rank of a resultant matrix
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If I multiply a rank one symmetric positive semidefinite matrix with a diagonal matrix(diagonal matrices are full rank), both matrices have the same dimensions. Can I say/predict anything about the rank of the resultant matrix?
Thanks.
matrix-rank
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If I multiply a rank one symmetric positive semidefinite matrix with a diagonal matrix(diagonal matrices are full rank), both matrices have the same dimensions. Can I say/predict anything about the rank of the resultant matrix?
Thanks.
matrix-rank
1
Yes, it will be at most a rank one matrix. In general, given two matrices $A,B$, you have $textrank(AB) le mintextrank(A),textrank(B)$. So, if one of the matrices has rank 1, that is the upper bound for the rank of the product of the two matrices.
– InterstellarProbe
Jul 31 at 18:39
@InterstellarProbe The diagonal matrix is known to be full rank.
– amd
Jul 31 at 19:51
@amd I gave one piece of information to get the OP started. I did not post it as an answer because it is not a complete answer. I was just hoping it would help the OP figure it out on his/her own. While the diagonal matrix is known to be full rank, the other is rank one.
– InterstellarProbe
Jul 31 at 20:27
add a comment |Â
up vote
-4
down vote
favorite
up vote
-4
down vote
favorite
If I multiply a rank one symmetric positive semidefinite matrix with a diagonal matrix(diagonal matrices are full rank), both matrices have the same dimensions. Can I say/predict anything about the rank of the resultant matrix?
Thanks.
matrix-rank
If I multiply a rank one symmetric positive semidefinite matrix with a diagonal matrix(diagonal matrices are full rank), both matrices have the same dimensions. Can I say/predict anything about the rank of the resultant matrix?
Thanks.
matrix-rank
asked Jul 31 at 18:19
Adil
13
13
1
Yes, it will be at most a rank one matrix. In general, given two matrices $A,B$, you have $textrank(AB) le mintextrank(A),textrank(B)$. So, if one of the matrices has rank 1, that is the upper bound for the rank of the product of the two matrices.
– InterstellarProbe
Jul 31 at 18:39
@InterstellarProbe The diagonal matrix is known to be full rank.
– amd
Jul 31 at 19:51
@amd I gave one piece of information to get the OP started. I did not post it as an answer because it is not a complete answer. I was just hoping it would help the OP figure it out on his/her own. While the diagonal matrix is known to be full rank, the other is rank one.
– InterstellarProbe
Jul 31 at 20:27
add a comment |Â
1
Yes, it will be at most a rank one matrix. In general, given two matrices $A,B$, you have $textrank(AB) le mintextrank(A),textrank(B)$. So, if one of the matrices has rank 1, that is the upper bound for the rank of the product of the two matrices.
– InterstellarProbe
Jul 31 at 18:39
@InterstellarProbe The diagonal matrix is known to be full rank.
– amd
Jul 31 at 19:51
@amd I gave one piece of information to get the OP started. I did not post it as an answer because it is not a complete answer. I was just hoping it would help the OP figure it out on his/her own. While the diagonal matrix is known to be full rank, the other is rank one.
– InterstellarProbe
Jul 31 at 20:27
1
1
Yes, it will be at most a rank one matrix. In general, given two matrices $A,B$, you have $textrank(AB) le mintextrank(A),textrank(B)$. So, if one of the matrices has rank 1, that is the upper bound for the rank of the product of the two matrices.
– InterstellarProbe
Jul 31 at 18:39
Yes, it will be at most a rank one matrix. In general, given two matrices $A,B$, you have $textrank(AB) le mintextrank(A),textrank(B)$. So, if one of the matrices has rank 1, that is the upper bound for the rank of the product of the two matrices.
– InterstellarProbe
Jul 31 at 18:39
@InterstellarProbe The diagonal matrix is known to be full rank.
– amd
Jul 31 at 19:51
@InterstellarProbe The diagonal matrix is known to be full rank.
– amd
Jul 31 at 19:51
@amd I gave one piece of information to get the OP started. I did not post it as an answer because it is not a complete answer. I was just hoping it would help the OP figure it out on his/her own. While the diagonal matrix is known to be full rank, the other is rank one.
– InterstellarProbe
Jul 31 at 20:27
@amd I gave one piece of information to get the OP started. I did not post it as an answer because it is not a complete answer. I was just hoping it would help the OP figure it out on his/her own. While the diagonal matrix is known to be full rank, the other is rank one.
– InterstellarProbe
Jul 31 at 20:27
add a comment |Â
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1
Yes, it will be at most a rank one matrix. In general, given two matrices $A,B$, you have $textrank(AB) le mintextrank(A),textrank(B)$. So, if one of the matrices has rank 1, that is the upper bound for the rank of the product of the two matrices.
– InterstellarProbe
Jul 31 at 18:39
@InterstellarProbe The diagonal matrix is known to be full rank.
– amd
Jul 31 at 19:51
@amd I gave one piece of information to get the OP started. I did not post it as an answer because it is not a complete answer. I was just hoping it would help the OP figure it out on his/her own. While the diagonal matrix is known to be full rank, the other is rank one.
– InterstellarProbe
Jul 31 at 20:27