Complementary minor of a kernel of given full-rank matrix $A$ is equal to minor of $A$.

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
0
down vote

favorite












Let $d leq n$, $d,n inmathbbN$. Suppose $beginpmatrixA & B endpmatrix,beginpmatrixC \ D endpmatrix$ be a block matrix with $A in Mat_mathbbZ^dtimes d,B in Mat_mathbbZ^dtimes (n-d), C in Mat_mathbbZ^dtimes (n-d), D in Mat_mathbbZ^(n-d)times (n-)d$ such that 1) $beginpmatrixA & B endpmatrix$ has rank $d$ and 2) $$beginpmatrixA & B endpmatrixbeginpmatrixC \ D endpmatrix = 0 $$
which is equivalent to say
$$AC + BD=0.$$
Also suppose that each columns of $beginpmatrixC \ D endpmatrix$ consists of a $mathbbZ$-basis of $ker beginpmatrixA & B endpmatrix$.
Then can we say $det(A) = det(D)$? It is mentioned in some book as a basic fact of linear algebra, but I don't know how to prove it. Any hint will be appreciated.







share|cite|improve this question

























    up vote
    0
    down vote

    favorite












    Let $d leq n$, $d,n inmathbbN$. Suppose $beginpmatrixA & B endpmatrix,beginpmatrixC \ D endpmatrix$ be a block matrix with $A in Mat_mathbbZ^dtimes d,B in Mat_mathbbZ^dtimes (n-d), C in Mat_mathbbZ^dtimes (n-d), D in Mat_mathbbZ^(n-d)times (n-)d$ such that 1) $beginpmatrixA & B endpmatrix$ has rank $d$ and 2) $$beginpmatrixA & B endpmatrixbeginpmatrixC \ D endpmatrix = 0 $$
    which is equivalent to say
    $$AC + BD=0.$$
    Also suppose that each columns of $beginpmatrixC \ D endpmatrix$ consists of a $mathbbZ$-basis of $ker beginpmatrixA & B endpmatrix$.
    Then can we say $det(A) = det(D)$? It is mentioned in some book as a basic fact of linear algebra, but I don't know how to prove it. Any hint will be appreciated.







    share|cite|improve this question























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Let $d leq n$, $d,n inmathbbN$. Suppose $beginpmatrixA & B endpmatrix,beginpmatrixC \ D endpmatrix$ be a block matrix with $A in Mat_mathbbZ^dtimes d,B in Mat_mathbbZ^dtimes (n-d), C in Mat_mathbbZ^dtimes (n-d), D in Mat_mathbbZ^(n-d)times (n-)d$ such that 1) $beginpmatrixA & B endpmatrix$ has rank $d$ and 2) $$beginpmatrixA & B endpmatrixbeginpmatrixC \ D endpmatrix = 0 $$
      which is equivalent to say
      $$AC + BD=0.$$
      Also suppose that each columns of $beginpmatrixC \ D endpmatrix$ consists of a $mathbbZ$-basis of $ker beginpmatrixA & B endpmatrix$.
      Then can we say $det(A) = det(D)$? It is mentioned in some book as a basic fact of linear algebra, but I don't know how to prove it. Any hint will be appreciated.







      share|cite|improve this question













      Let $d leq n$, $d,n inmathbbN$. Suppose $beginpmatrixA & B endpmatrix,beginpmatrixC \ D endpmatrix$ be a block matrix with $A in Mat_mathbbZ^dtimes d,B in Mat_mathbbZ^dtimes (n-d), C in Mat_mathbbZ^dtimes (n-d), D in Mat_mathbbZ^(n-d)times (n-)d$ such that 1) $beginpmatrixA & B endpmatrix$ has rank $d$ and 2) $$beginpmatrixA & B endpmatrixbeginpmatrixC \ D endpmatrix = 0 $$
      which is equivalent to say
      $$AC + BD=0.$$
      Also suppose that each columns of $beginpmatrixC \ D endpmatrix$ consists of a $mathbbZ$-basis of $ker beginpmatrixA & B endpmatrix$.
      Then can we say $det(A) = det(D)$? It is mentioned in some book as a basic fact of linear algebra, but I don't know how to prove it. Any hint will be appreciated.









      share|cite|improve this question












      share|cite|improve this question




      share|cite|improve this question








      edited Aug 6 at 3:43
























      asked Aug 6 at 2:57









      user124697

      607512




      607512




















          1 Answer
          1






          active

          oldest

          votes

















          up vote
          1
          down vote



          accepted










          Take $d=1$ and $n=2$; let $A=3$, $B=0$, $C=0$, $D=1$. These satisfy the hypotheses, yet $det Anot= det D$.






          share|cite|improve this answer























          • Thank you for very simple counterexample :)
            – user124697
            Aug 6 at 18:54










          Your Answer




          StackExchange.ifUsing("editor", function ()
          return StackExchange.using("mathjaxEditing", function ()
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          );
          );
          , "mathjax-editing");

          StackExchange.ready(function()
          var channelOptions =
          tags: "".split(" "),
          id: "69"
          ;
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function()
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled)
          StackExchange.using("snippets", function()
          createEditor();
          );

          else
          createEditor();

          );

          function createEditor()
          StackExchange.prepareEditor(
          heartbeatType: 'answer',
          convertImagesToLinks: true,
          noModals: false,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          );



          );








           

          draft saved


          draft discarded


















          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2873550%2fcomplementary-minor-of-a-kernel-of-given-full-rank-matrix-a-is-equal-to-minor%23new-answer', 'question_page');

          );

          Post as a guest






























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          1
          down vote



          accepted










          Take $d=1$ and $n=2$; let $A=3$, $B=0$, $C=0$, $D=1$. These satisfy the hypotheses, yet $det Anot= det D$.






          share|cite|improve this answer























          • Thank you for very simple counterexample :)
            – user124697
            Aug 6 at 18:54














          up vote
          1
          down vote



          accepted










          Take $d=1$ and $n=2$; let $A=3$, $B=0$, $C=0$, $D=1$. These satisfy the hypotheses, yet $det Anot= det D$.






          share|cite|improve this answer























          • Thank you for very simple counterexample :)
            – user124697
            Aug 6 at 18:54












          up vote
          1
          down vote



          accepted







          up vote
          1
          down vote



          accepted






          Take $d=1$ and $n=2$; let $A=3$, $B=0$, $C=0$, $D=1$. These satisfy the hypotheses, yet $det Anot= det D$.






          share|cite|improve this answer















          Take $d=1$ and $n=2$; let $A=3$, $B=0$, $C=0$, $D=1$. These satisfy the hypotheses, yet $det Anot= det D$.







          share|cite|improve this answer















          share|cite|improve this answer



          share|cite|improve this answer








          edited Aug 6 at 8:14


























          answered Aug 6 at 6:25









          ancientmathematician

          4,1381312




          4,1381312











          • Thank you for very simple counterexample :)
            – user124697
            Aug 6 at 18:54
















          • Thank you for very simple counterexample :)
            – user124697
            Aug 6 at 18:54















          Thank you for very simple counterexample :)
          – user124697
          Aug 6 at 18:54




          Thank you for very simple counterexample :)
          – user124697
          Aug 6 at 18:54












           

          draft saved


          draft discarded


























           


          draft saved


          draft discarded














          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2873550%2fcomplementary-minor-of-a-kernel-of-given-full-rank-matrix-a-is-equal-to-minor%23new-answer', 'question_page');

          );

          Post as a guest













































































          Comments

          Popular posts from this blog

          What is the equation of a 3D cone with generalised tilt?

          Color the edges and diagonals of a regular polygon

          Relationship between determinant of matrix and determinant of adjoint?