Permutation of n ,not all different things, taking r at a time

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
1
down vote

favorite












Please read it once again, it's not as easy as it seems.



Is there any Mathematical formula or finite approach to solve this type of problem.
Eg - Find the permutation of word "MALAYALAM" taking 5 at a time.



I have written a program which can solve this type of problem ,but I couldn't found any method to do it on paper.



My programming approach -
(i) Find all the combination taking r at a time



(ii) Remove duplicates from combination by sorting



(iii) Find the permutation of individual combination and then sum up, to get the answer.



Please help me,
Thanks




permutations




share|cite|improve this question



















  • Possible duplicate of Number of ways of forming 4 letter words using the letters of the word RAMANA
    – user190080
    Jul 15 at 13:39














up vote
1
down vote

favorite












Please read it once again, it's not as easy as it seems.



Is there any Mathematical formula or finite approach to solve this type of problem.
Eg - Find the permutation of word "MALAYALAM" taking 5 at a time.



I have written a program which can solve this type of problem ,but I couldn't found any method to do it on paper.



My programming approach -
(i) Find all the combination taking r at a time



(ii) Remove duplicates from combination by sorting



(iii) Find the permutation of individual combination and then sum up, to get the answer.



Please help me,
Thanks




permutations




share|cite|improve this question



















  • Possible duplicate of Number of ways of forming 4 letter words using the letters of the word RAMANA
    – user190080
    Jul 15 at 13:39












up vote
1
down vote

favorite









up vote
1
down vote

favorite











Please read it once again, it's not as easy as it seems.



Is there any Mathematical formula or finite approach to solve this type of problem.
Eg - Find the permutation of word "MALAYALAM" taking 5 at a time.



I have written a program which can solve this type of problem ,but I couldn't found any method to do it on paper.



My programming approach -
(i) Find all the combination taking r at a time



(ii) Remove duplicates from combination by sorting



(iii) Find the permutation of individual combination and then sum up, to get the answer.



Please help me,
Thanks




permutations




share|cite|improve this question











Please read it once again, it's not as easy as it seems.



Is there any Mathematical formula or finite approach to solve this type of problem.
Eg - Find the permutation of word "MALAYALAM" taking 5 at a time.



I have written a program which can solve this type of problem ,but I couldn't found any method to do it on paper.



My programming approach -
(i) Find all the combination taking r at a time



(ii) Remove duplicates from combination by sorting



(iii) Find the permutation of individual combination and then sum up, to get the answer.



Please help me,
Thanks





permutations





share|cite|improve this question










share|cite|improve this question




share|cite|improve this question









asked Jul 15 at 4:42









RAHUL JAISWAL

83




83











  • Possible duplicate of Number of ways of forming 4 letter words using the letters of the word RAMANA
    – user190080
    Jul 15 at 13:39
















  • Possible duplicate of Number of ways of forming 4 letter words using the letters of the word RAMANA
    – user190080
    Jul 15 at 13:39















Possible duplicate of Number of ways of forming 4 letter words using the letters of the word RAMANA
– user190080
Jul 15 at 13:39




Possible duplicate of Number of ways of forming 4 letter words using the letters of the word RAMANA
– user190080
Jul 15 at 13:39










1 Answer
1






active

oldest

votes

















up vote
0
down vote



accepted










Yes, there is a formula.

The word has one Y, two each of M and L and four of A



and the formula would be to find the coefficient of $x^5$ in $5!(1+fracx1!)(1+fracx1!+fracx^22!)^2 (1+fracx1! + fracx^22! + fracx^33! + fracx^44!)$



To understand why this works, you can see here






share|cite|improve this answer























  • Thanks frnd ,I got it
    – RAHUL JAISWAL
    Jul 15 at 14:51










  • You're welcome !
    – true blue anil
    Jul 15 at 19:07










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
0
down vote



accepted










Yes, there is a formula.

The word has one Y, two each of M and L and four of A



and the formula would be to find the coefficient of $x^5$ in $5!(1+fracx1!)(1+fracx1!+fracx^22!)^2 (1+fracx1! + fracx^22! + fracx^33! + fracx^44!)$



To understand why this works, you can see here






share|cite|improve this answer























  • Thanks frnd ,I got it
    – RAHUL JAISWAL
    Jul 15 at 14:51










  • You're welcome !
    – true blue anil
    Jul 15 at 19:07














up vote
0
down vote



accepted










Yes, there is a formula.

The word has one Y, two each of M and L and four of A



and the formula would be to find the coefficient of $x^5$ in $5!(1+fracx1!)(1+fracx1!+fracx^22!)^2 (1+fracx1! + fracx^22! + fracx^33! + fracx^44!)$



To understand why this works, you can see here






share|cite|improve this answer























  • Thanks frnd ,I got it
    – RAHUL JAISWAL
    Jul 15 at 14:51










  • You're welcome !
    – true blue anil
    Jul 15 at 19:07












up vote
0
down vote



accepted







up vote
0
down vote



accepted






Yes, there is a formula.

The word has one Y, two each of M and L and four of A



and the formula would be to find the coefficient of $x^5$ in $5!(1+fracx1!)(1+fracx1!+fracx^22!)^2 (1+fracx1! + fracx^22! + fracx^33! + fracx^44!)$



To understand why this works, you can see here






share|cite|improve this answer















Yes, there is a formula.

The word has one Y, two each of M and L and four of A



and the formula would be to find the coefficient of $x^5$ in $5!(1+fracx1!)(1+fracx1!+fracx^22!)^2 (1+fracx1! + fracx^22! + fracx^33! + fracx^44!)$



To understand why this works, you can see here







share|cite|improve this answer















share|cite|improve this answer



share|cite|improve this answer








edited Jul 15 at 7:43


























answered Jul 15 at 7:26









true blue anil

20.3k11841




20.3k11841











  • Thanks frnd ,I got it
    – RAHUL JAISWAL
    Jul 15 at 14:51










  • You're welcome !
    – true blue anil
    Jul 15 at 19:07
















  • Thanks frnd ,I got it
    – RAHUL JAISWAL
    Jul 15 at 14:51










  • You're welcome !
    – true blue anil
    Jul 15 at 19:07















Thanks frnd ,I got it
– RAHUL JAISWAL
Jul 15 at 14:51




Thanks frnd ,I got it
– RAHUL JAISWAL
Jul 15 at 14:51












You're welcome !
– true blue anil
Jul 15 at 19:07




You're welcome !
– true blue anil
Jul 15 at 19:07












 

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