Error/difference of sampling an element from a set
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Assume there is a set, $A_j=x_1, x_2,...,x_n$. What should be the error associated in selecting/choosing an element from $A_j$, given each element of $A_j$ has an equal probability ($1/n$) of getting selected?
Would average provide a good estimate?
e.g.,
$Error=|x'-(sum_i=1^nx_i)/n|$
The ultimate goal is to estimate the sample statistics (mean, variance) where, the sample is composed of $x'_1,x'_2,...,x'_k$ where $x'_i$ is drawn from $k$ number of sets $A_1,A_2,...,A_k$.
probability standard-deviation variance means
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Assume there is a set, $A_j=x_1, x_2,...,x_n$. What should be the error associated in selecting/choosing an element from $A_j$, given each element of $A_j$ has an equal probability ($1/n$) of getting selected?
Would average provide a good estimate?
e.g.,
$Error=|x'-(sum_i=1^nx_i)/n|$
The ultimate goal is to estimate the sample statistics (mean, variance) where, the sample is composed of $x'_1,x'_2,...,x'_k$ where $x'_i$ is drawn from $k$ number of sets $A_1,A_2,...,A_k$.
probability standard-deviation variance means
Somewhat tautologically, if you are interested with deviation from the mean, then the deviation from the mean is a good estimate of that error. But as long as you don't specify what you mean by "the error" this question doesn't have an answer.
– Mees de Vries
Jul 23 at 10:43
@MeesdeVries I edited the question so that it gives more clarity on what I'm looking for. Please check.
– cuser
Jul 23 at 11:28
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up vote
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Assume there is a set, $A_j=x_1, x_2,...,x_n$. What should be the error associated in selecting/choosing an element from $A_j$, given each element of $A_j$ has an equal probability ($1/n$) of getting selected?
Would average provide a good estimate?
e.g.,
$Error=|x'-(sum_i=1^nx_i)/n|$
The ultimate goal is to estimate the sample statistics (mean, variance) where, the sample is composed of $x'_1,x'_2,...,x'_k$ where $x'_i$ is drawn from $k$ number of sets $A_1,A_2,...,A_k$.
probability standard-deviation variance means
Assume there is a set, $A_j=x_1, x_2,...,x_n$. What should be the error associated in selecting/choosing an element from $A_j$, given each element of $A_j$ has an equal probability ($1/n$) of getting selected?
Would average provide a good estimate?
e.g.,
$Error=|x'-(sum_i=1^nx_i)/n|$
The ultimate goal is to estimate the sample statistics (mean, variance) where, the sample is composed of $x'_1,x'_2,...,x'_k$ where $x'_i$ is drawn from $k$ number of sets $A_1,A_2,...,A_k$.
probability standard-deviation variance means
edited Jul 24 at 9:34
asked Jul 23 at 10:30
cuser
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Somewhat tautologically, if you are interested with deviation from the mean, then the deviation from the mean is a good estimate of that error. But as long as you don't specify what you mean by "the error" this question doesn't have an answer.
– Mees de Vries
Jul 23 at 10:43
@MeesdeVries I edited the question so that it gives more clarity on what I'm looking for. Please check.
– cuser
Jul 23 at 11:28
add a comment |Â
Somewhat tautologically, if you are interested with deviation from the mean, then the deviation from the mean is a good estimate of that error. But as long as you don't specify what you mean by "the error" this question doesn't have an answer.
– Mees de Vries
Jul 23 at 10:43
@MeesdeVries I edited the question so that it gives more clarity on what I'm looking for. Please check.
– cuser
Jul 23 at 11:28
Somewhat tautologically, if you are interested with deviation from the mean, then the deviation from the mean is a good estimate of that error. But as long as you don't specify what you mean by "the error" this question doesn't have an answer.
– Mees de Vries
Jul 23 at 10:43
Somewhat tautologically, if you are interested with deviation from the mean, then the deviation from the mean is a good estimate of that error. But as long as you don't specify what you mean by "the error" this question doesn't have an answer.
– Mees de Vries
Jul 23 at 10:43
@MeesdeVries I edited the question so that it gives more clarity on what I'm looking for. Please check.
– cuser
Jul 23 at 11:28
@MeesdeVries I edited the question so that it gives more clarity on what I'm looking for. Please check.
– cuser
Jul 23 at 11:28
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
0
down vote
You may want to look at the link. You may report both RMSE and MAE.
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
You may want to look at the link. You may report both RMSE and MAE.
add a comment |Â
up vote
0
down vote
You may want to look at the link. You may report both RMSE and MAE.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
You may want to look at the link. You may report both RMSE and MAE.
You may want to look at the link. You may report both RMSE and MAE.
answered Jul 23 at 10:44


Waqas
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4910
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Somewhat tautologically, if you are interested with deviation from the mean, then the deviation from the mean is a good estimate of that error. But as long as you don't specify what you mean by "the error" this question doesn't have an answer.
– Mees de Vries
Jul 23 at 10:43
@MeesdeVries I edited the question so that it gives more clarity on what I'm looking for. Please check.
– cuser
Jul 23 at 11:28