characterizing complex functions whose Laurent series coefficients have bounded 1-norm
Clash Royale CLAN TAG#URR8PPP
up vote
1
down vote
favorite
Suppose $h:mathbbTtomathbbC$ is a complex function on the unit circle with a valid Laurent series about zero:
$$
h(z) = sum_k=-infty^infty c_k z^kqquadtextfor |z|=1
$$
The coefficients $c_k$ satisfy certain constraints, and I would like to translate them to equivalent constraints on the function $h(z)$.
First question: is it true that the following statements are equivalent?
The coefficients satisfy $sum_k=-infty^infty |c_k| le 1$
The function satisfies $|h(z)| le 1$ for all $|z| = 1$.
It's clear that 1 implies 2 because $|h(z)| le sum_k|c_k||z^k| = sum_k|c_k|$ by the triangle inequality. Is the converse even true? How to prove it?
Second question: In addition to item 1 above, further assume that the coefficients $c_k$ are all real and nonnegative. Is there a nice way to represent this more complicated constraint on the coefficients as a constraint on $h$ ?
complex-analysis laurent-series
add a comment |Â
up vote
1
down vote
favorite
Suppose $h:mathbbTtomathbbC$ is a complex function on the unit circle with a valid Laurent series about zero:
$$
h(z) = sum_k=-infty^infty c_k z^kqquadtextfor |z|=1
$$
The coefficients $c_k$ satisfy certain constraints, and I would like to translate them to equivalent constraints on the function $h(z)$.
First question: is it true that the following statements are equivalent?
The coefficients satisfy $sum_k=-infty^infty |c_k| le 1$
The function satisfies $|h(z)| le 1$ for all $|z| = 1$.
It's clear that 1 implies 2 because $|h(z)| le sum_k|c_k||z^k| = sum_k|c_k|$ by the triangle inequality. Is the converse even true? How to prove it?
Second question: In addition to item 1 above, further assume that the coefficients $c_k$ are all real and nonnegative. Is there a nice way to represent this more complicated constraint on the coefficients as a constraint on $h$ ?
complex-analysis laurent-series
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Suppose $h:mathbbTtomathbbC$ is a complex function on the unit circle with a valid Laurent series about zero:
$$
h(z) = sum_k=-infty^infty c_k z^kqquadtextfor |z|=1
$$
The coefficients $c_k$ satisfy certain constraints, and I would like to translate them to equivalent constraints on the function $h(z)$.
First question: is it true that the following statements are equivalent?
The coefficients satisfy $sum_k=-infty^infty |c_k| le 1$
The function satisfies $|h(z)| le 1$ for all $|z| = 1$.
It's clear that 1 implies 2 because $|h(z)| le sum_k|c_k||z^k| = sum_k|c_k|$ by the triangle inequality. Is the converse even true? How to prove it?
Second question: In addition to item 1 above, further assume that the coefficients $c_k$ are all real and nonnegative. Is there a nice way to represent this more complicated constraint on the coefficients as a constraint on $h$ ?
complex-analysis laurent-series
Suppose $h:mathbbTtomathbbC$ is a complex function on the unit circle with a valid Laurent series about zero:
$$
h(z) = sum_k=-infty^infty c_k z^kqquadtextfor |z|=1
$$
The coefficients $c_k$ satisfy certain constraints, and I would like to translate them to equivalent constraints on the function $h(z)$.
First question: is it true that the following statements are equivalent?
The coefficients satisfy $sum_k=-infty^infty |c_k| le 1$
The function satisfies $|h(z)| le 1$ for all $|z| = 1$.
It's clear that 1 implies 2 because $|h(z)| le sum_k|c_k||z^k| = sum_k|c_k|$ by the triangle inequality. Is the converse even true? How to prove it?
Second question: In addition to item 1 above, further assume that the coefficients $c_k$ are all real and nonnegative. Is there a nice way to represent this more complicated constraint on the coefficients as a constraint on $h$ ?
complex-analysis laurent-series
edited Jul 26 at 15:46
asked Jul 26 at 6:59
Laurent Lessard
1,4211211
1,4211211
add a comment |Â
add a comment |Â
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2863144%2fcharacterizing-complex-functions-whose-laurent-series-coefficients-have-bounded%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password