Can anyone help with find the properties associated with $prod$ of product [closed]
Clash Royale CLAN TAG#URR8PPP
up vote
-1
down vote
favorite
I can easily find some commonly used properties of $displaystylesum $ but I can't seem to find anything about commonly known formulas of $displaystyleprod$ except $displaystyleprod_i=1^n i = n! $
Thanks! Also do let me know what did you type in the search bar.
products infinite-product
closed as unclear what you're asking by mathcounterexamples.net, Claudius, Did, Delta-u, Isaac Browne Jul 26 at 22:31
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |Â
up vote
-1
down vote
favorite
I can easily find some commonly used properties of $displaystylesum $ but I can't seem to find anything about commonly known formulas of $displaystyleprod$ except $displaystyleprod_i=1^n i = n! $
Thanks! Also do let me know what did you type in the search bar.
products infinite-product
closed as unclear what you're asking by mathcounterexamples.net, Claudius, Did, Delta-u, Isaac Browne Jul 26 at 22:31
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
Can you precise what you're looking for? Finite products? Infinite products? General algebraic properties?
– mathcounterexamples.net
Jul 26 at 9:48
@mathcounterexamples.net you know... The basic ones like we have for sigma i and i^2 and i^3 .... The ones that are a "must know"
– William
Jul 26 at 9:51
add a comment |Â
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
I can easily find some commonly used properties of $displaystylesum $ but I can't seem to find anything about commonly known formulas of $displaystyleprod$ except $displaystyleprod_i=1^n i = n! $
Thanks! Also do let me know what did you type in the search bar.
products infinite-product
I can easily find some commonly used properties of $displaystylesum $ but I can't seem to find anything about commonly known formulas of $displaystyleprod$ except $displaystyleprod_i=1^n i = n! $
Thanks! Also do let me know what did you type in the search bar.
products infinite-product
edited Jul 26 at 18:10
Daniel Buck
2,3041623
2,3041623
asked Jul 26 at 9:43
William
731214
731214
closed as unclear what you're asking by mathcounterexamples.net, Claudius, Did, Delta-u, Isaac Browne Jul 26 at 22:31
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
closed as unclear what you're asking by mathcounterexamples.net, Claudius, Did, Delta-u, Isaac Browne Jul 26 at 22:31
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
Can you precise what you're looking for? Finite products? Infinite products? General algebraic properties?
– mathcounterexamples.net
Jul 26 at 9:48
@mathcounterexamples.net you know... The basic ones like we have for sigma i and i^2 and i^3 .... The ones that are a "must know"
– William
Jul 26 at 9:51
add a comment |Â
Can you precise what you're looking for? Finite products? Infinite products? General algebraic properties?
– mathcounterexamples.net
Jul 26 at 9:48
@mathcounterexamples.net you know... The basic ones like we have for sigma i and i^2 and i^3 .... The ones that are a "must know"
– William
Jul 26 at 9:51
Can you precise what you're looking for? Finite products? Infinite products? General algebraic properties?
– mathcounterexamples.net
Jul 26 at 9:48
Can you precise what you're looking for? Finite products? Infinite products? General algebraic properties?
– mathcounterexamples.net
Jul 26 at 9:48
@mathcounterexamples.net you know... The basic ones like we have for sigma i and i^2 and i^3 .... The ones that are a "must know"
– William
Jul 26 at 9:51
@mathcounterexamples.net you know... The basic ones like we have for sigma i and i^2 and i^3 .... The ones that are a "must know"
– William
Jul 26 at 9:51
add a comment |Â
3 Answers
3
active
oldest
votes
up vote
1
down vote
$$
logprod ?=sumlog,?
$$
allows you to transfer properties of summations to products.
add a comment |Â
up vote
1
down vote
Examples: The Wallis Product for $pi.$ And Euler's product $sinpi x=pi x prod_n=1^infty(1-x^2/n^2).$ Neither of these is easy to prove. See "Wallis product" in Wikipedia.
A useful theorem, which you can find (for example) in the old classic Infinite Sequences And Series, by Bromwich:
(1). If $a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1+a_n)$ converges.
(2). If $1>a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1-a_n)>0.$
Euler used (2) to show that $sum_pin P;(1/p)=infty,$ where $P$ is the set of primes (and an immediate corollary, a proof that $P$ is infinite, obtained by analytic methods), as follows:
For $2leq Min Bbb N$ let $P(M)$ be the set of primes that are not more than $M.$ We have $$prod_pin P(1-1/p)^-1geq prod_pin P(M)(1-1/p)^-1=$$ $$=prod_pin P(M)(sum_j=0^inftyp^-j)>$$ $$>prod_pin P(M)(sum_j=0^Mp^-j).$$ Now if the last expression above is completely expanded, every $n^-1$ for $1leq nleq M$ will appear at least once as a term (Exactly once, actually, because of unique prime decomposition). There will generally be a whole lot of other terms as well. So for every $Mgeq 2 $ we have $$prod_pin P(1-1/p)^-1>sum_n=1^Mn^-1.$$ But since $sum_n=1^inftyn^-1$ diverges we must have $prod_pin P;(1-1/p)^-1=infty, $ so $prod_pin P;(1-1/p)=0.$ By (2), therefore $sum_pin P;(1/p) =infty.$
The Bromwich book can be read without any pre-requisites.
– DanielWainfleet
Jul 26 at 20:00
add a comment |Â
up vote
0
down vote
One key word is "finite products". Some hints are given in introductory combinatorics books, e.g. in the following books.
Riordan, J.: An Introduction to Combinatorial Analysis. Princeton University Press, 1958
Comtet, L.: Advanced Combinatorics: The Art of Finite and Innite Expansions.
Reidel, 1974
Graham, R. L.; Knuth, D. E.; Patashnik, O.: Concrete Mathematics: A Foundation for Computer Science. Addison-Wesley, 1994
Charalambides, Ch. A.: Enumerative combinatorics. CRC Press, 2002
add a comment |Â
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
$$
logprod ?=sumlog,?
$$
allows you to transfer properties of summations to products.
add a comment |Â
up vote
1
down vote
$$
logprod ?=sumlog,?
$$
allows you to transfer properties of summations to products.
add a comment |Â
up vote
1
down vote
up vote
1
down vote
$$
logprod ?=sumlog,?
$$
allows you to transfer properties of summations to products.
$$
logprod ?=sumlog,?
$$
allows you to transfer properties of summations to products.
edited Jul 26 at 17:47
answered Jul 26 at 12:59
Yves Daoust
111k665203
111k665203
add a comment |Â
add a comment |Â
up vote
1
down vote
Examples: The Wallis Product for $pi.$ And Euler's product $sinpi x=pi x prod_n=1^infty(1-x^2/n^2).$ Neither of these is easy to prove. See "Wallis product" in Wikipedia.
A useful theorem, which you can find (for example) in the old classic Infinite Sequences And Series, by Bromwich:
(1). If $a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1+a_n)$ converges.
(2). If $1>a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1-a_n)>0.$
Euler used (2) to show that $sum_pin P;(1/p)=infty,$ where $P$ is the set of primes (and an immediate corollary, a proof that $P$ is infinite, obtained by analytic methods), as follows:
For $2leq Min Bbb N$ let $P(M)$ be the set of primes that are not more than $M.$ We have $$prod_pin P(1-1/p)^-1geq prod_pin P(M)(1-1/p)^-1=$$ $$=prod_pin P(M)(sum_j=0^inftyp^-j)>$$ $$>prod_pin P(M)(sum_j=0^Mp^-j).$$ Now if the last expression above is completely expanded, every $n^-1$ for $1leq nleq M$ will appear at least once as a term (Exactly once, actually, because of unique prime decomposition). There will generally be a whole lot of other terms as well. So for every $Mgeq 2 $ we have $$prod_pin P(1-1/p)^-1>sum_n=1^Mn^-1.$$ But since $sum_n=1^inftyn^-1$ diverges we must have $prod_pin P;(1-1/p)^-1=infty, $ so $prod_pin P;(1-1/p)=0.$ By (2), therefore $sum_pin P;(1/p) =infty.$
The Bromwich book can be read without any pre-requisites.
– DanielWainfleet
Jul 26 at 20:00
add a comment |Â
up vote
1
down vote
Examples: The Wallis Product for $pi.$ And Euler's product $sinpi x=pi x prod_n=1^infty(1-x^2/n^2).$ Neither of these is easy to prove. See "Wallis product" in Wikipedia.
A useful theorem, which you can find (for example) in the old classic Infinite Sequences And Series, by Bromwich:
(1). If $a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1+a_n)$ converges.
(2). If $1>a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1-a_n)>0.$
Euler used (2) to show that $sum_pin P;(1/p)=infty,$ where $P$ is the set of primes (and an immediate corollary, a proof that $P$ is infinite, obtained by analytic methods), as follows:
For $2leq Min Bbb N$ let $P(M)$ be the set of primes that are not more than $M.$ We have $$prod_pin P(1-1/p)^-1geq prod_pin P(M)(1-1/p)^-1=$$ $$=prod_pin P(M)(sum_j=0^inftyp^-j)>$$ $$>prod_pin P(M)(sum_j=0^Mp^-j).$$ Now if the last expression above is completely expanded, every $n^-1$ for $1leq nleq M$ will appear at least once as a term (Exactly once, actually, because of unique prime decomposition). There will generally be a whole lot of other terms as well. So for every $Mgeq 2 $ we have $$prod_pin P(1-1/p)^-1>sum_n=1^Mn^-1.$$ But since $sum_n=1^inftyn^-1$ diverges we must have $prod_pin P;(1-1/p)^-1=infty, $ so $prod_pin P;(1-1/p)=0.$ By (2), therefore $sum_pin P;(1/p) =infty.$
The Bromwich book can be read without any pre-requisites.
– DanielWainfleet
Jul 26 at 20:00
add a comment |Â
up vote
1
down vote
up vote
1
down vote
Examples: The Wallis Product for $pi.$ And Euler's product $sinpi x=pi x prod_n=1^infty(1-x^2/n^2).$ Neither of these is easy to prove. See "Wallis product" in Wikipedia.
A useful theorem, which you can find (for example) in the old classic Infinite Sequences And Series, by Bromwich:
(1). If $a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1+a_n)$ converges.
(2). If $1>a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1-a_n)>0.$
Euler used (2) to show that $sum_pin P;(1/p)=infty,$ where $P$ is the set of primes (and an immediate corollary, a proof that $P$ is infinite, obtained by analytic methods), as follows:
For $2leq Min Bbb N$ let $P(M)$ be the set of primes that are not more than $M.$ We have $$prod_pin P(1-1/p)^-1geq prod_pin P(M)(1-1/p)^-1=$$ $$=prod_pin P(M)(sum_j=0^inftyp^-j)>$$ $$>prod_pin P(M)(sum_j=0^Mp^-j).$$ Now if the last expression above is completely expanded, every $n^-1$ for $1leq nleq M$ will appear at least once as a term (Exactly once, actually, because of unique prime decomposition). There will generally be a whole lot of other terms as well. So for every $Mgeq 2 $ we have $$prod_pin P(1-1/p)^-1>sum_n=1^Mn^-1.$$ But since $sum_n=1^inftyn^-1$ diverges we must have $prod_pin P;(1-1/p)^-1=infty, $ so $prod_pin P;(1-1/p)=0.$ By (2), therefore $sum_pin P;(1/p) =infty.$
Examples: The Wallis Product for $pi.$ And Euler's product $sinpi x=pi x prod_n=1^infty(1-x^2/n^2).$ Neither of these is easy to prove. See "Wallis product" in Wikipedia.
A useful theorem, which you can find (for example) in the old classic Infinite Sequences And Series, by Bromwich:
(1). If $a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1+a_n)$ converges.
(2). If $1>a_ngeq 0$ for every $n$ then $sum_n=1^inftya_n$ converges iff $prod_n=1^infty(1-a_n)>0.$
Euler used (2) to show that $sum_pin P;(1/p)=infty,$ where $P$ is the set of primes (and an immediate corollary, a proof that $P$ is infinite, obtained by analytic methods), as follows:
For $2leq Min Bbb N$ let $P(M)$ be the set of primes that are not more than $M.$ We have $$prod_pin P(1-1/p)^-1geq prod_pin P(M)(1-1/p)^-1=$$ $$=prod_pin P(M)(sum_j=0^inftyp^-j)>$$ $$>prod_pin P(M)(sum_j=0^Mp^-j).$$ Now if the last expression above is completely expanded, every $n^-1$ for $1leq nleq M$ will appear at least once as a term (Exactly once, actually, because of unique prime decomposition). There will generally be a whole lot of other terms as well. So for every $Mgeq 2 $ we have $$prod_pin P(1-1/p)^-1>sum_n=1^Mn^-1.$$ But since $sum_n=1^inftyn^-1$ diverges we must have $prod_pin P;(1-1/p)^-1=infty, $ so $prod_pin P;(1-1/p)=0.$ By (2), therefore $sum_pin P;(1/p) =infty.$
edited Jul 26 at 20:03
answered Jul 26 at 19:52
DanielWainfleet
31.5k31542
31.5k31542
The Bromwich book can be read without any pre-requisites.
– DanielWainfleet
Jul 26 at 20:00
add a comment |Â
The Bromwich book can be read without any pre-requisites.
– DanielWainfleet
Jul 26 at 20:00
The Bromwich book can be read without any pre-requisites.
– DanielWainfleet
Jul 26 at 20:00
The Bromwich book can be read without any pre-requisites.
– DanielWainfleet
Jul 26 at 20:00
add a comment |Â
up vote
0
down vote
One key word is "finite products". Some hints are given in introductory combinatorics books, e.g. in the following books.
Riordan, J.: An Introduction to Combinatorial Analysis. Princeton University Press, 1958
Comtet, L.: Advanced Combinatorics: The Art of Finite and Innite Expansions.
Reidel, 1974
Graham, R. L.; Knuth, D. E.; Patashnik, O.: Concrete Mathematics: A Foundation for Computer Science. Addison-Wesley, 1994
Charalambides, Ch. A.: Enumerative combinatorics. CRC Press, 2002
add a comment |Â
up vote
0
down vote
One key word is "finite products". Some hints are given in introductory combinatorics books, e.g. in the following books.
Riordan, J.: An Introduction to Combinatorial Analysis. Princeton University Press, 1958
Comtet, L.: Advanced Combinatorics: The Art of Finite and Innite Expansions.
Reidel, 1974
Graham, R. L.; Knuth, D. E.; Patashnik, O.: Concrete Mathematics: A Foundation for Computer Science. Addison-Wesley, 1994
Charalambides, Ch. A.: Enumerative combinatorics. CRC Press, 2002
add a comment |Â
up vote
0
down vote
up vote
0
down vote
One key word is "finite products". Some hints are given in introductory combinatorics books, e.g. in the following books.
Riordan, J.: An Introduction to Combinatorial Analysis. Princeton University Press, 1958
Comtet, L.: Advanced Combinatorics: The Art of Finite and Innite Expansions.
Reidel, 1974
Graham, R. L.; Knuth, D. E.; Patashnik, O.: Concrete Mathematics: A Foundation for Computer Science. Addison-Wesley, 1994
Charalambides, Ch. A.: Enumerative combinatorics. CRC Press, 2002
One key word is "finite products". Some hints are given in introductory combinatorics books, e.g. in the following books.
Riordan, J.: An Introduction to Combinatorial Analysis. Princeton University Press, 1958
Comtet, L.: Advanced Combinatorics: The Art of Finite and Innite Expansions.
Reidel, 1974
Graham, R. L.; Knuth, D. E.; Patashnik, O.: Concrete Mathematics: A Foundation for Computer Science. Addison-Wesley, 1994
Charalambides, Ch. A.: Enumerative combinatorics. CRC Press, 2002
answered Jul 26 at 12:39
IV_
940221
940221
add a comment |Â
add a comment |Â
Can you precise what you're looking for? Finite products? Infinite products? General algebraic properties?
– mathcounterexamples.net
Jul 26 at 9:48
@mathcounterexamples.net you know... The basic ones like we have for sigma i and i^2 and i^3 .... The ones that are a "must know"
– William
Jul 26 at 9:51