Proofs for the Spherical Laws of sines and Cosines

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I am looking for "classical" proofs for the spherical laws of sines and cosines. A proof that relies only on knowledge that was common to the ancient greek geometers, not containing analytical geometry and vectors and such.
Thanks!







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    I am looking for "classical" proofs for the spherical laws of sines and cosines. A proof that relies only on knowledge that was common to the ancient greek geometers, not containing analytical geometry and vectors and such.
    Thanks!







    share|cite|improve this question























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I am looking for "classical" proofs for the spherical laws of sines and cosines. A proof that relies only on knowledge that was common to the ancient greek geometers, not containing analytical geometry and vectors and such.
      Thanks!







      share|cite|improve this question













      I am looking for "classical" proofs for the spherical laws of sines and cosines. A proof that relies only on knowledge that was common to the ancient greek geometers, not containing analytical geometry and vectors and such.
      Thanks!









      share|cite|improve this question












      share|cite|improve this question




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      edited Jul 23 at 7:45
























      asked Jul 23 at 7:28









      Gouni Jacobi

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          Let $A$, $B$, $C$ the vertices of a spherical triangle on a sphere of unit radius and center $O$ (see diagram below). Spherical angle $angle ACB=gamma$ is by definition angle $angle ECF$ formed by tangent lines at $C$.



          In right triangles $OCE$ and $OCF$ we have then $EC=tan b$ and $FC=tan a$, so by the cosine rule in triangle $CEF$:



          $$
          EF^2=tan^2 a+tan^2 b-2tan atan bcosgamma.
          $$
          On the other hand we also have $OE=sec b$ and $OF=sec a$, so by the cosine rule in triangle $OEF$:
          $$
          EF^2=sec^2 a+sec^2 b-2sec asec bcos c.
          $$
          Equating the right hand sides of both formulas leads, after some simplifications, to:
          $$
          cos c=cos acos b+sin a sin bcosgamma,
          $$
          which is the spherical cosine rule.



          enter image description here



          This proof works as long as $a$ and $b$ are acute angles, but I think it can also be extended, with some modifications, to the other cases.






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            1 Answer
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            up vote
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            Let $A$, $B$, $C$ the vertices of a spherical triangle on a sphere of unit radius and center $O$ (see diagram below). Spherical angle $angle ACB=gamma$ is by definition angle $angle ECF$ formed by tangent lines at $C$.



            In right triangles $OCE$ and $OCF$ we have then $EC=tan b$ and $FC=tan a$, so by the cosine rule in triangle $CEF$:



            $$
            EF^2=tan^2 a+tan^2 b-2tan atan bcosgamma.
            $$
            On the other hand we also have $OE=sec b$ and $OF=sec a$, so by the cosine rule in triangle $OEF$:
            $$
            EF^2=sec^2 a+sec^2 b-2sec asec bcos c.
            $$
            Equating the right hand sides of both formulas leads, after some simplifications, to:
            $$
            cos c=cos acos b+sin a sin bcosgamma,
            $$
            which is the spherical cosine rule.



            enter image description here



            This proof works as long as $a$ and $b$ are acute angles, but I think it can also be extended, with some modifications, to the other cases.






            share|cite|improve this answer



























              up vote
              0
              down vote













              Let $A$, $B$, $C$ the vertices of a spherical triangle on a sphere of unit radius and center $O$ (see diagram below). Spherical angle $angle ACB=gamma$ is by definition angle $angle ECF$ formed by tangent lines at $C$.



              In right triangles $OCE$ and $OCF$ we have then $EC=tan b$ and $FC=tan a$, so by the cosine rule in triangle $CEF$:



              $$
              EF^2=tan^2 a+tan^2 b-2tan atan bcosgamma.
              $$
              On the other hand we also have $OE=sec b$ and $OF=sec a$, so by the cosine rule in triangle $OEF$:
              $$
              EF^2=sec^2 a+sec^2 b-2sec asec bcos c.
              $$
              Equating the right hand sides of both formulas leads, after some simplifications, to:
              $$
              cos c=cos acos b+sin a sin bcosgamma,
              $$
              which is the spherical cosine rule.



              enter image description here



              This proof works as long as $a$ and $b$ are acute angles, but I think it can also be extended, with some modifications, to the other cases.






              share|cite|improve this answer

























                up vote
                0
                down vote










                up vote
                0
                down vote









                Let $A$, $B$, $C$ the vertices of a spherical triangle on a sphere of unit radius and center $O$ (see diagram below). Spherical angle $angle ACB=gamma$ is by definition angle $angle ECF$ formed by tangent lines at $C$.



                In right triangles $OCE$ and $OCF$ we have then $EC=tan b$ and $FC=tan a$, so by the cosine rule in triangle $CEF$:



                $$
                EF^2=tan^2 a+tan^2 b-2tan atan bcosgamma.
                $$
                On the other hand we also have $OE=sec b$ and $OF=sec a$, so by the cosine rule in triangle $OEF$:
                $$
                EF^2=sec^2 a+sec^2 b-2sec asec bcos c.
                $$
                Equating the right hand sides of both formulas leads, after some simplifications, to:
                $$
                cos c=cos acos b+sin a sin bcosgamma,
                $$
                which is the spherical cosine rule.



                enter image description here



                This proof works as long as $a$ and $b$ are acute angles, but I think it can also be extended, with some modifications, to the other cases.






                share|cite|improve this answer















                Let $A$, $B$, $C$ the vertices of a spherical triangle on a sphere of unit radius and center $O$ (see diagram below). Spherical angle $angle ACB=gamma$ is by definition angle $angle ECF$ formed by tangent lines at $C$.



                In right triangles $OCE$ and $OCF$ we have then $EC=tan b$ and $FC=tan a$, so by the cosine rule in triangle $CEF$:



                $$
                EF^2=tan^2 a+tan^2 b-2tan atan bcosgamma.
                $$
                On the other hand we also have $OE=sec b$ and $OF=sec a$, so by the cosine rule in triangle $OEF$:
                $$
                EF^2=sec^2 a+sec^2 b-2sec asec bcos c.
                $$
                Equating the right hand sides of both formulas leads, after some simplifications, to:
                $$
                cos c=cos acos b+sin a sin bcosgamma,
                $$
                which is the spherical cosine rule.



                enter image description here



                This proof works as long as $a$ and $b$ are acute angles, but I think it can also be extended, with some modifications, to the other cases.







                share|cite|improve this answer















                share|cite|improve this answer



                share|cite|improve this answer








                edited Jul 23 at 14:19


























                answered Jul 23 at 14:11









                Aretino

                21.7k21342




                21.7k21342






















                     

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