A question about Narasimhan-Seshadri Donaldson theorem.

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
2
down vote

favorite
1












I see a statement of the theorem in Jonathan Evans' lecture note 13




An indecomposable Hermitian holomorphic vector bundle $mathcal E$ on
a Riemann surface $M$ is stable if and only if there is a compatible
unitary connection on $mathcal E$ with constant central cervature
$$star F_nabla=-2pi imu(mathcal E)$$




Some notations: $F_nabla$ is the curvature of the connection $nabla$, $mu(mathcal E)=fracc_1(mathcal E)textrank(mathcal E)$ is the slope of $mathcal E$.



Now I do not understand the statement, because from Atiyah & Bott's paper, The Yang-Mills Equations over Riemann Surfaces sec 5, we can identify the space of all unitary connection on $E$ and that of all holomorphic structures over $E$, where $E$ is the underlying complex vector bundle of $mathcal E$. So now we are given a holomorphic structure $mathcal E$, I think the unitary connection is uniquely determined. So is this theorem telling us that this unique-determined connection has this property?







share|cite|improve this question























    up vote
    2
    down vote

    favorite
    1












    I see a statement of the theorem in Jonathan Evans' lecture note 13




    An indecomposable Hermitian holomorphic vector bundle $mathcal E$ on
    a Riemann surface $M$ is stable if and only if there is a compatible
    unitary connection on $mathcal E$ with constant central cervature
    $$star F_nabla=-2pi imu(mathcal E)$$




    Some notations: $F_nabla$ is the curvature of the connection $nabla$, $mu(mathcal E)=fracc_1(mathcal E)textrank(mathcal E)$ is the slope of $mathcal E$.



    Now I do not understand the statement, because from Atiyah & Bott's paper, The Yang-Mills Equations over Riemann Surfaces sec 5, we can identify the space of all unitary connection on $E$ and that of all holomorphic structures over $E$, where $E$ is the underlying complex vector bundle of $mathcal E$. So now we are given a holomorphic structure $mathcal E$, I think the unitary connection is uniquely determined. So is this theorem telling us that this unique-determined connection has this property?







    share|cite|improve this question





















      up vote
      2
      down vote

      favorite
      1









      up vote
      2
      down vote

      favorite
      1






      1





      I see a statement of the theorem in Jonathan Evans' lecture note 13




      An indecomposable Hermitian holomorphic vector bundle $mathcal E$ on
      a Riemann surface $M$ is stable if and only if there is a compatible
      unitary connection on $mathcal E$ with constant central cervature
      $$star F_nabla=-2pi imu(mathcal E)$$




      Some notations: $F_nabla$ is the curvature of the connection $nabla$, $mu(mathcal E)=fracc_1(mathcal E)textrank(mathcal E)$ is the slope of $mathcal E$.



      Now I do not understand the statement, because from Atiyah & Bott's paper, The Yang-Mills Equations over Riemann Surfaces sec 5, we can identify the space of all unitary connection on $E$ and that of all holomorphic structures over $E$, where $E$ is the underlying complex vector bundle of $mathcal E$. So now we are given a holomorphic structure $mathcal E$, I think the unitary connection is uniquely determined. So is this theorem telling us that this unique-determined connection has this property?







      share|cite|improve this question











      I see a statement of the theorem in Jonathan Evans' lecture note 13




      An indecomposable Hermitian holomorphic vector bundle $mathcal E$ on
      a Riemann surface $M$ is stable if and only if there is a compatible
      unitary connection on $mathcal E$ with constant central cervature
      $$star F_nabla=-2pi imu(mathcal E)$$




      Some notations: $F_nabla$ is the curvature of the connection $nabla$, $mu(mathcal E)=fracc_1(mathcal E)textrank(mathcal E)$ is the slope of $mathcal E$.



      Now I do not understand the statement, because from Atiyah & Bott's paper, The Yang-Mills Equations over Riemann Surfaces sec 5, we can identify the space of all unitary connection on $E$ and that of all holomorphic structures over $E$, where $E$ is the underlying complex vector bundle of $mathcal E$. So now we are given a holomorphic structure $mathcal E$, I think the unitary connection is uniquely determined. So is this theorem telling us that this unique-determined connection has this property?









      share|cite|improve this question










      share|cite|improve this question




      share|cite|improve this question









      asked Jul 26 at 17:18









      Display Name

      375212




      375212

























          active

          oldest

          votes











          Your Answer




          StackExchange.ifUsing("editor", function ()
          return StackExchange.using("mathjaxEditing", function ()
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          );
          );
          , "mathjax-editing");

          StackExchange.ready(function()
          var channelOptions =
          tags: "".split(" "),
          id: "69"
          ;
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function()
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled)
          StackExchange.using("snippets", function()
          createEditor();
          );

          else
          createEditor();

          );

          function createEditor()
          StackExchange.prepareEditor(
          heartbeatType: 'answer',
          convertImagesToLinks: true,
          noModals: false,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          );



          );








           

          draft saved


          draft discarded


















          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2863618%2fa-question-about-narasimhan-seshadri-donaldson-theorem%23new-answer', 'question_page');

          );

          Post as a guest



































          active

          oldest

          votes













          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes










           

          draft saved


          draft discarded


























           


          draft saved


          draft discarded














          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2863618%2fa-question-about-narasimhan-seshadri-donaldson-theorem%23new-answer', 'question_page');

          );

          Post as a guest













































































          Comments

          Popular posts from this blog

          Color the edges and diagonals of a regular polygon

          Relationship between determinant of matrix and determinant of adjoint?

          What is the equation of a 3D cone with generalised tilt?