2nd Point of Sector that lies on Circle on a 2D coordinate plane?

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Hey can anyone help in finding the second coordinate of sector that lies on circle.



I have a circle of radius 10 units, centred at (0,0). I am parting a sector of angle theta(sector can be minor or major). I have coordinate of First points of sector that lie on circle wanna find other points.



How to achieve that?



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  • Please recall that if the OP is solved you can evaluate to accept an answer among the given, more details here meta.stackexchange.com/questions/5234/…
    – gimusi
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up vote
0
down vote

favorite












Hey can anyone help in finding the second coordinate of sector that lies on circle.



I have a circle of radius 10 units, centred at (0,0). I am parting a sector of angle theta(sector can be minor or major). I have coordinate of First points of sector that lie on circle wanna find other points.



How to achieve that?



enter image description here







share|cite|improve this question





















  • Please recall that if the OP is solved you can evaluate to accept an answer among the given, more details here meta.stackexchange.com/questions/5234/…
    – gimusi
    yesterday












up vote
0
down vote

favorite









up vote
0
down vote

favorite











Hey can anyone help in finding the second coordinate of sector that lies on circle.



I have a circle of radius 10 units, centred at (0,0). I am parting a sector of angle theta(sector can be minor or major). I have coordinate of First points of sector that lie on circle wanna find other points.



How to achieve that?



enter image description here







share|cite|improve this question













Hey can anyone help in finding the second coordinate of sector that lies on circle.



I have a circle of radius 10 units, centred at (0,0). I am parting a sector of angle theta(sector can be minor or major). I have coordinate of First points of sector that lie on circle wanna find other points.



How to achieve that?



enter image description here









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 26 at 8:17









José Carlos Santos

113k1696174




113k1696174









asked Jul 26 at 8:10









NMahendroo

1




1











  • Please recall that if the OP is solved you can evaluate to accept an answer among the given, more details here meta.stackexchange.com/questions/5234/…
    – gimusi
    yesterday
















  • Please recall that if the OP is solved you can evaluate to accept an answer among the given, more details here meta.stackexchange.com/questions/5234/…
    – gimusi
    yesterday















Please recall that if the OP is solved you can evaluate to accept an answer among the given, more details here meta.stackexchange.com/questions/5234/…
– gimusi
yesterday




Please recall that if the OP is solved you can evaluate to accept an answer among the given, more details here meta.stackexchange.com/questions/5234/…
– gimusi
yesterday










1 Answer
1






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up vote
0
down vote













Let use polar coordinates, then



  • $x=Rsin theta$

  • $y=Rcos theta$

indeed for



  • $theta=0$ we have the point $(0,R)$


  • $theta=pi/2$ we have the point $(R,0)$


and so on.






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  • Thanks for the fast reply, it helped me.
    – NMahendroo
    Jul 26 at 11:20










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
0
down vote













Let use polar coordinates, then



  • $x=Rsin theta$

  • $y=Rcos theta$

indeed for



  • $theta=0$ we have the point $(0,R)$


  • $theta=pi/2$ we have the point $(R,0)$


and so on.






share|cite|improve this answer





















  • Thanks for the fast reply, it helped me.
    – NMahendroo
    Jul 26 at 11:20














up vote
0
down vote













Let use polar coordinates, then



  • $x=Rsin theta$

  • $y=Rcos theta$

indeed for



  • $theta=0$ we have the point $(0,R)$


  • $theta=pi/2$ we have the point $(R,0)$


and so on.






share|cite|improve this answer





















  • Thanks for the fast reply, it helped me.
    – NMahendroo
    Jul 26 at 11:20












up vote
0
down vote










up vote
0
down vote









Let use polar coordinates, then



  • $x=Rsin theta$

  • $y=Rcos theta$

indeed for



  • $theta=0$ we have the point $(0,R)$


  • $theta=pi/2$ we have the point $(R,0)$


and so on.






share|cite|improve this answer













Let use polar coordinates, then



  • $x=Rsin theta$

  • $y=Rcos theta$

indeed for



  • $theta=0$ we have the point $(0,R)$


  • $theta=pi/2$ we have the point $(R,0)$


and so on.







share|cite|improve this answer













share|cite|improve this answer



share|cite|improve this answer











answered Jul 26 at 8:13









gimusi

65k73583




65k73583











  • Thanks for the fast reply, it helped me.
    – NMahendroo
    Jul 26 at 11:20
















  • Thanks for the fast reply, it helped me.
    – NMahendroo
    Jul 26 at 11:20















Thanks for the fast reply, it helped me.
– NMahendroo
Jul 26 at 11:20




Thanks for the fast reply, it helped me.
– NMahendroo
Jul 26 at 11:20












 

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