Largest Orthogonal circle for a given circle
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What is the radius of the largest orthogonal circle (as a function of R)that can be constructed for a given circle of radius R?
Definition of Largest circle-the circle that spans the longest section of the circumference of given circle of radius R on it’s convex side
geometry euclidean-geometry circle orthogonality mathematica
add a comment |Â
up vote
1
down vote
favorite
What is the radius of the largest orthogonal circle (as a function of R)that can be constructed for a given circle of radius R?
Definition of Largest circle-the circle that spans the longest section of the circumference of given circle of radius R on it’s convex side
geometry euclidean-geometry circle orthogonality mathematica
1
no upper bound.
– Will Jagy
Jul 28 at 3:26
@WillJagy what if I change the definition of theâ€Âlargest circle†to the circle that spans the longest section of the circumference on it’s convex side
– user472374
Jul 28 at 3:27
@WillJagy i can’t wrap my head around NO UPPER BOUND, rather intuitively, I speculate NO LOWER BOUND
– user472374
Jul 28 at 3:37
@user472374: The "largest orthogonal circle" is a straight line through the center. For any other orthogonal circle-circle you may have, there's a larger orthogonal circle-circle (which has less curvature and is therefore closer to being a straight line). This is what WillJagy means by "no upper bound".
– Blue
Jul 28 at 3:37
@Blue Yeah, I get it now
– user472374
Jul 28 at 4:30
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
What is the radius of the largest orthogonal circle (as a function of R)that can be constructed for a given circle of radius R?
Definition of Largest circle-the circle that spans the longest section of the circumference of given circle of radius R on it’s convex side
geometry euclidean-geometry circle orthogonality mathematica
What is the radius of the largest orthogonal circle (as a function of R)that can be constructed for a given circle of radius R?
Definition of Largest circle-the circle that spans the longest section of the circumference of given circle of radius R on it’s convex side
geometry euclidean-geometry circle orthogonality mathematica
edited Jul 28 at 3:29
asked Jul 28 at 3:23
user472374
63
63
1
no upper bound.
– Will Jagy
Jul 28 at 3:26
@WillJagy what if I change the definition of theâ€Âlargest circle†to the circle that spans the longest section of the circumference on it’s convex side
– user472374
Jul 28 at 3:27
@WillJagy i can’t wrap my head around NO UPPER BOUND, rather intuitively, I speculate NO LOWER BOUND
– user472374
Jul 28 at 3:37
@user472374: The "largest orthogonal circle" is a straight line through the center. For any other orthogonal circle-circle you may have, there's a larger orthogonal circle-circle (which has less curvature and is therefore closer to being a straight line). This is what WillJagy means by "no upper bound".
– Blue
Jul 28 at 3:37
@Blue Yeah, I get it now
– user472374
Jul 28 at 4:30
add a comment |Â
1
no upper bound.
– Will Jagy
Jul 28 at 3:26
@WillJagy what if I change the definition of theâ€Âlargest circle†to the circle that spans the longest section of the circumference on it’s convex side
– user472374
Jul 28 at 3:27
@WillJagy i can’t wrap my head around NO UPPER BOUND, rather intuitively, I speculate NO LOWER BOUND
– user472374
Jul 28 at 3:37
@user472374: The "largest orthogonal circle" is a straight line through the center. For any other orthogonal circle-circle you may have, there's a larger orthogonal circle-circle (which has less curvature and is therefore closer to being a straight line). This is what WillJagy means by "no upper bound".
– Blue
Jul 28 at 3:37
@Blue Yeah, I get it now
– user472374
Jul 28 at 4:30
1
1
no upper bound.
– Will Jagy
Jul 28 at 3:26
no upper bound.
– Will Jagy
Jul 28 at 3:26
@WillJagy what if I change the definition of theâ€Âlargest circle†to the circle that spans the longest section of the circumference on it’s convex side
– user472374
Jul 28 at 3:27
@WillJagy what if I change the definition of theâ€Âlargest circle†to the circle that spans the longest section of the circumference on it’s convex side
– user472374
Jul 28 at 3:27
@WillJagy i can’t wrap my head around NO UPPER BOUND, rather intuitively, I speculate NO LOWER BOUND
– user472374
Jul 28 at 3:37
@WillJagy i can’t wrap my head around NO UPPER BOUND, rather intuitively, I speculate NO LOWER BOUND
– user472374
Jul 28 at 3:37
@user472374: The "largest orthogonal circle" is a straight line through the center. For any other orthogonal circle-circle you may have, there's a larger orthogonal circle-circle (which has less curvature and is therefore closer to being a straight line). This is what WillJagy means by "no upper bound".
– Blue
Jul 28 at 3:37
@user472374: The "largest orthogonal circle" is a straight line through the center. For any other orthogonal circle-circle you may have, there's a larger orthogonal circle-circle (which has less curvature and is therefore closer to being a straight line). This is what WillJagy means by "no upper bound".
– Blue
Jul 28 at 3:37
@Blue Yeah, I get it now
– user472374
Jul 28 at 4:30
@Blue Yeah, I get it now
– user472374
Jul 28 at 4:30
add a comment |Â
1 Answer
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For any (true) circle orthogonal to a given circle, you can always find a larger one, with ever-more of the given circle's circumference on its "convex side". So, there is no "largest" (true) circle.
Now, larger and larger circles have smaller and smaller curvature; larger and larger orthogonal circles get closer and closer to the center of the given circle. Thus, this sequence of circles, as they say, "tend toward" a straight line through the given circle's center. It's sometimes philosophically helpful to consider a line to be a circle, just one of infinite radius. (A number of theorems become easier to state.) In that sense, the "largest circle" is that line through the center.
1
Thanks You for your answer!
– user472374
Jul 28 at 4:36
add a comment |Â
1 Answer
1
active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
For any (true) circle orthogonal to a given circle, you can always find a larger one, with ever-more of the given circle's circumference on its "convex side". So, there is no "largest" (true) circle.
Now, larger and larger circles have smaller and smaller curvature; larger and larger orthogonal circles get closer and closer to the center of the given circle. Thus, this sequence of circles, as they say, "tend toward" a straight line through the given circle's center. It's sometimes philosophically helpful to consider a line to be a circle, just one of infinite radius. (A number of theorems become easier to state.) In that sense, the "largest circle" is that line through the center.
1
Thanks You for your answer!
– user472374
Jul 28 at 4:36
add a comment |Â
up vote
1
down vote
For any (true) circle orthogonal to a given circle, you can always find a larger one, with ever-more of the given circle's circumference on its "convex side". So, there is no "largest" (true) circle.
Now, larger and larger circles have smaller and smaller curvature; larger and larger orthogonal circles get closer and closer to the center of the given circle. Thus, this sequence of circles, as they say, "tend toward" a straight line through the given circle's center. It's sometimes philosophically helpful to consider a line to be a circle, just one of infinite radius. (A number of theorems become easier to state.) In that sense, the "largest circle" is that line through the center.
1
Thanks You for your answer!
– user472374
Jul 28 at 4:36
add a comment |Â
up vote
1
down vote
up vote
1
down vote
For any (true) circle orthogonal to a given circle, you can always find a larger one, with ever-more of the given circle's circumference on its "convex side". So, there is no "largest" (true) circle.
Now, larger and larger circles have smaller and smaller curvature; larger and larger orthogonal circles get closer and closer to the center of the given circle. Thus, this sequence of circles, as they say, "tend toward" a straight line through the given circle's center. It's sometimes philosophically helpful to consider a line to be a circle, just one of infinite radius. (A number of theorems become easier to state.) In that sense, the "largest circle" is that line through the center.
For any (true) circle orthogonal to a given circle, you can always find a larger one, with ever-more of the given circle's circumference on its "convex side". So, there is no "largest" (true) circle.
Now, larger and larger circles have smaller and smaller curvature; larger and larger orthogonal circles get closer and closer to the center of the given circle. Thus, this sequence of circles, as they say, "tend toward" a straight line through the given circle's center. It's sometimes philosophically helpful to consider a line to be a circle, just one of infinite radius. (A number of theorems become easier to state.) In that sense, the "largest circle" is that line through the center.
answered Jul 28 at 4:35


Blue
43.6k868141
43.6k868141
1
Thanks You for your answer!
– user472374
Jul 28 at 4:36
add a comment |Â
1
Thanks You for your answer!
– user472374
Jul 28 at 4:36
1
1
Thanks You for your answer!
– user472374
Jul 28 at 4:36
Thanks You for your answer!
– user472374
Jul 28 at 4:36
add a comment |Â
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1
no upper bound.
– Will Jagy
Jul 28 at 3:26
@WillJagy what if I change the definition of theâ€Âlargest circle†to the circle that spans the longest section of the circumference on it’s convex side
– user472374
Jul 28 at 3:27
@WillJagy i can’t wrap my head around NO UPPER BOUND, rather intuitively, I speculate NO LOWER BOUND
– user472374
Jul 28 at 3:37
@user472374: The "largest orthogonal circle" is a straight line through the center. For any other orthogonal circle-circle you may have, there's a larger orthogonal circle-circle (which has less curvature and is therefore closer to being a straight line). This is what WillJagy means by "no upper bound".
– Blue
Jul 28 at 3:37
@Blue Yeah, I get it now
– user472374
Jul 28 at 4:30