Integration by parts 2

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Say $F(x)$ is the antiderivative of $f(x)$. $int_0^2 F(x)dx = 3$, $int_0^2 f(x)dx = 4$, $f(2) = 9$, $f(0) = 5$ and $F(2)=14$, and $F(0)=10$. Then $int_0^2 f(x) x dx$ equals?



With integration by parts, I get $x*f(x) - int_0^2 f(x)dx= [x*f(x) - 4]_0^2$ which equals $(2*f(2) - 4)-(0*f(0)-4) = 2(9) - 4 + 4 = 18$







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  • Integrate by part.
    – xbh
    Jul 26 at 1:33










  • Have you learned integration by parts yet?
    – sharding4
    Jul 26 at 1:33










  • I haven't, this is an advanced problem for this homework set. I think integration by parts is taught next week. I will read ahead now to attempt to answer it. Thank you for the tip!
    – Vera
    Jul 26 at 1:37










  • Gave it a shot, did I do it correctly?
    – Vera
    Jul 26 at 2:30














up vote
0
down vote

favorite












Say $F(x)$ is the antiderivative of $f(x)$. $int_0^2 F(x)dx = 3$, $int_0^2 f(x)dx = 4$, $f(2) = 9$, $f(0) = 5$ and $F(2)=14$, and $F(0)=10$. Then $int_0^2 f(x) x dx$ equals?



With integration by parts, I get $x*f(x) - int_0^2 f(x)dx= [x*f(x) - 4]_0^2$ which equals $(2*f(2) - 4)-(0*f(0)-4) = 2(9) - 4 + 4 = 18$







share|cite|improve this question





















  • Integrate by part.
    – xbh
    Jul 26 at 1:33










  • Have you learned integration by parts yet?
    – sharding4
    Jul 26 at 1:33










  • I haven't, this is an advanced problem for this homework set. I think integration by parts is taught next week. I will read ahead now to attempt to answer it. Thank you for the tip!
    – Vera
    Jul 26 at 1:37










  • Gave it a shot, did I do it correctly?
    – Vera
    Jul 26 at 2:30












up vote
0
down vote

favorite









up vote
0
down vote

favorite











Say $F(x)$ is the antiderivative of $f(x)$. $int_0^2 F(x)dx = 3$, $int_0^2 f(x)dx = 4$, $f(2) = 9$, $f(0) = 5$ and $F(2)=14$, and $F(0)=10$. Then $int_0^2 f(x) x dx$ equals?



With integration by parts, I get $x*f(x) - int_0^2 f(x)dx= [x*f(x) - 4]_0^2$ which equals $(2*f(2) - 4)-(0*f(0)-4) = 2(9) - 4 + 4 = 18$







share|cite|improve this question













Say $F(x)$ is the antiderivative of $f(x)$. $int_0^2 F(x)dx = 3$, $int_0^2 f(x)dx = 4$, $f(2) = 9$, $f(0) = 5$ and $F(2)=14$, and $F(0)=10$. Then $int_0^2 f(x) x dx$ equals?



With integration by parts, I get $x*f(x) - int_0^2 f(x)dx= [x*f(x) - 4]_0^2$ which equals $(2*f(2) - 4)-(0*f(0)-4) = 2(9) - 4 + 4 = 18$









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 26 at 3:02
























asked Jul 26 at 1:20









Vera

11




11











  • Integrate by part.
    – xbh
    Jul 26 at 1:33










  • Have you learned integration by parts yet?
    – sharding4
    Jul 26 at 1:33










  • I haven't, this is an advanced problem for this homework set. I think integration by parts is taught next week. I will read ahead now to attempt to answer it. Thank you for the tip!
    – Vera
    Jul 26 at 1:37










  • Gave it a shot, did I do it correctly?
    – Vera
    Jul 26 at 2:30
















  • Integrate by part.
    – xbh
    Jul 26 at 1:33










  • Have you learned integration by parts yet?
    – sharding4
    Jul 26 at 1:33










  • I haven't, this is an advanced problem for this homework set. I think integration by parts is taught next week. I will read ahead now to attempt to answer it. Thank you for the tip!
    – Vera
    Jul 26 at 1:37










  • Gave it a shot, did I do it correctly?
    – Vera
    Jul 26 at 2:30















Integrate by part.
– xbh
Jul 26 at 1:33




Integrate by part.
– xbh
Jul 26 at 1:33












Have you learned integration by parts yet?
– sharding4
Jul 26 at 1:33




Have you learned integration by parts yet?
– sharding4
Jul 26 at 1:33












I haven't, this is an advanced problem for this homework set. I think integration by parts is taught next week. I will read ahead now to attempt to answer it. Thank you for the tip!
– Vera
Jul 26 at 1:37




I haven't, this is an advanced problem for this homework set. I think integration by parts is taught next week. I will read ahead now to attempt to answer it. Thank you for the tip!
– Vera
Jul 26 at 1:37












Gave it a shot, did I do it correctly?
– Vera
Jul 26 at 2:30




Gave it a shot, did I do it correctly?
– Vera
Jul 26 at 2:30










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Hint: No. Try integration by parts.






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    1 Answer
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    1 Answer
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    active

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    up vote
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    down vote













    Hint: No. Try integration by parts.






    share|cite|improve this answer

























      up vote
      0
      down vote













      Hint: No. Try integration by parts.






      share|cite|improve this answer























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        up vote
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        Hint: No. Try integration by parts.






        share|cite|improve this answer













        Hint: No. Try integration by parts.







        share|cite|improve this answer













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        share|cite|improve this answer











        answered Jul 26 at 1:36









        MPW

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