A question on sequence.

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Given a sequence $$u_n = fracBigl(1+bigl(-1bigr)^nBigr)+15n+6$$ Find the number of terms of the sequence $u_n$ which satisfy the condition $ u_n in Bigl(frac1100,frac39100Bigr)$




My approach :



First I considered n to a odd natural number . I got the following inequality



$$frac1100 < frac15n+6 < frac39100 $$ Then considering n to be a even natural number : $$ frac1100 < frac35n+6 < frac39100$$



In both the cases I approximated the values of $n$, then found the number of odd and even natural number that lies within that range. My answer was 38. But the correct answer is 18. So please mention those range of odd $n$ values and even $n$ values , it will be very helpful for me and i can find where i did the mistake. And if there is a different approach to this question then please mention that too. I will be glad to know.







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  • 2




    To the OP: to prevent your questions from consistently getting down- and close-votes, please add your thoughts. To the down/close-voter(s): tell the OP to add context instead of just downvoting!!!
    – Rhys Hughes
    yesterday










  • Thank you sir. @RhysHughes. If you all comment below, i will definitely correct myself. But please don't down vote the question.
    – Identicon
    yesterday






  • 1




    you need to edit the question and add your thoughts on it or the down-votes will just keep coming...
    – Rhys Hughes
    yesterday










  • Ok sir, I will surely add them too . Thanks for your help.
    – Identicon
    yesterday






  • 1




    @Identicon I solved your problem here math.stackexchange.com/questions/2872249 If you want to see my solution undelete this topic and write your trying.
    – Michael Rozenberg
    yesterday














up vote
0
down vote

favorite
1












Given a sequence $$u_n = fracBigl(1+bigl(-1bigr)^nBigr)+15n+6$$ Find the number of terms of the sequence $u_n$ which satisfy the condition $ u_n in Bigl(frac1100,frac39100Bigr)$




My approach :



First I considered n to a odd natural number . I got the following inequality



$$frac1100 < frac15n+6 < frac39100 $$ Then considering n to be a even natural number : $$ frac1100 < frac35n+6 < frac39100$$



In both the cases I approximated the values of $n$, then found the number of odd and even natural number that lies within that range. My answer was 38. But the correct answer is 18. So please mention those range of odd $n$ values and even $n$ values , it will be very helpful for me and i can find where i did the mistake. And if there is a different approach to this question then please mention that too. I will be glad to know.







share|cite|improve this question

















  • 2




    To the OP: to prevent your questions from consistently getting down- and close-votes, please add your thoughts. To the down/close-voter(s): tell the OP to add context instead of just downvoting!!!
    – Rhys Hughes
    yesterday










  • Thank you sir. @RhysHughes. If you all comment below, i will definitely correct myself. But please don't down vote the question.
    – Identicon
    yesterday






  • 1




    you need to edit the question and add your thoughts on it or the down-votes will just keep coming...
    – Rhys Hughes
    yesterday










  • Ok sir, I will surely add them too . Thanks for your help.
    – Identicon
    yesterday






  • 1




    @Identicon I solved your problem here math.stackexchange.com/questions/2872249 If you want to see my solution undelete this topic and write your trying.
    – Michael Rozenberg
    yesterday












up vote
0
down vote

favorite
1









up vote
0
down vote

favorite
1






1





Given a sequence $$u_n = fracBigl(1+bigl(-1bigr)^nBigr)+15n+6$$ Find the number of terms of the sequence $u_n$ which satisfy the condition $ u_n in Bigl(frac1100,frac39100Bigr)$




My approach :



First I considered n to a odd natural number . I got the following inequality



$$frac1100 < frac15n+6 < frac39100 $$ Then considering n to be a even natural number : $$ frac1100 < frac35n+6 < frac39100$$



In both the cases I approximated the values of $n$, then found the number of odd and even natural number that lies within that range. My answer was 38. But the correct answer is 18. So please mention those range of odd $n$ values and even $n$ values , it will be very helpful for me and i can find where i did the mistake. And if there is a different approach to this question then please mention that too. I will be glad to know.







share|cite|improve this question













Given a sequence $$u_n = fracBigl(1+bigl(-1bigr)^nBigr)+15n+6$$ Find the number of terms of the sequence $u_n$ which satisfy the condition $ u_n in Bigl(frac1100,frac39100Bigr)$




My approach :



First I considered n to a odd natural number . I got the following inequality



$$frac1100 < frac15n+6 < frac39100 $$ Then considering n to be a even natural number : $$ frac1100 < frac35n+6 < frac39100$$



In both the cases I approximated the values of $n$, then found the number of odd and even natural number that lies within that range. My answer was 38. But the correct answer is 18. So please mention those range of odd $n$ values and even $n$ values , it will be very helpful for me and i can find where i did the mistake. And if there is a different approach to this question then please mention that too. I will be glad to know.









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited yesterday
























asked yesterday









Identicon

808




808







  • 2




    To the OP: to prevent your questions from consistently getting down- and close-votes, please add your thoughts. To the down/close-voter(s): tell the OP to add context instead of just downvoting!!!
    – Rhys Hughes
    yesterday










  • Thank you sir. @RhysHughes. If you all comment below, i will definitely correct myself. But please don't down vote the question.
    – Identicon
    yesterday






  • 1




    you need to edit the question and add your thoughts on it or the down-votes will just keep coming...
    – Rhys Hughes
    yesterday










  • Ok sir, I will surely add them too . Thanks for your help.
    – Identicon
    yesterday






  • 1




    @Identicon I solved your problem here math.stackexchange.com/questions/2872249 If you want to see my solution undelete this topic and write your trying.
    – Michael Rozenberg
    yesterday












  • 2




    To the OP: to prevent your questions from consistently getting down- and close-votes, please add your thoughts. To the down/close-voter(s): tell the OP to add context instead of just downvoting!!!
    – Rhys Hughes
    yesterday










  • Thank you sir. @RhysHughes. If you all comment below, i will definitely correct myself. But please don't down vote the question.
    – Identicon
    yesterday






  • 1




    you need to edit the question and add your thoughts on it or the down-votes will just keep coming...
    – Rhys Hughes
    yesterday










  • Ok sir, I will surely add them too . Thanks for your help.
    – Identicon
    yesterday






  • 1




    @Identicon I solved your problem here math.stackexchange.com/questions/2872249 If you want to see my solution undelete this topic and write your trying.
    – Michael Rozenberg
    yesterday







2




2




To the OP: to prevent your questions from consistently getting down- and close-votes, please add your thoughts. To the down/close-voter(s): tell the OP to add context instead of just downvoting!!!
– Rhys Hughes
yesterday




To the OP: to prevent your questions from consistently getting down- and close-votes, please add your thoughts. To the down/close-voter(s): tell the OP to add context instead of just downvoting!!!
– Rhys Hughes
yesterday












Thank you sir. @RhysHughes. If you all comment below, i will definitely correct myself. But please don't down vote the question.
– Identicon
yesterday




Thank you sir. @RhysHughes. If you all comment below, i will definitely correct myself. But please don't down vote the question.
– Identicon
yesterday




1




1




you need to edit the question and add your thoughts on it or the down-votes will just keep coming...
– Rhys Hughes
yesterday




you need to edit the question and add your thoughts on it or the down-votes will just keep coming...
– Rhys Hughes
yesterday












Ok sir, I will surely add them too . Thanks for your help.
– Identicon
yesterday




Ok sir, I will surely add them too . Thanks for your help.
– Identicon
yesterday




1




1




@Identicon I solved your problem here math.stackexchange.com/questions/2872249 If you want to see my solution undelete this topic and write your trying.
– Michael Rozenberg
yesterday




@Identicon I solved your problem here math.stackexchange.com/questions/2872249 If you want to see my solution undelete this topic and write your trying.
– Michael Rozenberg
yesterday










2 Answers
2






active

oldest

votes

















up vote
1
down vote



accepted










HINT:
Consider odd $n$ and solve simple inequalities like: $$frac 1 100 < frac 1 5n+ 6 < frac 39 100.$$



Do the same for even $n$.






share|cite|improve this answer





















  • I did the same. But my answer is different from the given answer . So can you complete it so that i can check . Please
    – Identicon
    yesterday










  • and what's your answer? in that case you better show your work in question.
    – pointguard0
    yesterday










  • I edited my question , can you please check it.
    – Identicon
    yesterday






  • 1




    i got the same answer and it seems to me that $18$ is a typo, should've been $38$.
    – pointguard0
    yesterday

















up vote
2
down vote













Hint: For $n=2m$ we get



$$frac1100<frac310m+6<frac39100$$
this becomes $$m<29.4$$
Can you proceed now?






share|cite|improve this answer























  • Shouldn't the $frac99100$ be $frac39100$?
    – Rhys Hughes
    yesterday











  • Thank you for your hint!
    – Dr. Sonnhard Graubner
    yesterday










  • Just corrected!
    – Dr. Sonnhard Graubner
    yesterday










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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










HINT:
Consider odd $n$ and solve simple inequalities like: $$frac 1 100 < frac 1 5n+ 6 < frac 39 100.$$



Do the same for even $n$.






share|cite|improve this answer





















  • I did the same. But my answer is different from the given answer . So can you complete it so that i can check . Please
    – Identicon
    yesterday










  • and what's your answer? in that case you better show your work in question.
    – pointguard0
    yesterday










  • I edited my question , can you please check it.
    – Identicon
    yesterday






  • 1




    i got the same answer and it seems to me that $18$ is a typo, should've been $38$.
    – pointguard0
    yesterday














up vote
1
down vote



accepted










HINT:
Consider odd $n$ and solve simple inequalities like: $$frac 1 100 < frac 1 5n+ 6 < frac 39 100.$$



Do the same for even $n$.






share|cite|improve this answer





















  • I did the same. But my answer is different from the given answer . So can you complete it so that i can check . Please
    – Identicon
    yesterday










  • and what's your answer? in that case you better show your work in question.
    – pointguard0
    yesterday










  • I edited my question , can you please check it.
    – Identicon
    yesterday






  • 1




    i got the same answer and it seems to me that $18$ is a typo, should've been $38$.
    – pointguard0
    yesterday












up vote
1
down vote



accepted







up vote
1
down vote



accepted






HINT:
Consider odd $n$ and solve simple inequalities like: $$frac 1 100 < frac 1 5n+ 6 < frac 39 100.$$



Do the same for even $n$.






share|cite|improve this answer













HINT:
Consider odd $n$ and solve simple inequalities like: $$frac 1 100 < frac 1 5n+ 6 < frac 39 100.$$



Do the same for even $n$.







share|cite|improve this answer













share|cite|improve this answer



share|cite|improve this answer











answered yesterday









pointguard0

516215




516215











  • I did the same. But my answer is different from the given answer . So can you complete it so that i can check . Please
    – Identicon
    yesterday










  • and what's your answer? in that case you better show your work in question.
    – pointguard0
    yesterday










  • I edited my question , can you please check it.
    – Identicon
    yesterday






  • 1




    i got the same answer and it seems to me that $18$ is a typo, should've been $38$.
    – pointguard0
    yesterday
















  • I did the same. But my answer is different from the given answer . So can you complete it so that i can check . Please
    – Identicon
    yesterday










  • and what's your answer? in that case you better show your work in question.
    – pointguard0
    yesterday










  • I edited my question , can you please check it.
    – Identicon
    yesterday






  • 1




    i got the same answer and it seems to me that $18$ is a typo, should've been $38$.
    – pointguard0
    yesterday















I did the same. But my answer is different from the given answer . So can you complete it so that i can check . Please
– Identicon
yesterday




I did the same. But my answer is different from the given answer . So can you complete it so that i can check . Please
– Identicon
yesterday












and what's your answer? in that case you better show your work in question.
– pointguard0
yesterday




and what's your answer? in that case you better show your work in question.
– pointguard0
yesterday












I edited my question , can you please check it.
– Identicon
yesterday




I edited my question , can you please check it.
– Identicon
yesterday




1




1




i got the same answer and it seems to me that $18$ is a typo, should've been $38$.
– pointguard0
yesterday




i got the same answer and it seems to me that $18$ is a typo, should've been $38$.
– pointguard0
yesterday










up vote
2
down vote













Hint: For $n=2m$ we get



$$frac1100<frac310m+6<frac39100$$
this becomes $$m<29.4$$
Can you proceed now?






share|cite|improve this answer























  • Shouldn't the $frac99100$ be $frac39100$?
    – Rhys Hughes
    yesterday











  • Thank you for your hint!
    – Dr. Sonnhard Graubner
    yesterday










  • Just corrected!
    – Dr. Sonnhard Graubner
    yesterday














up vote
2
down vote













Hint: For $n=2m$ we get



$$frac1100<frac310m+6<frac39100$$
this becomes $$m<29.4$$
Can you proceed now?






share|cite|improve this answer























  • Shouldn't the $frac99100$ be $frac39100$?
    – Rhys Hughes
    yesterday











  • Thank you for your hint!
    – Dr. Sonnhard Graubner
    yesterday










  • Just corrected!
    – Dr. Sonnhard Graubner
    yesterday












up vote
2
down vote










up vote
2
down vote









Hint: For $n=2m$ we get



$$frac1100<frac310m+6<frac39100$$
this becomes $$m<29.4$$
Can you proceed now?






share|cite|improve this answer















Hint: For $n=2m$ we get



$$frac1100<frac310m+6<frac39100$$
this becomes $$m<29.4$$
Can you proceed now?







share|cite|improve this answer















share|cite|improve this answer



share|cite|improve this answer








edited yesterday


























answered yesterday









Dr. Sonnhard Graubner

66.6k32659




66.6k32659











  • Shouldn't the $frac99100$ be $frac39100$?
    – Rhys Hughes
    yesterday











  • Thank you for your hint!
    – Dr. Sonnhard Graubner
    yesterday










  • Just corrected!
    – Dr. Sonnhard Graubner
    yesterday
















  • Shouldn't the $frac99100$ be $frac39100$?
    – Rhys Hughes
    yesterday











  • Thank you for your hint!
    – Dr. Sonnhard Graubner
    yesterday










  • Just corrected!
    – Dr. Sonnhard Graubner
    yesterday















Shouldn't the $frac99100$ be $frac39100$?
– Rhys Hughes
yesterday





Shouldn't the $frac99100$ be $frac39100$?
– Rhys Hughes
yesterday













Thank you for your hint!
– Dr. Sonnhard Graubner
yesterday




Thank you for your hint!
– Dr. Sonnhard Graubner
yesterday












Just corrected!
– Dr. Sonnhard Graubner
yesterday




Just corrected!
– Dr. Sonnhard Graubner
yesterday












 

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