What is this divisibility pattern called?

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Say I take the primes up to $P$, then there is a pattern of numbers that are divisible by those primes which is periodic every $kcdot P#$. What is this called, and is it symmetrical?



Also, since overlapping the prime elimination pattern with a translation of itself by +2 yields primes $n$ where $n-2$ is prime, why does the fact that no elimination pattern exists where this overlay creates a repeating pattern of sequential eliminations (i.e. there is no way for a repeating pattern to eliminate all $n$ after some point), not prove the infinitude of $n$?







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  • Yes, it's symmetric, since $P#-n$ has the same divisors as $n$.
    – joriki
    Aug 3 at 11:39















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Say I take the primes up to $P$, then there is a pattern of numbers that are divisible by those primes which is periodic every $kcdot P#$. What is this called, and is it symmetrical?



Also, since overlapping the prime elimination pattern with a translation of itself by +2 yields primes $n$ where $n-2$ is prime, why does the fact that no elimination pattern exists where this overlay creates a repeating pattern of sequential eliminations (i.e. there is no way for a repeating pattern to eliminate all $n$ after some point), not prove the infinitude of $n$?







share|cite|improve this question















This question has an open bounty worth +50
reputation from Daniel Castle ending ending at 2018-08-12 15:28:41Z">in 5 days.


Looking for an answer drawing from credible and/or official sources.















  • Yes, it's symmetric, since $P#-n$ has the same divisors as $n$.
    – joriki
    Aug 3 at 11:39













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Say I take the primes up to $P$, then there is a pattern of numbers that are divisible by those primes which is periodic every $kcdot P#$. What is this called, and is it symmetrical?



Also, since overlapping the prime elimination pattern with a translation of itself by +2 yields primes $n$ where $n-2$ is prime, why does the fact that no elimination pattern exists where this overlay creates a repeating pattern of sequential eliminations (i.e. there is no way for a repeating pattern to eliminate all $n$ after some point), not prove the infinitude of $n$?







share|cite|improve this question













Say I take the primes up to $P$, then there is a pattern of numbers that are divisible by those primes which is periodic every $kcdot P#$. What is this called, and is it symmetrical?



Also, since overlapping the prime elimination pattern with a translation of itself by +2 yields primes $n$ where $n-2$ is prime, why does the fact that no elimination pattern exists where this overlay creates a repeating pattern of sequential eliminations (i.e. there is no way for a repeating pattern to eliminate all $n$ after some point), not prove the infinitude of $n$?









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Aug 3 at 11:37









joriki

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164k10179328









asked Aug 3 at 0:14









Daniel Castle

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366315






This question has an open bounty worth +50
reputation from Daniel Castle ending ending at 2018-08-12 15:28:41Z">in 5 days.


Looking for an answer drawing from credible and/or official sources.








This question has an open bounty worth +50
reputation from Daniel Castle ending ending at 2018-08-12 15:28:41Z">in 5 days.


Looking for an answer drawing from credible and/or official sources.













  • Yes, it's symmetric, since $P#-n$ has the same divisors as $n$.
    – joriki
    Aug 3 at 11:39

















  • Yes, it's symmetric, since $P#-n$ has the same divisors as $n$.
    – joriki
    Aug 3 at 11:39
















Yes, it's symmetric, since $P#-n$ has the same divisors as $n$.
– joriki
Aug 3 at 11:39





Yes, it's symmetric, since $P#-n$ has the same divisors as $n$.
– joriki
Aug 3 at 11:39
















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