Convergence in probability, Y$X_n$ [closed]

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I'm struggling with the following problem



a) Show that if $X_n oversetpto X$ (convergence in probability) and $Y$ any random variable $X_nY oversetpto XY$



b) Find a case where the previous result isn't true if we change convergence in probability by convergence in distribution.



Thanks in advance for your help.







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closed as off-topic by spaceisdarkgreen, Taroccoesbrocco, Shailesh, amWhy, Adrian Keister Jul 27 at 0:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – spaceisdarkgreen, Taroccoesbrocco, Shailesh, amWhy, Adrian Keister
If this question can be reworded to fit the rules in the help center, please edit the question.
















    up vote
    -1
    down vote

    favorite












    I'm struggling with the following problem



    a) Show that if $X_n oversetpto X$ (convergence in probability) and $Y$ any random variable $X_nY oversetpto XY$



    b) Find a case where the previous result isn't true if we change convergence in probability by convergence in distribution.



    Thanks in advance for your help.







    share|cite|improve this question











    closed as off-topic by spaceisdarkgreen, Taroccoesbrocco, Shailesh, amWhy, Adrian Keister Jul 27 at 0:19


    This question appears to be off-topic. The users who voted to close gave this specific reason:


    • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – spaceisdarkgreen, Taroccoesbrocco, Shailesh, amWhy, Adrian Keister
    If this question can be reworded to fit the rules in the help center, please edit the question.














      up vote
      -1
      down vote

      favorite









      up vote
      -1
      down vote

      favorite











      I'm struggling with the following problem



      a) Show that if $X_n oversetpto X$ (convergence in probability) and $Y$ any random variable $X_nY oversetpto XY$



      b) Find a case where the previous result isn't true if we change convergence in probability by convergence in distribution.



      Thanks in advance for your help.







      share|cite|improve this question











      I'm struggling with the following problem



      a) Show that if $X_n oversetpto X$ (convergence in probability) and $Y$ any random variable $X_nY oversetpto XY$



      b) Find a case where the previous result isn't true if we change convergence in probability by convergence in distribution.



      Thanks in advance for your help.









      share|cite|improve this question










      share|cite|improve this question




      share|cite|improve this question









      asked Jul 26 at 2:25









      Matías

      11




      11




      closed as off-topic by spaceisdarkgreen, Taroccoesbrocco, Shailesh, amWhy, Adrian Keister Jul 27 at 0:19


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – spaceisdarkgreen, Taroccoesbrocco, Shailesh, amWhy, Adrian Keister
      If this question can be reworded to fit the rules in the help center, please edit the question.




      closed as off-topic by spaceisdarkgreen, Taroccoesbrocco, Shailesh, amWhy, Adrian Keister Jul 27 at 0:19


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – spaceisdarkgreen, Taroccoesbrocco, Shailesh, amWhy, Adrian Keister
      If this question can be reworded to fit the rules in the help center, please edit the question.




















          1 Answer
          1






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          accepted










          a), direct method:



          For any $c > 0$, you can show $$P(|X_n Y - X Y| > epsilon, |Y| ge c) to 0.$$



          Fix $delta > 0$. For an appropriately chosen $c > 0$, we have
          $$P(|X_n Y - XY| > epsilon)
          le P(|X_n Y - XY| > epsilon, |Y| ge c) + P(0 < |Y| < c)
          le fracdelta2 + fracdelta2 = delta$$
          for all large $n$.




          a), alternate method:



          The random vector $(X_n, Y)$ converges to $(X,Y)$ in probability. Thus by the continuous mapping theorem applied to this random vector, $X_n Y oversetpto XY$.




          b): Let $X$ be a nonzero symmetric random variable, and let $X_n := -X$ and $Y := X$. We have $X_n oversetdto -X$ because $X$ is symmetric. However, $X_n Y = -X^2$ while $X Y = X^2$.






          share|cite|improve this answer






























            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            0
            down vote



            accepted










            a), direct method:



            For any $c > 0$, you can show $$P(|X_n Y - X Y| > epsilon, |Y| ge c) to 0.$$



            Fix $delta > 0$. For an appropriately chosen $c > 0$, we have
            $$P(|X_n Y - XY| > epsilon)
            le P(|X_n Y - XY| > epsilon, |Y| ge c) + P(0 < |Y| < c)
            le fracdelta2 + fracdelta2 = delta$$
            for all large $n$.




            a), alternate method:



            The random vector $(X_n, Y)$ converges to $(X,Y)$ in probability. Thus by the continuous mapping theorem applied to this random vector, $X_n Y oversetpto XY$.




            b): Let $X$ be a nonzero symmetric random variable, and let $X_n := -X$ and $Y := X$. We have $X_n oversetdto -X$ because $X$ is symmetric. However, $X_n Y = -X^2$ while $X Y = X^2$.






            share|cite|improve this answer



























              up vote
              0
              down vote



              accepted










              a), direct method:



              For any $c > 0$, you can show $$P(|X_n Y - X Y| > epsilon, |Y| ge c) to 0.$$



              Fix $delta > 0$. For an appropriately chosen $c > 0$, we have
              $$P(|X_n Y - XY| > epsilon)
              le P(|X_n Y - XY| > epsilon, |Y| ge c) + P(0 < |Y| < c)
              le fracdelta2 + fracdelta2 = delta$$
              for all large $n$.




              a), alternate method:



              The random vector $(X_n, Y)$ converges to $(X,Y)$ in probability. Thus by the continuous mapping theorem applied to this random vector, $X_n Y oversetpto XY$.




              b): Let $X$ be a nonzero symmetric random variable, and let $X_n := -X$ and $Y := X$. We have $X_n oversetdto -X$ because $X$ is symmetric. However, $X_n Y = -X^2$ while $X Y = X^2$.






              share|cite|improve this answer

























                up vote
                0
                down vote



                accepted







                up vote
                0
                down vote



                accepted






                a), direct method:



                For any $c > 0$, you can show $$P(|X_n Y - X Y| > epsilon, |Y| ge c) to 0.$$



                Fix $delta > 0$. For an appropriately chosen $c > 0$, we have
                $$P(|X_n Y - XY| > epsilon)
                le P(|X_n Y - XY| > epsilon, |Y| ge c) + P(0 < |Y| < c)
                le fracdelta2 + fracdelta2 = delta$$
                for all large $n$.




                a), alternate method:



                The random vector $(X_n, Y)$ converges to $(X,Y)$ in probability. Thus by the continuous mapping theorem applied to this random vector, $X_n Y oversetpto XY$.




                b): Let $X$ be a nonzero symmetric random variable, and let $X_n := -X$ and $Y := X$. We have $X_n oversetdto -X$ because $X$ is symmetric. However, $X_n Y = -X^2$ while $X Y = X^2$.






                share|cite|improve this answer















                a), direct method:



                For any $c > 0$, you can show $$P(|X_n Y - X Y| > epsilon, |Y| ge c) to 0.$$



                Fix $delta > 0$. For an appropriately chosen $c > 0$, we have
                $$P(|X_n Y - XY| > epsilon)
                le P(|X_n Y - XY| > epsilon, |Y| ge c) + P(0 < |Y| < c)
                le fracdelta2 + fracdelta2 = delta$$
                for all large $n$.




                a), alternate method:



                The random vector $(X_n, Y)$ converges to $(X,Y)$ in probability. Thus by the continuous mapping theorem applied to this random vector, $X_n Y oversetpto XY$.




                b): Let $X$ be a nonzero symmetric random variable, and let $X_n := -X$ and $Y := X$. We have $X_n oversetdto -X$ because $X$ is symmetric. However, $X_n Y = -X^2$ while $X Y = X^2$.







                share|cite|improve this answer















                share|cite|improve this answer



                share|cite|improve this answer








                edited Jul 26 at 19:25









                E-A

                1,8051312




                1,8051312











                answered Jul 26 at 2:56









                angryavian

                34.6k12874




                34.6k12874












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