: $2^x=4x$

    2 answers



I am trying to solve $2^x = 4x$. Have taken logs on both sides, represented as an exponent and haven't got it close to the form from which I could find a solution.




algebra-precalculus




share|cite|improve this question












This question already has an answer here:



  • Solve for $x$: $2^x=4x$

    2 answers



I am trying to solve $2^x = 4x$. Have taken logs on both sides, represented as an exponent and haven't got it close to the form from which I could find a solution.





This question already has an answer here:



  • Solve for $x$: $2^x=4x$

    2 answers





algebra-precalculus





share|cite|improve this question










share|cite|improve this question




share|cite|improve this question









asked Aug 3 at 20:13









Alexander

1




1




marked as duplicate by Dietrich Burde, amWhy algebra-precalculus
Users with the  algebra-precalculus badge can single-handedly close algebra-precalculus questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();

);
);
);
 Aug 3 at 20:17


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






marked as duplicate by Dietrich Burde, amWhy algebra-precalculus
Users with the  algebra-precalculus badge can single-handedly close algebra-precalculus questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();

);
);
);
 Aug 3 at 20:17


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.













  • See here, and this question.
    – Dietrich Burde
    Aug 3 at 20:15











  • The difference function $xto 2^x-4x$ is convex, there are two solutions, the one is $4$, the other one is numerically $0.30990693238069053545461578388772986095dots$ (as delivered by pari/gp via the command solve( x=0, 3.5, 2^x-4*x )).
    – dan_fulea
    Aug 3 at 20:19
















  • See here, and this question.
    – Dietrich Burde
    Aug 3 at 20:15











  • The difference function $xto 2^x-4x$ is convex, there are two solutions, the one is $4$, the other one is numerically $0.30990693238069053545461578388772986095dots$ (as delivered by pari/gp via the command solve( x=0, 3.5, 2^x-4*x )).
    – dan_fulea
    Aug 3 at 20:19















See here, and this question.
– Dietrich Burde
Aug 3 at 20:15





See here, and this question.
– Dietrich Burde
Aug 3 at 20:15













The difference function $xto 2^x-4x$ is convex, there are two solutions, the one is $4$, the other one is numerically $0.30990693238069053545461578388772986095dots$ (as delivered by pari/gp via the command solve( x=0, 3.5, 2^x-4*x )).
– dan_fulea
Aug 3 at 20:19




The difference function $xto 2^x-4x$ is convex, there are two solutions, the one is $4$, the other one is numerically $0.30990693238069053545461578388772986095dots$ (as delivered by pari/gp via the command solve( x=0, 3.5, 2^x-4*x )).
– dan_fulea
Aug 3 at 20:19










1 Answer
1






active

oldest

votes

















up vote
0
down vote













Note you can write $4=2^2$ so that you have $2^x=2^2x$, dividing by $2^2$ you have $2^x-2=x$. But this is really as far as this goes since these type of equations require special functions to solve. WolframAlpha gives
$$
x= - dfracW_nleft(-dfraclog 24right)log 2
$$
Note that you can try a few 'nice' solutions and see that $x=4$ works.






share|cite|improve this answer




























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote













    Note you can write $4=2^2$ so that you have $2^x=2^2x$, dividing by $2^2$ you have $2^x-2=x$. But this is really as far as this goes since these type of equations require special functions to solve. WolframAlpha gives
    $$
    x= - dfracW_nleft(-dfraclog 24right)log 2
    $$
    Note that you can try a few 'nice' solutions and see that $x=4$ works.






    share|cite|improve this answer

























      up vote
      0
      down vote













      Note you can write $4=2^2$ so that you have $2^x=2^2x$, dividing by $2^2$ you have $2^x-2=x$. But this is really as far as this goes since these type of equations require special functions to solve. WolframAlpha gives
      $$
      x= - dfracW_nleft(-dfraclog 24right)log 2
      $$
      Note that you can try a few 'nice' solutions and see that $x=4$ works.






      share|cite|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        Note you can write $4=2^2$ so that you have $2^x=2^2x$, dividing by $2^2$ you have $2^x-2=x$. But this is really as far as this goes since these type of equations require special functions to solve. WolframAlpha gives
        $$
        x= - dfracW_nleft(-dfraclog 24right)log 2
        $$
        Note that you can try a few 'nice' solutions and see that $x=4$ works.






        share|cite|improve this answer













        Note you can write $4=2^2$ so that you have $2^x=2^2x$, dividing by $2^2$ you have $2^x-2=x$. But this is really as far as this goes since these type of equations require special functions to solve. WolframAlpha gives
        $$
        x= - dfracW_nleft(-dfraclog 24right)log 2
        $$
        Note that you can try a few 'nice' solutions and see that $x=4$ works.







        share|cite|improve this answer













        share|cite|improve this answer



        share|cite|improve this answer











        answered Aug 3 at 20:17









        mathematics2x2life

        7,58121636




        7,58121636












            Comments

            Post a Comment

            Popular posts from this blog

            What is the equation of a 3D cone with generalised tilt?

            Image
            Clash Royale CLAN TAG #URR8PPP up vote 2 down vote favorite What is the equation of a 3D cone with generalized tilt? I've noticed that in most equations given to represent a cone, there is no parameter which defines the tilt of the cone in 3D space and that most of them have their point at the origin $(0,0,0)$ - I was wondering if anyone could give me a more generalized cone equation for a cone in any position in 3D space 3d share | cite | improve this question edited Jul 25 '16 at 0:05 ervx 9,425 3 13 36 asked Jul 24 '16 at 15:38 Charlene 11 2 2 Welcome to Math.SE! Could you please explain a few things to help people give an answer useful to you: 1. What do you mean by "generalized tilt"? 2. Are you asking about a right circular cone? Does the angle at the vertex matter? 3. What form of answer (implicit, parametric...?) are you looking for? 4. If this is homework, what tools do you have available, an...
            Read more

            Relationship between determinant of matrix and determinant of adjoint?

            Image
            Clash Royale CLAN TAG #URR8PPP up vote 2 down vote favorite We are studying adjoints in class, and I was curious if there is a relationship between the determinant of matrix A, and the determinant of the adjoint of matrix A? I assume there would be a relationship because finding the adjoint requires creating a cofactor matrix and then transposing it. linear-algebra determinant adjoint-operators share | cite | improve this question asked Nov 17 '17 at 17:32 CluelessCoder 32 5 For a square matrix $A$ of order $n$, we have $A(operatornameadj A)=(operatornameadj A)A=|A|I_n$ where $I_n$ is the identity matrix of order $n$. This should tell you about the determinant of the adjoint in terms of that of $A$ (use multiplicative property and other elementary properties of determinants). – Prasun Biswas Nov 17 '17 at 17:35 1 @CluelessCoder: see here: math.stackexchange.com/questions/516127/…...
            Read more

            Color the edges and diagonals of a regular polygon

            Image
            Clash Royale CLAN TAG #URR8PPP up vote 5 down vote favorite 1 Here is the problem: For what $n$ is it possible to color the edges and diagonals of an $n$-side regular polygon with $dfracbinomn23$ colors, such that you use every color exactly three times and for every color the three segments (edges or diagonals) with that color form a triangle? Trivially $nequiv 0 text or 1 pmod3$. I can also prove that if the statement is true for $k$ than it is true for $3k$ as well. How to finish? Please help! Thanks combinatorial-geometry share | cite | improve this question edited Aug 6 at 21:57 alcana 118 4 asked Aug 6 at 21:15 Leo Gardner 356 11 Even assuming "polyhpn" in the title is a typo for polygon , it is unclear what you mean by "the edges and sides". Aren't the side of a regular polygon the same as the edges? A regular $n$-sided polygon has $n$ edges. – hardmath Aug 6 at 21:20 3 $n$ ne...
            Read more