complexity - boolean circle and the class EXP

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I would like to have some help on the following question on complexity topic:



Prove: For every $k in mathbbN$, there is a language $Ain EXP$, such that $A$ have no series of boolean-circles $c_1, c_2, c_3...$ ,such that for every $nin mathbbN$, the size of $c_n$ is $n^k$.



($c_n$ gets input in length n)



I think that the proper way is to prove it by contradiction, but I don't really know how..



Any help will be appreciated! =)




computational-complexity




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    up vote
    0
    down vote

    favorite












    I would like to have some help on the following question on complexity topic:



    Prove: For every $k in mathbbN$, there is a language $Ain EXP$, such that $A$ have no series of boolean-circles $c_1, c_2, c_3...$ ,such that for every $nin mathbbN$, the size of $c_n$ is $n^k$.



    ($c_n$ gets input in length n)



    I think that the proper way is to prove it by contradiction, but I don't really know how..



    Any help will be appreciated! =)




    computational-complexity




    share|cite|improve this question





















      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I would like to have some help on the following question on complexity topic:



      Prove: For every $k in mathbbN$, there is a language $Ain EXP$, such that $A$ have no series of boolean-circles $c_1, c_2, c_3...$ ,such that for every $nin mathbbN$, the size of $c_n$ is $n^k$.



      ($c_n$ gets input in length n)



      I think that the proper way is to prove it by contradiction, but I don't really know how..



      Any help will be appreciated! =)




      computational-complexity




      share|cite|improve this question











      I would like to have some help on the following question on complexity topic:



      Prove: For every $k in mathbbN$, there is a language $Ain EXP$, such that $A$ have no series of boolean-circles $c_1, c_2, c_3...$ ,such that for every $nin mathbbN$, the size of $c_n$ is $n^k$.



      ($c_n$ gets input in length n)



      I think that the proper way is to prove it by contradiction, but I don't really know how..



      Any help will be appreciated! =)





      computational-complexity





      share|cite|improve this question










      share|cite|improve this question




      share|cite|improve this question









      asked Jul 22 at 9:03









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