How can I transform a function into an improper integral [closed]
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By transform I mean show that $f(a) =10^a = int_0^infty textof something $
I want to find that something, the integrand
Have found nothing online, no complex numbers, I know how to find infinite series. Thank you very much in advance!
integration functions improper-integrals
closed as unclear what you're asking by JMoravitz, copper.hat, amWhy, Lord Shark the Unknown, max_zorn Aug 2 at 5:58
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
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up vote
-1
down vote
favorite
By transform I mean show that $f(a) =10^a = int_0^infty textof something $
I want to find that something, the integrand
Have found nothing online, no complex numbers, I know how to find infinite series. Thank you very much in advance!
integration functions improper-integrals
closed as unclear what you're asking by JMoravitz, copper.hat, amWhy, Lord Shark the Unknown, max_zorn Aug 2 at 5:58
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
Not sure what you mean by transform here...
– hjpotter92
Aug 1 at 22:16
This is very unclear what you are wanting. If the integral expression is being integrated with respect to $a$, the result will be a constant number, and not equal to a function of $a$. You could if you insist choose your favorite function $g(x)$, which satisfies $int_0^infty g(x)dx = 1$ and write $f(a)=int_0^infty (f(a)g(x)dx)$, noting that $f(a)$ would be a constant with respect to the variable of integration but this seems rather pointless to do.
– JMoravitz
Aug 1 at 22:19
Let something be $1_[0,10^a]$.
– copper.hat
Aug 1 at 22:30
Do you perhaps want the upper limit of integration to be $a?$ Just a guess.
– saulspatz
Aug 1 at 22:41
Are you looking for something like $$int_0^infty frac2cdot 10^api(1+x^2), dx=10^a$$
– gimusi
Aug 2 at 2:07
add a comment |Â
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
By transform I mean show that $f(a) =10^a = int_0^infty textof something $
I want to find that something, the integrand
Have found nothing online, no complex numbers, I know how to find infinite series. Thank you very much in advance!
integration functions improper-integrals
By transform I mean show that $f(a) =10^a = int_0^infty textof something $
I want to find that something, the integrand
Have found nothing online, no complex numbers, I know how to find infinite series. Thank you very much in advance!
integration functions improper-integrals
edited Aug 2 at 2:55
Michael Hardy
204k23185460
204k23185460
asked Aug 1 at 22:14


Victor Orta
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closed as unclear what you're asking by JMoravitz, copper.hat, amWhy, Lord Shark the Unknown, max_zorn Aug 2 at 5:58
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
closed as unclear what you're asking by JMoravitz, copper.hat, amWhy, Lord Shark the Unknown, max_zorn Aug 2 at 5:58
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
Not sure what you mean by transform here...
– hjpotter92
Aug 1 at 22:16
This is very unclear what you are wanting. If the integral expression is being integrated with respect to $a$, the result will be a constant number, and not equal to a function of $a$. You could if you insist choose your favorite function $g(x)$, which satisfies $int_0^infty g(x)dx = 1$ and write $f(a)=int_0^infty (f(a)g(x)dx)$, noting that $f(a)$ would be a constant with respect to the variable of integration but this seems rather pointless to do.
– JMoravitz
Aug 1 at 22:19
Let something be $1_[0,10^a]$.
– copper.hat
Aug 1 at 22:30
Do you perhaps want the upper limit of integration to be $a?$ Just a guess.
– saulspatz
Aug 1 at 22:41
Are you looking for something like $$int_0^infty frac2cdot 10^api(1+x^2), dx=10^a$$
– gimusi
Aug 2 at 2:07
add a comment |Â
Not sure what you mean by transform here...
– hjpotter92
Aug 1 at 22:16
This is very unclear what you are wanting. If the integral expression is being integrated with respect to $a$, the result will be a constant number, and not equal to a function of $a$. You could if you insist choose your favorite function $g(x)$, which satisfies $int_0^infty g(x)dx = 1$ and write $f(a)=int_0^infty (f(a)g(x)dx)$, noting that $f(a)$ would be a constant with respect to the variable of integration but this seems rather pointless to do.
– JMoravitz
Aug 1 at 22:19
Let something be $1_[0,10^a]$.
– copper.hat
Aug 1 at 22:30
Do you perhaps want the upper limit of integration to be $a?$ Just a guess.
– saulspatz
Aug 1 at 22:41
Are you looking for something like $$int_0^infty frac2cdot 10^api(1+x^2), dx=10^a$$
– gimusi
Aug 2 at 2:07
Not sure what you mean by transform here...
– hjpotter92
Aug 1 at 22:16
Not sure what you mean by transform here...
– hjpotter92
Aug 1 at 22:16
This is very unclear what you are wanting. If the integral expression is being integrated with respect to $a$, the result will be a constant number, and not equal to a function of $a$. You could if you insist choose your favorite function $g(x)$, which satisfies $int_0^infty g(x)dx = 1$ and write $f(a)=int_0^infty (f(a)g(x)dx)$, noting that $f(a)$ would be a constant with respect to the variable of integration but this seems rather pointless to do.
– JMoravitz
Aug 1 at 22:19
This is very unclear what you are wanting. If the integral expression is being integrated with respect to $a$, the result will be a constant number, and not equal to a function of $a$. You could if you insist choose your favorite function $g(x)$, which satisfies $int_0^infty g(x)dx = 1$ and write $f(a)=int_0^infty (f(a)g(x)dx)$, noting that $f(a)$ would be a constant with respect to the variable of integration but this seems rather pointless to do.
– JMoravitz
Aug 1 at 22:19
Let something be $1_[0,10^a]$.
– copper.hat
Aug 1 at 22:30
Let something be $1_[0,10^a]$.
– copper.hat
Aug 1 at 22:30
Do you perhaps want the upper limit of integration to be $a?$ Just a guess.
– saulspatz
Aug 1 at 22:41
Do you perhaps want the upper limit of integration to be $a?$ Just a guess.
– saulspatz
Aug 1 at 22:41
Are you looking for something like $$int_0^infty frac2cdot 10^api(1+x^2), dx=10^a$$
– gimusi
Aug 2 at 2:07
Are you looking for something like $$int_0^infty frac2cdot 10^api(1+x^2), dx=10^a$$
– gimusi
Aug 2 at 2:07
add a comment |Â
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Not sure what you mean by transform here...
– hjpotter92
Aug 1 at 22:16
This is very unclear what you are wanting. If the integral expression is being integrated with respect to $a$, the result will be a constant number, and not equal to a function of $a$. You could if you insist choose your favorite function $g(x)$, which satisfies $int_0^infty g(x)dx = 1$ and write $f(a)=int_0^infty (f(a)g(x)dx)$, noting that $f(a)$ would be a constant with respect to the variable of integration but this seems rather pointless to do.
– JMoravitz
Aug 1 at 22:19
Let something be $1_[0,10^a]$.
– copper.hat
Aug 1 at 22:30
Do you perhaps want the upper limit of integration to be $a?$ Just a guess.
– saulspatz
Aug 1 at 22:41
Are you looking for something like $$int_0^infty frac2cdot 10^api(1+x^2), dx=10^a$$
– gimusi
Aug 2 at 2:07