Is the number of irreducible unitary representations of a finitely-generated group of a given dimension finite?

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Let $Gamma$ be a finitely-generated group. Fix an integer $ngeq 1$. Is it possible that $Gamma$ has infinitely many pairwise non-isomorphic irreducible unitary representations of dimension $n$?



I tried to show that it is not possible:



We can fix a generating set $S$, and think of a unitary representation $rho$ as a function $Srightarrow U(n)$. Since $U(n)^S$ is compact, it would suffice to show that every element of $U(n)^S$ which corresponds to an irreducible representation has an open neighborhood $U$, such that all unitary representations that are mapped into $U$ are isomorphic to $rho$. I don't know if that's true.







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    Doesn't $Gamma=Bbb Z$, $n=1$ give a counterexample? I'm pretty sure the unit circel in the complex plane is infinite.
    – David C. Ullrich
    Jul 22 at 15:05















up vote
-3
down vote

favorite












Let $Gamma$ be a finitely-generated group. Fix an integer $ngeq 1$. Is it possible that $Gamma$ has infinitely many pairwise non-isomorphic irreducible unitary representations of dimension $n$?



I tried to show that it is not possible:



We can fix a generating set $S$, and think of a unitary representation $rho$ as a function $Srightarrow U(n)$. Since $U(n)^S$ is compact, it would suffice to show that every element of $U(n)^S$ which corresponds to an irreducible representation has an open neighborhood $U$, such that all unitary representations that are mapped into $U$ are isomorphic to $rho$. I don't know if that's true.







share|cite|improve this question















  • 2




    Doesn't $Gamma=Bbb Z$, $n=1$ give a counterexample? I'm pretty sure the unit circel in the complex plane is infinite.
    – David C. Ullrich
    Jul 22 at 15:05













up vote
-3
down vote

favorite









up vote
-3
down vote

favorite











Let $Gamma$ be a finitely-generated group. Fix an integer $ngeq 1$. Is it possible that $Gamma$ has infinitely many pairwise non-isomorphic irreducible unitary representations of dimension $n$?



I tried to show that it is not possible:



We can fix a generating set $S$, and think of a unitary representation $rho$ as a function $Srightarrow U(n)$. Since $U(n)^S$ is compact, it would suffice to show that every element of $U(n)^S$ which corresponds to an irreducible representation has an open neighborhood $U$, such that all unitary representations that are mapped into $U$ are isomorphic to $rho$. I don't know if that's true.







share|cite|improve this question











Let $Gamma$ be a finitely-generated group. Fix an integer $ngeq 1$. Is it possible that $Gamma$ has infinitely many pairwise non-isomorphic irreducible unitary representations of dimension $n$?



I tried to show that it is not possible:



We can fix a generating set $S$, and think of a unitary representation $rho$ as a function $Srightarrow U(n)$. Since $U(n)^S$ is compact, it would suffice to show that every element of $U(n)^S$ which corresponds to an irreducible representation has an open neighborhood $U$, such that all unitary representations that are mapped into $U$ are isomorphic to $rho$. I don't know if that's true.









share|cite|improve this question










share|cite|improve this question




share|cite|improve this question









asked Jul 22 at 15:03









Scott Harris

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  • 2




    Doesn't $Gamma=Bbb Z$, $n=1$ give a counterexample? I'm pretty sure the unit circel in the complex plane is infinite.
    – David C. Ullrich
    Jul 22 at 15:05













  • 2




    Doesn't $Gamma=Bbb Z$, $n=1$ give a counterexample? I'm pretty sure the unit circel in the complex plane is infinite.
    – David C. Ullrich
    Jul 22 at 15:05








2




2




Doesn't $Gamma=Bbb Z$, $n=1$ give a counterexample? I'm pretty sure the unit circel in the complex plane is infinite.
– David C. Ullrich
Jul 22 at 15:05





Doesn't $Gamma=Bbb Z$, $n=1$ give a counterexample? I'm pretty sure the unit circel in the complex plane is infinite.
– David C. Ullrich
Jul 22 at 15:05
















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