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Coordinate of a Point Inside a Triangle [closed]
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Coordinates to my triangle are $A(-1,10)$, $B(-7,1)$, $C(5,2)$
using trigonometry I can find the distance between $A-B$, $B-C$, and $C-A$.
There is a point inside this triangle which is $7$ units from point $A$, $5.5$ units from $B$ and $9$ units from $C$. How do I find this point?
linear-algebra trigonometry
edited Jul 26 at 17:13
Math Lover
12.3k21232
asked Jul 26 at 17:09
Mankomal Singh
32
closed as off-topic by amWhy, Math Lover, Isaac Browne, Jyrki Lahtonen, José Carlos Santos Jul 27 at 14:30
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." РamWhy, Math Lover, Isaac Browne, Jyrki Lahtonen, Jos̩ Carlos Santos
add a comment |Â
up vote
0
down vote
favorite
Coordinates to my triangle are $A(-1,10)$, $B(-7,1)$, $C(5,2)$
using trigonometry I can find the distance between $A-B$, $B-C$, and $C-A$.
There is a point inside this triangle which is $7$ units from point $A$, $5.5$ units from $B$ and $9$ units from $C$. How do I find this point?
linear-algebra trigonometry
edited Jul 26 at 17:13
Math Lover
12.3k21232
asked Jul 26 at 17:09
Mankomal Singh
32
closed as off-topic by amWhy, Math Lover, Isaac Browne, Jyrki Lahtonen, José Carlos Santos Jul 27 at 14:30
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." РamWhy, Math Lover, Isaac Browne, Jyrki Lahtonen, Jos̩ Carlos Santos
BTW It seems there is no such point. Can you check the numbers?
– mvw
Jul 26 at 17:18
I have plotted a physical graph and there could be a slight variation in decimals, how were you able to tell that there is no such point what methodology you have used ?
– Mankomal Singh
Jul 26 at 17:27
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Coordinates to my triangle are $A(-1,10)$, $B(-7,1)$, $C(5,2)$
using trigonometry I can find the distance between $A-B$, $B-C$, and $C-A$.
There is a point inside this triangle which is $7$ units from point $A$, $5.5$ units from $B$ and $9$ units from $C$. How do I find this point?
linear-algebra trigonometry
edited Jul 26 at 17:13
Math Lover
12.3k21232
asked Jul 26 at 17:09
Mankomal Singh
32
Coordinates to my triangle are $A(-1,10)$, $B(-7,1)$, $C(5,2)$
using trigonometry I can find the distance between $A-B$, $B-C$, and $C-A$.
There is a point inside this triangle which is $7$ units from point $A$, $5.5$ units from $B$ and $9$ units from $C$. How do I find this point?
linear-algebra trigonometry
edited Jul 26 at 17:13
Math Lover
12.3k21232
asked Jul 26 at 17:09
Mankomal Singh
32
edited Jul 26 at 17:13
Math Lover
12.3k21232
edited Jul 26 at 17:13
Math Lover
12.3k21232
edited Jul 26 at 17:13
Math Lover
12.3k21232
12.3k21232
asked Jul 26 at 17:09
Mankomal Singh
32
asked Jul 26 at 17:09
Mankomal Singh
32
asked Jul 26 at 17:09
Mankomal Singh
32
32
closed as off-topic by amWhy, Math Lover, Isaac Browne, Jyrki Lahtonen, José Carlos Santos Jul 27 at 14:30
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." РamWhy, Math Lover, Isaac Browne, Jyrki Lahtonen, Jos̩ Carlos Santos
closed as off-topic by amWhy, Math Lover, Isaac Browne, Jyrki Lahtonen, José Carlos Santos Jul 27 at 14:30
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." РamWhy, Math Lover, Isaac Browne, Jyrki Lahtonen, Jos̩ Carlos Santos
BTW It seems there is no such point. Can you check the numbers?
– mvw
Jul 26 at 17:18
I have plotted a physical graph and there could be a slight variation in decimals, how were you able to tell that there is no such point what methodology you have used ?
– Mankomal Singh
Jul 26 at 17:27
add a comment |Â
BTW It seems there is no such point. Can you check the numbers?
– mvw
Jul 26 at 17:18
I have plotted a physical graph and there could be a slight variation in decimals, how were you able to tell that there is no such point what methodology you have used ?
– Mankomal Singh
Jul 26 at 17:27
BTW It seems there is no such point. Can you check the numbers?
– mvw
Jul 26 at 17:18
BTW It seems there is no such point. Can you check the numbers?
– mvw
Jul 26 at 17:18
I have plotted a physical graph and there could be a slight variation in decimals, how were you able to tell that there is no such point what methodology you have used ?
– Mankomal Singh
Jul 26 at 17:27
I have plotted a physical graph and there could be a slight variation in decimals, how were you able to tell that there is no such point what methodology you have used ?
– Mankomal Singh
Jul 26 at 17:27
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
0
down vote
accepted
Let the point you want to locate be $P(x,y)$, then you have been given the distances $PA, PB$ and $PC$ as $7, 5.5$ and $9$ respectively. So
beginalign*
PA^2&=(x+1)^2+(y-10)^2=7^2\
PB^2&=(x+7)^2+(y-1)^2=(5.5)^2\
PC^2&=(x-5)^2+(y-2)^2=9^2
endalign*
From these equations you can get (by subtraction etc.) two linear equations in $x$ and $y$. If they have a solution, then you get your point $P$, otherwise the point doesn't exist.
answered Jul 26 at 19:03
Anurag A
22.2k12243
add a comment |Â
up vote
0
down vote
There is a point inside this triangle which is $7$ units from point
$A$, $5.5$ units from $B$ and $9$ units from $C$. How do I find this
point?
Hint: All points which are $7$ units away from point $A$ form a $dotsc$ with $dotsc$ $=7$.
answered Jul 26 at 17:12
mvw
30.2k22250
not able to understand "form a .... with ... =7"
– Mankomal Singh
Jul 26 at 17:27
yea thats the problem i am not able to understand how to go about, sorry for being dumb
– Mankomal Singh
Jul 26 at 17:36
can you share your email ID, I can share an online graph with you to explain what I am doing, the issue is I am trying to find a specific point on the graph which will reside inside this triangle
– Mankomal Singh
Jul 26 at 17:38
That i understood that each of these individual distances basically represent a circle/arc of the radius that I had given you, but how willl it help in determining the coordinate of intersection of these circles?
– Mankomal Singh
Jul 26 at 17:43
yes they intersect at 2 points now
– Mankomal Singh
Jul 26 at 17:51
 |Â
show 5 more comments
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Let the point you want to locate be $P(x,y)$, then you have been given the distances $PA, PB$ and $PC$ as $7, 5.5$ and $9$ respectively. So
beginalign*
PA^2&=(x+1)^2+(y-10)^2=7^2\
PB^2&=(x+7)^2+(y-1)^2=(5.5)^2\
PC^2&=(x-5)^2+(y-2)^2=9^2
endalign*
From these equations you can get (by subtraction etc.) two linear equations in $x$ and $y$. If they have a solution, then you get your point $P$, otherwise the point doesn't exist.
answered Jul 26 at 19:03
Anurag A
22.2k12243
add a comment |Â
up vote
0
down vote
accepted
Let the point you want to locate be $P(x,y)$, then you have been given the distances $PA, PB$ and $PC$ as $7, 5.5$ and $9$ respectively. So
beginalign*
PA^2&=(x+1)^2+(y-10)^2=7^2\
PB^2&=(x+7)^2+(y-1)^2=(5.5)^2\
PC^2&=(x-5)^2+(y-2)^2=9^2
endalign*
From these equations you can get (by subtraction etc.) two linear equations in $x$ and $y$. If they have a solution, then you get your point $P$, otherwise the point doesn't exist.
answered Jul 26 at 19:03
Anurag A
22.2k12243
add a comment |Â
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Let the point you want to locate be $P(x,y)$, then you have been given the distances $PA, PB$ and $PC$ as $7, 5.5$ and $9$ respectively. So
beginalign*
PA^2&=(x+1)^2+(y-10)^2=7^2\
PB^2&=(x+7)^2+(y-1)^2=(5.5)^2\
PC^2&=(x-5)^2+(y-2)^2=9^2
endalign*
From these equations you can get (by subtraction etc.) two linear equations in $x$ and $y$. If they have a solution, then you get your point $P$, otherwise the point doesn't exist.
answered Jul 26 at 19:03
Anurag A
22.2k12243
Let the point you want to locate be $P(x,y)$, then you have been given the distances $PA, PB$ and $PC$ as $7, 5.5$ and $9$ respectively. So
beginalign*
PA^2&=(x+1)^2+(y-10)^2=7^2\
PB^2&=(x+7)^2+(y-1)^2=(5.5)^2\
PC^2&=(x-5)^2+(y-2)^2=9^2
endalign*
From these equations you can get (by subtraction etc.) two linear equations in $x$ and $y$. If they have a solution, then you get your point $P$, otherwise the point doesn't exist.
answered Jul 26 at 19:03
Anurag A
22.2k12243
answered Jul 26 at 19:03
Anurag A
22.2k12243
answered Jul 26 at 19:03
Anurag A
22.2k12243
answered Jul 26 at 19:03
Anurag A
22.2k12243
22.2k12243
add a comment |Â
add a comment |Â
up vote
0
down vote
There is a point inside this triangle which is $7$ units from point
$A$, $5.5$ units from $B$ and $9$ units from $C$. How do I find this
point?
Hint: All points which are $7$ units away from point $A$ form a $dotsc$ with $dotsc$ $=7$.
answered Jul 26 at 17:12
mvw
30.2k22250
not able to understand "form a .... with ... =7"
– Mankomal Singh
Jul 26 at 17:27
yea thats the problem i am not able to understand how to go about, sorry for being dumb
– Mankomal Singh
Jul 26 at 17:36
can you share your email ID, I can share an online graph with you to explain what I am doing, the issue is I am trying to find a specific point on the graph which will reside inside this triangle
– Mankomal Singh
Jul 26 at 17:38
That i understood that each of these individual distances basically represent a circle/arc of the radius that I had given you, but how willl it help in determining the coordinate of intersection of these circles?
– Mankomal Singh
Jul 26 at 17:43
yes they intersect at 2 points now
– Mankomal Singh
Jul 26 at 17:51
 |Â
show 5 more comments
up vote
0
down vote
There is a point inside this triangle which is $7$ units from point
$A$, $5.5$ units from $B$ and $9$ units from $C$. How do I find this
point?
Hint: All points which are $7$ units away from point $A$ form a $dotsc$ with $dotsc$ $=7$.
answered Jul 26 at 17:12
mvw
30.2k22250
not able to understand "form a .... with ... =7"
– Mankomal Singh
Jul 26 at 17:27
yea thats the problem i am not able to understand how to go about, sorry for being dumb
– Mankomal Singh
Jul 26 at 17:36
can you share your email ID, I can share an online graph with you to explain what I am doing, the issue is I am trying to find a specific point on the graph which will reside inside this triangle
– Mankomal Singh
Jul 26 at 17:38
That i understood that each of these individual distances basically represent a circle/arc of the radius that I had given you, but how willl it help in determining the coordinate of intersection of these circles?
– Mankomal Singh
Jul 26 at 17:43
yes they intersect at 2 points now
– Mankomal Singh
Jul 26 at 17:51
 |Â
show 5 more comments
up vote
0
down vote
up vote
0
down vote
There is a point inside this triangle which is $7$ units from point
$A$, $5.5$ units from $B$ and $9$ units from $C$. How do I find this
point?
Hint: All points which are $7$ units away from point $A$ form a $dotsc$ with $dotsc$ $=7$.
answered Jul 26 at 17:12
mvw
30.2k22250
There is a point inside this triangle which is $7$ units from point
$A$, $5.5$ units from $B$ and $9$ units from $C$. How do I find this
point?
Hint: All points which are $7$ units away from point $A$ form a $dotsc$ with $dotsc$ $=7$.
answered Jul 26 at 17:12
mvw
30.2k22250
answered Jul 26 at 17:12
mvw
30.2k22250
answered Jul 26 at 17:12
mvw
30.2k22250
answered Jul 26 at 17:12
mvw
30.2k22250
30.2k22250
not able to understand "form a .... with ... =7"
– Mankomal Singh
Jul 26 at 17:27
yea thats the problem i am not able to understand how to go about, sorry for being dumb
– Mankomal Singh
Jul 26 at 17:36
can you share your email ID, I can share an online graph with you to explain what I am doing, the issue is I am trying to find a specific point on the graph which will reside inside this triangle
– Mankomal Singh
Jul 26 at 17:38
That i understood that each of these individual distances basically represent a circle/arc of the radius that I had given you, but how willl it help in determining the coordinate of intersection of these circles?
– Mankomal Singh
Jul 26 at 17:43
yes they intersect at 2 points now
– Mankomal Singh
Jul 26 at 17:51
 |Â
show 5 more comments
not able to understand "form a .... with ... =7"
– Mankomal Singh
Jul 26 at 17:27
yea thats the problem i am not able to understand how to go about, sorry for being dumb
– Mankomal Singh
Jul 26 at 17:36
can you share your email ID, I can share an online graph with you to explain what I am doing, the issue is I am trying to find a specific point on the graph which will reside inside this triangle
– Mankomal Singh
Jul 26 at 17:38
That i understood that each of these individual distances basically represent a circle/arc of the radius that I had given you, but how willl it help in determining the coordinate of intersection of these circles?
– Mankomal Singh
Jul 26 at 17:43
yes they intersect at 2 points now
– Mankomal Singh
Jul 26 at 17:51
not able to understand "form a .... with ... =7"
– Mankomal Singh
Jul 26 at 17:27
not able to understand "form a .... with ... =7"
– Mankomal Singh
Jul 26 at 17:27
yea thats the problem i am not able to understand how to go about, sorry for being dumb
– Mankomal Singh
Jul 26 at 17:36
yea thats the problem i am not able to understand how to go about, sorry for being dumb
– Mankomal Singh
Jul 26 at 17:36
can you share your email ID, I can share an online graph with you to explain what I am doing, the issue is I am trying to find a specific point on the graph which will reside inside this triangle
– Mankomal Singh
Jul 26 at 17:38
can you share your email ID, I can share an online graph with you to explain what I am doing, the issue is I am trying to find a specific point on the graph which will reside inside this triangle
– Mankomal Singh
Jul 26 at 17:38
That i understood that each of these individual distances basically represent a circle/arc of the radius that I had given you, but how willl it help in determining the coordinate of intersection of these circles?
– Mankomal Singh
Jul 26 at 17:43
That i understood that each of these individual distances basically represent a circle/arc of the radius that I had given you, but how willl it help in determining the coordinate of intersection of these circles?
– Mankomal Singh
Jul 26 at 17:43
yes they intersect at 2 points now
– Mankomal Singh
Jul 26 at 17:51
yes they intersect at 2 points now
– Mankomal Singh
Jul 26 at 17:51
 |Â
show 5 more comments
BTW It seems there is no such point. Can you check the numbers?
– mvw
Jul 26 at 17:18
I have plotted a physical graph and there could be a slight variation in decimals, how were you able to tell that there is no such point what methodology you have used ?
– Mankomal Singh
Jul 26 at 17:27