Form of series solution in Differential equation
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Find the equation that doesn't have a series solution in form of
$$y(x)=sum_n=0^inftya_nx^n $$
$$ 1.;;fracd^2ydx^2+fracsin xxy=0 qquad 2.;;fracd^2ydx^2+fraccos xxy=0$$ $$ 3.;;fracd^2ydx^2+sin(x)y=0qquad 4.;;fracd^2ydx^2+cos(x)y=0$$
$y''+P(x)y'+Q(x)y=0 $
It seems $Q(x)$ in every choice is analytic to me. How should I solve it?
differential-equations
 |Â
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up vote
0
down vote
favorite
Find the equation that doesn't have a series solution in form of
$$y(x)=sum_n=0^inftya_nx^n $$
$$ 1.;;fracd^2ydx^2+fracsin xxy=0 qquad 2.;;fracd^2ydx^2+fraccos xxy=0$$ $$ 3.;;fracd^2ydx^2+sin(x)y=0qquad 4.;;fracd^2ydx^2+cos(x)y=0$$
$y''+P(x)y'+Q(x)y=0 $
It seems $Q(x)$ in every choice is analytic to me. How should I solve it?
differential-equations
3
whats the limit $cos(x)/x$ as $xto 0$?
– Calvin Khor
Jul 27 at 12:28
In one of these choices, $Q(x)$ is not analytic at $x=0$
– Dylan
Jul 27 at 12:45
Isn't cosx/x representable as power series which means analytic?
– NK Yu
Jul 27 at 12:52
1
Try to find the power series of $cos x/x$. You'll see that the leading term is $1/x$
– Dylan
Jul 27 at 12:53
1
@NKYu Do the same calculation for $frac sin x x$ and see the difference.
– Isham
Jul 27 at 13:03
 |Â
show 2 more comments
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Find the equation that doesn't have a series solution in form of
$$y(x)=sum_n=0^inftya_nx^n $$
$$ 1.;;fracd^2ydx^2+fracsin xxy=0 qquad 2.;;fracd^2ydx^2+fraccos xxy=0$$ $$ 3.;;fracd^2ydx^2+sin(x)y=0qquad 4.;;fracd^2ydx^2+cos(x)y=0$$
$y''+P(x)y'+Q(x)y=0 $
It seems $Q(x)$ in every choice is analytic to me. How should I solve it?
differential-equations
Find the equation that doesn't have a series solution in form of
$$y(x)=sum_n=0^inftya_nx^n $$
$$ 1.;;fracd^2ydx^2+fracsin xxy=0 qquad 2.;;fracd^2ydx^2+fraccos xxy=0$$ $$ 3.;;fracd^2ydx^2+sin(x)y=0qquad 4.;;fracd^2ydx^2+cos(x)y=0$$
$y''+P(x)y'+Q(x)y=0 $
It seems $Q(x)$ in every choice is analytic to me. How should I solve it?
differential-equations
edited Jul 27 at 12:26
Bernard
110k635102
110k635102
asked Jul 27 at 12:19
NK Yu
1847
1847
3
whats the limit $cos(x)/x$ as $xto 0$?
– Calvin Khor
Jul 27 at 12:28
In one of these choices, $Q(x)$ is not analytic at $x=0$
– Dylan
Jul 27 at 12:45
Isn't cosx/x representable as power series which means analytic?
– NK Yu
Jul 27 at 12:52
1
Try to find the power series of $cos x/x$. You'll see that the leading term is $1/x$
– Dylan
Jul 27 at 12:53
1
@NKYu Do the same calculation for $frac sin x x$ and see the difference.
– Isham
Jul 27 at 13:03
 |Â
show 2 more comments
3
whats the limit $cos(x)/x$ as $xto 0$?
– Calvin Khor
Jul 27 at 12:28
In one of these choices, $Q(x)$ is not analytic at $x=0$
– Dylan
Jul 27 at 12:45
Isn't cosx/x representable as power series which means analytic?
– NK Yu
Jul 27 at 12:52
1
Try to find the power series of $cos x/x$. You'll see that the leading term is $1/x$
– Dylan
Jul 27 at 12:53
1
@NKYu Do the same calculation for $frac sin x x$ and see the difference.
– Isham
Jul 27 at 13:03
3
3
whats the limit $cos(x)/x$ as $xto 0$?
– Calvin Khor
Jul 27 at 12:28
whats the limit $cos(x)/x$ as $xto 0$?
– Calvin Khor
Jul 27 at 12:28
In one of these choices, $Q(x)$ is not analytic at $x=0$
– Dylan
Jul 27 at 12:45
In one of these choices, $Q(x)$ is not analytic at $x=0$
– Dylan
Jul 27 at 12:45
Isn't cosx/x representable as power series which means analytic?
– NK Yu
Jul 27 at 12:52
Isn't cosx/x representable as power series which means analytic?
– NK Yu
Jul 27 at 12:52
1
1
Try to find the power series of $cos x/x$. You'll see that the leading term is $1/x$
– Dylan
Jul 27 at 12:53
Try to find the power series of $cos x/x$. You'll see that the leading term is $1/x$
– Dylan
Jul 27 at 12:53
1
1
@NKYu Do the same calculation for $frac sin x x$ and see the difference.
– Isham
Jul 27 at 13:03
@NKYu Do the same calculation for $frac sin x x$ and see the difference.
– Isham
Jul 27 at 13:03
 |Â
show 2 more comments
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3
whats the limit $cos(x)/x$ as $xto 0$?
– Calvin Khor
Jul 27 at 12:28
In one of these choices, $Q(x)$ is not analytic at $x=0$
– Dylan
Jul 27 at 12:45
Isn't cosx/x representable as power series which means analytic?
– NK Yu
Jul 27 at 12:52
1
Try to find the power series of $cos x/x$. You'll see that the leading term is $1/x$
– Dylan
Jul 27 at 12:53
1
@NKYu Do the same calculation for $frac sin x x$ and see the difference.
– Isham
Jul 27 at 13:03