How often will two random integers between one and three (boundary inclusive) be the same?

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
-2
down vote

favorite












Assuming the answer is one out of three? And, also, would this be a good distillation of how to understand the "Monty Hall" problem?




probability monty-hall




share|cite|improve this question





















  • The connection with the Monty Hall problem seems slender. In that problem, everything depends on the superior knowledge of the host. You get information from the fact that Monty does not open a certain door. Hard to connect that up to a truly random draw.
    – lulu
    Aug 6 at 0:06














up vote
-2
down vote

favorite












Assuming the answer is one out of three? And, also, would this be a good distillation of how to understand the "Monty Hall" problem?




probability monty-hall




share|cite|improve this question





















  • The connection with the Monty Hall problem seems slender. In that problem, everything depends on the superior knowledge of the host. You get information from the fact that Monty does not open a certain door. Hard to connect that up to a truly random draw.
    – lulu
    Aug 6 at 0:06












up vote
-2
down vote

favorite









up vote
-2
down vote

favorite











Assuming the answer is one out of three? And, also, would this be a good distillation of how to understand the "Monty Hall" problem?




probability monty-hall




share|cite|improve this question













Assuming the answer is one out of three? And, also, would this be a good distillation of how to understand the "Monty Hall" problem?





probability monty-hall





share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Aug 5 at 23:56
























asked Aug 5 at 23:39









user92272

11




11











  • The connection with the Monty Hall problem seems slender. In that problem, everything depends on the superior knowledge of the host. You get information from the fact that Monty does not open a certain door. Hard to connect that up to a truly random draw.
    – lulu
    Aug 6 at 0:06
















  • The connection with the Monty Hall problem seems slender. In that problem, everything depends on the superior knowledge of the host. You get information from the fact that Monty does not open a certain door. Hard to connect that up to a truly random draw.
    – lulu
    Aug 6 at 0:06















The connection with the Monty Hall problem seems slender. In that problem, everything depends on the superior knowledge of the host. You get information from the fact that Monty does not open a certain door. Hard to connect that up to a truly random draw.
– lulu
Aug 6 at 0:06




The connection with the Monty Hall problem seems slender. In that problem, everything depends on the superior knowledge of the host. You get information from the fact that Monty does not open a certain door. Hard to connect that up to a truly random draw.
– lulu
Aug 6 at 0:06










1 Answer
1






active

oldest

votes

















up vote
1
down vote













If the numbers are integers then 1/3, but how does this relate to monty hall at all?






share|cite|improve this answer





















  • Thanks Dean. So I've been making a concerted effort to simplify Monty Hall into the easiest way to understand (for myself at least). The lightbulb for me was in the fact that it only makes sense to NOT shift to the remaining door, if you actually happened to have guessed correctly initially, but that only happens 33% of the time, so you are always advantaged by switching. So in attempting to distill that down even further, success rate in shifting to the remaining door would be the same as the probability of two random numbers between one and three NOT being the same, which would be 2/3.
    – user92272
    Aug 5 at 23:46











Your Answer




StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "69"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: false,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);








 

draft saved


draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2873436%2fhow-often-will-two-random-integers-between-one-and-three-boundary-inclusive-be%23new-answer', 'question_page');

);

Post as a guest

















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote













If the numbers are integers then 1/3, but how does this relate to monty hall at all?






share|cite|improve this answer





















  • Thanks Dean. So I've been making a concerted effort to simplify Monty Hall into the easiest way to understand (for myself at least). The lightbulb for me was in the fact that it only makes sense to NOT shift to the remaining door, if you actually happened to have guessed correctly initially, but that only happens 33% of the time, so you are always advantaged by switching. So in attempting to distill that down even further, success rate in shifting to the remaining door would be the same as the probability of two random numbers between one and three NOT being the same, which would be 2/3.
    – user92272
    Aug 5 at 23:46















up vote
1
down vote













If the numbers are integers then 1/3, but how does this relate to monty hall at all?






share|cite|improve this answer





















  • Thanks Dean. So I've been making a concerted effort to simplify Monty Hall into the easiest way to understand (for myself at least). The lightbulb for me was in the fact that it only makes sense to NOT shift to the remaining door, if you actually happened to have guessed correctly initially, but that only happens 33% of the time, so you are always advantaged by switching. So in attempting to distill that down even further, success rate in shifting to the remaining door would be the same as the probability of two random numbers between one and three NOT being the same, which would be 2/3.
    – user92272
    Aug 5 at 23:46













up vote
1
down vote










up vote
1
down vote









If the numbers are integers then 1/3, but how does this relate to monty hall at all?






share|cite|improve this answer













If the numbers are integers then 1/3, but how does this relate to monty hall at all?







share|cite|improve this answer













share|cite|improve this answer



share|cite|improve this answer











answered Aug 5 at 23:41









Dean Yang

1388




1388











  • Thanks Dean. So I've been making a concerted effort to simplify Monty Hall into the easiest way to understand (for myself at least). The lightbulb for me was in the fact that it only makes sense to NOT shift to the remaining door, if you actually happened to have guessed correctly initially, but that only happens 33% of the time, so you are always advantaged by switching. So in attempting to distill that down even further, success rate in shifting to the remaining door would be the same as the probability of two random numbers between one and three NOT being the same, which would be 2/3.
    – user92272
    Aug 5 at 23:46

















  • Thanks Dean. So I've been making a concerted effort to simplify Monty Hall into the easiest way to understand (for myself at least). The lightbulb for me was in the fact that it only makes sense to NOT shift to the remaining door, if you actually happened to have guessed correctly initially, but that only happens 33% of the time, so you are always advantaged by switching. So in attempting to distill that down even further, success rate in shifting to the remaining door would be the same as the probability of two random numbers between one and three NOT being the same, which would be 2/3.
    – user92272
    Aug 5 at 23:46
















Thanks Dean. So I've been making a concerted effort to simplify Monty Hall into the easiest way to understand (for myself at least). The lightbulb for me was in the fact that it only makes sense to NOT shift to the remaining door, if you actually happened to have guessed correctly initially, but that only happens 33% of the time, so you are always advantaged by switching. So in attempting to distill that down even further, success rate in shifting to the remaining door would be the same as the probability of two random numbers between one and three NOT being the same, which would be 2/3.
– user92272
Aug 5 at 23:46





Thanks Dean. So I've been making a concerted effort to simplify Monty Hall into the easiest way to understand (for myself at least). The lightbulb for me was in the fact that it only makes sense to NOT shift to the remaining door, if you actually happened to have guessed correctly initially, but that only happens 33% of the time, so you are always advantaged by switching. So in attempting to distill that down even further, success rate in shifting to the remaining door would be the same as the probability of two random numbers between one and three NOT being the same, which would be 2/3.
– user92272
Aug 5 at 23:46













 

draft saved


draft discarded


























 


draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2873436%2fhow-often-will-two-random-integers-between-one-and-three-boundary-inclusive-be%23new-answer', 'question_page');

);

Post as a guest
































































Comments

Post a Comment

Popular posts from this blog

What is the equation of a 3D cone with generalised tilt?

Image
Clash Royale CLAN TAG #URR8PPP up vote 2 down vote favorite What is the equation of a 3D cone with generalized tilt? I've noticed that in most equations given to represent a cone, there is no parameter which defines the tilt of the cone in 3D space and that most of them have their point at the origin $(0,0,0)$ - I was wondering if anyone could give me a more generalized cone equation for a cone in any position in 3D space 3d share | cite | improve this question edited Jul 25 '16 at 0:05 ervx 9,425 3 13 36 asked Jul 24 '16 at 15:38 Charlene 11 2 2 Welcome to Math.SE! Could you please explain a few things to help people give an answer useful to you: 1. What do you mean by "generalized tilt"? 2. Are you asking about a right circular cone? Does the angle at the vertex matter? 3. What form of answer (implicit, parametric...?) are you looking for? 4. If this is homework, what tools do you have available, an...
Read more

Relationship between determinant of matrix and determinant of adjoint?

Image
Clash Royale CLAN TAG #URR8PPP up vote 2 down vote favorite We are studying adjoints in class, and I was curious if there is a relationship between the determinant of matrix A, and the determinant of the adjoint of matrix A? I assume there would be a relationship because finding the adjoint requires creating a cofactor matrix and then transposing it. linear-algebra determinant adjoint-operators share | cite | improve this question asked Nov 17 '17 at 17:32 CluelessCoder 32 5 For a square matrix $A$ of order $n$, we have $A(operatornameadj A)=(operatornameadj A)A=|A|I_n$ where $I_n$ is the identity matrix of order $n$. This should tell you about the determinant of the adjoint in terms of that of $A$ (use multiplicative property and other elementary properties of determinants). – Prasun Biswas Nov 17 '17 at 17:35 1 @CluelessCoder: see here: math.stackexchange.com/questions/516127/…...
Read more

Color the edges and diagonals of a regular polygon

Image
Clash Royale CLAN TAG #URR8PPP up vote 5 down vote favorite 1 Here is the problem: For what $n$ is it possible to color the edges and diagonals of an $n$-side regular polygon with $dfracbinomn23$ colors, such that you use every color exactly three times and for every color the three segments (edges or diagonals) with that color form a triangle? Trivially $nequiv 0 text or 1 pmod3$. I can also prove that if the statement is true for $k$ than it is true for $3k$ as well. How to finish? Please help! Thanks combinatorial-geometry share | cite | improve this question edited Aug 6 at 21:57 alcana 118 4 asked Aug 6 at 21:15 Leo Gardner 356 11 Even assuming "polyhpn" in the title is a typo for polygon , it is unclear what you mean by "the edges and sides". Aren't the side of a regular polygon the same as the edges? A regular $n$-sided polygon has $n$ edges. – hardmath Aug 6 at 21:20 3 $n$ ne...
Read more