Can anyone help with find the properties associated with $prod$ of product [closed]

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I can easily find some commonly used properties of $displaystylesum $ but I can't seem to find anything about commonly known formulas of $displaystyleprod$ except $displaystyleprod_i=1^n i = n! $



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closed as unclear what you're asking by mathcounterexamples.net, Claudius, Did, Delta-u, Isaac Browne Jul 26 at 22:31


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.














  • Can you precise what you're looking for? Finite products? Infinite products? General algebraic properties?
    – mathcounterexamples.net
    Jul 26 at 9:48











  • @mathcounterexamples.net you know... The basic ones like we have for sigma i and i^2 and i^3 .... The ones that are a "must know"
    – William
    Jul 26 at 9:51














up vote
-1
down vote

favorite












I can easily find some commonly used properties of $displaystylesum $ but I can't seem to find anything about commonly known formulas of $displaystyleprod$ except $displaystyleprod_i=1^n i = n! $



Thanks! Also do let me know what did you type in the search bar.







share|cite|improve this question













closed as unclear what you're asking by mathcounterexamples.net, Claudius, Did, Delta-u, Isaac Browne Jul 26 at 22:31


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.














  • Can you precise what you're looking for? Finite products? Infinite products? General algebraic properties?
    – mathcounterexamples.net
    Jul 26 at 9:48











  • @mathcounterexamples.net you know... The basic ones like we have for sigma i and i^2 and i^3 .... The ones that are a "must know"
    – William
    Jul 26 at 9:51












up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











I can easily find some commonly used properties of $displaystylesum $ but I can't seem to find anything about commonly known formulas of $displaystyleprod$ except $displaystyleprod_i=1^n i = n! $



Thanks! Also do let me know what did you type in the search bar.







share|cite|improve this question













I can easily find some commonly used properties of $displaystylesum $ but I can't seem to find anything about commonly known formulas of $displaystyleprod$ except $displaystyleprod_i=1^n i = n! $



Thanks! Also do let me know what did you type in the search bar.









share|cite|improve this question












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share|cite|improve this question








edited Jul 26 at 18:10









Daniel Buck

2,3041623




2,3041623









asked Jul 26 at 9:43









William

731214




731214




closed as unclear what you're asking by mathcounterexamples.net, Claudius, Did, Delta-u, Isaac Browne Jul 26 at 22:31


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.






closed as unclear what you're asking by mathcounterexamples.net, Claudius, Did, Delta-u, Isaac Browne Jul 26 at 22:31


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.













  • Can you precise what you're looking for? Finite products? Infinite products? General algebraic properties?
    – mathcounterexamples.net
    Jul 26 at 9:48











  • @mathcounterexamples.net you know... The basic ones like we have for sigma i and i^2 and i^3 .... The ones that are a "must know"
    – William
    Jul 26 at 9:51
















  • Can you precise what you're looking for? Finite products? Infinite products? General algebraic properties?
    – mathcounterexamples.net
    Jul 26 at 9:48











  • @mathcounterexamples.net you know... The basic ones like we have for sigma i and i^2 and i^3 .... The ones that are a "must know"
    – William
    Jul 26 at 9:51















Can you precise what you're looking for? Finite products? Infinite products? General algebraic properties?
– mathcounterexamples.net
Jul 26 at 9:48





Can you precise what you're looking for? Finite products? Infinite products? General algebraic properties?
– mathcounterexamples.net
Jul 26 at 9:48













@mathcounterexamples.net you know... The basic ones like we have for sigma i and i^2 and i^3 .... The ones that are a "must know"
– William
Jul 26 at 9:51




@mathcounterexamples.net you know... The basic ones like we have for sigma i and i^2 and i^3 .... The ones that are a "must know"
– William
Jul 26 at 9:51










3 Answers
3






active

oldest

votes

















up vote
1
down vote













$$
logprod ?=sumlog,?
$$
allows you to transfer properties of summations to products.






share|cite|improve this answer






























    up vote
    1
    down vote













    Examples: The Wallis Product for $pi.$ And Euler's product $sinpi x=pi x prod_n=1^infty(1-x^2/n^2).$ Neither of these is easy to prove. See "Wallis product" in Wikipedia.



    A useful theorem, which you can find (for example) in the old classic Infinite Sequences And Series, by Bromwich:



    (1). If $a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1+a_n)$ converges.



    (2). If $1>a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1-a_n)>0.$



    Euler used (2) to show that $sum_pin P;(1/p)=infty,$ where $P$ is the set of primes (and an immediate corollary, a proof that $P$ is infinite, obtained by analytic methods), as follows:



    For $2leq Min Bbb N$ let $P(M)$ be the set of primes that are not more than $M.$ We have $$prod_pin P(1-1/p)^-1geq prod_pin P(M)(1-1/p)^-1=$$ $$=prod_pin P(M)(sum_j=0^inftyp^-j)>$$ $$>prod_pin P(M)(sum_j=0^Mp^-j).$$ Now if the last expression above is completely expanded, every $n^-1$ for $1leq nleq M$ will appear at least once as a term (Exactly once, actually, because of unique prime decomposition). There will generally be a whole lot of other terms as well. So for every $Mgeq 2 $ we have $$prod_pin P(1-1/p)^-1>sum_n=1^Mn^-1.$$ But since $sum_n=1^inftyn^-1$ diverges we must have $prod_pin P;(1-1/p)^-1=infty, $ so $prod_pin P;(1-1/p)=0.$ By (2), therefore $sum_pin P;(1/p) =infty.$






    share|cite|improve this answer























    • The Bromwich book can be read without any pre-requisites.
      – DanielWainfleet
      Jul 26 at 20:00

















    up vote
    0
    down vote













    One key word is "finite products". Some hints are given in introductory combinatorics books, e.g. in the following books.



    Riordan, J.: An Introduction to Combinatorial Analysis. Princeton University Press, 1958



    Comtet, L.: Advanced Combinatorics: The Art of Finite and Innite Expansions.
    Reidel, 1974



    Graham, R. L.; Knuth, D. E.; Patashnik, O.: Concrete Mathematics: A Foundation for Computer Science. Addison-Wesley, 1994



    Charalambides, Ch. A.: Enumerative combinatorics. CRC Press, 2002






    share|cite|improve this answer




























      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      1
      down vote













      $$
      logprod ?=sumlog,?
      $$
      allows you to transfer properties of summations to products.






      share|cite|improve this answer



























        up vote
        1
        down vote













        $$
        logprod ?=sumlog,?
        $$
        allows you to transfer properties of summations to products.






        share|cite|improve this answer

























          up vote
          1
          down vote










          up vote
          1
          down vote









          $$
          logprod ?=sumlog,?
          $$
          allows you to transfer properties of summations to products.






          share|cite|improve this answer















          $$
          logprod ?=sumlog,?
          $$
          allows you to transfer properties of summations to products.







          share|cite|improve this answer















          share|cite|improve this answer



          share|cite|improve this answer








          edited Jul 26 at 17:47


























          answered Jul 26 at 12:59









          Yves Daoust

          111k665203




          111k665203




















              up vote
              1
              down vote













              Examples: The Wallis Product for $pi.$ And Euler's product $sinpi x=pi x prod_n=1^infty(1-x^2/n^2).$ Neither of these is easy to prove. See "Wallis product" in Wikipedia.



              A useful theorem, which you can find (for example) in the old classic Infinite Sequences And Series, by Bromwich:



              (1). If $a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1+a_n)$ converges.



              (2). If $1>a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1-a_n)>0.$



              Euler used (2) to show that $sum_pin P;(1/p)=infty,$ where $P$ is the set of primes (and an immediate corollary, a proof that $P$ is infinite, obtained by analytic methods), as follows:



              For $2leq Min Bbb N$ let $P(M)$ be the set of primes that are not more than $M.$ We have $$prod_pin P(1-1/p)^-1geq prod_pin P(M)(1-1/p)^-1=$$ $$=prod_pin P(M)(sum_j=0^inftyp^-j)>$$ $$>prod_pin P(M)(sum_j=0^Mp^-j).$$ Now if the last expression above is completely expanded, every $n^-1$ for $1leq nleq M$ will appear at least once as a term (Exactly once, actually, because of unique prime decomposition). There will generally be a whole lot of other terms as well. So for every $Mgeq 2 $ we have $$prod_pin P(1-1/p)^-1>sum_n=1^Mn^-1.$$ But since $sum_n=1^inftyn^-1$ diverges we must have $prod_pin P;(1-1/p)^-1=infty, $ so $prod_pin P;(1-1/p)=0.$ By (2), therefore $sum_pin P;(1/p) =infty.$






              share|cite|improve this answer























              • The Bromwich book can be read without any pre-requisites.
                – DanielWainfleet
                Jul 26 at 20:00














              up vote
              1
              down vote













              Examples: The Wallis Product for $pi.$ And Euler's product $sinpi x=pi x prod_n=1^infty(1-x^2/n^2).$ Neither of these is easy to prove. See "Wallis product" in Wikipedia.



              A useful theorem, which you can find (for example) in the old classic Infinite Sequences And Series, by Bromwich:



              (1). If $a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1+a_n)$ converges.



              (2). If $1>a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1-a_n)>0.$



              Euler used (2) to show that $sum_pin P;(1/p)=infty,$ where $P$ is the set of primes (and an immediate corollary, a proof that $P$ is infinite, obtained by analytic methods), as follows:



              For $2leq Min Bbb N$ let $P(M)$ be the set of primes that are not more than $M.$ We have $$prod_pin P(1-1/p)^-1geq prod_pin P(M)(1-1/p)^-1=$$ $$=prod_pin P(M)(sum_j=0^inftyp^-j)>$$ $$>prod_pin P(M)(sum_j=0^Mp^-j).$$ Now if the last expression above is completely expanded, every $n^-1$ for $1leq nleq M$ will appear at least once as a term (Exactly once, actually, because of unique prime decomposition). There will generally be a whole lot of other terms as well. So for every $Mgeq 2 $ we have $$prod_pin P(1-1/p)^-1>sum_n=1^Mn^-1.$$ But since $sum_n=1^inftyn^-1$ diverges we must have $prod_pin P;(1-1/p)^-1=infty, $ so $prod_pin P;(1-1/p)=0.$ By (2), therefore $sum_pin P;(1/p) =infty.$






              share|cite|improve this answer























              • The Bromwich book can be read without any pre-requisites.
                – DanielWainfleet
                Jul 26 at 20:00












              up vote
              1
              down vote










              up vote
              1
              down vote









              Examples: The Wallis Product for $pi.$ And Euler's product $sinpi x=pi x prod_n=1^infty(1-x^2/n^2).$ Neither of these is easy to prove. See "Wallis product" in Wikipedia.



              A useful theorem, which you can find (for example) in the old classic Infinite Sequences And Series, by Bromwich:



              (1). If $a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1+a_n)$ converges.



              (2). If $1>a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1-a_n)>0.$



              Euler used (2) to show that $sum_pin P;(1/p)=infty,$ where $P$ is the set of primes (and an immediate corollary, a proof that $P$ is infinite, obtained by analytic methods), as follows:



              For $2leq Min Bbb N$ let $P(M)$ be the set of primes that are not more than $M.$ We have $$prod_pin P(1-1/p)^-1geq prod_pin P(M)(1-1/p)^-1=$$ $$=prod_pin P(M)(sum_j=0^inftyp^-j)>$$ $$>prod_pin P(M)(sum_j=0^Mp^-j).$$ Now if the last expression above is completely expanded, every $n^-1$ for $1leq nleq M$ will appear at least once as a term (Exactly once, actually, because of unique prime decomposition). There will generally be a whole lot of other terms as well. So for every $Mgeq 2 $ we have $$prod_pin P(1-1/p)^-1>sum_n=1^Mn^-1.$$ But since $sum_n=1^inftyn^-1$ diverges we must have $prod_pin P;(1-1/p)^-1=infty, $ so $prod_pin P;(1-1/p)=0.$ By (2), therefore $sum_pin P;(1/p) =infty.$






              share|cite|improve this answer















              Examples: The Wallis Product for $pi.$ And Euler's product $sinpi x=pi x prod_n=1^infty(1-x^2/n^2).$ Neither of these is easy to prove. See "Wallis product" in Wikipedia.



              A useful theorem, which you can find (for example) in the old classic Infinite Sequences And Series, by Bromwich:



              (1). If $a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1+a_n)$ converges.



              (2). If $1>a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1-a_n)>0.$



              Euler used (2) to show that $sum_pin P;(1/p)=infty,$ where $P$ is the set of primes (and an immediate corollary, a proof that $P$ is infinite, obtained by analytic methods), as follows:



              For $2leq Min Bbb N$ let $P(M)$ be the set of primes that are not more than $M.$ We have $$prod_pin P(1-1/p)^-1geq prod_pin P(M)(1-1/p)^-1=$$ $$=prod_pin P(M)(sum_j=0^inftyp^-j)>$$ $$>prod_pin P(M)(sum_j=0^Mp^-j).$$ Now if the last expression above is completely expanded, every $n^-1$ for $1leq nleq M$ will appear at least once as a term (Exactly once, actually, because of unique prime decomposition). There will generally be a whole lot of other terms as well. So for every $Mgeq 2 $ we have $$prod_pin P(1-1/p)^-1>sum_n=1^Mn^-1.$$ But since $sum_n=1^inftyn^-1$ diverges we must have $prod_pin P;(1-1/p)^-1=infty, $ so $prod_pin P;(1-1/p)=0.$ By (2), therefore $sum_pin P;(1/p) =infty.$







              share|cite|improve this answer















              share|cite|improve this answer



              share|cite|improve this answer








              edited Jul 26 at 20:03


























              answered Jul 26 at 19:52









              DanielWainfleet

              31.5k31542




              31.5k31542











              • The Bromwich book can be read without any pre-requisites.
                – DanielWainfleet
                Jul 26 at 20:00
















              • The Bromwich book can be read without any pre-requisites.
                – DanielWainfleet
                Jul 26 at 20:00















              The Bromwich book can be read without any pre-requisites.
              – DanielWainfleet
              Jul 26 at 20:00




              The Bromwich book can be read without any pre-requisites.
              – DanielWainfleet
              Jul 26 at 20:00










              up vote
              0
              down vote













              One key word is "finite products". Some hints are given in introductory combinatorics books, e.g. in the following books.



              Riordan, J.: An Introduction to Combinatorial Analysis. Princeton University Press, 1958



              Comtet, L.: Advanced Combinatorics: The Art of Finite and Innite Expansions.
              Reidel, 1974



              Graham, R. L.; Knuth, D. E.; Patashnik, O.: Concrete Mathematics: A Foundation for Computer Science. Addison-Wesley, 1994



              Charalambides, Ch. A.: Enumerative combinatorics. CRC Press, 2002






              share|cite|improve this answer

























                up vote
                0
                down vote













                One key word is "finite products". Some hints are given in introductory combinatorics books, e.g. in the following books.



                Riordan, J.: An Introduction to Combinatorial Analysis. Princeton University Press, 1958



                Comtet, L.: Advanced Combinatorics: The Art of Finite and Innite Expansions.
                Reidel, 1974



                Graham, R. L.; Knuth, D. E.; Patashnik, O.: Concrete Mathematics: A Foundation for Computer Science. Addison-Wesley, 1994



                Charalambides, Ch. A.: Enumerative combinatorics. CRC Press, 2002






                share|cite|improve this answer























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  One key word is "finite products". Some hints are given in introductory combinatorics books, e.g. in the following books.



                  Riordan, J.: An Introduction to Combinatorial Analysis. Princeton University Press, 1958



                  Comtet, L.: Advanced Combinatorics: The Art of Finite and Innite Expansions.
                  Reidel, 1974



                  Graham, R. L.; Knuth, D. E.; Patashnik, O.: Concrete Mathematics: A Foundation for Computer Science. Addison-Wesley, 1994



                  Charalambides, Ch. A.: Enumerative combinatorics. CRC Press, 2002






                  share|cite|improve this answer













                  One key word is "finite products". Some hints are given in introductory combinatorics books, e.g. in the following books.



                  Riordan, J.: An Introduction to Combinatorial Analysis. Princeton University Press, 1958



                  Comtet, L.: Advanced Combinatorics: The Art of Finite and Innite Expansions.
                  Reidel, 1974



                  Graham, R. L.; Knuth, D. E.; Patashnik, O.: Concrete Mathematics: A Foundation for Computer Science. Addison-Wesley, 1994



                  Charalambides, Ch. A.: Enumerative combinatorics. CRC Press, 2002







                  share|cite|improve this answer













                  share|cite|improve this answer



                  share|cite|improve this answer











                  answered Jul 26 at 12:39









                  IV_

                  940221




                  940221












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