completion and localization
Clash Royale CLAN TAG#URR8PPP
up vote
0
down vote
favorite
Let $S$ be the polynomial ring $k[x_1,..,x_n]$ over a field $k$, $M=langle x_1,...,x_n rangle$, and let $R=S/I$ for some ideal $I$ of $S$. We know that the completion of $S$ with respect to $M$ is the formal power series ring $mathcalS=k[![x_1,...,x_n]!]$ and the completion of $R$ is $mathcalR=mathcalS/ImathcalS$. Now let $a$ be a non zero element of $R$ and $R_a$ be the localization of $R$ with respect to $a$. Is it true that $widehatR_a$ is the lozalization of $mathcalR$ with respect to $a$, i.e. $widehatR_acongmathcalR_a$ ?
commutative-algebra
add a comment |Â
up vote
0
down vote
favorite
Let $S$ be the polynomial ring $k[x_1,..,x_n]$ over a field $k$, $M=langle x_1,...,x_n rangle$, and let $R=S/I$ for some ideal $I$ of $S$. We know that the completion of $S$ with respect to $M$ is the formal power series ring $mathcalS=k[![x_1,...,x_n]!]$ and the completion of $R$ is $mathcalR=mathcalS/ImathcalS$. Now let $a$ be a non zero element of $R$ and $R_a$ be the localization of $R$ with respect to $a$. Is it true that $widehatR_a$ is the lozalization of $mathcalR$ with respect to $a$, i.e. $widehatR_acongmathcalR_a$ ?
commutative-algebra
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Let $S$ be the polynomial ring $k[x_1,..,x_n]$ over a field $k$, $M=langle x_1,...,x_n rangle$, and let $R=S/I$ for some ideal $I$ of $S$. We know that the completion of $S$ with respect to $M$ is the formal power series ring $mathcalS=k[![x_1,...,x_n]!]$ and the completion of $R$ is $mathcalR=mathcalS/ImathcalS$. Now let $a$ be a non zero element of $R$ and $R_a$ be the localization of $R$ with respect to $a$. Is it true that $widehatR_a$ is the lozalization of $mathcalR$ with respect to $a$, i.e. $widehatR_acongmathcalR_a$ ?
commutative-algebra
Let $S$ be the polynomial ring $k[x_1,..,x_n]$ over a field $k$, $M=langle x_1,...,x_n rangle$, and let $R=S/I$ for some ideal $I$ of $S$. We know that the completion of $S$ with respect to $M$ is the formal power series ring $mathcalS=k[![x_1,...,x_n]!]$ and the completion of $R$ is $mathcalR=mathcalS/ImathcalS$. Now let $a$ be a non zero element of $R$ and $R_a$ be the localization of $R$ with respect to $a$. Is it true that $widehatR_a$ is the lozalization of $mathcalR$ with respect to $a$, i.e. $widehatR_acongmathcalR_a$ ?
commutative-algebra
edited Aug 4 at 20:22
user26857
38.7k123678
38.7k123678
asked Jul 31 at 20:24


greenspider
93
93
add a comment |Â
add a comment |Â
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2868449%2fcompletion-and-localization%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password