A question on sequence.

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Given a sequence $$u_n = fracBigl(1+bigl(-1bigr)^nBigr)+15n+6$$ Find the number of terms of the sequence $u_n$ which satisfy the condition $ u_n in Bigl(frac1100,frac39100Bigr)$
My approach :
First I considered n to a odd natural number . I got the following inequality
$$frac1100 < frac15n+6 < frac39100 $$ Then considering n to be a even natural number : $$ frac1100 < frac35n+6 < frac39100$$
In both the cases I approximated the values of $n$, then found the number of odd and even natural number that lies within that range. My answer was 38. But the correct answer is 18. So please mention those range of odd $n$ values and even $n$ values , it will be very helpful for me and i can find where i did the mistake. And if there is a different approach to this question then please mention that too. I will be glad to know.
sequences-and-series
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show 1 more comment
up vote
0
down vote
favorite
Given a sequence $$u_n = fracBigl(1+bigl(-1bigr)^nBigr)+15n+6$$ Find the number of terms of the sequence $u_n$ which satisfy the condition $ u_n in Bigl(frac1100,frac39100Bigr)$
My approach :
First I considered n to a odd natural number . I got the following inequality
$$frac1100 < frac15n+6 < frac39100 $$ Then considering n to be a even natural number : $$ frac1100 < frac35n+6 < frac39100$$
In both the cases I approximated the values of $n$, then found the number of odd and even natural number that lies within that range. My answer was 38. But the correct answer is 18. So please mention those range of odd $n$ values and even $n$ values , it will be very helpful for me and i can find where i did the mistake. And if there is a different approach to this question then please mention that too. I will be glad to know.
sequences-and-series
2
To the OP: to prevent your questions from consistently getting down- and close-votes, please add your thoughts. To the down/close-voter(s): tell the OP to add context instead of just downvoting!!!
â Rhys Hughes
yesterday
Thank you sir. @RhysHughes. If you all comment below, i will definitely correct myself. But please don't down vote the question.
â Identicon
yesterday
1
you need to edit the question and add your thoughts on it or the down-votes will just keep coming...
â Rhys Hughes
yesterday
Ok sir, I will surely add them too . Thanks for your help.
â Identicon
yesterday
1
@Identicon I solved your problem here math.stackexchange.com/questions/2872249 If you want to see my solution undelete this topic and write your trying.
â Michael Rozenberg
yesterday
 |Â
show 1 more comment
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Given a sequence $$u_n = fracBigl(1+bigl(-1bigr)^nBigr)+15n+6$$ Find the number of terms of the sequence $u_n$ which satisfy the condition $ u_n in Bigl(frac1100,frac39100Bigr)$
My approach :
First I considered n to a odd natural number . I got the following inequality
$$frac1100 < frac15n+6 < frac39100 $$ Then considering n to be a even natural number : $$ frac1100 < frac35n+6 < frac39100$$
In both the cases I approximated the values of $n$, then found the number of odd and even natural number that lies within that range. My answer was 38. But the correct answer is 18. So please mention those range of odd $n$ values and even $n$ values , it will be very helpful for me and i can find where i did the mistake. And if there is a different approach to this question then please mention that too. I will be glad to know.
sequences-and-series
Given a sequence $$u_n = fracBigl(1+bigl(-1bigr)^nBigr)+15n+6$$ Find the number of terms of the sequence $u_n$ which satisfy the condition $ u_n in Bigl(frac1100,frac39100Bigr)$
My approach :
First I considered n to a odd natural number . I got the following inequality
$$frac1100 < frac15n+6 < frac39100 $$ Then considering n to be a even natural number : $$ frac1100 < frac35n+6 < frac39100$$
In both the cases I approximated the values of $n$, then found the number of odd and even natural number that lies within that range. My answer was 38. But the correct answer is 18. So please mention those range of odd $n$ values and even $n$ values , it will be very helpful for me and i can find where i did the mistake. And if there is a different approach to this question then please mention that too. I will be glad to know.
sequences-and-series
edited yesterday
asked yesterday
Identicon
808
808
2
To the OP: to prevent your questions from consistently getting down- and close-votes, please add your thoughts. To the down/close-voter(s): tell the OP to add context instead of just downvoting!!!
â Rhys Hughes
yesterday
Thank you sir. @RhysHughes. If you all comment below, i will definitely correct myself. But please don't down vote the question.
â Identicon
yesterday
1
you need to edit the question and add your thoughts on it or the down-votes will just keep coming...
â Rhys Hughes
yesterday
Ok sir, I will surely add them too . Thanks for your help.
â Identicon
yesterday
1
@Identicon I solved your problem here math.stackexchange.com/questions/2872249 If you want to see my solution undelete this topic and write your trying.
â Michael Rozenberg
yesterday
 |Â
show 1 more comment
2
To the OP: to prevent your questions from consistently getting down- and close-votes, please add your thoughts. To the down/close-voter(s): tell the OP to add context instead of just downvoting!!!
â Rhys Hughes
yesterday
Thank you sir. @RhysHughes. If you all comment below, i will definitely correct myself. But please don't down vote the question.
â Identicon
yesterday
1
you need to edit the question and add your thoughts on it or the down-votes will just keep coming...
â Rhys Hughes
yesterday
Ok sir, I will surely add them too . Thanks for your help.
â Identicon
yesterday
1
@Identicon I solved your problem here math.stackexchange.com/questions/2872249 If you want to see my solution undelete this topic and write your trying.
â Michael Rozenberg
yesterday
2
2
To the OP: to prevent your questions from consistently getting down- and close-votes, please add your thoughts. To the down/close-voter(s): tell the OP to add context instead of just downvoting!!!
â Rhys Hughes
yesterday
To the OP: to prevent your questions from consistently getting down- and close-votes, please add your thoughts. To the down/close-voter(s): tell the OP to add context instead of just downvoting!!!
â Rhys Hughes
yesterday
Thank you sir. @RhysHughes. If you all comment below, i will definitely correct myself. But please don't down vote the question.
â Identicon
yesterday
Thank you sir. @RhysHughes. If you all comment below, i will definitely correct myself. But please don't down vote the question.
â Identicon
yesterday
1
1
you need to edit the question and add your thoughts on it or the down-votes will just keep coming...
â Rhys Hughes
yesterday
you need to edit the question and add your thoughts on it or the down-votes will just keep coming...
â Rhys Hughes
yesterday
Ok sir, I will surely add them too . Thanks for your help.
â Identicon
yesterday
Ok sir, I will surely add them too . Thanks for your help.
â Identicon
yesterday
1
1
@Identicon I solved your problem here math.stackexchange.com/questions/2872249 If you want to see my solution undelete this topic and write your trying.
â Michael Rozenberg
yesterday
@Identicon I solved your problem here math.stackexchange.com/questions/2872249 If you want to see my solution undelete this topic and write your trying.
â Michael Rozenberg
yesterday
 |Â
show 1 more comment
2 Answers
2
active
oldest
votes
up vote
1
down vote
accepted
HINT:
Consider odd $n$ and solve simple inequalities like: $$frac 1 100 < frac 1 5n+ 6 < frac 39 100.$$
Do the same for even $n$.
I did the same. But my answer is different from the given answer . So can you complete it so that i can check . Please
â Identicon
yesterday
and what's your answer? in that case you better show your work in question.
â pointguard0
yesterday
I edited my question , can you please check it.
â Identicon
yesterday
1
i got the same answer and it seems to me that $18$ is a typo, should've been $38$.
â pointguard0
yesterday
add a comment |Â
up vote
2
down vote
Hint: For $n=2m$ we get
$$frac1100<frac310m+6<frac39100$$
this becomes $$m<29.4$$
Can you proceed now?
Shouldn't the $frac99100$ be $frac39100$?
â Rhys Hughes
yesterday
Thank you for your hint!
â Dr. Sonnhard Graubner
yesterday
Just corrected!
â Dr. Sonnhard Graubner
yesterday
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
HINT:
Consider odd $n$ and solve simple inequalities like: $$frac 1 100 < frac 1 5n+ 6 < frac 39 100.$$
Do the same for even $n$.
I did the same. But my answer is different from the given answer . So can you complete it so that i can check . Please
â Identicon
yesterday
and what's your answer? in that case you better show your work in question.
â pointguard0
yesterday
I edited my question , can you please check it.
â Identicon
yesterday
1
i got the same answer and it seems to me that $18$ is a typo, should've been $38$.
â pointguard0
yesterday
add a comment |Â
up vote
1
down vote
accepted
HINT:
Consider odd $n$ and solve simple inequalities like: $$frac 1 100 < frac 1 5n+ 6 < frac 39 100.$$
Do the same for even $n$.
I did the same. But my answer is different from the given answer . So can you complete it so that i can check . Please
â Identicon
yesterday
and what's your answer? in that case you better show your work in question.
â pointguard0
yesterday
I edited my question , can you please check it.
â Identicon
yesterday
1
i got the same answer and it seems to me that $18$ is a typo, should've been $38$.
â pointguard0
yesterday
add a comment |Â
up vote
1
down vote
accepted
up vote
1
down vote
accepted
HINT:
Consider odd $n$ and solve simple inequalities like: $$frac 1 100 < frac 1 5n+ 6 < frac 39 100.$$
Do the same for even $n$.
HINT:
Consider odd $n$ and solve simple inequalities like: $$frac 1 100 < frac 1 5n+ 6 < frac 39 100.$$
Do the same for even $n$.
answered yesterday
pointguard0
516215
516215
I did the same. But my answer is different from the given answer . So can you complete it so that i can check . Please
â Identicon
yesterday
and what's your answer? in that case you better show your work in question.
â pointguard0
yesterday
I edited my question , can you please check it.
â Identicon
yesterday
1
i got the same answer and it seems to me that $18$ is a typo, should've been $38$.
â pointguard0
yesterday
add a comment |Â
I did the same. But my answer is different from the given answer . So can you complete it so that i can check . Please
â Identicon
yesterday
and what's your answer? in that case you better show your work in question.
â pointguard0
yesterday
I edited my question , can you please check it.
â Identicon
yesterday
1
i got the same answer and it seems to me that $18$ is a typo, should've been $38$.
â pointguard0
yesterday
I did the same. But my answer is different from the given answer . So can you complete it so that i can check . Please
â Identicon
yesterday
I did the same. But my answer is different from the given answer . So can you complete it so that i can check . Please
â Identicon
yesterday
and what's your answer? in that case you better show your work in question.
â pointguard0
yesterday
and what's your answer? in that case you better show your work in question.
â pointguard0
yesterday
I edited my question , can you please check it.
â Identicon
yesterday
I edited my question , can you please check it.
â Identicon
yesterday
1
1
i got the same answer and it seems to me that $18$ is a typo, should've been $38$.
â pointguard0
yesterday
i got the same answer and it seems to me that $18$ is a typo, should've been $38$.
â pointguard0
yesterday
add a comment |Â
up vote
2
down vote
Hint: For $n=2m$ we get
$$frac1100<frac310m+6<frac39100$$
this becomes $$m<29.4$$
Can you proceed now?
Shouldn't the $frac99100$ be $frac39100$?
â Rhys Hughes
yesterday
Thank you for your hint!
â Dr. Sonnhard Graubner
yesterday
Just corrected!
â Dr. Sonnhard Graubner
yesterday
add a comment |Â
up vote
2
down vote
Hint: For $n=2m$ we get
$$frac1100<frac310m+6<frac39100$$
this becomes $$m<29.4$$
Can you proceed now?
Shouldn't the $frac99100$ be $frac39100$?
â Rhys Hughes
yesterday
Thank you for your hint!
â Dr. Sonnhard Graubner
yesterday
Just corrected!
â Dr. Sonnhard Graubner
yesterday
add a comment |Â
up vote
2
down vote
up vote
2
down vote
Hint: For $n=2m$ we get
$$frac1100<frac310m+6<frac39100$$
this becomes $$m<29.4$$
Can you proceed now?
Hint: For $n=2m$ we get
$$frac1100<frac310m+6<frac39100$$
this becomes $$m<29.4$$
Can you proceed now?
edited yesterday
answered yesterday
Dr. Sonnhard Graubner
66.6k32659
66.6k32659
Shouldn't the $frac99100$ be $frac39100$?
â Rhys Hughes
yesterday
Thank you for your hint!
â Dr. Sonnhard Graubner
yesterday
Just corrected!
â Dr. Sonnhard Graubner
yesterday
add a comment |Â
Shouldn't the $frac99100$ be $frac39100$?
â Rhys Hughes
yesterday
Thank you for your hint!
â Dr. Sonnhard Graubner
yesterday
Just corrected!
â Dr. Sonnhard Graubner
yesterday
Shouldn't the $frac99100$ be $frac39100$?
â Rhys Hughes
yesterday
Shouldn't the $frac99100$ be $frac39100$?
â Rhys Hughes
yesterday
Thank you for your hint!
â Dr. Sonnhard Graubner
yesterday
Thank you for your hint!
â Dr. Sonnhard Graubner
yesterday
Just corrected!
â Dr. Sonnhard Graubner
yesterday
Just corrected!
â Dr. Sonnhard Graubner
yesterday
add a comment |Â
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2
To the OP: to prevent your questions from consistently getting down- and close-votes, please add your thoughts. To the down/close-voter(s): tell the OP to add context instead of just downvoting!!!
â Rhys Hughes
yesterday
Thank you sir. @RhysHughes. If you all comment below, i will definitely correct myself. But please don't down vote the question.
â Identicon
yesterday
1
you need to edit the question and add your thoughts on it or the down-votes will just keep coming...
â Rhys Hughes
yesterday
Ok sir, I will surely add them too . Thanks for your help.
â Identicon
yesterday
1
@Identicon I solved your problem here math.stackexchange.com/questions/2872249 If you want to see my solution undelete this topic and write your trying.
â Michael Rozenberg
yesterday