Relationship Between Convolution and Fourier Analysis
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While I am reading a lecture note about a rendering of lighting and its reflection on surfaces, I've found the following change of formula using Fourier Analysis
The author appended the following slides too, but can't understand how to formula converted with those hints.
Any hint for good starting of understanding this conversion?
The full lecture note is available at link
fourier-analysis convolution
 |Â
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up vote
1
down vote
favorite
While I am reading a lecture note about a rendering of lighting and its reflection on surfaces, I've found the following change of formula using Fourier Analysis
The author appended the following slides too, but can't understand how to formula converted with those hints.
Any hint for good starting of understanding this conversion?
The full lecture note is available at link
fourier-analysis convolution
The Fourier transform of a convolution is a product and vice versa: $$widehatf*g = hat f cdot hat g$$ (with some factor depending of what definition of Fourier transform is being used.)
â md2perpe
Jul 15 at 7:26
Only for circular convolution which the above is not.
â mathreadler
Jul 15 at 7:40
@md2perpe product of what?
â Beverlie
Jul 15 at 8:06
@Beverlie. The Fourier transform of convolution of two functions is the product of the Fourier transforms of the two functions.
â md2perpe
Jul 15 at 8:25
@mathreadler. What kind of convolution is this? I don't want to deep-dive into the formulas right now.
â md2perpe
Jul 15 at 8:27
 |Â
show 2 more comments
up vote
1
down vote
favorite
up vote
1
down vote
favorite
While I am reading a lecture note about a rendering of lighting and its reflection on surfaces, I've found the following change of formula using Fourier Analysis
The author appended the following slides too, but can't understand how to formula converted with those hints.
Any hint for good starting of understanding this conversion?
The full lecture note is available at link
fourier-analysis convolution
While I am reading a lecture note about a rendering of lighting and its reflection on surfaces, I've found the following change of formula using Fourier Analysis
The author appended the following slides too, but can't understand how to formula converted with those hints.
Any hint for good starting of understanding this conversion?
The full lecture note is available at link
fourier-analysis convolution
edited Jul 15 at 5:20
asked Jul 15 at 4:31
Beverlie
1,078318
1,078318
The Fourier transform of a convolution is a product and vice versa: $$widehatf*g = hat f cdot hat g$$ (with some factor depending of what definition of Fourier transform is being used.)
â md2perpe
Jul 15 at 7:26
Only for circular convolution which the above is not.
â mathreadler
Jul 15 at 7:40
@md2perpe product of what?
â Beverlie
Jul 15 at 8:06
@Beverlie. The Fourier transform of convolution of two functions is the product of the Fourier transforms of the two functions.
â md2perpe
Jul 15 at 8:25
@mathreadler. What kind of convolution is this? I don't want to deep-dive into the formulas right now.
â md2perpe
Jul 15 at 8:27
 |Â
show 2 more comments
The Fourier transform of a convolution is a product and vice versa: $$widehatf*g = hat f cdot hat g$$ (with some factor depending of what definition of Fourier transform is being used.)
â md2perpe
Jul 15 at 7:26
Only for circular convolution which the above is not.
â mathreadler
Jul 15 at 7:40
@md2perpe product of what?
â Beverlie
Jul 15 at 8:06
@Beverlie. The Fourier transform of convolution of two functions is the product of the Fourier transforms of the two functions.
â md2perpe
Jul 15 at 8:25
@mathreadler. What kind of convolution is this? I don't want to deep-dive into the formulas right now.
â md2perpe
Jul 15 at 8:27
The Fourier transform of a convolution is a product and vice versa: $$widehatf*g = hat f cdot hat g$$ (with some factor depending of what definition of Fourier transform is being used.)
â md2perpe
Jul 15 at 7:26
The Fourier transform of a convolution is a product and vice versa: $$widehatf*g = hat f cdot hat g$$ (with some factor depending of what definition of Fourier transform is being used.)
â md2perpe
Jul 15 at 7:26
Only for circular convolution which the above is not.
â mathreadler
Jul 15 at 7:40
Only for circular convolution which the above is not.
â mathreadler
Jul 15 at 7:40
@md2perpe product of what?
â Beverlie
Jul 15 at 8:06
@md2perpe product of what?
â Beverlie
Jul 15 at 8:06
@Beverlie. The Fourier transform of convolution of two functions is the product of the Fourier transforms of the two functions.
â md2perpe
Jul 15 at 8:25
@Beverlie. The Fourier transform of convolution of two functions is the product of the Fourier transforms of the two functions.
â md2perpe
Jul 15 at 8:25
@mathreadler. What kind of convolution is this? I don't want to deep-dive into the formulas right now.
â md2perpe
Jul 15 at 8:27
@mathreadler. What kind of convolution is this? I don't want to deep-dive into the formulas right now.
â md2perpe
Jul 15 at 8:27
 |Â
show 2 more comments
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The Fourier transform of a convolution is a product and vice versa: $$widehatf*g = hat f cdot hat g$$ (with some factor depending of what definition of Fourier transform is being used.)
â md2perpe
Jul 15 at 7:26
Only for circular convolution which the above is not.
â mathreadler
Jul 15 at 7:40
@md2perpe product of what?
â Beverlie
Jul 15 at 8:06
@Beverlie. The Fourier transform of convolution of two functions is the product of the Fourier transforms of the two functions.
â md2perpe
Jul 15 at 8:25
@mathreadler. What kind of convolution is this? I don't want to deep-dive into the formulas right now.
â md2perpe
Jul 15 at 8:27