Casino problem Similar to Roulette
Clash Royale CLAN TAG#URR8PPP
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Consider a Setup similar to roulette , but here we have 1-36 numbers.
Where Number 12,24 and 36 gives 17 Times , but rest of the numbers gives 34 times amount that is bid on number.
While the calculation of Casino house edge, I am having doubt at my way of calculation
As the probability of getting a number is 1/36 in Idle setup.
Now if we bid on the number which is one of the 33 number(one that returns 34 times), the probability is (1/33)
house edge would be (1/33)*34-(32/33)
Now if we are bidding on one of the number that returns 17 times ie . 12 ,24 and 36
Then would the house edge be (1/3)* 17 -(2/3)
I am bit doubtfull of my calculation , can someone suggest or confirm about my steps of house edge calculation.
probability
add a comment |Â
up vote
1
down vote
favorite
Consider a Setup similar to roulette , but here we have 1-36 numbers.
Where Number 12,24 and 36 gives 17 Times , but rest of the numbers gives 34 times amount that is bid on number.
While the calculation of Casino house edge, I am having doubt at my way of calculation
As the probability of getting a number is 1/36 in Idle setup.
Now if we bid on the number which is one of the 33 number(one that returns 34 times), the probability is (1/33)
house edge would be (1/33)*34-(32/33)
Now if we are bidding on one of the number that returns 17 times ie . 12 ,24 and 36
Then would the house edge be (1/3)* 17 -(2/3)
I am bit doubtfull of my calculation , can someone suggest or confirm about my steps of house edge calculation.
probability
Why would anybody ever bet on $12$ or $24$ or $36$?
– Henry
yesterday
i do agree with you , but if it is there then can you tell me what i am doing is right in calculations.To make problem more biased to these three number , say if person gets 12 then he or she wins 34 times plus 17 time the bid.
– Anup Bali
yesterday
Say person gets 12 or 24 or 36 , he or she wins 34 plus 17 times the bid
– Anup Bali
23 hours ago
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Consider a Setup similar to roulette , but here we have 1-36 numbers.
Where Number 12,24 and 36 gives 17 Times , but rest of the numbers gives 34 times amount that is bid on number.
While the calculation of Casino house edge, I am having doubt at my way of calculation
As the probability of getting a number is 1/36 in Idle setup.
Now if we bid on the number which is one of the 33 number(one that returns 34 times), the probability is (1/33)
house edge would be (1/33)*34-(32/33)
Now if we are bidding on one of the number that returns 17 times ie . 12 ,24 and 36
Then would the house edge be (1/3)* 17 -(2/3)
I am bit doubtfull of my calculation , can someone suggest or confirm about my steps of house edge calculation.
probability
Consider a Setup similar to roulette , but here we have 1-36 numbers.
Where Number 12,24 and 36 gives 17 Times , but rest of the numbers gives 34 times amount that is bid on number.
While the calculation of Casino house edge, I am having doubt at my way of calculation
As the probability of getting a number is 1/36 in Idle setup.
Now if we bid on the number which is one of the 33 number(one that returns 34 times), the probability is (1/33)
house edge would be (1/33)*34-(32/33)
Now if we are bidding on one of the number that returns 17 times ie . 12 ,24 and 36
Then would the house edge be (1/3)* 17 -(2/3)
I am bit doubtfull of my calculation , can someone suggest or confirm about my steps of house edge calculation.
probability
asked yesterday


Anup Bali
92
92
Why would anybody ever bet on $12$ or $24$ or $36$?
– Henry
yesterday
i do agree with you , but if it is there then can you tell me what i am doing is right in calculations.To make problem more biased to these three number , say if person gets 12 then he or she wins 34 times plus 17 time the bid.
– Anup Bali
yesterday
Say person gets 12 or 24 or 36 , he or she wins 34 plus 17 times the bid
– Anup Bali
23 hours ago
add a comment |Â
Why would anybody ever bet on $12$ or $24$ or $36$?
– Henry
yesterday
i do agree with you , but if it is there then can you tell me what i am doing is right in calculations.To make problem more biased to these three number , say if person gets 12 then he or she wins 34 times plus 17 time the bid.
– Anup Bali
yesterday
Say person gets 12 or 24 or 36 , he or she wins 34 plus 17 times the bid
– Anup Bali
23 hours ago
Why would anybody ever bet on $12$ or $24$ or $36$?
– Henry
yesterday
Why would anybody ever bet on $12$ or $24$ or $36$?
– Henry
yesterday
i do agree with you , but if it is there then can you tell me what i am doing is right in calculations.To make problem more biased to these three number , say if person gets 12 then he or she wins 34 times plus 17 time the bid.
– Anup Bali
yesterday
i do agree with you , but if it is there then can you tell me what i am doing is right in calculations.To make problem more biased to these three number , say if person gets 12 then he or she wins 34 times plus 17 time the bid.
– Anup Bali
yesterday
Say person gets 12 or 24 or 36 , he or she wins 34 plus 17 times the bid
– Anup Bali
23 hours ago
Say person gets 12 or 24 or 36 , he or she wins 34 plus 17 times the bid
– Anup Bali
23 hours ago
add a comment |Â
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Why would anybody ever bet on $12$ or $24$ or $36$?
– Henry
yesterday
i do agree with you , but if it is there then can you tell me what i am doing is right in calculations.To make problem more biased to these three number , say if person gets 12 then he or she wins 34 times plus 17 time the bid.
– Anup Bali
yesterday
Say person gets 12 or 24 or 36 , he or she wins 34 plus 17 times the bid
– Anup Bali
23 hours ago