Mixing
Uncontextualized square root of $nu$ over a Euclidian norm
Clash Royale CLAN TAG#URR8PPP
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I have not seen this v show up anywhere else in the paper, and then it pops up here. What would it be?
Full paper here
$$minleft[1, fracsqrtvmathbfW_i,cdot right]$$
Can I assume this is an Euclidian norm operation on the row $i$? Why is the two in subscript?
The original notation from the paper is
linear-algebra matrices stochastic-processes
edited Aug 3 at 4:06
Michael Hardy
204k23185460
asked Aug 3 at 1:19
user2723494
31
add a comment |Â
up vote
0
down vote
favorite
I have not seen this v show up anywhere else in the paper, and then it pops up here. What would it be?
Full paper here
$$minleft[1, fracsqrtvmathbfW_i,cdot right]$$
Can I assume this is an Euclidian norm operation on the row $i$? Why is the two in subscript?
The original notation from the paper is
linear-algebra matrices stochastic-processes
edited Aug 3 at 4:06
Michael Hardy
204k23185460
asked Aug 3 at 1:19
user2723494
31
1
Typically $|cdot|_p$ denotes the $p$-norm. For vector $v = (v_1, v_2, dotsc, v_n)$, this would be the value $|v|_p = sqrt[p]^p + $. With $p=2$, we recover the usual Euclidean norm. That being said, I don't have the energy to read through that entire paper to find the equation that you are interested in and parse all of the notation leading up to it. It would be helpful if you added some details to your question.
– Xander Henderson
Aug 3 at 1:46
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have not seen this v show up anywhere else in the paper, and then it pops up here. What would it be?
Full paper here
$$minleft[1, fracsqrtvmathbfW_i,cdot right]$$
Can I assume this is an Euclidian norm operation on the row $i$? Why is the two in subscript?
The original notation from the paper is
linear-algebra matrices stochastic-processes
edited Aug 3 at 4:06
Michael Hardy
204k23185460
asked Aug 3 at 1:19
user2723494
31
I have not seen this v show up anywhere else in the paper, and then it pops up here. What would it be?
Full paper here
$$minleft[1, fracsqrtvmathbfW_i,cdot right]$$
Can I assume this is an Euclidian norm operation on the row $i$? Why is the two in subscript?
The original notation from the paper is
linear-algebra matrices stochastic-processes
edited Aug 3 at 4:06
Michael Hardy
204k23185460
asked Aug 3 at 1:19
user2723494
31
edited Aug 3 at 4:06
Michael Hardy
204k23185460
edited Aug 3 at 4:06
Michael Hardy
204k23185460
edited Aug 3 at 4:06
Michael Hardy
204k23185460
204k23185460
asked Aug 3 at 1:19
user2723494
31
asked Aug 3 at 1:19
user2723494
31
asked Aug 3 at 1:19
user2723494
31
31
1
Typically $|cdot|_p$ denotes the $p$-norm. For vector $v = (v_1, v_2, dotsc, v_n)$, this would be the value $|v|_p = sqrt[p]^p + $. With $p=2$, we recover the usual Euclidean norm. That being said, I don't have the energy to read through that entire paper to find the equation that you are interested in and parse all of the notation leading up to it. It would be helpful if you added some details to your question.
– Xander Henderson
Aug 3 at 1:46
add a comment |Â
1
Typically $|cdot|_p$ denotes the $p$-norm. For vector $v = (v_1, v_2, dotsc, v_n)$, this would be the value $|v|_p = sqrt[p]^p + $. With $p=2$, we recover the usual Euclidean norm. That being said, I don't have the energy to read through that entire paper to find the equation that you are interested in and parse all of the notation leading up to it. It would be helpful if you added some details to your question.
– Xander Henderson
Aug 3 at 1:46
1
1
Typically $|cdot|_p$ denotes the $p$-norm. For vector $v = (v_1, v_2, dotsc, v_n)$, this would be the value $|v|_p = sqrt[p]^p + $. With $p=2$, we recover the usual Euclidean norm. That being said, I don't have the energy to read through that entire paper to find the equation that you are interested in and parse all of the notation leading up to it. It would be helpful if you added some details to your question.
– Xander Henderson
Aug 3 at 1:46
Typically $|cdot|_p$ denotes the $p$-norm. For vector $v = (v_1, v_2, dotsc, v_n)$, this would be the value $|v|_p = sqrt[p]^p + $. With $p=2$, we recover the usual Euclidean norm. That being said, I don't have the energy to read through that entire paper to find the equation that you are interested in and parse all of the notation leading up to it. It would be helpful if you added some details to your question.
– Xander Henderson
Aug 3 at 1:46
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
0
down vote
accepted
The paper explains it perfectly:
"...where $nu in mathbbR^+$ is a regularization parameter...", that is, a scalar parameter that governs the "smoothness" of a function. It is basically the length of the weight vector; the smaller that length, the simpler and smoother the function.
The "2" in $| cdot |_2$ means the squared norm, i.e., $sqrtx_1^2 + x_2^2 + ldots$. If it had be an "3", then $sqrt[3]x_1^3 + x_2^3 + ldots $
answered Aug 3 at 1:28
David G. Stork
7,3202728
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
The paper explains it perfectly:
"...where $nu in mathbbR^+$ is a regularization parameter...", that is, a scalar parameter that governs the "smoothness" of a function. It is basically the length of the weight vector; the smaller that length, the simpler and smoother the function.
The "2" in $| cdot |_2$ means the squared norm, i.e., $sqrtx_1^2 + x_2^2 + ldots$. If it had be an "3", then $sqrt[3]x_1^3 + x_2^3 + ldots $
answered Aug 3 at 1:28
David G. Stork
7,3202728
add a comment |Â
up vote
0
down vote
accepted
The paper explains it perfectly:
"...where $nu in mathbbR^+$ is a regularization parameter...", that is, a scalar parameter that governs the "smoothness" of a function. It is basically the length of the weight vector; the smaller that length, the simpler and smoother the function.
The "2" in $| cdot |_2$ means the squared norm, i.e., $sqrtx_1^2 + x_2^2 + ldots$. If it had be an "3", then $sqrt[3]x_1^3 + x_2^3 + ldots $
answered Aug 3 at 1:28
David G. Stork
7,3202728
add a comment |Â
up vote
0
down vote
accepted
up vote
0
down vote
accepted
The paper explains it perfectly:
"...where $nu in mathbbR^+$ is a regularization parameter...", that is, a scalar parameter that governs the "smoothness" of a function. It is basically the length of the weight vector; the smaller that length, the simpler and smoother the function.
The "2" in $| cdot |_2$ means the squared norm, i.e., $sqrtx_1^2 + x_2^2 + ldots$. If it had be an "3", then $sqrt[3]x_1^3 + x_2^3 + ldots $
answered Aug 3 at 1:28
David G. Stork
7,3202728
The paper explains it perfectly:
"...where $nu in mathbbR^+$ is a regularization parameter...", that is, a scalar parameter that governs the "smoothness" of a function. It is basically the length of the weight vector; the smaller that length, the simpler and smoother the function.
The "2" in $| cdot |_2$ means the squared norm, i.e., $sqrtx_1^2 + x_2^2 + ldots$. If it had be an "3", then $sqrt[3]x_1^3 + x_2^3 + ldots $
answered Aug 3 at 1:28
David G. Stork
7,3202728
edited Aug 3 at 1:31
answered Aug 3 at 1:28
David G. Stork
7,3202728
answered Aug 3 at 1:28
David G. Stork
7,3202728
answered Aug 3 at 1:28
David G. Stork
7,3202728
7,3202728
add a comment |Â
add a comment |Â
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1
Typically $|cdot|_p$ denotes the $p$-norm. For vector $v = (v_1, v_2, dotsc, v_n)$, this would be the value $|v|_p = sqrt[p]^p + $. With $p=2$, we recover the usual Euclidean norm. That being said, I don't have the energy to read through that entire paper to find the equation that you are interested in and parse all of the notation leading up to it. It would be helpful if you added some details to your question.
– Xander Henderson
Aug 3 at 1:46