Correspondence between dual of the space of continuous maps and signed measures

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On the first page of Chapter 4 of Einsiedler an Ward's Ergodic Theory: With a View Towards Number Theory, the following statement is found:



Let $(X, d)$ be a compact metric.
Recall that the dual space $C(X)^*$ of continuous real functionals on $C(X)$ of continuous functions $Xto mathbf R$ can be naturally identified with the space of finite signed measures on $X$ equipped with the weak* topology.



I want to confirm if the correspondence is given by the following map:



Let $mathcal F$ be the space of all the finite signed measures on $X$.
Define $phi:mathcal Fto C(X)^*$ as
$$phi(mu) = (fmapsto int f dmu)$$







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  • 1




    That is correct. This is, in fact, an isometric isomorphism if you endow measures with total variation norm.
    – Kavi Rama Murthy
    Jul 27 at 7:58










  • @KaviRamaMurthy Can you confirm one more thing? Is the weak* topology on $mathcal F$ (see OP) defined as follows: We say $mu_nto mu$ in the weak* topology if $int_X f dmu_nto int_X f dmu$ for all $fin C(X)$?
    – caffeinemachine
    Jul 27 at 17:25










  • Yes. Probabilists wrongly call this weak convergence, but it is weak* convergence.
    – Kavi Rama Murthy
    Jul 27 at 23:19














up vote
2
down vote

favorite












On the first page of Chapter 4 of Einsiedler an Ward's Ergodic Theory: With a View Towards Number Theory, the following statement is found:



Let $(X, d)$ be a compact metric.
Recall that the dual space $C(X)^*$ of continuous real functionals on $C(X)$ of continuous functions $Xto mathbf R$ can be naturally identified with the space of finite signed measures on $X$ equipped with the weak* topology.



I want to confirm if the correspondence is given by the following map:



Let $mathcal F$ be the space of all the finite signed measures on $X$.
Define $phi:mathcal Fto C(X)^*$ as
$$phi(mu) = (fmapsto int f dmu)$$







share|cite|improve this question















  • 1




    That is correct. This is, in fact, an isometric isomorphism if you endow measures with total variation norm.
    – Kavi Rama Murthy
    Jul 27 at 7:58










  • @KaviRamaMurthy Can you confirm one more thing? Is the weak* topology on $mathcal F$ (see OP) defined as follows: We say $mu_nto mu$ in the weak* topology if $int_X f dmu_nto int_X f dmu$ for all $fin C(X)$?
    – caffeinemachine
    Jul 27 at 17:25










  • Yes. Probabilists wrongly call this weak convergence, but it is weak* convergence.
    – Kavi Rama Murthy
    Jul 27 at 23:19












up vote
2
down vote

favorite









up vote
2
down vote

favorite











On the first page of Chapter 4 of Einsiedler an Ward's Ergodic Theory: With a View Towards Number Theory, the following statement is found:



Let $(X, d)$ be a compact metric.
Recall that the dual space $C(X)^*$ of continuous real functionals on $C(X)$ of continuous functions $Xto mathbf R$ can be naturally identified with the space of finite signed measures on $X$ equipped with the weak* topology.



I want to confirm if the correspondence is given by the following map:



Let $mathcal F$ be the space of all the finite signed measures on $X$.
Define $phi:mathcal Fto C(X)^*$ as
$$phi(mu) = (fmapsto int f dmu)$$







share|cite|improve this question











On the first page of Chapter 4 of Einsiedler an Ward's Ergodic Theory: With a View Towards Number Theory, the following statement is found:



Let $(X, d)$ be a compact metric.
Recall that the dual space $C(X)^*$ of continuous real functionals on $C(X)$ of continuous functions $Xto mathbf R$ can be naturally identified with the space of finite signed measures on $X$ equipped with the weak* topology.



I want to confirm if the correspondence is given by the following map:



Let $mathcal F$ be the space of all the finite signed measures on $X$.
Define $phi:mathcal Fto C(X)^*$ as
$$phi(mu) = (fmapsto int f dmu)$$









share|cite|improve this question










share|cite|improve this question




share|cite|improve this question









asked Jul 27 at 7:36









caffeinemachine

6,07221145




6,07221145







  • 1




    That is correct. This is, in fact, an isometric isomorphism if you endow measures with total variation norm.
    – Kavi Rama Murthy
    Jul 27 at 7:58










  • @KaviRamaMurthy Can you confirm one more thing? Is the weak* topology on $mathcal F$ (see OP) defined as follows: We say $mu_nto mu$ in the weak* topology if $int_X f dmu_nto int_X f dmu$ for all $fin C(X)$?
    – caffeinemachine
    Jul 27 at 17:25










  • Yes. Probabilists wrongly call this weak convergence, but it is weak* convergence.
    – Kavi Rama Murthy
    Jul 27 at 23:19












  • 1




    That is correct. This is, in fact, an isometric isomorphism if you endow measures with total variation norm.
    – Kavi Rama Murthy
    Jul 27 at 7:58










  • @KaviRamaMurthy Can you confirm one more thing? Is the weak* topology on $mathcal F$ (see OP) defined as follows: We say $mu_nto mu$ in the weak* topology if $int_X f dmu_nto int_X f dmu$ for all $fin C(X)$?
    – caffeinemachine
    Jul 27 at 17:25










  • Yes. Probabilists wrongly call this weak convergence, but it is weak* convergence.
    – Kavi Rama Murthy
    Jul 27 at 23:19







1




1




That is correct. This is, in fact, an isometric isomorphism if you endow measures with total variation norm.
– Kavi Rama Murthy
Jul 27 at 7:58




That is correct. This is, in fact, an isometric isomorphism if you endow measures with total variation norm.
– Kavi Rama Murthy
Jul 27 at 7:58












@KaviRamaMurthy Can you confirm one more thing? Is the weak* topology on $mathcal F$ (see OP) defined as follows: We say $mu_nto mu$ in the weak* topology if $int_X f dmu_nto int_X f dmu$ for all $fin C(X)$?
– caffeinemachine
Jul 27 at 17:25




@KaviRamaMurthy Can you confirm one more thing? Is the weak* topology on $mathcal F$ (see OP) defined as follows: We say $mu_nto mu$ in the weak* topology if $int_X f dmu_nto int_X f dmu$ for all $fin C(X)$?
– caffeinemachine
Jul 27 at 17:25












Yes. Probabilists wrongly call this weak convergence, but it is weak* convergence.
– Kavi Rama Murthy
Jul 27 at 23:19




Yes. Probabilists wrongly call this weak convergence, but it is weak* convergence.
– Kavi Rama Murthy
Jul 27 at 23:19















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