Volume of $(n-1)$- simplex in $n$-dimension.
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This post gives a general way to calculate $k$-simplex in $n$-dimensional space with $kleq n$. My question is, if $k=n-1$ and give vertices $v_0, cdots, v_n-1$ are linearly independent, can we show that the simplex $S$ generated by $v_0, cdots , v_n-1$ has a volume $Vol(S) = frac1n!detbeginpmatrixbf v_0 & cdots & bf v_n-1endpmatrix$?
linear-algebra volume simplex
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This post gives a general way to calculate $k$-simplex in $n$-dimensional space with $kleq n$. My question is, if $k=n-1$ and give vertices $v_0, cdots, v_n-1$ are linearly independent, can we show that the simplex $S$ generated by $v_0, cdots , v_n-1$ has a volume $Vol(S) = frac1n!detbeginpmatrixbf v_0 & cdots & bf v_n-1endpmatrix$?
linear-algebra volume simplex
1
Surely the volume is zero? The (affine) dimension of the set $operatornameaff v_0,...,v_n-1 $ is $n-1$. For example, if $n=2$ we can take the simplex generated by $e_1,e_2$ which is just s line segment and hence has measure zero.
â copper.hat
Aug 6 at 2:28
@copper.hat Oh, I think the case when we calculate the volume of it as that in the some $n-1$-dimensional hyperplane.
â user124697
Aug 6 at 2:34
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
This post gives a general way to calculate $k$-simplex in $n$-dimensional space with $kleq n$. My question is, if $k=n-1$ and give vertices $v_0, cdots, v_n-1$ are linearly independent, can we show that the simplex $S$ generated by $v_0, cdots , v_n-1$ has a volume $Vol(S) = frac1n!detbeginpmatrixbf v_0 & cdots & bf v_n-1endpmatrix$?
linear-algebra volume simplex
This post gives a general way to calculate $k$-simplex in $n$-dimensional space with $kleq n$. My question is, if $k=n-1$ and give vertices $v_0, cdots, v_n-1$ are linearly independent, can we show that the simplex $S$ generated by $v_0, cdots , v_n-1$ has a volume $Vol(S) = frac1n!detbeginpmatrixbf v_0 & cdots & bf v_n-1endpmatrix$?
linear-algebra volume simplex
asked Aug 6 at 2:11
user124697
607512
607512
1
Surely the volume is zero? The (affine) dimension of the set $operatornameaff v_0,...,v_n-1 $ is $n-1$. For example, if $n=2$ we can take the simplex generated by $e_1,e_2$ which is just s line segment and hence has measure zero.
â copper.hat
Aug 6 at 2:28
@copper.hat Oh, I think the case when we calculate the volume of it as that in the some $n-1$-dimensional hyperplane.
â user124697
Aug 6 at 2:34
add a comment |Â
1
Surely the volume is zero? The (affine) dimension of the set $operatornameaff v_0,...,v_n-1 $ is $n-1$. For example, if $n=2$ we can take the simplex generated by $e_1,e_2$ which is just s line segment and hence has measure zero.
â copper.hat
Aug 6 at 2:28
@copper.hat Oh, I think the case when we calculate the volume of it as that in the some $n-1$-dimensional hyperplane.
â user124697
Aug 6 at 2:34
1
1
Surely the volume is zero? The (affine) dimension of the set $operatornameaff v_0,...,v_n-1 $ is $n-1$. For example, if $n=2$ we can take the simplex generated by $e_1,e_2$ which is just s line segment and hence has measure zero.
â copper.hat
Aug 6 at 2:28
Surely the volume is zero? The (affine) dimension of the set $operatornameaff v_0,...,v_n-1 $ is $n-1$. For example, if $n=2$ we can take the simplex generated by $e_1,e_2$ which is just s line segment and hence has measure zero.
â copper.hat
Aug 6 at 2:28
@copper.hat Oh, I think the case when we calculate the volume of it as that in the some $n-1$-dimensional hyperplane.
â user124697
Aug 6 at 2:34
@copper.hat Oh, I think the case when we calculate the volume of it as that in the some $n-1$-dimensional hyperplane.
â user124697
Aug 6 at 2:34
add a comment |Â
1 Answer
1
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1
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accepted
I think this is a direct consequence of the Cayley-Menger determinant.
Thanks! I got it.
â user124697
Aug 6 at 2:35
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
I think this is a direct consequence of the Cayley-Menger determinant.
Thanks! I got it.
â user124697
Aug 6 at 2:35
add a comment |Â
up vote
1
down vote
accepted
I think this is a direct consequence of the Cayley-Menger determinant.
Thanks! I got it.
â user124697
Aug 6 at 2:35
add a comment |Â
up vote
1
down vote
accepted
up vote
1
down vote
accepted
I think this is a direct consequence of the Cayley-Menger determinant.
I think this is a direct consequence of the Cayley-Menger determinant.
answered Aug 6 at 2:30
Jimmy Mixco
2013
2013
Thanks! I got it.
â user124697
Aug 6 at 2:35
add a comment |Â
Thanks! I got it.
â user124697
Aug 6 at 2:35
Thanks! I got it.
â user124697
Aug 6 at 2:35
Thanks! I got it.
â user124697
Aug 6 at 2:35
add a comment |Â
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1
Surely the volume is zero? The (affine) dimension of the set $operatornameaff v_0,...,v_n-1 $ is $n-1$. For example, if $n=2$ we can take the simplex generated by $e_1,e_2$ which is just s line segment and hence has measure zero.
â copper.hat
Aug 6 at 2:28
@copper.hat Oh, I think the case when we calculate the volume of it as that in the some $n-1$-dimensional hyperplane.
â user124697
Aug 6 at 2:34