Complementary minor of a kernel of given full-rank matrix $A$ is equal to minor of $A$.
Clash Royale CLAN TAG#URR8PPP
up vote
0
down vote
favorite
Let $d leq n$, $d,n inmathbbN$. Suppose $beginpmatrixA & B endpmatrix,beginpmatrixC \ D endpmatrix$ be a block matrix with $A in Mat_mathbbZ^dtimes d,B in Mat_mathbbZ^dtimes (n-d), C in Mat_mathbbZ^dtimes (n-d), D in Mat_mathbbZ^(n-d)times (n-)d$ such that 1) $beginpmatrixA & B endpmatrix$ has rank $d$ and 2) $$beginpmatrixA & B endpmatrixbeginpmatrixC \ D endpmatrix = 0 $$
which is equivalent to say
$$AC + BD=0.$$
Also suppose that each columns of $beginpmatrixC \ D endpmatrix$ consists of a $mathbbZ$-basis of $ker beginpmatrixA & B endpmatrix$.
Then can we say $det(A) = det(D)$? It is mentioned in some book as a basic fact of linear algebra, but I don't know how to prove it. Any hint will be appreciated.
linear-algebra change-of-basis
add a comment |Â
up vote
0
down vote
favorite
Let $d leq n$, $d,n inmathbbN$. Suppose $beginpmatrixA & B endpmatrix,beginpmatrixC \ D endpmatrix$ be a block matrix with $A in Mat_mathbbZ^dtimes d,B in Mat_mathbbZ^dtimes (n-d), C in Mat_mathbbZ^dtimes (n-d), D in Mat_mathbbZ^(n-d)times (n-)d$ such that 1) $beginpmatrixA & B endpmatrix$ has rank $d$ and 2) $$beginpmatrixA & B endpmatrixbeginpmatrixC \ D endpmatrix = 0 $$
which is equivalent to say
$$AC + BD=0.$$
Also suppose that each columns of $beginpmatrixC \ D endpmatrix$ consists of a $mathbbZ$-basis of $ker beginpmatrixA & B endpmatrix$.
Then can we say $det(A) = det(D)$? It is mentioned in some book as a basic fact of linear algebra, but I don't know how to prove it. Any hint will be appreciated.
linear-algebra change-of-basis
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Let $d leq n$, $d,n inmathbbN$. Suppose $beginpmatrixA & B endpmatrix,beginpmatrixC \ D endpmatrix$ be a block matrix with $A in Mat_mathbbZ^dtimes d,B in Mat_mathbbZ^dtimes (n-d), C in Mat_mathbbZ^dtimes (n-d), D in Mat_mathbbZ^(n-d)times (n-)d$ such that 1) $beginpmatrixA & B endpmatrix$ has rank $d$ and 2) $$beginpmatrixA & B endpmatrixbeginpmatrixC \ D endpmatrix = 0 $$
which is equivalent to say
$$AC + BD=0.$$
Also suppose that each columns of $beginpmatrixC \ D endpmatrix$ consists of a $mathbbZ$-basis of $ker beginpmatrixA & B endpmatrix$.
Then can we say $det(A) = det(D)$? It is mentioned in some book as a basic fact of linear algebra, but I don't know how to prove it. Any hint will be appreciated.
linear-algebra change-of-basis
Let $d leq n$, $d,n inmathbbN$. Suppose $beginpmatrixA & B endpmatrix,beginpmatrixC \ D endpmatrix$ be a block matrix with $A in Mat_mathbbZ^dtimes d,B in Mat_mathbbZ^dtimes (n-d), C in Mat_mathbbZ^dtimes (n-d), D in Mat_mathbbZ^(n-d)times (n-)d$ such that 1) $beginpmatrixA & B endpmatrix$ has rank $d$ and 2) $$beginpmatrixA & B endpmatrixbeginpmatrixC \ D endpmatrix = 0 $$
which is equivalent to say
$$AC + BD=0.$$
Also suppose that each columns of $beginpmatrixC \ D endpmatrix$ consists of a $mathbbZ$-basis of $ker beginpmatrixA & B endpmatrix$.
Then can we say $det(A) = det(D)$? It is mentioned in some book as a basic fact of linear algebra, but I don't know how to prove it. Any hint will be appreciated.
linear-algebra change-of-basis
edited Aug 6 at 3:43
asked Aug 6 at 2:57
user124697
607512
607512
add a comment |Â
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
Take $d=1$ and $n=2$; let $A=3$, $B=0$, $C=0$, $D=1$. These satisfy the hypotheses, yet $det Anot= det D$.
Thank you for very simple counterexample :)
â user124697
Aug 6 at 18:54
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Take $d=1$ and $n=2$; let $A=3$, $B=0$, $C=0$, $D=1$. These satisfy the hypotheses, yet $det Anot= det D$.
Thank you for very simple counterexample :)
â user124697
Aug 6 at 18:54
add a comment |Â
up vote
1
down vote
accepted
Take $d=1$ and $n=2$; let $A=3$, $B=0$, $C=0$, $D=1$. These satisfy the hypotheses, yet $det Anot= det D$.
Thank you for very simple counterexample :)
â user124697
Aug 6 at 18:54
add a comment |Â
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Take $d=1$ and $n=2$; let $A=3$, $B=0$, $C=0$, $D=1$. These satisfy the hypotheses, yet $det Anot= det D$.
Take $d=1$ and $n=2$; let $A=3$, $B=0$, $C=0$, $D=1$. These satisfy the hypotheses, yet $det Anot= det D$.
edited Aug 6 at 8:14
answered Aug 6 at 6:25
ancientmathematician
4,1381312
4,1381312
Thank you for very simple counterexample :)
â user124697
Aug 6 at 18:54
add a comment |Â
Thank you for very simple counterexample :)
â user124697
Aug 6 at 18:54
Thank you for very simple counterexample :)
â user124697
Aug 6 at 18:54
Thank you for very simple counterexample :)
â user124697
Aug 6 at 18:54
add a comment |Â
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2873550%2fcomplementary-minor-of-a-kernel-of-given-full-rank-matrix-a-is-equal-to-minor%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password