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How much faster is $T_2$ than $T_1$ in percent $%$? [on hold]
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Say a program runs and results in $T_1 = 157s$ then is modified and runs in $T_2 = 16s$.
What is the correct way to display (in %):
- How much faster is $T_2$ than $T_1$?
- How much of an increase is the completion time of $T_2$ than $T_1$?
I imagine them to be read as:
- $T_2$ is __% faster than $T_1$
- $T_2$ was an increase of __% in completion time
With the latter being something along the lines of "... $4000$% ..." or "... 32x ..." or so.
percentages
asked Aug 3 at 17:23
pstatix
1396
put on hold as off-topic by amWhy, John Ma, Xander Henderson, Shailesh, Taroccoesbrocco Aug 4 at 4:14
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, John Ma, Xander Henderson, Shailesh, Taroccoesbrocco
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up vote
1
down vote
favorite
Say a program runs and results in $T_1 = 157s$ then is modified and runs in $T_2 = 16s$.
What is the correct way to display (in %):
- How much faster is $T_2$ than $T_1$?
- How much of an increase is the completion time of $T_2$ than $T_1$?
I imagine them to be read as:
- $T_2$ is __% faster than $T_1$
- $T_2$ was an increase of __% in completion time
With the latter being something along the lines of "... $4000$% ..." or "... 32x ..." or so.
percentages
asked Aug 3 at 17:23
pstatix
1396
put on hold as off-topic by amWhy, John Ma, Xander Henderson, Shailesh, Taroccoesbrocco Aug 4 at 4:14
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, John Ma, Xander Henderson, Shailesh, Taroccoesbrocco
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Say a program runs and results in $T_1 = 157s$ then is modified and runs in $T_2 = 16s$.
What is the correct way to display (in %):
- How much faster is $T_2$ than $T_1$?
- How much of an increase is the completion time of $T_2$ than $T_1$?
I imagine them to be read as:
- $T_2$ is __% faster than $T_1$
- $T_2$ was an increase of __% in completion time
With the latter being something along the lines of "... $4000$% ..." or "... 32x ..." or so.
percentages
asked Aug 3 at 17:23
pstatix
1396
Say a program runs and results in $T_1 = 157s$ then is modified and runs in $T_2 = 16s$.
What is the correct way to display (in %):
- How much faster is $T_2$ than $T_1$?
- How much of an increase is the completion time of $T_2$ than $T_1$?
I imagine them to be read as:
- $T_2$ is __% faster than $T_1$
- $T_2$ was an increase of __% in completion time
With the latter being something along the lines of "... $4000$% ..." or "... 32x ..." or so.
percentages
asked Aug 3 at 17:23
pstatix
1396
edited Aug 3 at 17:33
asked Aug 3 at 17:23
pstatix
1396
asked Aug 3 at 17:23
pstatix
1396
asked Aug 3 at 17:23
pstatix
1396
1396
put on hold as off-topic by amWhy, John Ma, Xander Henderson, Shailesh, Taroccoesbrocco Aug 4 at 4:14
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, John Ma, Xander Henderson, Shailesh, Taroccoesbrocco
put on hold as off-topic by amWhy, John Ma, Xander Henderson, Shailesh, Taroccoesbrocco Aug 4 at 4:14
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, John Ma, Xander Henderson, Shailesh, Taroccoesbrocco
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1 Answer
1
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1
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accepted
A way is use, with reference to time, the ratio
$$p_T=fracT_1-T_2T_1=frac141157approx 0.898=89.8%$$
or as an alternative with reference to speed
$$p_S=fracfrac1T_2frac1T_2=fracT_1T_2approx 9.81=981%$$
answered Aug 3 at 17:27
gimusi
63.7k73480
So that says $T_2$ is approximately $89.9%$ faster than $T_1$ since it is relative to $T_1$ right? How would I say "$T_2$ is a __% increase in completion time"?
– pstatix
Aug 3 at 17:31
@pstatix $p_T$ is a mesure of the time saved by $T_2$ with respect to $T_1$ (we save 90% of the time while $p_S$ is a mesur of how mach $T_2$ is faster ($T_2$ is about 10 times faster than $T_1$).
– gimusi
Aug 3 at 17:38
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
A way is use, with reference to time, the ratio
$$p_T=fracT_1-T_2T_1=frac141157approx 0.898=89.8%$$
or as an alternative with reference to speed
$$p_S=fracfrac1T_2frac1T_2=fracT_1T_2approx 9.81=981%$$
answered Aug 3 at 17:27
gimusi
63.7k73480
So that says $T_2$ is approximately $89.9%$ faster than $T_1$ since it is relative to $T_1$ right? How would I say "$T_2$ is a __% increase in completion time"?
– pstatix
Aug 3 at 17:31
@pstatix $p_T$ is a mesure of the time saved by $T_2$ with respect to $T_1$ (we save 90% of the time while $p_S$ is a mesur of how mach $T_2$ is faster ($T_2$ is about 10 times faster than $T_1$).
– gimusi
Aug 3 at 17:38
add a comment |Â
up vote
1
down vote
accepted
A way is use, with reference to time, the ratio
$$p_T=fracT_1-T_2T_1=frac141157approx 0.898=89.8%$$
or as an alternative with reference to speed
$$p_S=fracfrac1T_2frac1T_2=fracT_1T_2approx 9.81=981%$$
answered Aug 3 at 17:27
gimusi
63.7k73480
So that says $T_2$ is approximately $89.9%$ faster than $T_1$ since it is relative to $T_1$ right? How would I say "$T_2$ is a __% increase in completion time"?
– pstatix
Aug 3 at 17:31
@pstatix $p_T$ is a mesure of the time saved by $T_2$ with respect to $T_1$ (we save 90% of the time while $p_S$ is a mesur of how mach $T_2$ is faster ($T_2$ is about 10 times faster than $T_1$).
– gimusi
Aug 3 at 17:38
add a comment |Â
up vote
1
down vote
accepted
up vote
1
down vote
accepted
A way is use, with reference to time, the ratio
$$p_T=fracT_1-T_2T_1=frac141157approx 0.898=89.8%$$
or as an alternative with reference to speed
$$p_S=fracfrac1T_2frac1T_2=fracT_1T_2approx 9.81=981%$$
answered Aug 3 at 17:27
gimusi
63.7k73480
A way is use, with reference to time, the ratio
$$p_T=fracT_1-T_2T_1=frac141157approx 0.898=89.8%$$
or as an alternative with reference to speed
$$p_S=fracfrac1T_2frac1T_2=fracT_1T_2approx 9.81=981%$$
answered Aug 3 at 17:27
gimusi
63.7k73480
edited Aug 3 at 17:35
answered Aug 3 at 17:27
gimusi
63.7k73480
answered Aug 3 at 17:27
gimusi
63.7k73480
answered Aug 3 at 17:27
gimusi
63.7k73480
63.7k73480
So that says $T_2$ is approximately $89.9%$ faster than $T_1$ since it is relative to $T_1$ right? How would I say "$T_2$ is a __% increase in completion time"?
– pstatix
Aug 3 at 17:31
@pstatix $p_T$ is a mesure of the time saved by $T_2$ with respect to $T_1$ (we save 90% of the time while $p_S$ is a mesur of how mach $T_2$ is faster ($T_2$ is about 10 times faster than $T_1$).
– gimusi
Aug 3 at 17:38
add a comment |Â
So that says $T_2$ is approximately $89.9%$ faster than $T_1$ since it is relative to $T_1$ right? How would I say "$T_2$ is a __% increase in completion time"?
– pstatix
Aug 3 at 17:31
@pstatix $p_T$ is a mesure of the time saved by $T_2$ with respect to $T_1$ (we save 90% of the time while $p_S$ is a mesur of how mach $T_2$ is faster ($T_2$ is about 10 times faster than $T_1$).
– gimusi
Aug 3 at 17:38
So that says $T_2$ is approximately $89.9%$ faster than $T_1$ since it is relative to $T_1$ right? How would I say "$T_2$ is a __% increase in completion time"?
– pstatix
Aug 3 at 17:31
So that says $T_2$ is approximately $89.9%$ faster than $T_1$ since it is relative to $T_1$ right? How would I say "$T_2$ is a __% increase in completion time"?
– pstatix
Aug 3 at 17:31
@pstatix $p_T$ is a mesure of the time saved by $T_2$ with respect to $T_1$ (we save 90% of the time while $p_S$ is a mesur of how mach $T_2$ is faster ($T_2$ is about 10 times faster than $T_1$).
– gimusi
Aug 3 at 17:38
@pstatix $p_T$ is a mesure of the time saved by $T_2$ with respect to $T_1$ (we save 90% of the time while $p_S$ is a mesur of how mach $T_2$ is faster ($T_2$ is about 10 times faster than $T_1$).
– gimusi
Aug 3 at 17:38
add a comment |Â