Can we solve for $delta$ in $fracÀ2 - fracRrβ = arcsinbiggl(frac(R+r)sin(δ)rbiggr)+fracRrδ$?
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Solve for $delta$:
$$fracpi2 - fracRrβ = arcsinleft(frac(R+r)sin deltarright)+fracRrδ$$
My problem is that I can't comprehend how to get both $delta$s out of a trig operation at the same time. If I apply 'sine' to both sides, I understand the 'arcsine' will be canceled, but does this operation apply 'sine' to $fracRrdelta$ on the right, making it $sinleft(fracRrdeltaright)$ ???
Is this problem a question of a trigonometric derivative?
My second question is perhaps a more important one. I do not have a textbook pertaining to trigonometry, much less trigonometric derivatives. The math book I currently own is about matrices and calculus, but only having to do with 'regular' derivatives; no trigonometry derivatives, obviously.
What is a good textbook for trigonometry (regular trig-algebra)?
What is a good textbook for trigonometry derivatives? Is there a textbook that contains both of these subjects?
Thanks is advance.
algebra-precalculus trigonometry
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up vote
0
down vote
favorite
Solve for $delta$:
$$fracpi2 - fracRrβ = arcsinleft(frac(R+r)sin deltarright)+fracRrδ$$
My problem is that I can't comprehend how to get both $delta$s out of a trig operation at the same time. If I apply 'sine' to both sides, I understand the 'arcsine' will be canceled, but does this operation apply 'sine' to $fracRrdelta$ on the right, making it $sinleft(fracRrdeltaright)$ ???
Is this problem a question of a trigonometric derivative?
My second question is perhaps a more important one. I do not have a textbook pertaining to trigonometry, much less trigonometric derivatives. The math book I currently own is about matrices and calculus, but only having to do with 'regular' derivatives; no trigonometry derivatives, obviously.
What is a good textbook for trigonometry (regular trig-algebra)?
What is a good textbook for trigonometry derivatives? Is there a textbook that contains both of these subjects?
Thanks is advance.
algebra-precalculus trigonometry
You need a numerical method. Remember that $x=cos(x)$ does not show analytical solutions. If you give test values for $r,R,beta$, I could shos you.
– Claude Leibovici
yesterday
You should ask for textbook recommendations in a separate question. That said, do a search first. I'm pretty sure that people have asked for such recommendations a few times.
– Blue
yesterday
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Solve for $delta$:
$$fracpi2 - fracRrβ = arcsinleft(frac(R+r)sin deltarright)+fracRrδ$$
My problem is that I can't comprehend how to get both $delta$s out of a trig operation at the same time. If I apply 'sine' to both sides, I understand the 'arcsine' will be canceled, but does this operation apply 'sine' to $fracRrdelta$ on the right, making it $sinleft(fracRrdeltaright)$ ???
Is this problem a question of a trigonometric derivative?
My second question is perhaps a more important one. I do not have a textbook pertaining to trigonometry, much less trigonometric derivatives. The math book I currently own is about matrices and calculus, but only having to do with 'regular' derivatives; no trigonometry derivatives, obviously.
What is a good textbook for trigonometry (regular trig-algebra)?
What is a good textbook for trigonometry derivatives? Is there a textbook that contains both of these subjects?
Thanks is advance.
algebra-precalculus trigonometry
Solve for $delta$:
$$fracpi2 - fracRrβ = arcsinleft(frac(R+r)sin deltarright)+fracRrδ$$
My problem is that I can't comprehend how to get both $delta$s out of a trig operation at the same time. If I apply 'sine' to both sides, I understand the 'arcsine' will be canceled, but does this operation apply 'sine' to $fracRrdelta$ on the right, making it $sinleft(fracRrdeltaright)$ ???
Is this problem a question of a trigonometric derivative?
My second question is perhaps a more important one. I do not have a textbook pertaining to trigonometry, much less trigonometric derivatives. The math book I currently own is about matrices and calculus, but only having to do with 'regular' derivatives; no trigonometry derivatives, obviously.
What is a good textbook for trigonometry (regular trig-algebra)?
What is a good textbook for trigonometry derivatives? Is there a textbook that contains both of these subjects?
Thanks is advance.
algebra-precalculus trigonometry
edited yesterday


Blue
43.6k868141
43.6k868141
asked yesterday
user101434
44
44
You need a numerical method. Remember that $x=cos(x)$ does not show analytical solutions. If you give test values for $r,R,beta$, I could shos you.
– Claude Leibovici
yesterday
You should ask for textbook recommendations in a separate question. That said, do a search first. I'm pretty sure that people have asked for such recommendations a few times.
– Blue
yesterday
add a comment |Â
You need a numerical method. Remember that $x=cos(x)$ does not show analytical solutions. If you give test values for $r,R,beta$, I could shos you.
– Claude Leibovici
yesterday
You should ask for textbook recommendations in a separate question. That said, do a search first. I'm pretty sure that people have asked for such recommendations a few times.
– Blue
yesterday
You need a numerical method. Remember that $x=cos(x)$ does not show analytical solutions. If you give test values for $r,R,beta$, I could shos you.
– Claude Leibovici
yesterday
You need a numerical method. Remember that $x=cos(x)$ does not show analytical solutions. If you give test values for $r,R,beta$, I could shos you.
– Claude Leibovici
yesterday
You should ask for textbook recommendations in a separate question. That said, do a search first. I'm pretty sure that people have asked for such recommendations a few times.
– Blue
yesterday
You should ask for textbook recommendations in a separate question. That said, do a search first. I'm pretty sure that people have asked for such recommendations a few times.
– Blue
yesterday
add a comment |Â
1 Answer
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Letting $Q = R/r$ and rearranging a bit gives
$$
fracpi2 - Qbeta - Qdelta = arcsin bigl( (Q + 1) sin delta bigr)
$$
then taking $sin(cdot)$ of both sides and using $sin (pi/2 - x) = cos x$ results in
$$
cos bigl( Q(beta + delta) bigr) = (Q + 1) sin delta.
$$
If $Q = 1$ then the equation can be solved exactly. Otherwise, you can rewrite the equation as
$$
delta = f(delta) = arcsin left( fraccos bigl( Q(beta + delta) bigr)Q + 1 right)
$$
and repeatedly apply $f$ to some initial guess for a solution $delta$. It turns out that this fixed-point iteration converges in this particular case.
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
Letting $Q = R/r$ and rearranging a bit gives
$$
fracpi2 - Qbeta - Qdelta = arcsin bigl( (Q + 1) sin delta bigr)
$$
then taking $sin(cdot)$ of both sides and using $sin (pi/2 - x) = cos x$ results in
$$
cos bigl( Q(beta + delta) bigr) = (Q + 1) sin delta.
$$
If $Q = 1$ then the equation can be solved exactly. Otherwise, you can rewrite the equation as
$$
delta = f(delta) = arcsin left( fraccos bigl( Q(beta + delta) bigr)Q + 1 right)
$$
and repeatedly apply $f$ to some initial guess for a solution $delta$. It turns out that this fixed-point iteration converges in this particular case.
add a comment |Â
up vote
2
down vote
Letting $Q = R/r$ and rearranging a bit gives
$$
fracpi2 - Qbeta - Qdelta = arcsin bigl( (Q + 1) sin delta bigr)
$$
then taking $sin(cdot)$ of both sides and using $sin (pi/2 - x) = cos x$ results in
$$
cos bigl( Q(beta + delta) bigr) = (Q + 1) sin delta.
$$
If $Q = 1$ then the equation can be solved exactly. Otherwise, you can rewrite the equation as
$$
delta = f(delta) = arcsin left( fraccos bigl( Q(beta + delta) bigr)Q + 1 right)
$$
and repeatedly apply $f$ to some initial guess for a solution $delta$. It turns out that this fixed-point iteration converges in this particular case.
add a comment |Â
up vote
2
down vote
up vote
2
down vote
Letting $Q = R/r$ and rearranging a bit gives
$$
fracpi2 - Qbeta - Qdelta = arcsin bigl( (Q + 1) sin delta bigr)
$$
then taking $sin(cdot)$ of both sides and using $sin (pi/2 - x) = cos x$ results in
$$
cos bigl( Q(beta + delta) bigr) = (Q + 1) sin delta.
$$
If $Q = 1$ then the equation can be solved exactly. Otherwise, you can rewrite the equation as
$$
delta = f(delta) = arcsin left( fraccos bigl( Q(beta + delta) bigr)Q + 1 right)
$$
and repeatedly apply $f$ to some initial guess for a solution $delta$. It turns out that this fixed-point iteration converges in this particular case.
Letting $Q = R/r$ and rearranging a bit gives
$$
fracpi2 - Qbeta - Qdelta = arcsin bigl( (Q + 1) sin delta bigr)
$$
then taking $sin(cdot)$ of both sides and using $sin (pi/2 - x) = cos x$ results in
$$
cos bigl( Q(beta + delta) bigr) = (Q + 1) sin delta.
$$
If $Q = 1$ then the equation can be solved exactly. Otherwise, you can rewrite the equation as
$$
delta = f(delta) = arcsin left( fraccos bigl( Q(beta + delta) bigr)Q + 1 right)
$$
and repeatedly apply $f$ to some initial guess for a solution $delta$. It turns out that this fixed-point iteration converges in this particular case.
answered yesterday
D. G.
464
464
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You need a numerical method. Remember that $x=cos(x)$ does not show analytical solutions. If you give test values for $r,R,beta$, I could shos you.
– Claude Leibovici
yesterday
You should ask for textbook recommendations in a separate question. That said, do a search first. I'm pretty sure that people have asked for such recommendations a few times.
– Blue
yesterday