Expressing a function in terms of another

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I know this is a very nonsense question. But, it has become challenging for me to visualize. I have two functions as seen following:



$$rho=sum_jin Jfraclambda_jmu_j$$
and
$$theta=sum_jin Jfraclambda_jmu_j^2$$



Is there any way to express $theta$ in terms of $rho$ or vice versa?







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  • 1




    I would say, "No." How would you express $frac1a+frac1b$ in terms of $frac1a^2+frac1b^2?$
    – saulspatz
    Jul 25 at 16:18










  • I also said, "No" and that's why I wanted to get more opinions. On the other hand, it seems, I can write $theta = sum_jin Jfraclambda_jmu_jfrac1mu_j stackrel?= frac1mu_jsum_jin Jfraclambda_jmu_j$. Then, what is gonna happen with $frac1mu_j$?
    – user8028576
    Jul 25 at 16:24











  • You can't pull $1/u_j$ out of the summation sign. Its value is different in every term of the sum.
    – saulspatz
    Jul 25 at 16:28










  • @saulspatz, I am well aware of that. Just trying to put here something to get help if there is any possible way of doing that.
    – user8028576
    Jul 25 at 16:30










  • My best attempt: $$theta= - sum_j in J fracpartialpartial mu_j rho$$ but it's really not easier than just writing $$theta = sum_j in J fraclambda_jmu_j^2.$$
    – md2perpe
    Jul 25 at 18:29















up vote
0
down vote

favorite












I know this is a very nonsense question. But, it has become challenging for me to visualize. I have two functions as seen following:



$$rho=sum_jin Jfraclambda_jmu_j$$
and
$$theta=sum_jin Jfraclambda_jmu_j^2$$



Is there any way to express $theta$ in terms of $rho$ or vice versa?







share|cite|improve this question

















  • 1




    I would say, "No." How would you express $frac1a+frac1b$ in terms of $frac1a^2+frac1b^2?$
    – saulspatz
    Jul 25 at 16:18










  • I also said, "No" and that's why I wanted to get more opinions. On the other hand, it seems, I can write $theta = sum_jin Jfraclambda_jmu_jfrac1mu_j stackrel?= frac1mu_jsum_jin Jfraclambda_jmu_j$. Then, what is gonna happen with $frac1mu_j$?
    – user8028576
    Jul 25 at 16:24











  • You can't pull $1/u_j$ out of the summation sign. Its value is different in every term of the sum.
    – saulspatz
    Jul 25 at 16:28










  • @saulspatz, I am well aware of that. Just trying to put here something to get help if there is any possible way of doing that.
    – user8028576
    Jul 25 at 16:30










  • My best attempt: $$theta= - sum_j in J fracpartialpartial mu_j rho$$ but it's really not easier than just writing $$theta = sum_j in J fraclambda_jmu_j^2.$$
    – md2perpe
    Jul 25 at 18:29













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I know this is a very nonsense question. But, it has become challenging for me to visualize. I have two functions as seen following:



$$rho=sum_jin Jfraclambda_jmu_j$$
and
$$theta=sum_jin Jfraclambda_jmu_j^2$$



Is there any way to express $theta$ in terms of $rho$ or vice versa?







share|cite|improve this question













I know this is a very nonsense question. But, it has become challenging for me to visualize. I have two functions as seen following:



$$rho=sum_jin Jfraclambda_jmu_j$$
and
$$theta=sum_jin Jfraclambda_jmu_j^2$$



Is there any way to express $theta$ in terms of $rho$ or vice versa?









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 25 at 16:38
























asked Jul 25 at 16:14









user8028576

277




277







  • 1




    I would say, "No." How would you express $frac1a+frac1b$ in terms of $frac1a^2+frac1b^2?$
    – saulspatz
    Jul 25 at 16:18










  • I also said, "No" and that's why I wanted to get more opinions. On the other hand, it seems, I can write $theta = sum_jin Jfraclambda_jmu_jfrac1mu_j stackrel?= frac1mu_jsum_jin Jfraclambda_jmu_j$. Then, what is gonna happen with $frac1mu_j$?
    – user8028576
    Jul 25 at 16:24











  • You can't pull $1/u_j$ out of the summation sign. Its value is different in every term of the sum.
    – saulspatz
    Jul 25 at 16:28










  • @saulspatz, I am well aware of that. Just trying to put here something to get help if there is any possible way of doing that.
    – user8028576
    Jul 25 at 16:30










  • My best attempt: $$theta= - sum_j in J fracpartialpartial mu_j rho$$ but it's really not easier than just writing $$theta = sum_j in J fraclambda_jmu_j^2.$$
    – md2perpe
    Jul 25 at 18:29













  • 1




    I would say, "No." How would you express $frac1a+frac1b$ in terms of $frac1a^2+frac1b^2?$
    – saulspatz
    Jul 25 at 16:18










  • I also said, "No" and that's why I wanted to get more opinions. On the other hand, it seems, I can write $theta = sum_jin Jfraclambda_jmu_jfrac1mu_j stackrel?= frac1mu_jsum_jin Jfraclambda_jmu_j$. Then, what is gonna happen with $frac1mu_j$?
    – user8028576
    Jul 25 at 16:24











  • You can't pull $1/u_j$ out of the summation sign. Its value is different in every term of the sum.
    – saulspatz
    Jul 25 at 16:28










  • @saulspatz, I am well aware of that. Just trying to put here something to get help if there is any possible way of doing that.
    – user8028576
    Jul 25 at 16:30










  • My best attempt: $$theta= - sum_j in J fracpartialpartial mu_j rho$$ but it's really not easier than just writing $$theta = sum_j in J fraclambda_jmu_j^2.$$
    – md2perpe
    Jul 25 at 18:29








1




1




I would say, "No." How would you express $frac1a+frac1b$ in terms of $frac1a^2+frac1b^2?$
– saulspatz
Jul 25 at 16:18




I would say, "No." How would you express $frac1a+frac1b$ in terms of $frac1a^2+frac1b^2?$
– saulspatz
Jul 25 at 16:18












I also said, "No" and that's why I wanted to get more opinions. On the other hand, it seems, I can write $theta = sum_jin Jfraclambda_jmu_jfrac1mu_j stackrel?= frac1mu_jsum_jin Jfraclambda_jmu_j$. Then, what is gonna happen with $frac1mu_j$?
– user8028576
Jul 25 at 16:24





I also said, "No" and that's why I wanted to get more opinions. On the other hand, it seems, I can write $theta = sum_jin Jfraclambda_jmu_jfrac1mu_j stackrel?= frac1mu_jsum_jin Jfraclambda_jmu_j$. Then, what is gonna happen with $frac1mu_j$?
– user8028576
Jul 25 at 16:24













You can't pull $1/u_j$ out of the summation sign. Its value is different in every term of the sum.
– saulspatz
Jul 25 at 16:28




You can't pull $1/u_j$ out of the summation sign. Its value is different in every term of the sum.
– saulspatz
Jul 25 at 16:28












@saulspatz, I am well aware of that. Just trying to put here something to get help if there is any possible way of doing that.
– user8028576
Jul 25 at 16:30




@saulspatz, I am well aware of that. Just trying to put here something to get help if there is any possible way of doing that.
– user8028576
Jul 25 at 16:30












My best attempt: $$theta= - sum_j in J fracpartialpartial mu_j rho$$ but it's really not easier than just writing $$theta = sum_j in J fraclambda_jmu_j^2.$$
– md2perpe
Jul 25 at 18:29





My best attempt: $$theta= - sum_j in J fracpartialpartial mu_j rho$$ but it's really not easier than just writing $$theta = sum_j in J fraclambda_jmu_j^2.$$
– md2perpe
Jul 25 at 18:29
















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