Simultaneous asymptotic expansion in multiple points

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Let $Omegasubsetmathbb R$ be open and connected. Assume I have some non-linear, smooth function $g:Omega tomathbb R$.



Given disjoint base points $a_1,ldots,a_nin Omega$ (and possible $pminfty)$, I want to find an asymptotic expansion $hat g $ of $g$ such that at each base point $a_k$, $hat g$ is an asymptotic expansion of $g$ up to order $c_k$.



For example if $g(x) = sqrt1+frac1x^2$, then $hat g = 1+frac 1x$ is asymptotic to $g$ both at $0$ and $infty$ up to first order.



(at $0$, $g(x)approx frac 1x + frac 12 x - frac 18 x^3 pmldots$ and at $infty$, $g(x)approx 1+frac12x^2- frac18x^4pmldots$)



One naive way to do it would be to take an appropriate bump function $phi$ and do $hat g = sum phi(x-a_k)cdot hat g_k(x)$ where $hat g_k$ is the local asymptotic expansion at $a_k$. However this is a bad way to do it since we would like to have that, for "nice" functions $g$, the expansion converges globally against the target function when we increase the orders.



Are there any common techniques to tackle these kinds of problems?







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  • Perhaps matched asymptotic expansions might be something similar to what you want?
    – Antonio Vargas
    Aug 1 at 23:50














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Let $Omegasubsetmathbb R$ be open and connected. Assume I have some non-linear, smooth function $g:Omega tomathbb R$.



Given disjoint base points $a_1,ldots,a_nin Omega$ (and possible $pminfty)$, I want to find an asymptotic expansion $hat g $ of $g$ such that at each base point $a_k$, $hat g$ is an asymptotic expansion of $g$ up to order $c_k$.



For example if $g(x) = sqrt1+frac1x^2$, then $hat g = 1+frac 1x$ is asymptotic to $g$ both at $0$ and $infty$ up to first order.



(at $0$, $g(x)approx frac 1x + frac 12 x - frac 18 x^3 pmldots$ and at $infty$, $g(x)approx 1+frac12x^2- frac18x^4pmldots$)



One naive way to do it would be to take an appropriate bump function $phi$ and do $hat g = sum phi(x-a_k)cdot hat g_k(x)$ where $hat g_k$ is the local asymptotic expansion at $a_k$. However this is a bad way to do it since we would like to have that, for "nice" functions $g$, the expansion converges globally against the target function when we increase the orders.



Are there any common techniques to tackle these kinds of problems?







share|cite|improve this question



















  • Perhaps matched asymptotic expansions might be something similar to what you want?
    – Antonio Vargas
    Aug 1 at 23:50












up vote
0
down vote

favorite









up vote
0
down vote

favorite











Let $Omegasubsetmathbb R$ be open and connected. Assume I have some non-linear, smooth function $g:Omega tomathbb R$.



Given disjoint base points $a_1,ldots,a_nin Omega$ (and possible $pminfty)$, I want to find an asymptotic expansion $hat g $ of $g$ such that at each base point $a_k$, $hat g$ is an asymptotic expansion of $g$ up to order $c_k$.



For example if $g(x) = sqrt1+frac1x^2$, then $hat g = 1+frac 1x$ is asymptotic to $g$ both at $0$ and $infty$ up to first order.



(at $0$, $g(x)approx frac 1x + frac 12 x - frac 18 x^3 pmldots$ and at $infty$, $g(x)approx 1+frac12x^2- frac18x^4pmldots$)



One naive way to do it would be to take an appropriate bump function $phi$ and do $hat g = sum phi(x-a_k)cdot hat g_k(x)$ where $hat g_k$ is the local asymptotic expansion at $a_k$. However this is a bad way to do it since we would like to have that, for "nice" functions $g$, the expansion converges globally against the target function when we increase the orders.



Are there any common techniques to tackle these kinds of problems?







share|cite|improve this question











Let $Omegasubsetmathbb R$ be open and connected. Assume I have some non-linear, smooth function $g:Omega tomathbb R$.



Given disjoint base points $a_1,ldots,a_nin Omega$ (and possible $pminfty)$, I want to find an asymptotic expansion $hat g $ of $g$ such that at each base point $a_k$, $hat g$ is an asymptotic expansion of $g$ up to order $c_k$.



For example if $g(x) = sqrt1+frac1x^2$, then $hat g = 1+frac 1x$ is asymptotic to $g$ both at $0$ and $infty$ up to first order.



(at $0$, $g(x)approx frac 1x + frac 12 x - frac 18 x^3 pmldots$ and at $infty$, $g(x)approx 1+frac12x^2- frac18x^4pmldots$)



One naive way to do it would be to take an appropriate bump function $phi$ and do $hat g = sum phi(x-a_k)cdot hat g_k(x)$ where $hat g_k$ is the local asymptotic expansion at $a_k$. However this is a bad way to do it since we would like to have that, for "nice" functions $g$, the expansion converges globally against the target function when we increase the orders.



Are there any common techniques to tackle these kinds of problems?









share|cite|improve this question










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asked Aug 1 at 16:52









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  • Perhaps matched asymptotic expansions might be something similar to what you want?
    – Antonio Vargas
    Aug 1 at 23:50
















  • Perhaps matched asymptotic expansions might be something similar to what you want?
    – Antonio Vargas
    Aug 1 at 23:50















Perhaps matched asymptotic expansions might be something similar to what you want?
– Antonio Vargas
Aug 1 at 23:50




Perhaps matched asymptotic expansions might be something similar to what you want?
– Antonio Vargas
Aug 1 at 23:50















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