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Algebra Solution to Question
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At the start of lunch Jimmy and Jake each brought out a new bag of $x$ marbles to play with their friends. By the end of lunch they were surprised to see they still had the same number as each other even though overall Jimmy had gained $5$ marbles and Jake had ended up with the double of $3$ less than his original amount. How many marbles were originally in the bags?
My attempt
$2x=(x+5)+2(x-3)$
$x=1$
The correct solution is $11$ marbles
algebra-precalculus word-problem
edited 2 days ago
Mike Pierce
10.9k93573
asked Aug 4 at 3:41
Nicolas
354
add a comment |Â
up vote
1
down vote
favorite
At the start of lunch Jimmy and Jake each brought out a new bag of $x$ marbles to play with their friends. By the end of lunch they were surprised to see they still had the same number as each other even though overall Jimmy had gained $5$ marbles and Jake had ended up with the double of $3$ less than his original amount. How many marbles were originally in the bags?
My attempt
$2x=(x+5)+2(x-3)$
$x=1$
The correct solution is $11$ marbles
algebra-precalculus word-problem
edited 2 days ago
Mike Pierce
10.9k93573
asked Aug 4 at 3:41
Nicolas
354
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
At the start of lunch Jimmy and Jake each brought out a new bag of $x$ marbles to play with their friends. By the end of lunch they were surprised to see they still had the same number as each other even though overall Jimmy had gained $5$ marbles and Jake had ended up with the double of $3$ less than his original amount. How many marbles were originally in the bags?
My attempt
$2x=(x+5)+2(x-3)$
$x=1$
The correct solution is $11$ marbles
algebra-precalculus word-problem
edited 2 days ago
Mike Pierce
10.9k93573
asked Aug 4 at 3:41
Nicolas
354
At the start of lunch Jimmy and Jake each brought out a new bag of $x$ marbles to play with their friends. By the end of lunch they were surprised to see they still had the same number as each other even though overall Jimmy had gained $5$ marbles and Jake had ended up with the double of $3$ less than his original amount. How many marbles were originally in the bags?
My attempt
$2x=(x+5)+2(x-3)$
$x=1$
The correct solution is $11$ marbles
algebra-precalculus word-problem
edited 2 days ago
Mike Pierce
10.9k93573
asked Aug 4 at 3:41
Nicolas
354
edited 2 days ago
Mike Pierce
10.9k93573
edited 2 days ago
Mike Pierce
10.9k93573
edited 2 days ago
Mike Pierce
10.9k93573
10.9k93573
asked Aug 4 at 3:41
Nicolas
354
asked Aug 4 at 3:41
Nicolas
354
asked Aug 4 at 3:41
Nicolas
354
354
add a comment |Â
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
Jimmy end up gaining $5$: $x+5$
Jack end up with double of $3$ less than original amount. $2(x-3)$
$$x+5=2(x-3)$$
Note that they have other friends to gain or lose from, hence both of them gain additional marbles. The question doesn't mean their sum stays the same.
answered Aug 4 at 3:47
Siong Thye Goh
76.5k134794
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Jimmy end up gaining $5$: $x+5$
Jack end up with double of $3$ less than original amount. $2(x-3)$
$$x+5=2(x-3)$$
Note that they have other friends to gain or lose from, hence both of them gain additional marbles. The question doesn't mean their sum stays the same.
answered Aug 4 at 3:47
Siong Thye Goh
76.5k134794
add a comment |Â
up vote
1
down vote
accepted
Jimmy end up gaining $5$: $x+5$
Jack end up with double of $3$ less than original amount. $2(x-3)$
$$x+5=2(x-3)$$
Note that they have other friends to gain or lose from, hence both of them gain additional marbles. The question doesn't mean their sum stays the same.
answered Aug 4 at 3:47
Siong Thye Goh
76.5k134794
add a comment |Â
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Jimmy end up gaining $5$: $x+5$
Jack end up with double of $3$ less than original amount. $2(x-3)$
$$x+5=2(x-3)$$
Note that they have other friends to gain or lose from, hence both of them gain additional marbles. The question doesn't mean their sum stays the same.
answered Aug 4 at 3:47
Siong Thye Goh
76.5k134794
Jimmy end up gaining $5$: $x+5$
Jack end up with double of $3$ less than original amount. $2(x-3)$
$$x+5=2(x-3)$$
Note that they have other friends to gain or lose from, hence both of them gain additional marbles. The question doesn't mean their sum stays the same.
answered Aug 4 at 3:47
Siong Thye Goh
76.5k134794
edited Aug 4 at 3:54
answered Aug 4 at 3:47
Siong Thye Goh
76.5k134794
answered Aug 4 at 3:47
Siong Thye Goh
76.5k134794
answered Aug 4 at 3:47
Siong Thye Goh
76.5k134794
76.5k134794
add a comment |Â
add a comment |Â
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