Action of torus on an affine toric variety

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Let $V$ be an affine toric variety (where the base field is $mathbb C$), i.e., $V$ is an irreducible affine variety containing a torus $T$ as a Zariski open subset and $T$ has an action on $V$.



The action if $T$ on $V$ is given by a morphism $Ttimes Vrightarrow V$. Let $finmathbb C[V]$, a regular function on $V$. For $tin T$, we define $tcdot f$ which is given by $pmapsto f(t^-1cdot p)$.



My question is why $tcdot finmathbb C[V]$.



This is from the book 'Toric varieties' by Cox, Little, Schenck; page 19, Theorem 1.1.17



Thank you.







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    up vote
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    Let $V$ be an affine toric variety (where the base field is $mathbb C$), i.e., $V$ is an irreducible affine variety containing a torus $T$ as a Zariski open subset and $T$ has an action on $V$.



    The action if $T$ on $V$ is given by a morphism $Ttimes Vrightarrow V$. Let $finmathbb C[V]$, a regular function on $V$. For $tin T$, we define $tcdot f$ which is given by $pmapsto f(t^-1cdot p)$.



    My question is why $tcdot finmathbb C[V]$.



    This is from the book 'Toric varieties' by Cox, Little, Schenck; page 19, Theorem 1.1.17



    Thank you.







    share|cite|improve this question





















      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      Let $V$ be an affine toric variety (where the base field is $mathbb C$), i.e., $V$ is an irreducible affine variety containing a torus $T$ as a Zariski open subset and $T$ has an action on $V$.



      The action if $T$ on $V$ is given by a morphism $Ttimes Vrightarrow V$. Let $finmathbb C[V]$, a regular function on $V$. For $tin T$, we define $tcdot f$ which is given by $pmapsto f(t^-1cdot p)$.



      My question is why $tcdot finmathbb C[V]$.



      This is from the book 'Toric varieties' by Cox, Little, Schenck; page 19, Theorem 1.1.17



      Thank you.







      share|cite|improve this question











      Let $V$ be an affine toric variety (where the base field is $mathbb C$), i.e., $V$ is an irreducible affine variety containing a torus $T$ as a Zariski open subset and $T$ has an action on $V$.



      The action if $T$ on $V$ is given by a morphism $Ttimes Vrightarrow V$. Let $finmathbb C[V]$, a regular function on $V$. For $tin T$, we define $tcdot f$ which is given by $pmapsto f(t^-1cdot p)$.



      My question is why $tcdot finmathbb C[V]$.



      This is from the book 'Toric varieties' by Cox, Little, Schenck; page 19, Theorem 1.1.17



      Thank you.









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      share|cite|improve this question




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      asked Jul 16 at 6:29









      2015

      1,2881521




      1,2881521




















          1 Answer
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          Recall that a function in $Bbb C[V]$ is the same as a regular map $Vto Bbb A^1_Bbb C$, and that the composition of regular maps is a regular map.



          The map $i:Tto T$ given by $tmapsto t^-1$ is a regular map, and the map $m:Ttimes V$ given by $(t,p)mapsto tcdot p$ is a regular map. Thus $Vstackrelt_0times idto Ttimes V stackrelitimes idto Ttimes V stackrelmto V$ for a fixed $t_0$ is given by $vmapsto t_0^-1cdot v$. Further, post-composing with $f: Vto Bbb A^1_Bbb C$ gives us that the composite map is $pmapsto f(t_0^-1cdot p)$ and since this is a composition of regular maps, it is a regular map from $Vto Bbb A^1_Bbb C$ and thus an element of $Bbb C[V]$.






          share|cite|improve this answer





















          • I understand your argument and I will accept the answer. I have one additional question : if $f$ is given by some polynomial then can we say anything about the polynomial of $t_0cdot f$?
            – 2015
            Jul 16 at 6:55










          • I can't think of anything simpler than "translate the input by $t_0^-1$". The degree will remain the same, the roots of $f$ will be the roots of $f$ translated, etc. It's analogous to taking a polynomial $f(x)=a_nx^n+cdots+a_1x+a_0$ and asking what happens when we shift by $x=x+1$.
            – KReiser
            Jul 16 at 7:08










          • Thank you for your answer.
            – 2015
            Jul 16 at 7:09










          Your Answer




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          1 Answer
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          1 Answer
          1






          active

          oldest

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          active

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          up vote
          4
          down vote



          accepted










          Recall that a function in $Bbb C[V]$ is the same as a regular map $Vto Bbb A^1_Bbb C$, and that the composition of regular maps is a regular map.



          The map $i:Tto T$ given by $tmapsto t^-1$ is a regular map, and the map $m:Ttimes V$ given by $(t,p)mapsto tcdot p$ is a regular map. Thus $Vstackrelt_0times idto Ttimes V stackrelitimes idto Ttimes V stackrelmto V$ for a fixed $t_0$ is given by $vmapsto t_0^-1cdot v$. Further, post-composing with $f: Vto Bbb A^1_Bbb C$ gives us that the composite map is $pmapsto f(t_0^-1cdot p)$ and since this is a composition of regular maps, it is a regular map from $Vto Bbb A^1_Bbb C$ and thus an element of $Bbb C[V]$.






          share|cite|improve this answer





















          • I understand your argument and I will accept the answer. I have one additional question : if $f$ is given by some polynomial then can we say anything about the polynomial of $t_0cdot f$?
            – 2015
            Jul 16 at 6:55










          • I can't think of anything simpler than "translate the input by $t_0^-1$". The degree will remain the same, the roots of $f$ will be the roots of $f$ translated, etc. It's analogous to taking a polynomial $f(x)=a_nx^n+cdots+a_1x+a_0$ and asking what happens when we shift by $x=x+1$.
            – KReiser
            Jul 16 at 7:08










          • Thank you for your answer.
            – 2015
            Jul 16 at 7:09














          up vote
          4
          down vote



          accepted










          Recall that a function in $Bbb C[V]$ is the same as a regular map $Vto Bbb A^1_Bbb C$, and that the composition of regular maps is a regular map.



          The map $i:Tto T$ given by $tmapsto t^-1$ is a regular map, and the map $m:Ttimes V$ given by $(t,p)mapsto tcdot p$ is a regular map. Thus $Vstackrelt_0times idto Ttimes V stackrelitimes idto Ttimes V stackrelmto V$ for a fixed $t_0$ is given by $vmapsto t_0^-1cdot v$. Further, post-composing with $f: Vto Bbb A^1_Bbb C$ gives us that the composite map is $pmapsto f(t_0^-1cdot p)$ and since this is a composition of regular maps, it is a regular map from $Vto Bbb A^1_Bbb C$ and thus an element of $Bbb C[V]$.






          share|cite|improve this answer





















          • I understand your argument and I will accept the answer. I have one additional question : if $f$ is given by some polynomial then can we say anything about the polynomial of $t_0cdot f$?
            – 2015
            Jul 16 at 6:55










          • I can't think of anything simpler than "translate the input by $t_0^-1$". The degree will remain the same, the roots of $f$ will be the roots of $f$ translated, etc. It's analogous to taking a polynomial $f(x)=a_nx^n+cdots+a_1x+a_0$ and asking what happens when we shift by $x=x+1$.
            – KReiser
            Jul 16 at 7:08










          • Thank you for your answer.
            – 2015
            Jul 16 at 7:09












          up vote
          4
          down vote



          accepted







          up vote
          4
          down vote



          accepted






          Recall that a function in $Bbb C[V]$ is the same as a regular map $Vto Bbb A^1_Bbb C$, and that the composition of regular maps is a regular map.



          The map $i:Tto T$ given by $tmapsto t^-1$ is a regular map, and the map $m:Ttimes V$ given by $(t,p)mapsto tcdot p$ is a regular map. Thus $Vstackrelt_0times idto Ttimes V stackrelitimes idto Ttimes V stackrelmto V$ for a fixed $t_0$ is given by $vmapsto t_0^-1cdot v$. Further, post-composing with $f: Vto Bbb A^1_Bbb C$ gives us that the composite map is $pmapsto f(t_0^-1cdot p)$ and since this is a composition of regular maps, it is a regular map from $Vto Bbb A^1_Bbb C$ and thus an element of $Bbb C[V]$.






          share|cite|improve this answer













          Recall that a function in $Bbb C[V]$ is the same as a regular map $Vto Bbb A^1_Bbb C$, and that the composition of regular maps is a regular map.



          The map $i:Tto T$ given by $tmapsto t^-1$ is a regular map, and the map $m:Ttimes V$ given by $(t,p)mapsto tcdot p$ is a regular map. Thus $Vstackrelt_0times idto Ttimes V stackrelitimes idto Ttimes V stackrelmto V$ for a fixed $t_0$ is given by $vmapsto t_0^-1cdot v$. Further, post-composing with $f: Vto Bbb A^1_Bbb C$ gives us that the composite map is $pmapsto f(t_0^-1cdot p)$ and since this is a composition of regular maps, it is a regular map from $Vto Bbb A^1_Bbb C$ and thus an element of $Bbb C[V]$.







          share|cite|improve this answer













          share|cite|improve this answer



          share|cite|improve this answer











          answered Jul 16 at 6:43









          KReiser

          7,62511230




          7,62511230











          • I understand your argument and I will accept the answer. I have one additional question : if $f$ is given by some polynomial then can we say anything about the polynomial of $t_0cdot f$?
            – 2015
            Jul 16 at 6:55










          • I can't think of anything simpler than "translate the input by $t_0^-1$". The degree will remain the same, the roots of $f$ will be the roots of $f$ translated, etc. It's analogous to taking a polynomial $f(x)=a_nx^n+cdots+a_1x+a_0$ and asking what happens when we shift by $x=x+1$.
            – KReiser
            Jul 16 at 7:08










          • Thank you for your answer.
            – 2015
            Jul 16 at 7:09
















          • I understand your argument and I will accept the answer. I have one additional question : if $f$ is given by some polynomial then can we say anything about the polynomial of $t_0cdot f$?
            – 2015
            Jul 16 at 6:55










          • I can't think of anything simpler than "translate the input by $t_0^-1$". The degree will remain the same, the roots of $f$ will be the roots of $f$ translated, etc. It's analogous to taking a polynomial $f(x)=a_nx^n+cdots+a_1x+a_0$ and asking what happens when we shift by $x=x+1$.
            – KReiser
            Jul 16 at 7:08










          • Thank you for your answer.
            – 2015
            Jul 16 at 7:09















          I understand your argument and I will accept the answer. I have one additional question : if $f$ is given by some polynomial then can we say anything about the polynomial of $t_0cdot f$?
          – 2015
          Jul 16 at 6:55




          I understand your argument and I will accept the answer. I have one additional question : if $f$ is given by some polynomial then can we say anything about the polynomial of $t_0cdot f$?
          – 2015
          Jul 16 at 6:55












          I can't think of anything simpler than "translate the input by $t_0^-1$". The degree will remain the same, the roots of $f$ will be the roots of $f$ translated, etc. It's analogous to taking a polynomial $f(x)=a_nx^n+cdots+a_1x+a_0$ and asking what happens when we shift by $x=x+1$.
          – KReiser
          Jul 16 at 7:08




          I can't think of anything simpler than "translate the input by $t_0^-1$". The degree will remain the same, the roots of $f$ will be the roots of $f$ translated, etc. It's analogous to taking a polynomial $f(x)=a_nx^n+cdots+a_1x+a_0$ and asking what happens when we shift by $x=x+1$.
          – KReiser
          Jul 16 at 7:08












          Thank you for your answer.
          – 2015
          Jul 16 at 7:09




          Thank you for your answer.
          – 2015
          Jul 16 at 7:09












           

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