Question about equivalence relation that concludes C=D [closed]

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Here is a statement I retrieved from Munkres Topology. It states that for x in a set A



yCx if and only if yDx concludes that C=D. I don’t quite understand how this conclusion come from.







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closed as unclear what you're asking by Andrés E. Caicedo, Mostafa Ayaz, Isaac Browne, Leucippus, Xander Henderson Jul 24 at 0:38


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.














  • Do you know what a relation is, and, as a consequence, when two relations are equal?
    – Adayah
    Jul 23 at 17:36











  • I think two relations are equal if they have the same set of collection of ordered pair ?
    – Ling Min Hao
    Jul 23 at 17:38














up vote
0
down vote

favorite












Here is a statement I retrieved from Munkres Topology. It states that for x in a set A



yCx if and only if yDx concludes that C=D. I don’t quite understand how this conclusion come from.







share|cite|improve this question













closed as unclear what you're asking by Andrés E. Caicedo, Mostafa Ayaz, Isaac Browne, Leucippus, Xander Henderson Jul 24 at 0:38


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.














  • Do you know what a relation is, and, as a consequence, when two relations are equal?
    – Adayah
    Jul 23 at 17:36











  • I think two relations are equal if they have the same set of collection of ordered pair ?
    – Ling Min Hao
    Jul 23 at 17:38












up vote
0
down vote

favorite









up vote
0
down vote

favorite











Here is a statement I retrieved from Munkres Topology. It states that for x in a set A



yCx if and only if yDx concludes that C=D. I don’t quite understand how this conclusion come from.







share|cite|improve this question













Here is a statement I retrieved from Munkres Topology. It states that for x in a set A



yCx if and only if yDx concludes that C=D. I don’t quite understand how this conclusion come from.









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 23 at 18:09









Andrés E. Caicedo

63.2k7151235




63.2k7151235









asked Jul 23 at 17:34









Ling Min Hao

31118




31118




closed as unclear what you're asking by Andrés E. Caicedo, Mostafa Ayaz, Isaac Browne, Leucippus, Xander Henderson Jul 24 at 0:38


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.






closed as unclear what you're asking by Andrés E. Caicedo, Mostafa Ayaz, Isaac Browne, Leucippus, Xander Henderson Jul 24 at 0:38


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.













  • Do you know what a relation is, and, as a consequence, when two relations are equal?
    – Adayah
    Jul 23 at 17:36











  • I think two relations are equal if they have the same set of collection of ordered pair ?
    – Ling Min Hao
    Jul 23 at 17:38
















  • Do you know what a relation is, and, as a consequence, when two relations are equal?
    – Adayah
    Jul 23 at 17:36











  • I think two relations are equal if they have the same set of collection of ordered pair ?
    – Ling Min Hao
    Jul 23 at 17:38















Do you know what a relation is, and, as a consequence, when two relations are equal?
– Adayah
Jul 23 at 17:36





Do you know what a relation is, and, as a consequence, when two relations are equal?
– Adayah
Jul 23 at 17:36













I think two relations are equal if they have the same set of collection of ordered pair ?
– Ling Min Hao
Jul 23 at 17:38




I think two relations are equal if they have the same set of collection of ordered pair ?
– Ling Min Hao
Jul 23 at 17:38










1 Answer
1






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up vote
1
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accepted










From the context, I am guessing that $C$ and $D$ are relations on the same set $A$. The formal definition of relation is a set of ordered pairs. So both $C$ and $D$ are subsets of $A times A$.



The syntactic sugar notation for a relation $Rsubseteq A times A$ is to write $x mathrelR y$ when $(x,y) in R$. So the statement $y mathrelC x iff y mathrelD x$ is syntactically equivalent to $(y,x) in C iff (y,x) in D$. But this is equivalent to $C = D$ as sets.






share|cite|improve this answer




























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    1
    down vote



    accepted










    From the context, I am guessing that $C$ and $D$ are relations on the same set $A$. The formal definition of relation is a set of ordered pairs. So both $C$ and $D$ are subsets of $A times A$.



    The syntactic sugar notation for a relation $Rsubseteq A times A$ is to write $x mathrelR y$ when $(x,y) in R$. So the statement $y mathrelC x iff y mathrelD x$ is syntactically equivalent to $(y,x) in C iff (y,x) in D$. But this is equivalent to $C = D$ as sets.






    share|cite|improve this answer

























      up vote
      1
      down vote



      accepted










      From the context, I am guessing that $C$ and $D$ are relations on the same set $A$. The formal definition of relation is a set of ordered pairs. So both $C$ and $D$ are subsets of $A times A$.



      The syntactic sugar notation for a relation $Rsubseteq A times A$ is to write $x mathrelR y$ when $(x,y) in R$. So the statement $y mathrelC x iff y mathrelD x$ is syntactically equivalent to $(y,x) in C iff (y,x) in D$. But this is equivalent to $C = D$ as sets.






      share|cite|improve this answer























        up vote
        1
        down vote



        accepted







        up vote
        1
        down vote



        accepted






        From the context, I am guessing that $C$ and $D$ are relations on the same set $A$. The formal definition of relation is a set of ordered pairs. So both $C$ and $D$ are subsets of $A times A$.



        The syntactic sugar notation for a relation $Rsubseteq A times A$ is to write $x mathrelR y$ when $(x,y) in R$. So the statement $y mathrelC x iff y mathrelD x$ is syntactically equivalent to $(y,x) in C iff (y,x) in D$. But this is equivalent to $C = D$ as sets.






        share|cite|improve this answer













        From the context, I am guessing that $C$ and $D$ are relations on the same set $A$. The formal definition of relation is a set of ordered pairs. So both $C$ and $D$ are subsets of $A times A$.



        The syntactic sugar notation for a relation $Rsubseteq A times A$ is to write $x mathrelR y$ when $(x,y) in R$. So the statement $y mathrelC x iff y mathrelD x$ is syntactically equivalent to $(y,x) in C iff (y,x) in D$. But this is equivalent to $C = D$ as sets.







        share|cite|improve this answer













        share|cite|improve this answer



        share|cite|improve this answer











        answered Jul 23 at 17:52









        Matthew Leingang

        15k12143




        15k12143












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