Mixing
confusion with infinity… [closed]
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Lets take a number say x(=100).
Now lets take a look at division....
100/100=1, 100/10=10, 100/0.5= 200 and so on. As we go on decreasing the denominator, the result is getting bigger and bigger. So i order to get the highest possible result i.e +infinity, we have to divide it by the lowest possible denominator i.e -infinity. But we are dividing by zero to get the highest possible number.
And similarly, if we keep on increasing the denominator we get the lower result. So if we divide anything by infinity, its result should be -infinity (which is the lowest possible). Why zero?
Take 100/infinity. Why is it not -894232132 or -1254565123 or whatever else negative?
infinity
asked Aug 2 at 14:18
Gaurav Bhattarai
13
closed as unclear what you're asking by amWhy, m_t_, Lord Shark the Unknown, John Ma, Key Flex Aug 2 at 15:00
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
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up vote
-6
down vote
favorite
Lets take a number say x(=100).
Now lets take a look at division....
100/100=1, 100/10=10, 100/0.5= 200 and so on. As we go on decreasing the denominator, the result is getting bigger and bigger. So i order to get the highest possible result i.e +infinity, we have to divide it by the lowest possible denominator i.e -infinity. But we are dividing by zero to get the highest possible number.
And similarly, if we keep on increasing the denominator we get the lower result. So if we divide anything by infinity, its result should be -infinity (which is the lowest possible). Why zero?
Take 100/infinity. Why is it not -894232132 or -1254565123 or whatever else negative?
infinity
asked Aug 2 at 14:18
Gaurav Bhattarai
13
closed as unclear what you're asking by amWhy, m_t_, Lord Shark the Unknown, John Ma, Key Flex Aug 2 at 15:00
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
Diviion don't change sign if you dividing by positive number, 1/2 is positive, 1/4 is positive, 1/x will be positive as long x is positive, and speaking wise the result aproach 0 and not -infinity
– cand
Aug 2 at 14:22
You are using number without sign; thus when you decrease the denominator, you get decreasing positive number. The "limit" is $0$ because it is the lowest.
– Mauro ALLEGRANZA
Aug 2 at 14:22
100/-100 is not bigger than 1, 10, or 200
– Goldname
Aug 2 at 14:23
add a comment |Â
up vote
-6
down vote
favorite
up vote
-6
down vote
favorite
Lets take a number say x(=100).
Now lets take a look at division....
100/100=1, 100/10=10, 100/0.5= 200 and so on. As we go on decreasing the denominator, the result is getting bigger and bigger. So i order to get the highest possible result i.e +infinity, we have to divide it by the lowest possible denominator i.e -infinity. But we are dividing by zero to get the highest possible number.
And similarly, if we keep on increasing the denominator we get the lower result. So if we divide anything by infinity, its result should be -infinity (which is the lowest possible). Why zero?
Take 100/infinity. Why is it not -894232132 or -1254565123 or whatever else negative?
infinity
asked Aug 2 at 14:18
Gaurav Bhattarai
13
Lets take a number say x(=100).
Now lets take a look at division....
100/100=1, 100/10=10, 100/0.5= 200 and so on. As we go on decreasing the denominator, the result is getting bigger and bigger. So i order to get the highest possible result i.e +infinity, we have to divide it by the lowest possible denominator i.e -infinity. But we are dividing by zero to get the highest possible number.
And similarly, if we keep on increasing the denominator we get the lower result. So if we divide anything by infinity, its result should be -infinity (which is the lowest possible). Why zero?
Take 100/infinity. Why is it not -894232132 or -1254565123 or whatever else negative?
infinity
asked Aug 2 at 14:18
Gaurav Bhattarai
13
asked Aug 2 at 14:18
Gaurav Bhattarai
13
asked Aug 2 at 14:18
Gaurav Bhattarai
13
asked Aug 2 at 14:18
Gaurav Bhattarai
13
13
closed as unclear what you're asking by amWhy, m_t_, Lord Shark the Unknown, John Ma, Key Flex Aug 2 at 15:00
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
closed as unclear what you're asking by amWhy, m_t_, Lord Shark the Unknown, John Ma, Key Flex Aug 2 at 15:00
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
Diviion don't change sign if you dividing by positive number, 1/2 is positive, 1/4 is positive, 1/x will be positive as long x is positive, and speaking wise the result aproach 0 and not -infinity
– cand
Aug 2 at 14:22
You are using number without sign; thus when you decrease the denominator, you get decreasing positive number. The "limit" is $0$ because it is the lowest.
– Mauro ALLEGRANZA
Aug 2 at 14:22
100/-100 is not bigger than 1, 10, or 200
– Goldname
Aug 2 at 14:23
add a comment |Â
Diviion don't change sign if you dividing by positive number, 1/2 is positive, 1/4 is positive, 1/x will be positive as long x is positive, and speaking wise the result aproach 0 and not -infinity
– cand
Aug 2 at 14:22
You are using number without sign; thus when you decrease the denominator, you get decreasing positive number. The "limit" is $0$ because it is the lowest.
– Mauro ALLEGRANZA
Aug 2 at 14:22
100/-100 is not bigger than 1, 10, or 200
– Goldname
Aug 2 at 14:23
Diviion don't change sign if you dividing by positive number, 1/2 is positive, 1/4 is positive, 1/x will be positive as long x is positive, and speaking wise the result aproach 0 and not -infinity
– cand
Aug 2 at 14:22
Diviion don't change sign if you dividing by positive number, 1/2 is positive, 1/4 is positive, 1/x will be positive as long x is positive, and speaking wise the result aproach 0 and not -infinity
– cand
Aug 2 at 14:22
You are using number without sign; thus when you decrease the denominator, you get decreasing positive number. The "limit" is $0$ because it is the lowest.
– Mauro ALLEGRANZA
Aug 2 at 14:22
You are using number without sign; thus when you decrease the denominator, you get decreasing positive number. The "limit" is $0$ because it is the lowest.
– Mauro ALLEGRANZA
Aug 2 at 14:22
100/-100 is not bigger than 1, 10, or 200
– Goldname
Aug 2 at 14:23
100/-100 is not bigger than 1, 10, or 200
– Goldname
Aug 2 at 14:23
add a comment |Â
2 Answers
2
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1
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I just want to recall some basic rules of arithmetic:
$$fracab=fracab,frac-ab=-fracab,fraca-b=-fracab,frac-a-b=fracab$$
Therefore, dividing a positive number by another positive number will always result in another positive number, even when the either the numerator or the denominator are approaching to infinity.
When the numerator is increasing so is the value of the fraction but when the denominator rises you will end up by zero. Negative infinity is not the lowest possible. In fact it is a huge number, with a minus sign. The "lowest possible" in your context would be zero. Nothing else.
answered Aug 2 at 14:23
mrtaurho
609117
add a comment |Â
up vote
-1
down vote
let me explain you.
Size of nos. depend on their modulus values.
$-4$ is obviously bigger than $3$ because of its modulus value.
Now coming to the point where we say $-4<3$ or $-5<-4$.
Negative sign is just introduced to numbers to distinguish them from the numbers on the right side of the number line.
Its a convention to say that all negative numbers are smaller than the positive ones. Its just a mere convention to avoid the number line being purely symmetrical and irrelevant.
answered Aug 2 at 14:29
Love Invariants
77715
The asymmetry of the number line is much more than a convention: the nonnegative reals are exactly the reals which have square roots. If you're just looking at the reals with addition, then yes they are "symmetric," but when multiplication enters the picture everything changes.
– Noah Schweber
Aug 4 at 3:07
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
I just want to recall some basic rules of arithmetic:
$$fracab=fracab,frac-ab=-fracab,fraca-b=-fracab,frac-a-b=fracab$$
Therefore, dividing a positive number by another positive number will always result in another positive number, even when the either the numerator or the denominator are approaching to infinity.
When the numerator is increasing so is the value of the fraction but when the denominator rises you will end up by zero. Negative infinity is not the lowest possible. In fact it is a huge number, with a minus sign. The "lowest possible" in your context would be zero. Nothing else.
answered Aug 2 at 14:23
mrtaurho
609117
add a comment |Â
up vote
1
down vote
I just want to recall some basic rules of arithmetic:
$$fracab=fracab,frac-ab=-fracab,fraca-b=-fracab,frac-a-b=fracab$$
Therefore, dividing a positive number by another positive number will always result in another positive number, even when the either the numerator or the denominator are approaching to infinity.
When the numerator is increasing so is the value of the fraction but when the denominator rises you will end up by zero. Negative infinity is not the lowest possible. In fact it is a huge number, with a minus sign. The "lowest possible" in your context would be zero. Nothing else.
answered Aug 2 at 14:23
mrtaurho
609117
add a comment |Â
up vote
1
down vote
up vote
1
down vote
I just want to recall some basic rules of arithmetic:
$$fracab=fracab,frac-ab=-fracab,fraca-b=-fracab,frac-a-b=fracab$$
Therefore, dividing a positive number by another positive number will always result in another positive number, even when the either the numerator or the denominator are approaching to infinity.
When the numerator is increasing so is the value of the fraction but when the denominator rises you will end up by zero. Negative infinity is not the lowest possible. In fact it is a huge number, with a minus sign. The "lowest possible" in your context would be zero. Nothing else.
answered Aug 2 at 14:23
mrtaurho
609117
I just want to recall some basic rules of arithmetic:
$$fracab=fracab,frac-ab=-fracab,fraca-b=-fracab,frac-a-b=fracab$$
Therefore, dividing a positive number by another positive number will always result in another positive number, even when the either the numerator or the denominator are approaching to infinity.
When the numerator is increasing so is the value of the fraction but when the denominator rises you will end up by zero. Negative infinity is not the lowest possible. In fact it is a huge number, with a minus sign. The "lowest possible" in your context would be zero. Nothing else.
answered Aug 2 at 14:23
mrtaurho
609117
answered Aug 2 at 14:23
mrtaurho
609117
answered Aug 2 at 14:23
mrtaurho
609117
answered Aug 2 at 14:23
mrtaurho
609117
609117
add a comment |Â
add a comment |Â
up vote
-1
down vote
let me explain you.
Size of nos. depend on their modulus values.
$-4$ is obviously bigger than $3$ because of its modulus value.
Now coming to the point where we say $-4<3$ or $-5<-4$.
Negative sign is just introduced to numbers to distinguish them from the numbers on the right side of the number line.
Its a convention to say that all negative numbers are smaller than the positive ones. Its just a mere convention to avoid the number line being purely symmetrical and irrelevant.
answered Aug 2 at 14:29
Love Invariants
77715
The asymmetry of the number line is much more than a convention: the nonnegative reals are exactly the reals which have square roots. If you're just looking at the reals with addition, then yes they are "symmetric," but when multiplication enters the picture everything changes.
– Noah Schweber
Aug 4 at 3:07
add a comment |Â
up vote
-1
down vote
let me explain you.
Size of nos. depend on their modulus values.
$-4$ is obviously bigger than $3$ because of its modulus value.
Now coming to the point where we say $-4<3$ or $-5<-4$.
Negative sign is just introduced to numbers to distinguish them from the numbers on the right side of the number line.
Its a convention to say that all negative numbers are smaller than the positive ones. Its just a mere convention to avoid the number line being purely symmetrical and irrelevant.
answered Aug 2 at 14:29
Love Invariants
77715
The asymmetry of the number line is much more than a convention: the nonnegative reals are exactly the reals which have square roots. If you're just looking at the reals with addition, then yes they are "symmetric," but when multiplication enters the picture everything changes.
– Noah Schweber
Aug 4 at 3:07
add a comment |Â
up vote
-1
down vote
up vote
-1
down vote
let me explain you.
Size of nos. depend on their modulus values.
$-4$ is obviously bigger than $3$ because of its modulus value.
Now coming to the point where we say $-4<3$ or $-5<-4$.
Negative sign is just introduced to numbers to distinguish them from the numbers on the right side of the number line.
Its a convention to say that all negative numbers are smaller than the positive ones. Its just a mere convention to avoid the number line being purely symmetrical and irrelevant.
answered Aug 2 at 14:29
Love Invariants
77715
let me explain you.
Size of nos. depend on their modulus values.
$-4$ is obviously bigger than $3$ because of its modulus value.
Now coming to the point where we say $-4<3$ or $-5<-4$.
Negative sign is just introduced to numbers to distinguish them from the numbers on the right side of the number line.
Its a convention to say that all negative numbers are smaller than the positive ones. Its just a mere convention to avoid the number line being purely symmetrical and irrelevant.
answered Aug 2 at 14:29
Love Invariants
77715
answered Aug 2 at 14:29
Love Invariants
77715
answered Aug 2 at 14:29
Love Invariants
77715
answered Aug 2 at 14:29
Love Invariants
77715
77715
The asymmetry of the number line is much more than a convention: the nonnegative reals are exactly the reals which have square roots. If you're just looking at the reals with addition, then yes they are "symmetric," but when multiplication enters the picture everything changes.
– Noah Schweber
Aug 4 at 3:07
add a comment |Â
The asymmetry of the number line is much more than a convention: the nonnegative reals are exactly the reals which have square roots. If you're just looking at the reals with addition, then yes they are "symmetric," but when multiplication enters the picture everything changes.
– Noah Schweber
Aug 4 at 3:07
The asymmetry of the number line is much more than a convention: the nonnegative reals are exactly the reals which have square roots. If you're just looking at the reals with addition, then yes they are "symmetric," but when multiplication enters the picture everything changes.
– Noah Schweber
Aug 4 at 3:07
The asymmetry of the number line is much more than a convention: the nonnegative reals are exactly the reals which have square roots. If you're just looking at the reals with addition, then yes they are "symmetric," but when multiplication enters the picture everything changes.
– Noah Schweber
Aug 4 at 3:07
add a comment |Â
Diviion don't change sign if you dividing by positive number, 1/2 is positive, 1/4 is positive, 1/x will be positive as long x is positive, and speaking wise the result aproach 0 and not -infinity
– cand
Aug 2 at 14:22
You are using number without sign; thus when you decrease the denominator, you get decreasing positive number. The "limit" is $0$ because it is the lowest.
– Mauro ALLEGRANZA
Aug 2 at 14:22
100/-100 is not bigger than 1, 10, or 200
– Goldname
Aug 2 at 14:23